Hibernate Composite Key - add another key from #JoinColumns - java

So, I have the following entity:
#Entity
public class EntityOne{
#EmbeddedId
private EntityOneIdentity entityOneIdentity;
#ManyToOne
#JoinColumns(value = {
#JoinColumn(name = "MerchantID", referencedColumnName = "MerchantID"),
#JoinColumn(name = "TenantID", referencedColumnName = "TenantID")})
private Merchant merchant;
.......
}
With Identity (Composite key):
#Embeddable
public class EntityOneIdentity implements Serializable {
#Column(name = "EntityID")
private String entityID;
#Column(name = "TenantID")
private String tenantID;
....
}
My challenge is that I need the #JoinColumn("TenantID") that comes from Merchant Entity to also be a PK in my EntityOne (just tenantId! The "MerchantId" will be left as it is). The only thing I found was the #MapId adnotation, but this adds both FK mentioned in #JoinColumns to my wanted Primary Keys.
Thank you in advance!

Solved it by marking #JoinColumns with insertable/updatebla false and by creating an extra merchantId field which value I set in the merchant setter

Related

how to reference a composite key in hibernate JPA?

I want to reference a composite key (using #EmbeddedId) as a foreign key. I followed other tutorials but none seem to work in my case.
I have to create 3 entities, place, visit, and tourist. visit has a primary key composed of 2 foreign keys ( place_id, and tourist_id)
here is the "place" class, tourist is the written in the same way.
`
#Entity
#Table(name = "place")
public class Place {
#Id
#Generated
private Long id;
#OneToMany
#JoinColumns({
#JoinColumn(name = "visit_id1", referencedColumnName = "place_id"),
#JoinColumn(name = "visit_id2", referencedColumnName = "tourist_id")
})
private ArrayList<Visit> placeVisit;
}
second a visit class which has the composite key:
#Entity
#Table(name = "visit")
public class Visit {
#EmbeddedId
private VisitId id;
}
//the id class
#Embeddable
public class VisitId implements Serializable {
#ManyToOne
#JoinColumn(name = "place_id",referencedColumnName = "id")
private Place place;
#ManyToOne
#JoinColumn(name = "tourist_id",referencedColumnName = "id")
private Tourist tourist;
}
`
when executing, spring boot tells me that there is a #JoinColumn which refrences place_id but the target entity Place, does not have such an attribute.
I searched allot but I can't find a similar case.
when executing, spring boot tells me that there is a #JoinColumn which refrences place_id but the target entity Place, does not have such an attribute. I searched allot but I can't find a similar case.

I have to persist a Map<EntityType, List<EntityType>> with JPA

I'm trying to persist an Entity that has a Map as one of its values. To be more precise. I have the #Entity Request that have a compound primary key with three elements. This primary key is composed by an id, the User an Map<EntityType, List<EntityType>> where the first EntityType is the selected service and the related value is the list of the items where the service will be applied to.
Below the code that I have but I'm missing the annotation that i have to use for the Map. I read online that the good way to go is the create a wrapper entity like to one that i created (SelectedService2MyItem) that holds the list and then the map is just a key-value pair between two entity but I can't make it works and I don't know how to proceed.
Does anyone can help me?
Request Entity
#Entity
public class Request {
#EmbeddedId
private RequestId id;
#Column
private String name;
#ManyToOne
#JoinColumn(name = "user_id", foreignKey = #ForeignKey(name = "FK_user_id"), nullable=false)
private User user;
//Getter, setter, constructor omitted
}
RequestId
#Embeddable
public class RequestId {
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#ManyToOne
#JoinColumn(name = "user_id", foreignKey = #ForeignKey(name = "FK_user_id"), nullable=false)
private User user;
private Map<ServiceOffered, SelectedService2MyItem> service2MyItem = new HashMap<ServiceOffered, SelectedService2MyItem>();
//Getter, setter, constructor omitted
}
SelectedService2MyItem
#Entity
public class SelectedService2MyItem {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id", updatable = false, nullable = false)
private Long id;
#OneToMany(mappedBy = "id")
private List<MyItem> myItemsSelected;
//Getter, setter, constructor omitted
}

JPA: Reference column in the child entity is null when using unidirectional #OneToMany

