This question already has answers here:
How to parse month full form string using DateFormat in Java?
(4 answers)
Closed 2 years ago.
I want to convert this date but parse exemption it should be like this result "2019-12-28 14:00:00"
try {
String strCurrentDate = "April 08 2020 4:24 AM"
SimpleDateFormat format = new SimpleDateFormat("MMM dd yyyy hh:mm a");
Date newDate = format.parse(strCurrentDate);
format = new SimpleDateFormat("MMM dd,yyyy hh:mm a");
String date = format.format(newDate);
Log.d("datessscc", date);
} catch (ParseException e) {
e.printStackTrace();
}
Please change your SimpleDateFormat
Try This:
SimpleDateFormat input = new SimpleDateFormat("MMM dd yyyy hh:mm a");
SimpleDateFormat output = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try {
Date getAbbreviate=input.parse("May 22 2020 4:22 AM"); // parse input
Log.i("ouput_Date", "onCreate: "+output.format(getAbbreviate)); // format output
String date=output.format(getAbbreviate);
} catch (ParseException e) {
e.printStackTrace();
}
Related
This question already has answers here:
java.text.ParseException: Unparseable date
(10 answers)
Closed 3 years ago.
I'm attempting to parse a new Date object, but I keep hitting the following error.
W/System.err: java.text.ParseException: Unparseable date: "Thu May 16 09:28:39 GMT+01:00 2019"
I've attempted various different patterns for dateFormat, but nothing seems to work.
This is where the error is.
c.setTime(dateFormat.parse(oldDate));
Code
public static String addDay(int numberOfDays) {
String oldDate = String.valueOf(new Date());
SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy'T'HH:mm:ss", Locale.ENGLISH);
Calendar c = Calendar.getInstance();
try {
c.setTime(dateFormat.parse(oldDate));
} catch (ParseException e) {
e.printStackTrace();
}
c.add(Calendar.DAY_OF_YEAR,numberOfDays);
dateFormat=new SimpleDateFormat("dd-MM-yyyy'T'HH:mm:ss", Locale.ENGLISH);
Date newDate=new Date(c.getTimeInMillis());
String resultDate=dateFormat.format(newDate);
return resultDate;
}
Try This function
In your question you are converting Date to string
then after you are once again Parsing String to Date
that is very Long way. you can directly set as
c.setTime(oldDate);
public static String addDay(int numberOfDays) {
Date oldDate = new Date();
SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy'T'HH:mm:ss", Locale.ENGLISH);
Calendar c = Calendar.getInstance();
c.setTime(oldDate);
c.add(Calendar.DAY_OF_YEAR,numberOfDays);
dateFormat=new SimpleDateFormat("dd-MM-yyyy'T'HH:mm:ss", Locale.ENGLISH);
Date newDate=new Date(c.getTimeInMillis());
String resultDate=dateFormat.format(newDate);
return resultDate;
}
The pattern should be like :
SimpleDateFormat sdf = new SimpleDateFormat("EE MMM dd HH:mm:ss z yyyy",
Locale.ENGLISH);
Then to print you need a second SimpleDateFormat:
Date parsedDate = sdf.parse(date);
SimpleDateFormat print = new SimpleDateFormat("MMM d, yyyy HH:mm:ss");
System.out.println(print.format(parsedDate));
Your pattern is wrong. You should use EEE MMM dd HH:mm:ss z yyyy
This question already has an answer here:
Fri Mar 30 00:00:00 CET 14 to dd/mm/yyyy
(1 answer)
Closed 5 years ago.
I have class which receives Date in string format from other class. It is now receiving two different formats
Format 1: YYYY_MM_DD
Format 2: EEE MMM dd HH:mm:ss z yyyy
now I want to write a method which receives this string and convert it into required format like this 'DDMMMYYYY '
You can try brute force to parse catching the exceptions:
edit:
using the java8 API (adapt the format as you need/want)
public String convertDateFormatJ8(String format) {
String retFormat = "ddMMyyy";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("[yyyy_dd_MM][yyyy-MM-dd HH:mm]");
try {
LocalDateTime localDate = LocalDateTime.parse(format, formatter);
return localDate.format(DateTimeFormatter.ofPattern(retFormat));
} catch (DateTimeParseException ex) {
System.err.println("impossible to parse to yyyy-MM-dd HH:mm");
}
try {
LocalDate localDate = LocalDate.parse(format, formatter);
return localDate.format(DateTimeFormatter.ofPattern(retFormat));
} catch (DateTimeParseException ex) {
System.err.println("impossible to parse to yyyy_dd_MM");
}
return null;
}
for old java versions
public String convertDateFormat(String format) {
DateFormat df1 = new SimpleDateFormat("YYYY_MM_DD");
DateFormat df2 = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
DateFormat dfResult = new SimpleDateFormat("DDMMMYYYY ");
Date d = null;
try {
d = df1.parse(format);
return dfResult.format(d);
} catch (ParseException e) {
System.err.println("impossible to parse to " + "YYYY_MM_DD");
}
try {
d = df2.parse(format);
return dfResult.format(d);
} catch (ParseException e) {
System.err.println("impossible to parse to " + "EEE MMM dd HH:mm:ss z yyyy");
}
return null;
}
if you give any other invalid string, the string returned will be null!
