Unzip files in FTP server using Java - java

I am trying to unzip files in the FTP location, but when i unzip i am not able to get all the files in FTP server, but when i try the code to unzip files to local machine it is working. I am sure somewhere while writing the data to FTP i am missing something.Below is my code. Please help me on this.
public void unzipFile(String inputFilePath, String outputFilePath) throws SocketException, IOException {
FileInputStream fis = null;
ZipInputStream zipIs = null;
ZipEntry zEntry = null;
InputStream in = null;
FTPClient ftpClientinput = new FTPClient();
FTPClient ftpClientoutput = new FTPClient();
String ftpUrl = "ftp://%s:%s#%s/%s;type=i";
ftpClientinput.connect(server, port);
ftpClientinput.login(user, pass);
ftpClientinput.enterLocalPassiveMode();
ftpClientinput.setFileType(FTP.BINARY_FILE_TYPE);
String uploadPath = "path";
ftpClientoutput.connect(server, port);
ftpClientoutput.login(user, pass);
ftpClientoutput.enterLocalPassiveMode();
ftpClientoutput.setFileType(FTP.BINARY_FILE_TYPE);
try {
// fis = new FileInputStream(inputFilePath);
String inputFile = "/Srikanth/RecordatiFRA_expenses.zip";
String outputFile = "/Srikanth/FR/";
in = ftpClientinput.retrieveFileStream(inputFile);
zipIs = new ZipInputStream(new BufferedInputStream(in));
while ((zEntry = zipIs.getNextEntry()) != null) {
try {
byte[] buffer = new byte[4 * 8192];
FileOutputStream fos = null;
OutputStream out = null;
// String opFilePath = outputFilePath + zEntry.getName();
String FTPFilePath = outputFile + zEntry.getName();
// System.out.println("Extracting file to "+opFilePath);
System.out.println("Extracting file to " + FTPFilePath);
// fos = new FileOutputStream(opFilePath);
out = ftpClientoutput.storeFileStream(FTPFilePath);
// System.out.println(out);
int size;
while ((size = zipIs.read(buffer, 0, buffer.length)) != -1) {
// fos.write(buffer, 0 , size);
out.write(buffer, 0, size);
}
// fos.flush();
// fos.close();
} catch (Exception ex) {
ex.getMessage();
}
}
zipIs.close();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
try {
if (ftpClientinput.isConnected()) {
ftpClientinput.logout();
ftpClientinput.disconnect();
}
} catch (IOException ex) {
ex.printStackTrace();
}
}
}

This method will do what you want, you can tweak it as you like.
I cleaned up and removed a lot that you didn't need; One thing to note is the use of try-with-resources blocks and not declaring your local variables so far from where they're used.
Your main error was that you needed to call completePendingCommand after certain methods as noted in their documentation.
Remember to read the documentation on methods you're using for the first time.
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.SocketException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
import org.apache.commons.net.ftp.FTP;
import org.apache.commons.net.ftp.FTPClient;
import org.apache.commons.net.ftp.FTPReply;
public static void unzipFTP(String server, int port, String user, String pass, String ftpPath)
throws SocketException, IOException {
FTPClient ftp = new FTPClient();
ftp.connect(server, port);
ftp.login(user, pass);
ftp.enterLocalPassiveMode();
ftp.setFileType(FTP.BINARY_FILE_TYPE);
try (InputStream ftpIn = ftp.retrieveFileStream(ftpPath);
ZipInputStream zipIn = new ZipInputStream(ftpIn);) {
// complete and verify the retrieve
if (!ftp.completePendingCommand()) {
throw new IOException(ftp.getReplyString());
}
// make the output un-zipped directory, should be unique sibling of the target zip
String outDir = ftpPath + "-" + System.currentTimeMillis() + "/";
ftp.makeDirectory(outDir);
if (!FTPReply.isPositiveCompletion(ftp.getReplyCode())) {
throw new IOException(ftp.getReplyString());
}
// write the un-zipped entries
ZipEntry zEntry;
while ((zEntry = zipIn.getNextEntry()) != null) {
try (OutputStream out = ftp.storeFileStream(outDir + zEntry.getName());) {
zipIn.transferTo(out);
}
if (!ftp.completePendingCommand()) {
throw new IOException(ftp.getReplyString());
}
}
} finally {
try {
if (ftp.isConnected()) {
ftp.logout();
ftp.disconnect();
}
} catch (IOException ex) {
ex.printStackTrace();
}
}
}

Related

How to download chosen file from ftp-server using java? [duplicate]