I have two entity classes.
Order.java
#Entity
#Table(name = "order_table")
public class Order implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#OneToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL, orphanRemoval = true)
#JoinColumn(name = "order_id", referencedColumnName = "id", nullable = false, insertable=false, updatable=false)
private Set<Item> items;
// getters & setters & toString
Item.java
#Entity
#Table(name = "item")
public class Item implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#Column(name = "order_id", nullable = false)
private Long orderId;
// getters & setters && toString
I created a test class like this:
#Test
public void createOrderWithItems() {
Item item = new Item();
item.setName("Iron Man");
Order order = new Order();
order.setName("Toy");
order.getItems().add(item);
Order created = service.createOrder(order);
Order orderById = service.getOrderById(order.getId());
System.out.println("Created Order: " + orderById);
Item itemById = service.getItemById(item.getId());
System.out.println("Created item: " + itemById);
Assert.notNull(created.getId(), "Order ID is Null");
}
Test is green but if you check output, you'll see that orderId field in the Item class is null.
Created Order: Order{id=1, name='Toy', items=[Item{id=2, name='Iron Man', orderId=null}]}
Created item: Item{id=2, name='Iron Man', orderId=null}
Does JPA not update this column in the db automatically? Is this column is redundant? If so, how can I retrieve this information from test code?
You need to set orderId explicitly.
item.setOrderId(order.getId());
order.getItems().add(item);
You can create a method addItem(Item item) in your Order class and hide this logic within it.
Cascading will create an entry in db but it won't initialize field. JPA annotations just indicate to JPA provider how to perform mapping between entity and table.
Moreover, check your annotations. #JoinColumn should be used in the entity which owns the relationship (the corresponding table has column as a foreign key). Check the top answer for this question for detailed explanations: What's the difference between #JoinColumn and mappedBy when using a JPA #OneToMany association

JPA mapping annotation error org.hibernate.MappingException: Foreign key must have same number of columns as the referenced primary key

I can't propper map DB tables with JPA annotation.
Tables Subject and Place is ManyToMany through JoinTable.
Subject.java
#Entity
#Table(name = "SUBJECT")
public class Subject implements Serializable {
#Id
#Column(name = "SID")
private Integer sid;
#Column(name = "NAME")
private String name;
// getters and setters
}
SubjectPlace.java
#Entity
#Table(name = "SUBJECT_PLACE")
public class SubjectPlace implements Serializable {
#Id
#Column(name = "SPID")
private Integer spid;
#ManyToOne
#JoinColumn(name = "SUB_KEY") //Subject FK
private Subject subject;
#ManyToOne
#JoinColumn(name = "PLC_KEY") //Place FK
private Place place;
// getters and setters
}
Place.java
#Entity
#Table(name = "PLACE")
public class Place implements Serializable {
#Id
#Column(name = "PID")
private Integer pid;
#Column(name = "NAME")
private String name;
#ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
#JoinTable(name = "SUBJECT_PLACE",
joinColumns = { #JoinColumn(name = "PLC_KEY", nullable = false, updatable = false) },
inverseJoinColumns = { #JoinColumn(name = "SUB_KEY", nullable = false, updatable = false) })
private Set<Subject> subjects;
// getters and setters
}
But than I need to link Person with Subject in selected Places. I mean that each Place has its own collection of Subject. And a Person have link to Subject whitch resides in particular Place.
like This:
Subject (M) -- (M) Place through JoinTable Subject (1) -- (M) Subject_Place (M) -- (1) Place
Person (M) -- (M) Subject_Place through JoinTable Person (1) -- (M) Person_Subject_Place (M) -- (1) Subject_Place
Person.java
#Entity
#Table(name = "PERSON")
public class Person implements Serializable {
#Id
#Column(name = "PRSID")
private Integer prsid;
#Column(name = "NAME")
private String name;
// How to annotate this code?
// I experience problem in this part of code
#OneToMany
#JoinColumn(name="SPID_KEY")
private List<SubjectPlace> subjectPlaces;
// getters and setters
}
PersonSubjectPlace.java
#Entity
#Table(name = "PERSON_SUBJECT_PLACE")
public class PersonSubjectPlace implements Serializable {
#Id
#Column(name = "PSPID") // Person_Subject_Place ID
private Integer pspid;
#ManyToOne
#JoinColumn(name = "PER_KEY") //Person FK
private Person person;
// How to annotate this code?
// I experience problem in this part of code
#ManyToOne
#JoinColumn(name = "SPID_KEY") //Subject_Place FK
private SubjectPlace subjectPlace;
// getters and setters
}
And when I try so get Persons and its Subjects, I get this error:
Caused by: org.hibernate.MappingException: Foreign key (FK2C3B79384AABC975:PERSON_SUBJECT_PLACE [SPID_KEY])) must have same number of columns as the referenced primary key (SUBJECT_PLACE [PLC_KEY,SUB_KEY])
What, How shoul I map?
In your OneToMany mapping you don't need to specify the foreign key, you just need to use mappedBy property to refer your mapping object, you can learn more about it in OneToMany Mapping Documentation, and here's what you need to map Person and PersonSubjectPlace entities:
In your Person class:
#OneToMany(mappedBy="person")
private List<PersonSubjectPlace> personsubjectPlaces;
In your PersonSubjectPlace class:
#ManyToOne
#JoinColumn(name="PRSID") //Specify the primary key of Person
private Person person;
For further information about the difference between JoinColumn and mappedBy you can take a look at this answer.
EDIT:
For the mapping between SubjectPlace and PersonSubjectPlace:
In your SubjectPlace class:
#OneToMany(mappedBy="subjectPlace")
private List<PersonSubjectPlace> personsubjectPlaces;
In your PersonSubjectPlace class:
#ManyToOne
#JoinColumn(name="SPID") //Specify the primary key of SubjectPerson
private SubjectPlace subjectPlace;
Note:
The best approach to map those classes is to use #JoinTable between Person and SubjectPlace, take a look at this #JoinTable example, because PersonSubjectPlace is pratically an asociation-entity between Person and SubjectPlace.
You should remove #Joincolumn annotation and add mappedBy variable to #OneToMany annotation.
#OneToMany(mappedBy = "spid")
You should have a variable in SubjectPlace that has a Person where you should put #JoinColumn annotation

