Finding a substring that is enclosed withing double quotes in java - java

My code :
String content = '<?xml version="1.0" encoding="UTF-8"?>
<svg width="16px" height="16px" viewBox="0 0 16 16" version="1.1"
xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink">
<!-- Generator: Sketch 64 (93537) - https://sketch.com -->
<title>Group 36 Copy 4</title>
<desc>Created with Sketch.</desc>
<g id="Portal" stroke="none" stroke-width="1" fill="none" fill-rule="evenodd">
<g id="Group-36-Copy-4" fill="#FFFFFF">
<path d="M0,7.162 L6,8.877 L6.00036056,9 C6.00036056,10.0543618 6.81623835,10.9181651 7.85109822,10.9945143 L8.00036056,11 C9.10493006,11 10.0003606,10.1045695 10.0003606,9 L10.0003606,9 L10.0003606,8.98076197 L16,7.266 L16.0003606,14 C16.0003606,15.1045695 15.1049301,16 14.0003606,16 L2.00036056,16 C0.895791064,16 0.000360563943,15.1045695 0.000360563943,14 L0,7.162 Z M14.0003606,4 C15.1049301,4 16.0003606,4.8954305 16.0003606,6 L16,6.226 L9.99950581,7.94095939 C9.96827529,6.8636983 9.0851817,6 8.00036056,6 C6.94978154,6 6.08839609,6.81003398 6.00669844,7.83960773 L0,6.122 L0.000360563943,6 C0.000360563943,4.8954305 0.895791064,4 2.00036056,4 L14.0003606,4 Z" id="Combined-Shape"></path>
<rect id="Rectangle" x="7.00036056" y="7" width="2" height="3" rx="1"></rect>
<path d="M10.0003606,0 C11.0547224,0 11.9185257,0.815877791 11.9948748,1.85073766 L12.0003606,2 L12.0003606,4 L10.0003606,4 L10.0003606,2 L6.00036056,2 L6.00036056,4 L4.00036056,4 L4.00036056,2 C4.00036056,0.945638205 4.81623835,0.0818348781 5.85109822,0.00548573643 L6.00036056,0 L10.0003606,0 Z" id="Path-21" fill-rule="nonzero"></path>
</g>
</g>
</svg>'
I have a string named "content" in java which holds any svg file's content that the user uploads. Now my task is to replace the value that is inside this attribute fill="#FFFFFF" with the input that my user has given.
Example : user input : ff0000
so now content string must replace this line <g id="Group-36-Copy-4" fill="#FFFFFF"> as <g id="Group-36-Copy-4" fill="#ff0000">
I am stucked. Please help.

if the fill you mention in the content never change, you can use the replace function.
content = content.replace("#FFFFFF",input)
Reference : https://www.javatpoint.com/java-string-replace

First, your code is not compilable, because you are using single quote which is for character type, you need to use double quotes for your String and escape all internal double quotes:
String content = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><svg width=\"16px\" height=\"16px\" viewBox=\"0 0 16 16\" version=\"1.1\"xmlns=\"http://www.w3.org/2000/svg\" xmlns:xlink=\"http://www.w3.org/1999/xlink\"><!-- Generator: Sketch 64 (93537) - https://sketch.com --><title>Group 36 Copy 4</title><desc>Created with Sketch.</desc><g id=\"Portal\" stroke=\"none\" stroke-width=\"1\" fill=\"none\" fill-rule=\"evenodd\"><g id=\"Group-36-Copy-4\" fill=\"#FFFFFF\"><path d=\"M0,7.162 L6,8.877 L6.00036056,9 C6.00036056,10.0543618 6.81623835,10.9181651 7.85109822,10.9945143 L8.00036056,11 C9.10493006,11 10.0003606,10.1045695 10.0003606,9 L10.0003606,9 L10.0003606,8.98076197 L16,7.266 L16.0003606,14 C16.0003606,15.1045695 15.1049301,16 14.0003606,16 L2.00036056,16 C0.895791064,16 0.000360563943,15.1045695 0.000360563943,14 L0,7.162 Z M14.0003606,4 C15.1049301,4 16.0003606,4.8954305 16.0003606,6 L16,6.226 L9.99950581,7.94095939 C9.96827529,6.8636983 9.0851817,6 8.00036056,6 C6.94978154,6 6.08839609,6.81003398 6.00669844,7.83960773 L0,6.122 L0.000360563943,6 C0.000360563943,4.8954305 0.895791064,4 2.00036056,4 L14.0003606,4 Z\" id=\"Combined-Shape\"></path><rect id=\"Rectangle\" x=\"7.00036056\" y=\"7\" width=\"2\" height=\"3\" rx=\"1\"></rect><path d=\"M10.0003606,0 C11.0547224,0 11.9185257,0.815877791 11.9948748,1.85073766 L12.0003606,2 L12.0003606,4 L10.0003606,4 L10.0003606,2 L6.00036056,2 L6.00036056,4 L4.00036056,4 L4.00036056,2 C4.00036056,0.945638205 4.81623835,0.0818348781 5.85109822,0.00548573643 L6.00036056,0 L10.0003606,0 Z\" id=\"Path-21\" fill-rule=\"nonzero\"></path></g></g></svg>";
then you can use String's replace:
content = content.replace("fill=\"#FFFFFF\"", String.format("fill=\"%s\"", replacement));
this, in case you want to replace in the same variable, use a different one otherwise.