With this code iI always get a empty file.
What I have to do with it?
login is always true. (ofc, here is not real password)
import org.apache.commons.net.ftp.FTPClient;
import org.apache.commons.net.ftp.FTPFile;
import java.io.*;
public class Logs {
public static void main(String[] args) {
FTPClient client = new FTPClient();
try {
client.connect("myac.cs-server.pro", 121);
boolean login = client.login("a3ro", "passWordIsSecret");
System.out.println(login);
String remoteFile1 = "myac_20150304.log";
File downloadFile1 = new File("C:\\Users\\Aero\\Desktop\\test\\myac.log");
OutputStream outputStream1 =
new BufferedOutputStream(new FileOutputStream(downloadFile1));
boolean success = client.retrieveFile(remoteFile1, outputStream1);
System.out.println(success);
outputStream1.close();
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
client.disconnect();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
Use FileOutputStream:
String filename = "test.txt";
FileOutputStream fos = new FileOutputStream(filename);
client.retrieveFile("/" + filename, fos);
Use something like this:
InputStream inputStream = client.retrieveFileStream(remoteFileNameHere);
To retrieve the remote file input stream.
Then you can use to copy the stream to desired file:
FileOutputStream out = new FileOutputStream(targetFile);
org.apache.commons.io.IOUtils.copy(in, out);

Upload file using org.apache.commons.net.ftp.FTPSClient

I am working on File Upload using Java API.
I want to upload file into server by using FTPS , I found that I can use Google library of apache commons net but I am facing issue in org.apache.commons.net.ftp.FTPSClient when i upload file.
Following is the error
Exception in thread "main" java.lang.NullPointerException
this is my code :
public static void main(String[] args) {
String server = "HOST";
int port = 21;
String user = "USER";
String pass = "PASS";
FTPSClient ftpClient;
try {
ftpClient = new FTPSClient();
try {
ftpClient.connect(server, port);
ftpClient.login(user, pass);
ftpClient.enterLocalPassiveMode();
ftpClient.setFileType(FTP.BINARY_FILE_TYPE);
// APPROACH #1: uploads first file using an InputStream
File firstLocalFile = new File("TEST1.CSV");
String firstRemoteFile = "TEST1.txt";
InputStream inputStream = new FileInputStream(firstLocalFile);
System.out.println("Start uploading first file");
boolean done = ftpClient.storeFile(firstRemoteFile, inputStream);
inputStream.close();
if (done) {
System.out.println("The first file is uploaded successfully.");
}
// APPROACH #2: uploads second file using an OutputStream
File secondLocalFile = new File("TEST2.CSV");
String secondRemoteFile = "TEST2.TXT";
inputStream = new FileInputStream(secondLocalFile);
System.out.println("Start uploading second file");
OutputStream outputStream = ftpClient.storeFileStream(secondRemoteFile);
byte[] bytesIn = new byte[4096];
int read = 0;
while ((read = inputStream.read(bytesIn)) != -1) {
outputStream.write(bytesIn, 0, read);
}
inputStream.close();
//outputStream.close();
boolean completed = ftpClient.completePendingCommand();
if (completed) {
System.out.println("The second file is uploaded successfully.");
}
} catch (IOException ex) {
System.out.println("Error: " + ex.getMessage());
ex.printStackTrace();
} finally {
try {
if (ftpClient.isConnected()) {
ftpClient.logout();
ftpClient.disconnect();
}
} catch (IOException ex) {
ex.printStackTrace();
}
}
} catch (NoSuchAlgorithmException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Any support is appreciated