JPA Compound key with #EmbeddedId

In a legacy database, I have three tables: Users, Workgroups, and UsersWorkgroup. UsersWorkgroup stores what role a user has in a workgroup.
Here are the relevant code snippets:
#Entity
#Table(name = "users_workgroup")
public class UsersWorkgroup implements Serializable {
private static final long serialVersionUID = 1L;
#EmbeddedId
protected UsersWorkgroupPK usersWorkgroupPK;
#JoinColumn(name = "idworkgroup", referencedColumnName = "idworkgroup")
#ManyToOne(optional = false)
private Workgroup workgroup;
#JoinColumn(name = "user_name", referencedColumnName = "user_name")
#ManyToOne(optional = false)
private Users users;
#Column(name = "role")
private Integer role;
#Embeddable
public class UsersWorkgroupPK implements Serializable {
#Basic(optional = false)
#Column(name = "idworkgroup", insertable=false, updatable=false)
private int idworkgroup;
#Basic(optional = false)
#Column(name = "user_name", insertable=false, updatable=false)
private String userName;
#Entity
#Table(name = "workgroup")
public class Workgroup implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "idworkgroup")
private Integer idworkgroup;
#Column(name = "name")
private String name;
#OneToMany(cascade = CascadeType.ALL, mappedBy = "idworkgroup")
private Collection<UsersWorkgroup> usersWorkgroupCollection;
And of course, problem is, it doesn't work.
Currently I get this exception:
Exception Description: An incompatible
mapping has been encountered between
[class entity.Workgroup] and [class
entity.UsersWorkgroup]. This usually
occurs when the cardinality of a
mapping does not correspond with the
cardinality of its backpointer.
Which I don't understand since OneToMany should match ManyToOne... Or is it a ManyToMany relationship? If I switch to #ManyToMany, I get this:
Exception Description: The target
entity of the relationship attribute
[workgroup] on the class [class
com.ericsson.rsg.ejb.entity.UsersWorkgroup]
cannot be determined. When not using
generics, ensure the target entity is
defined on the relationship mapping.
I'm trying to understand compound keys (embedded), but all the examples I could find have only simple columns that are not foreign keys (but that's the whole point of a compound key, isn't it?). Can the UsersWorkgroup table secretly be a join table?
Should I declare the PK class as a strict POJO class? Or should I put the #JoinColumn annotations in the PK class? How do I refer to the columns within the compound key from another table? Should I initialize the PK object in the refering class constructor, or is it not necessary?
I feel stuck completely.
First of all, I think your relation is a Many To Many, as a user can be in many groups, and a group can have many users (or I would assume so).
Second, as far as I know you have to reference both id_workgroup and user_name as JoinColumns, because they are part of the PK and a unit, so both should be referenced.
Also, I see the "equals" and "hashCode" methods missing from your embedded PK, as well as the getters/setters. I believe they are mandatory.
Your mapping looks fine except for mappedBy - it should be a property name, not a column name:
#OneToMany(cascade = CascadeType.ALL, mappedBy = "workgroup")
private Collection<UsersWorkgroup> usersWorkgroupCollection;

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