lets say there are two tables TICKET and USER
table USER(username, password, roles)
Table TICKET(ticketname,users_assigned)
the problem in the TICKET table is how can I have attribute List in table TICKET. can someone guide me on how to make the TICKET table. coz I'm planning to implement the Ticket table with List as a property using java Spring Data JPA ORM.but I don't know how to create tables that go with it
I was thinking maybe have another table TicketUser(username,ticketname). I just want to know if there's a better way to design this. thanks in advance.
Your thinking is correct.
First Step : add an id column to all you tables
second step : create a table TicketUser (userId, ticketId) referencing the respective foreign keys.
Or you can also let jpa create the table for you you just create classes in you code like
#Entity
public class User {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int id; // or long
private String name, password, roles;
#OneToMany
private List<Ticket> ticketList;
// constructor, getters, setters, etc.
}
For Ticket class
#Entity
public class Ticket {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int id; // or long
private name;
#ManyToOne
private User user;
//Constructor, Getter and Setters, ...
}
Related
I am wondering about best practices in database design with Hibernate.
I have a User entity that is going to have a lot of different settings. For each set of settings, I have to either add them as extra columns in the User table or create a separate entity and connect them with a #OneToOne relationship. It is my understanding that #OneToMany and #ManyToOne relationships should generally take place in separate tables because you should not have columns that are optional.
But it is kind of unclear for #OneToOne relationships. I think there is a case for using #OneToOne because ORMs will select all single attributes by default and having a lot of columns will slow down that process.
An example of what I am talking about can be illustrated by
#Entity
public class User{
#OneToOne
private ForumSettings forumSettings;
#OneToOne
private AccountSettings accountSettings;
#OneToOne
private SecuritySettings securitySettings;
}
vs
#Entity
public class User{
#Column
private boolean showNSFWContent; //Forum Setting
#Column
private int numberOfCommentsPerPage; //Forum Setting
#Column
private boolean subscribedToNewsLetter; //Account Setting
#Column
private boolean isAccountBanned; //Account Setting
#Column
private boolean isTwoFactorAuthenticationEnabled; //Security Setting
#Column
private boolean alertForSuspiciousLogin; //Security Setting
}
The above is a simple example to show the concept, but in practice there would be many more columns in the 2nd portion.
I know that this might be opinion based, but I am hoping someone could share the pros/cons of both choices.
Thank you very much
Your question is in general about Data normalization. Normalization is itself extensive field of study and basically is a way of structuring database tables avoiding redundancy and making sure that updates don’t introduce anomalies.
And first rule of normalization says a table shall contain no repeating groups. In your case it does.
SOLUTION 1 : Store UserSettings as Entity as map as OneToMany relationship
#Entity
public class User
#OneToMany
private List<UserSettings> userSettings;
And then you can query for particular setting type by joining User and UserSettings entities.
For example (JPQL)
SELECT user u
JOIN u.settings us
WHERE us.settings_type = 'account_settings'
and us.settings_value = 'secure' // or any other logic
Advantage of this approach is that UserSettings will have it is own persistence identity and can be queried by it's own. It it is not dependent on parent.
For example :
SELECT q from Query q where ...
Solution 2 : Store settings in a collection of basic elements
You can store User Settings in the collection (Each user will have it's own set of settings)
#Entity
public class User {
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
private long id;
private String name;
...
#ElementCollection
#CollectionTable(name="USER_SETTINGS")
#MapKeyColumn(name="SETTINGS_TYPE")
#Column(name="SETTINGS_VALUE")
Map<String, Boolean> userSettings = new HashMap<>();
UserSettings collection will be stored in a separate table with foreign key to User table. UserSettings does not have it is own persistence ID, is dependent on User entity and can be queried only through it is parent ('User')
Solution 3: Store User Settings as Embedded type
Embedded type is not an entity, it does not have it is own persistence ID and is depends on parent type, stored as part of parent record in database (in User table)
#Entity
public class User {
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
private long id;
private String name;
...
#Embedded
private UserSettings userSettings;
UserSettings is in separate class, but stored in User table.
#Embeddable
public class UserSettings {
private List<String> securitySettings; // or any other collection type
private List<Boolean> forumSettings;
TLDR;
I'm using spring boot and jpa.
I want to switch the foreign key of an object, in this case just switching the category of a vehicle.
But when i try to do that hibernate interprets it as if i'm trying to change the primary key of the category object instead of just switching the foreign key and I get this error
org.hibernate.HibernateException:identifier of an instance of abc.package.mode.Category was altered from 1 to 2
I have an entity Category which i'm using only for categorizing vehicle entity object.