You can use this approach and declare optional section in pattern :
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("[yyyy_MM_dd][EEE MMM dd HH:mm:ss Z yyyy]", Locale.ENGLISH);
This formatter will parse date for both patterns and then you can easily convert it to required format.
P.S. I've tested it but not sure which date should be parsable for EEE MMM dd HH:mm:ss Z yyyy template. So just play with it and use Java 8 approaches (Java Time)
This question already has answers here:
Illegal pattern character 'T' when parsing a date string to java.util.Date
(4 answers)
Converting ISO 8601-compliant String to java.util.Date
(31 answers)
Closed 7 years ago.
I'm getting the above Date format from our webservice. I have an idea on how to format the date, im just having issues with the fact it comes down as a string.
I have tried this but I need to return it as a String, which in a way isn't a problem.
This is what I have tried but it throws an Exception:
java.text.ParseException: Unparseable date:
"2016-02-26T00:00:00+02:00" (at offset 4)
Code:
public static String formatDate(String unFormattedTime) {
String formattedTime;
try {
SimpleDateFormat sdf = new SimpleDateFormat("dd MMM HH:mm");
Date date = sdf.parse(unFormattedTime);
formattedTime = sdf.format(date);
return formattedTime;
} catch (ParseException e) {
e.printStackTrace();
}
return "";
}
How could I format it in a format like dd MMM HH:mm?
Here you are with a working snippet of what you want to achieve:
public class FormatDateExample {
public static void main(String[] args) {
String date = "2016-02-26T00:00:00+02:00";
System.out.println(formatDate(date));
}
public static String formatDate(String unFormattedTime) {
String formattedTime;
try {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
Date date = sdf.parse(unFormattedTime);
sdf = new SimpleDateFormat("dd MMM HH:mm");
formattedTime = sdf.format(date);
return formattedTime;
} catch (ParseException e) {
e.printStackTrace();
}
return "";
}
}
First you have to parse the date with the given format you have
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
Date date = sdf.parse(unFormattedTime);
Then you have to format that date to the desired format "dd MMM HH:mm"
sdf = new SimpleDateFormat("dd MMM HH:mm");
formattedTime = sdf.format(date);
If you are using Java 8 you can try this:
LocalDate parsedDate = LocalDate.parse(unFormattedTime, ISO_OFFSET_DATE_TIME)
Ref:
https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html
https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html#ISO_OFFSET_DATE_TIME
This question already has answers here:
java date format yyyy-mm-dd.hh.MM.ss.ms
(3 answers)
Closed 7 years ago.
I have a date string which is as follows:
2015-12-24 08:06:44
Now I have a parse function:
public static String parseDate(String date) {
Date oldDate = null;
try {
System.out.println("Unparsed: "+date);
DateFormat oldFormat = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
oldDate = oldFormat.parse(date);
System.out.println("old Date parsed: "+oldDate);
DateFormat newFormat = new SimpleDateFormat("yyyy-mm-dd", Locale.ENGLISH);
Date result = newFormat.parse(oldDate.toString());
return result.toString();
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
The first System.out gives me:
Unparsed: 2015-12-24 08:06:44
The second one:
Sat Jan 24 08:06:44 GMT+05:30 2015
Whereas for the second one I have clearly mentioned the date format to be as:
new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
Please advise on what's wrong here
I only want to get the month and day from the input string - Desired would be Dec 24 from the above sample date string.
Its MM for month not mm.
DateFormat oldFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss a");
SimpleDateFormat doc
I have a program in which i will get date in the below format "2015-01-17"
Please tell me how can i convert this data to this format JAN 17 2015 .
import java.text.SimpleDateFormat;
public class TestDate {
public static void main(String args[]) throws Exception
{
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat sdf2 = new SimpleDateFormat("yyyy-MM-dd");
String s1 = "2015-01-17 ";
System.out.println("Result==> "+sdf1.format(sdf2.parse(s1)));
}
}
Change your sdf2 to use the MMM dd yyyy format instead...
String text = "2015-01-17";
try {
SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat sdf2 = new SimpleDateFormat("MMM dd yyyy");
Date date = sdf1.parse(text);
System.out.println("Result==> " + sdf2.format(date));
} catch (ParseException exp) {
exp.printStackTrace();
}
Which outputs...
Result==> Jan 17 2015
try this way
SimpleDateFormat formatter = new SimpleDateFormat("dd-MM-yyyy");
String dateInString = "2015-01-17";
try {
Date date = formatter.parse(dateInString);
System.out.println(date);
System.out.println(formatter.format(date));
} catch (ParseException e) {
e.printStackTrace();
}
According to the SimpleDateFormat documentation, you should be able to do that by parsing a date as follows: MMM dd yyyy.