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Finding exact match with equal sign with append function in SQL

sqlQueryString.append(" and upper(username) like upper(:searchString) ");
This code returns data like exampleusername, exampleusername1, exampleusername12...
I want it to return data with an exact match to the username that is being searched.
For example when I put in bobJacobs (an example username), I want it to return only bobJacobs records, not other records that may contain bobJacobs in them, for example samandbobJacobs24, bobJacobs23, etc.
I've tried:
sqlQueryString.append(" and upper(username) = upper(:searchString) ");
But it doesn't work. Any solutions?

Any suggestions how to create Regex for this in java for String.replaceAll()?

My String is like this.
{\\\"692950841314120\\\":[{\\\"type\\\":\\\"ads_management\\\",\\\"call_count\\\":3,\\\"total_cputime\\\":1,\\\"total_time\\\":5,\\\"estimated_time_to_regain_access\\\":0}]}
Since the key here is a variable value I am trying to replace this 692950841314120(or the values which I get from sever) with a constant like ID. My main goal is to parse this as POJO. I have tried using..
string.replaceAll("^[0-9]{15}$","ID")
but due to Slashes I think i am not able to get the desired value. Is there any better way to do this. I know I can do below Code but I don't want any ID123 if I added extra value and distort any other info in JSON.
string.replaceAll("[0-9]{15}","ID")

Strictly speaking, if you have a valid JSON string, you should parse it using something like GSON, rather than using regex. That being said, if you must use regex, you could try removing the starting and ending anchors:
string.replaceAll("[0-9]{15}", "ID")
Or maybe use double quotes instead:
string.replaceAll("\"[0-9]{15}\"", "ID")

It is safer to assume the value is inisde \" and \":.
You can then use
.replaceAll("(\\\\\")[0-9]{15}(\\\\\":)", "$1ID$2")
The regex is (\\")[0-9]{15}(\\":) and it means:
(\\") - match and capture \" substring into Group 1
[0-9]{15} - fifteen digits
(\\":) - Group 2: a \": substring.
The $1 and $2 are placeholders holding the Group 1 and 2 values.

You should use "A word boundary" \b.
Try this.
public static void main(String[] args) {
String input = "{\\\"692950841314120\\\":"
+ "[{\\\"type\\\":\\\"12345678901234567890\\\","
+ "\\\"call_count\\\":3,"
+ "\\\"total_cputime\\\":1,"
+ "\\\"total_time\\\":5,"
+ "\\\"estimated_time_to_regain_access\\\":0}]}";
System.out.println(input.replaceAll("\\b[0-9]{15}\\b", "ID"));
}
output:
{\"ID\":[{\"type\":\"12345678901234567890\",\"call_count\":3,\"total_cputime\":1,\"total_time\":5,\"estimated_time_to_regain_access\":0}]}

Unable to capture next line character in Java

I have a requirement of parsing through an python file which contains multiple sql queries and get the start and end positions of the query to get only the query part using JAVA
I am using .contains function to check for sql(''' as my opening character for the query and now for the closing character I have ''') but there are some cases where ''') comes in between the query when there is a variable involved which should not be detected as an end of the query.
Something like this :
spark.sql(''' SELECT .......
FROM.....
WHERE xxx IN ('''+ Variable +''')
''')
here the last but one line also gets detected as end of line if I use line.contains(" ''') ") which is wrong.
All I can think of is to check for next line character as the end of the query as each query is separated by two empty lines. So tried these if (line.contains(" ''')\n") & if (line.contains(" ''')\r\n") but none of them work for me.
Kindly let me know of any other way to do this.
Note that I do not have the privilege to change the query file.
Thanks

I believe simple contains won't solve this problem.
You will have to use Pattern if you are looking to match \n.
String query = "spark.sql(''' SELECT .......\n" +
"FROM..... \n" +
"WHERE xxx IN ('''+ Variable +''')\n" +
"''')";
Pattern pattern = Pattern.compile("^spark.sql\\('''(.*)'''\\)$", Pattern.DOTALL);
System.out.println(pattern.matcher(query).find());
Output:
true
Pattern.DOTALL tells Java to allow the dot to match newline characters, too.

Format the query result

I have particular query which will retrieve results as
Row[values=[a/b/c/s, bell]]
Row[values=[e/g/i/r, bell]]
after the execution of below line in java.
System.out.println(dataSet.getRow());
I need to display results as
a/b/c/s bell
e/g/i/r bell
and
a/b/c/s
e/g/i/r
Is there any regex for that?

(?<==\[)(([^,]+),\s+[^\]]+)
Try this.Grab the capture.See demo.If you want to remove , from first result use replace to remove , and replace by empty string.
https://regex101.com/r/nL5yL3/15

Java XMLInputFactory - truncates text when reading data with .getData()

I'm using XMLInputFactory to read data (sql queries) from xml file.
In some cases, the data is truncated. For example:
select CASE WHEN count(*) > 0 THEN 'LX1VQMSSRV069 OK' ELSE 'LX1VQMSSRV069 NOK' END from [PIWSLog].[dbo].[log]
is read as (text is truncated after the last '.'):
select CASE WHEN count(*) > 0 THEN 'LX1VQMSSRV069 OK' ELSE 'LX1VQMSSRV069 NOK' END from [PIWSLog].[dbo]
I've tested with several string and it seems that the problem is with the char's in [].[].[]..
I'm readind data using:
mySQLquery = event.asCharacters().getData();
Another situation is if the string has '\n'. Like, if it has two '\n', the event.asCharacters().getData(); reads correctly, but if it has three '\n' it truncates the string after the second '\n'. This is very odd!
Any idea what's the problem and how can I solve it?

The XMLInputFactory API is not obliged to give you all of the characters of a String in one go. It's permitted to pass you a sequence of events, each containing a fragment of the string.
You'll probably find that if you read another event after the one containing the truncated string, you'll find the remainder of your string (possibly after several events).