Related

JAVA- Integer.parseInt( str ) gives NumberFormatException, input is a str representing an integer

UPDATE -
chardetect
considers the srt file to be encoded as UTF-8 with a confidence score of 1.0. I have been reading in the file with:
Files.readAllLines
set to interpret it as utf-8. With the help of others here, I determined the single digit string in fact has a length of 2... the trick now is to figure out where that extra character is coming from. The following is a en excerpt of the hex dump:
00000000: efbb bf31 0d0a 3030 3a30 303a 3034 2c35 ...1..00:00:04,5
00000010: 3031 202d 2d3e 2030 303a 3030 3a30 362c 01 --> 00:00:06,
00000020: 3439 300d 0ae3 8199 e381 9fe3 8198 e381 490.............
00000030: 8ae3 8198 e381 b6e3 828a e381 95e3 818f ................
00000040: e381 b2e3 8293 0d0a 2d20 4c75 7069 6e20 ........- Lupin
00000050: 3230 3033 2070 7265 7365 6e74 7320 2d0d 2003 presents -.
00000060: 0a0d 0a32 0d0a 3030 3a30 303a 3036 2c35 ...2..00:00:06,5
00000070: 3030 202d 2d3e 2030 303a 3030 3a30 382c 00 --> 00:00:08,
00000080: 3032 340d 0a41 2053 7475 6469 6f20 4768 024..A Studio Gh
00000090: 6962 6c69 2046 696c 6d0d 0a0d 0a33 0d0a ibli Film....3..
000000a0: 3030 3a30 303a 3133 2c30 3437 202d 2d3e 00:00:13,047 -->
000000b0: 2030 303a 3030 3a31 352c 3132 360d 0a3c 00:00:15,126..<
000000c0: 666f 6e74 2063 6f6c 6f72 3d22 2338 3838 font color="#888
000000d0: 3838 3822 3ee3 81a1 e381 b2e3 828d e380 888">...........
000000e0: 80e3 8192 e382 93e3 818d e381 a7e3 81ad ................
000000f0: e380 82e3 8080 e381 bee3 819f e380 80e3 ................
00000100: 8182 e381 8ae3 8186 e381 ade3 8080 e382 ................
Original question:
I'm reading in a .srt file using java.nio.file.Files.readAllLines().
In .srt files, every subtitle has a number line - an integer that indexes the subtitle.
As captured, this line is a string.
When I use Integer.parsint( numberLineString ), I get
java.lang.NumberFormatException
I've troubleshot this as best I can, by:
homing in on a very specific subtitle so I know this isn't being caused by some errant subtitle that might have an erroneous index with non digit characters in it.
removing any potential \n or \r away from the index number
printing the variable passed to Integer.parsint() to verify it is definitely the index string, representing an integer.
As you can see, the exception thrown is even confessing it threw the exception for the input string "1"
Exception in thread "main" java.lang.NumberFormatException: For input string: "1"
at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:68)
at java.base/java.lang.Integer.parseInt(Integer.java:658)
at java.base/java.lang.Integer.parseInt(Integer.java:776)
at japanese.engine.kana.JPSubsParser.parseTitles(JPSubsParser.java:218)
at japanese.engine.kana.srtManager.main(srtManager.java:25)
I'm at a loss - any help would be appreciated.
Here is an extract from the file being read:
1
00:00:04,501 --> 00:00:06,490
すたじおじぶりさくひん
- Lupin 2003 presents -
2
00:00:06,500 --> 00:00:08,024
A Studio Ghibli Film
3
00:00:13,047 --> 00:00:15,126
<font color="#888888">ちひろ げんきでね。 また あおうね りさ</font>
<font color="#8888FF">Good Luck, Chihiro. We'll meet again</font>
Here is the relevant Java code:
public int parseTitles( Map<String, ArrayList<String>> subsMap ) {
/* Setup, get iterator for the Map
* Instantiate a charMatch object for checking for the various characters */
Iterator<String> keyIter = subsMap.keySet().iterator();
JPcharMatch charMatch = new JPcharMatch();
// Loop through the map
int tempCounter = 0;
while (keyIter.hasNext() && tempCounter == 0) {
//get the current title
ArrayList<String> titleLines = subsMap.get(keyIter.next());
String trimmedLine0 = titleLines.get(0).replace("\n", "").replace("\r", "").replace("\"", "");
int indexLineInt = Integer.parseInt( trimmedLine0 );
public class srtManager {
public static void main( String[] args ) {
Path subsFilePath = Paths.get("/Volumes/Multimedia/Coding/experimenting_srts/Sen to Chihiro Kanji+Hir+Eng.srt");
SubsFileDAO subsFileDAO = new SubsFileDAO(subsFilePath);
List<String> fileLines = subsFileDAO.getLinesList();
JPSubsParser parser = new JPSubsParser( fileLines );
Map<String, ArrayList<String>> subsMap = parser.getSubsMap();
// TODO analyze to detect kanji lines and store.
parser.parseTitles(subsMap);
}
}
You are trying to interpret BOM at beginning of file as a number.
You can remove it by hand before parsing:
String BOM = new String(new byte[] { (byte) 0xef, (byte) 0xbb, (byte) 0xbf});
int indexLineInt = Integer.parseInt( trimmedLine0.replaceAll(BOM, ""));
Alternatively, there are solutions like BOMInputStream that will remove BOM transparently from provided InputStream