#Entity
public class Category {
#Id
private Long id;
private String name;
}
Here is the Vehicle class which needs to be categorized.
#Entity
public class Vehicle {
#Id
#GeneratedValue(strategy = GenerationType.AUTO, generator="dish_seq")
private Long id;
private String name;
private Integer price;
#ManyToOne(fetch = FetchType.EAGER, cascade=CascadeType.DETACH)
private Category category;
}
Lets say there's 3 categories,
'Sedan'
'Convertible'
'Hatchback'
If i have a car object,
Nissan-PT76, $30000, category: [id:1, name:Sedan]
When i try to change category manually to [id:2, name:Convertible] and persist it, i get
org.hibernate.HibernateException:identifier of an instance of abc.package.mode.Category was altered from 1 to 2
I cannot switch from one existing object to another. I have tried to look this up in the internet but i couldn't find the right keywords to search for this kind of relationship in hibernate, or does it not allow this kind of relationship at all?
Add column reference to your Category field in the Vehicle class
#JoinColumn(name = "category_id", nullable = false)
I'm new to hibernate and am stumped by something that seems incredibly simple!
I have a table defining a Contact and a view that gives the contact an approved status.
#Entity
#Table(name="contacts")
public class Contact implements Serializable {
private static final long serialVersionUID = 1L;
#Id
private String email;
#OneToOne(targetEntity = BooleanType.class)
#JoinTable(
name="contactstatus",
joinColumns = #JoinColumn(name="email")
)
private boolean approved;
...
}
I simply want to set the approved flag by joining the view on the email primary key.
Running the above gives me:
Initial SessionFactory Creation failed.org.hibernate.AnnotationException:
#OneToOne or #ManyToOne on ...Contact.approved references an unknown entity:
org.hibernate.type.BooleanType
I realise I could combine the contact and approval columns into a single view, however other aspects of the contact are mutable.
I could also make Approved a custom type, and this is actually how I am working around this issue. However, I don't think this should be necessary in order to make the above work.
i am trying on many to many relationship, Team member can work on multiple projects and a project can have multiple team member , the table structure is as follows,
create table TBL_PROJECT_ONE(
id integer primary key generated always as identity(start with 12,increment by 3),
name varchar(50)
)
create table TBL_TEAM_MEMBER_ONE(
id integer primary key generated always as identity(start with 7,increment by 5),
name varchar(50),
salary integer
)
create table EMP_PRJ_CADRE(
MEMBER_ID integer references TBL_TEAM_MEMBER_ONE,
PRJ_ID integer references TBL_PROJECT_ONE,
CADRE varchar(10),
constraint PK_001_EMP_TEAM primary key (MEMBER_ID,PRJ_ID)
)
Here i have created a new table just to store the relationship,
Now please follow the Employee entity,
#Entity
#Table(name="TBL_TEAM_MEMBER_ONE")
public class EmployeeEntityFour implements Serializable{
public EmployeeEntityFour(){}
public EmployeeEntityFour(String empName,Integer salary){
...
..
}
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
#Column(name="ID")
private Integer empId;
#Column(name="NAME")
private String empName;
#Column(name="SALARY")
private Integer empSal;
#ElementCollection(fetch= FetchType.LAZY)
#CollectionTable(name="EMP_PRJ_CADRE")
#MapKeyJoinColumn(name="PRJ_ID")
#Column(name="CADRE")
private Map<ProjectEntityOne,String> employeeCadre;
...
..
.
}
Please follow the mapping for Project Entity,
#Entity
#Table(name="TBL_PROJECT_ONE")
public class ProjectEntityOne implements Serializable{
public ProjectEntityOne(){}
public ProjectEntityOne(String name){
this.projectName = name;
}
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
#Column(name="ID")
private Integer projectId;
#Column(name="NAME")
private String projectName;
#ElementCollection(fetch= FetchType.LAZY)
#CollectionTable(name="EMP_PRJ_CADRE")
#MapKeyJoinColumn(name="MEMBER_ID")
#Column(name="CADRE")
private Map<EmployeeEntityFour,String> employeeCadre;
....
..
.
