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How to change this for loop into stream?
public int calculateForSpliterator(String[] matchTab, String spliterator, RulesChecker rulesChecker) {
int finalScore = 0;
for (String element : matchTab) {
String[] splitScroes = element.split(spliterator);
int ourPoints = Integer.parseInt(splitScroes[0]);
int theirPoints = Integer.parseInt(splitScroes[1]);
finalScore += rulesChecker.checkRules(ourPoints, theirPoints);
}
return finalScore;
}
Assuming RulesChecker#checkRules returns an int, then you can use:
public int calculateForSpliterator(String[] matchTab, String spliterator, RulesChecker rulesChecker) {
return Arrays.stream(matchTab)
.map(element -> element.split(spliterator))
.mapToInt(splitScores -> rulesChecker.checkRules(Integer.parseInt(splitScores[0]),
Integer.parseInt(splitScores[1])))
.sum();
}
Notice how this isn't much more readable than your current solution, so I probably would keep the for-loop if I were you.
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I have dates like this in string that need leading zero's removed.
Here is what I need:
Remove leading zero's in between [- and :
Below are some of the examples and expected results
20200831000000.000[-05:EST] -> 20200831000000.000[-5:EST]
20200831000000.000[-08:30:EST] -> 20200831000000.000[-8:30:EST]
20200831000000.000[-10:EST] -> 20200831000000.000[-10:EST]
I can't figure this out as I'm new to regular expressions. I have tried the below but not working
"0+(?!$)"
this will work like you went :
public static void main(String[] args) {
String arr[] = {"20200831000000.000[-05:EST]","20200831000000.000[-08:30:EST]","20200831000000.000[-10:EST]"};
for(int i=0; i < arr.length ; i++){
arr[i] = arr[i].replaceAll("(?<=\\[-?)(0*)(?=.*\\])", "");
}
for(String s : arr){
System.out.println(s);
}
}
output :
20200831000000.000[-5:EST]
20200831000000.000[-8:30:EST]
20200831000000.000[-10:EST]
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I've got a 6 char long string, and I would like to check, if there is just one from each character. How to?
You could compare the number of distinct characters to the length of the string:
boolean charMoreThanOnce = s.chars().distinct().count() < s.length();
You can do it using a Set. You need unique elements and Set gurantees you containing the unique elements. HashSet is implementation of Set, you can use it to implement this idea.
public boolean ifAllCharsUnique(String input){
char[] arr = input.toCharArray();
int length = arr.length;
Set<Character> checker = new HashSet<>();
for(int i =0 ; i < length; i++){
if(checker.contains(arr[i]){
return false;
}
checker.add(arr[i]);
}
return true;
}
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I need help with a implementation of a function that gives me all combinations of ArrayList<ArrayList<String>> (not List<List<String>>) List in fix order.
An Example for what I need:
From:
List1:[1,2]
List2:[3,4]
List3:[5,6]
To:
String 1 "1,3,5"
String 2 "1,3,6"
String 3 "1,4,5"
String 4 "1,4,6"
String 5 "2,3,5"
String 6 "2,3,6"
String 7 "2,4,5"
String 8 "2,4,6"
All Strings in ArrayList<String> Object
Please help me, I have no idea how to implement it.
PS: The size of ArrayList<ArrayList<String>> is variable.
PSS: ...and the size from the ArrayList lists are variable.
After little changes from the old rev it works now (ArrayIndexOutOfBoundsException and deleting to much on result):
void generate(ArrayList<ArrayList<String>> lists,
ArrayList<String> result, int index) {
if (index >= lists.size()) {
System.out.println(String.valueOf(result));
return;
}
ArrayList<String> list = lists.get(index);
for (int i = 0; i < list.size(); i++) {
result.add(list.get(i));
generate(lists, result, index + 1);
result.remove(result.size() - 1);
}
}
}
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Hi How I write these several code in only one line
if (stimee.getText().toString().equals("0")) {stimevar="00"; }
if (stimee.getText().toString().equals("1")) {stimevar="01"; }
if (stimee.getText().toString().equals("2")) {stimevar="02"; }
if (stimee.getText().toString().equals("3")) {stimevar="03"; }
if (stimee.getText().toString().equals("4")) {stimevar="04"; }
if (stimee.getText().toString().equals("5")) {stimevar="05"; }
if (stimee.getText().toString().equals("6")) {stimevar="06"; }
if (stimee.getText().toString().equals("7")) {stimevar="07"; }
if (stimee.getText().toString().equals("8")) {stimevar="08"; }
if (stimee.getText().toString().equals("9")) {stimevar="09"; }
all you really need is:
stimevar="0"+stimee.getText().toString();
since i dont see an else clause in your question, this must solve your problem.
You can use a Map to store the values and then set the variable.
Map<String, String> map = new HashMap<>();
map.put("0", "00");
map.put("0", "01");
...
map.put("9", "09");
stimevar = map.get(stimee.getText().toString());
String str = stimee.getText().toString();
for (int i = 0; i <= 9; i++)
if (("" + i).equals(str))
stimevar = "0" + i;
// parse input value as integer
int value = Integer.parseInt(stimee.getText().toString());
// check input for values from 0 to 9
for (int i = 0; i < 10; i ++) {
// if found a match
if (value == i) {
// set variable
stimevar = String.format("%02d", i);
// and stop checking
break;
}
}
EDIT: Thanks to #Tom for pointing out parsing the String only once beforehand would be more effective.
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I have 5 distinct strings called, say, string1 through string5.
I want to write a simple if statement that runs if any two of the five strings contain the same string. How would I do that?
Thanks in advance!
Comparison is a binary operation, therefore you can always compare only two objects at a time. I would suggest using a cycle and comparing each string to the remaining ones.
public boolean multipleStringEquals(String[] strings) {
for (int i = 0; i < strings.length; i++) {
for (int j = i + 1; j < strings.length; j++) {
if (strings[i].equals(strings[j])) {
return true;
}
}
}
return false;
}