How can I combine multiple paths in an SVG file into a single path using Java

I am trying to build a road system network using paths on my svg. This is a sample of my path
<path id="L4H" style="fill:none;stroke-width:0.75;stroke-linecap:round;stroke-linejoin:round;stroke:rgb(0%,0%,0%);stroke-opacity:1;stroke-miterlimit:3;" d="M 0.000668985 396.649337 L 96.301547 396.649337 " transform="matrix(0.999999,0,0,0.997983,146.307925,-282.755491)"/>
<path id="L2" style="fill:none;stroke-width:0.75;stroke-linecap:round;stroke-linejoin:round;stroke:rgb(0%,0%,0%);stroke-opacity:1;stroke-miterlimit:3;" d="M -0.0000537782 396.648548 L 94.179729 396.648548 " transform="matrix(0.999999,0,0,0.997983,18.375054,-188.44611)"/>
<path id="L1" style="fill:none;stroke-width:0.75;stroke-linecap:round;stroke-linejoin:round;stroke:rgb(0%,0%,0%);stroke-opacity:1;stroke-miterlimit:3;" d="M -0.0000537782 396.65004 L 94.179729 396.65004 " transform="matrix(0.999999,0,0,0.997983,18.375054,-210.900725)"/>
<path id="L2toL4" style="fill:none;stroke-width:0.75;stroke-linecap:round;stroke-linejoin:round;stroke:rgb(0%,0%,0%);stroke-opacity:1;stroke-miterlimit:3;" d="M -0.00207423 396.650411 L 47.728842 396.64925 " transform="matrix(0.707106,-0.70568,0.707106,0.70568,-167.917758,-72.503655)"/>
<path id="L4V" style="fill:none;stroke-width:0.75;stroke-linecap:round;stroke-linejoin:round;stroke:rgb(0%,0%,0%);stroke-opacity:1;stroke-miterlimit:3;" d="M 0.00121335 396.648763 L 60.748749 396.648763 " transform="matrix(0.000000000000000061,-0.997983,0.999999,0.000000000000000061,-250.343675,173.723867)"/>
<path id="L3toL1" style="fill:none;stroke-width:0.75;stroke-linecap:round;stroke-linejoin:round;stroke:rgb(0%,0%,0%);stroke-opacity:1;stroke-miterlimit:3;" d="M -0.000472636 396.64847 L 16.722096 396.65008 " transform="matrix(0.672672,-0.738447,0.739939,0.671316,-180.940745,-81.32762)"/>
This path has various vertexes and edges that connect the road network (I use the graph as my data structure). My plan is to call a start vertex to say L4H and end vertex L1, get the shortest pathh and from the result, I would use Java to get the path. The problem is that I can do that for one path
Element element = doc.getElementById("L14");
pathData = element.getAttributeNode("d").getValue();
transformMatrix = element.getAttributeNode("transform").getValue();
parser.parse(pathData);
path = handler.getPath();
path.getElements().forEach(System.out::println);
String tempTransformMatrix1 = transformMatrix.replace("matrix(", "");
String tempTransformMatrix2 = tempTransformMatrix1.replace(")", "");
var a = tempTransformMatrix2.split(",");
path.getTransforms()
.add(Transform.affine(w, e, e,
e,f, s));
path.setStroke(Color.BLACK);
I would like to combine all paths for a route into an individual path before playing the transition. (I use batik for the SVG dom parsing)