}
In main method testing the code written is as follows,
ProjectEntityOne proj = new ProjectEntityOne("Citi Grand Central");
Map<EmployeeEntityFour,String> cadreMap = new HashMap<EmployeeEntityFour,String>();
cadreMap.put(new EmployeeEntityFour("Murlinarayan Muthu",34000), "Senior Software Engineer");
cadreMap.put(new EmployeeEntityFour("Gopalkrishna Rajnathan",64000), "Software Engineer");
cadreMap.put(new EmployeeEntityFour("Premanna Swaminathan",94000), "Project Manager");
proj.setEmployeeCadre(cadreMap);
em.persist(proj);
but i am getting an error which is
ERROR: 'PROJECTENTITYONE_ID' is not a column in table or VTI 'APP.EMP_PRJ_CADRE'.
When in both the entities i have specified #MapKeyJoinColumn than too i am getting an error as improper column for the third table.
Where i am missing
It somehow worked, i had to do some changes in the code,
first, the edited code in Entity ProjectEntityOne is as follows,
#ElementCollection(fetch= FetchType.LAZY)
#CollectionTable(name="EMP_PRJ_CADRE",joinColumns=#JoinColumn(name="PRJ_ID"))
#MapKeyJoinColumn(name="MEMBER_ID")
#Column(name="CADRE")
private Map<EmployeeEntityFour,String> employeeCadre;
What i have done here is i added #JoinedColumn in #CollectionTable,
Second change i did in Entity EmployeeEntityFour, the change is I removed Map of PorjectEntityOne from it,
in test,
i can save Project with Employee mapping but here all the employees should be already saved one.
i.e. the key of map
Map<EmployeeEntityFour,String> employeeCadre;
should be already persisted
and than we can persist project entity.
On employeeCadre in EmployeeEntityFour you need a #JoinColumn(name="MEMBER_ID") and you would also need a #JoinColumn(name="PRJ_ID") in the ProjectEntityOne employeeCadre.
But, I would not model it this way. First of all you cannot have a bi-directional ElementCollection mapping, and ElementCollection can only be owned by one side. The best solution would be to define an Cadre entity mapping to EMP_PRJ_CADRE table and have a OneToMany to it from both sides, and have it have a ManyToOne to each.
Alternatively you may use a ManyToMany with a MapKeyColumn, but I think you would be better off having an entity.
I am trying to figure out the best way to accomplish a relationship in hibernate. I have a Customer object. Each customer has a technical contact, a billing contact, and a sales contact. Each type of contact has the exact same data structure (phone, email, address, etc).
My first thought was to create a Contact table, and then have three columns in the Customer table - sales_contact, billing_contact, technical_contact. That would make three distinct foreign key one-to-one relationships between the same two tables. However, I have found that this is very difficult to map in Hibernate, at least using annotations.
Another thought was to make it a many to many relationship, and have a type flag in the mapping table. So, any Customer can have multiple Contacts (though no more than three, in this case) and any Contact can belong to multiple Customers. I was not sure how to map that one either, though. Would tere be a type field on the map table? Would this attribute show up on the Contact java model object? Would the Customer model have a Set of Contact objects. or three different individual Contact objects?
So I am really looking for two things here - 1. What is the best way to implement this in the database, and 2. How do I make Hibernate map that using annotations?
It can be as simple as :
#Entity
public class Contact {
#Id
private String id;
private String phome;
private String email;
private String address;
// ... Getters and Setters
}
#Entity
public class Customer {
#Id
#GeneratedValue
private String id;
#ManyToOne
#JoinColumn(name = "ID")
private Contact billingContact;
#ManyToOne
#JoinColumn(name = "ID")
private Contact salesContact;
#ManyToOne
#JoinColumn(name = "ID")
private Contact technicalContact;
public Customer() {
}
// ... Getters and Setters
}
Now, if you want to make the difference between a BillingContact and a SalesContact at the object level, you can make Contact abstract, and implement it with each type of contact. You will have to annotate the parent class with #Inheritance to specify the inheritance strategy of your choice (SINGLE_TABLE sounds appropriate here, it will use a technical discriminator column - see http://docs.jboss.org/hibernate/annotations/3.5/reference/en/html_single/#d0e1168).
How about using #OneToOne and just naming the #JoinColumn differently for each type:
#Entity
public class Contact {
#Id
private String id;
private String phone;
private String email;
private String address;
// ... Getters and Setters
}
#Entity
public class Customer {
#Id
#GeneratedValue
private String id;
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name="billingContact_ID")
private Contact billingContact;
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name="salesContact_ID")
private Contact salesContact;
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name="technicalContact_ID")
private Contact technicalContact;
public Customer() {
}
// ....
}
For each row in Customer table should create three rows in Contact table