Extract Image from webRTC Stream

I am trying to extract a single image from a webRtc stream.
The stream looks something like this:
--boundary
Content-Type: image/jpeg
Content-Length: 27778
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2!!22222222222222222222222222222222222222222222222222ˇ¿¿"ˇƒ
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ˇƒµw!1AQaq"2ÅBë°±¡ #3Rbr—
$4·%Ò&'()*56789:CDEFGHIJSTUVWXYZcdefghijstuvwxyzÇÉÑÖÜáàâäíìîïñóòôö¢£§•¶ß®©™≤≥¥µ∂∑∏π∫¬√ƒ≈∆«»… “”‘’÷◊ÿŸ⁄‚„‰ÂÊÁËÈÍÚÛÙıˆ˜¯˘˙ˇ⁄?ÏÅÊ¢∫∑[òYq¡©;ävh&Á*ckyöfi^£°ı®e6+°‘¨~’‰ëySX#óâÉIãr°ÃTÏ9ÌQ{“#3§ÌäR}hgfiÄhˆ4º1◊Ë ÌHsN>‚ìÎ#
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--boundary
"next image"
What I tried so far is, removing --boundary, Content Type and Content Lenght and just saving it as an image. But that doesn't work. So now I don't exactly know how I should approach this problem. Any Help would be welcome. Thanks.

Remove certain recurring elements in xml

I have a xml and want to remove certain elements from the xml document. Initially I wanted to remove the control characters coming in these elements or completely remove the data in these elements.
My sample payload is as below. I wanted to remove resume/content and comments.
<Jobs>
<candidates>
<address2/>
<application>
<comments><BR />Test emp1711 Newberg St. #4 Oregon, CA 97229 444-123-9752 testcandidate#gmail.com<BR />authorName: Test 1
comment content: <b>To: test test (test.test#yahoo.com)</b><br /><br />From: abc Recruitment Team (test#abc.com)<br /><br />Subject: Tester at abc<br /><br /><TEXTFORMAT LEADING="2"><P ALIGN="LEFT"><FONT FACE="Verdana" SIZE="12" COLOR="#353A3F" LETTERSPACING="0" KERNING="0">Hello test,</FONT></P></TEXTFORMAT><TEXTFORMAT LEADING="2"><P ALIGN="LEFT"><FONT FACE="Verdana" SIZE="12" COLOR="#353A3F" LETTERSPACING="0" KERNING="0"></FONT></P></TEXTFORMAT><TEXTFORMAT LEADING="2"><P ALIGN="LEFT"><FONT FACE="Verdana" SIZE="12" COLOR="#353A3F" LETTERSPACING="0" KERNING="0">Thank you for your interest in our abc opening. </FONT></P></comments>
<disposition>tesr Skills match</disposition>
<eId>xyz</eId>
<gender>Male</gender>
<lastUpdatedDate>1340687163</lastUpdatedDate>
<race>Undefined</race>
<resume>
<content>Test<BR />Human Resources Manager / Business Partner <BR /> portland, Oregon; 4454; <BR /> Phone 020 444456;Mobile 088768999;E-mail test#yahoo.com <BR /></content>
<format>Text</format>
</resume>
<sentDate>1789993473</sentDate>
<source>Linkedin</source>
<sourceType>Import</sourceType>
<veteranStatus>Undefined</veteranStatus>
<workflowState>Offer Accepted</workflowState>
<city>portland</city>
<companyName/>
<country>US</country>
<eId>xyz</eId>
</application>
</candidates>
<candidates>
<address2/>
<application>
<comments><BR />Test emp2711 Newberg St. #4 Oregon, CA 97229 444-123-9752 testcandidate2#gmail.com<BR />authorName: Test 2
</comments>
<disposition>Skills match</disposition>
<eId>xyz</eId>
<gender>female</gender>
<lastUpdatedDate>1340687163</lastUpdatedDate>
<race>Undefined</race>
<resume>
<content>Test<BR />Program Manager / Business Partner <BR /> portland, Oregon; 4454; <BR /> Phone 020 444456;Mobile 088768999;E-mail test#yahoo.com <BR /></content>
<format>Text</format>
</resume>
<sentDate>178444473</sentDate>
<source>Linkedin</source>
<sourceType>Import</sourceType>
<veteranStatus>Undefined</veteranStatus>
<workflowState>Offer Accepted</workflowState>
<city>portland</city>
<companyName/>
<country>US</country>
<eId>xyzabc</eId>`enter code here`
</application>
</candidates>
</Jobs>
Build the XML into a Document using DocumentBuilderFactory and pass it to a function like below: (nodeName would be "comments" etc.)
removeAllNodes(Document doc, String nodeName){
DocumentTraversal t = (DocumentTraversal) doc;
Node root = doc.getDocumentElement();
NodeIterator iterator =
t.createNodeIterator(root, NodeFilter.SHOW_ELEMENT, null, true);
for (Node n = iterator.nextNode(); n != null; n = iterator.nextNode()) {
Element e = (Element) n;
if (nodeName.equals(e.getTagName()))
root.removeChild(e);
}
}

displaytag customise pagination

I'm trying to style the <displaytag> to obtain something that look great.
The official demo look like :
http://demo.displaytag.org/displaytag-examples-1.2/example-paging.jsp
But I obtain only this :
How can I change the rendering of the pagination part of the displaytag so that page numbers are in <li> elements ?
Thanks in advance
To customise the pagination, I had to add a displayTag.properties file with the following properties :
paging.banner.no_items_found=<span class="pagebanner">No {0} found.</span>
paging.banner.one_item_found=<span class="pagebanner">One {0} found.</span>
paging.banner.all_items_found=<span class="pagebanner">{0} {1} found, displaying all {2}.</span>
paging.banner.some_items_found=<span class="pagebanner">{0} {1} found, displaying {2} to {3}.</span>
paging.banner.full=<div class="pagination"><ul><li class="prev disabled"><img src="static/images/first.png" alt="first" /></li><li class="prev disabled"><img src="static/images/previous.png" alt="previous" /></li>{0}<li><img src="static/images/next.png" alt="next" /></li><li class="next"><img src="static/images/last.png" alt="last" /></li></ul></div>
paging.banner.first=<div class="pagination"><ul><li class="prev"><img src="static/images/first.png" alt="first" /></li><li class="prev"><img src="static/images/previous.png" alt="previous" /></li>{0}<li><img src="static/images/next.png" alt="next" /></li><li class="next"><img src="static/images/last.png" alt="last" /></li></ul></div>
paging.banner.last=<div class="pagination"><ul><li class="prev"><img src="static/images/first.png" alt="first" /></li><li class="prev"><img src="static/images/previous.png" alt="previous" /></li>{0}<li class="next disabled"><img src="static/images/next.png" alt="next" /></li><li class="next disabled"><img src="static/images/last.png" alt="last" /></li></ul></div>
paging.banner.onepage=<div class="pagination"><ul>{0}</ul></div>
paging.banner.page.selected=<li><strong>{0}</strong></li>
paging.banner.page.link=<li>{0}</li>
paging.banner.page.separator=
In displayTag.properties:
paging.banner.placement=top
paging.banner.onepage=
paging.banner.first=<span class="pagination pagination-right"><ul>{0}<li>...{6}</li></ul></span>
paging.banner.full=<span class="pagination pagination-right"><ul><li>1\u00aa</li>{0}<li>...{6}</li></ul></span>
paging.banner.last=<span class="pagination pagination-right"><ul><li>1\u00aa</li>{0}</ul></span>
paging.banner.page.link=<li>{0}</li>
paging.banner.page.selected=<li class="disabled"><span>{0}</span></li>
paging.banner.page.separator=
Another format
More information on http://www.displaytag.org/1.2/configuration.html

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