How to copy file in resource folder in java

Need a quick help. I am new to Java..In my project I have input & output folder in resources. Inside input folder I have a csv file. I need to move that file to output folder through java code. How to copy that input file to output directory. I have tried in google but not getting a working solution. My project structure is based on standard maven project.
I think there are at least four methods you can use to move your csv file to some other directory.
I assume that you already know the absolute directory path.
Method 1. The way of apache commons
You can use apache commons io library.
public static void moveWithApacheCommonsIO()
{
File sourceFile = new File("resource/AssetsImportCompleteSample.csv");
File destinationFile = new File("resource/aa/AssetsImportCompleteSample.csv");
try {
FileUtils.moveFile(sourceFile, destinationFile);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Method 2. The way of java's NIO
You can also use nio (non-blocking io) in java
public static void moveWithFileNIO()
{
File sourceFile = new File("resource/AssetsImportCompleteSample.csv");
File destinationFile = new File("resource/aa/AssetsImportCompleteSample.csv");
FileInputStream inputStream = null;
FileOutputStream outputStream = null;
sourceFile.deleteOnExit();
try {
inputStream = new FileInputStream(sourceFile);
outputStream = new FileOutputStream(destinationFile);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
final FileChannel inChannel = inputStream.getChannel();
final FileChannel outChannel = outputStream.getChannel();
try {
inChannel.transferTo(0, inChannel.size(), outChannel);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
finally
{
try {
inChannel.close();
outChannel.close();
inputStream.close();
outputStream.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
Method 3. The traditional way of java's IO
You can use traditional method with file in and output stream in java.(Blocking IO)
public static void moveWithFileInOutStream()
{
File sourceFile = new File("resource/AssetsImportCompleteSample.csv");
File destinationFile = new File("resource/aa/AssetsImportCompleteSample.csv");
InputStream fin = null;
OutputStream fout = null;
sourceFile.deleteOnExit();
try {
fin = new BufferedInputStream(new FileInputStream(sourceFile));
fout = new BufferedOutputStream(new FileOutputStream(destinationFile));
byte[] readBytes = new byte[1024];
int readed = 0;
while((readed = fin.read(readBytes)) != -1)
{
fout.write(readBytes, 0, readed);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
finally
{
try {
fin.close();
fout.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
Method 4. Using JNI(Java Native Interface)
Finally, you can use some function like mv or MovFile depending on your Operating system with JNI.
I think it is out of scope of this topic. you can google it or see JNA library to accomplish your task if you want.
Here are complete code for you.
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.nio.channels.FileChannel;
import org.apache.commons.io.FileUtils;
public class MovefileTest {
public static void moveWithApacheCommonsIO()
{
File sourceFile = new File("resource/AssetsImportCompleteSample.csv");
File destinationFile = new File("resource/aa/AssetsImportCompleteSample.csv");
try {
FileUtils.moveFile(sourceFile, destinationFile);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static void moveWithFileInOutStream()
{
File sourceFile = new File("resource/AssetsImportCompleteSample.csv");
File destinationFile = new File("resource/aa/AssetsImportCompleteSample.csv");
InputStream fin = null;
OutputStream fout = null;
sourceFile.deleteOnExit();
try {
fin = new BufferedInputStream(new FileInputStream(sourceFile));
fout = new BufferedOutputStream(new FileOutputStream(destinationFile));
byte[] readBytes = new byte[1024];
int readed = 0;
while((readed = fin.read(readBytes)) != -1)
{
fout.write(readBytes, 0, readed);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
finally
{
try {
fin.close();
fout.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
public static void moveWithFileNIO()
{
File sourceFile = new File("resource/AssetsImportCompleteSample.csv");
File destinationFile = new File("resource/aa/AssetsImportCompleteSample.csv");
FileInputStream inputStream = null;
FileOutputStream outputStream = null;
sourceFile.deleteOnExit();
try {
inputStream = new FileInputStream(sourceFile);
outputStream = new FileOutputStream(destinationFile);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
final FileChannel inChannel = inputStream.getChannel();
final FileChannel outChannel = outputStream.getChannel();
try {
inChannel.transferTo(0, inChannel.size(), outChannel);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
finally
{
try {
inChannel.close();
outChannel.close();
inputStream.close();
outputStream.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
public static void main(String[] args) {
//moveWithApacheCommonsIO();
//moveWithFileNIO();
moveWithFileInOutStream();
}
}
Regards,

automatically unzip file while downloading that zip file

I have a download button in my webpage where when i click it, it downloads a zip file. now i want to have a function like, when i click the download button the zip file should automatically extract and save in a user defined folder.
i have an idea that if we can create a exe file and add it to the download button then it should automatically extract the zip file and save in folder
%>
<td align="center">
<img onclick="pullReport('<%=reportPath.toString()%>');" title="Click to download this Report" src="./images/down-bt.gif"/>
</td>
</tr>
<%} %>
this is the method that creates zip file
public ActionForward pullReport(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response)throws SQLException{
Connection connection=null;
boolean cont=false;
failureList.clear();
logger.info("dispatch = pullReport");
String filePaths=null;
String filePath = null;
String fileName = null;
String srcFileName = null;
String directory = null;
try{
Properties props = Application.getProperties();
String basePath = props.getProperty("std.report_location");
logger.info(" basepath " + basePath);
connection=ConnectionManager.getConnection();
StandardReportsForm standardReportsForm=(StandardReportsForm)form;
filePaths=standardReportsForm.getFilePath();
logger.info("filepaths " + filePaths);
ServletOutputStream fos = null;
InputStream is = null;
String [] filePathArr = filePaths.split(",");
FileIO fio = null;
FileIO srcFio = null;
if (filePathArr.length > 1) {
filePath = filePathArr[0].substring(0,filePathArr[0].lastIndexOf("."))+".zip";
logger.info(filePath + " creating zip file ......");
directory = basePath+filePath.substring(0,filePath.lastIndexOf('/'));
logger.info( " Direcory Name :" +directory);
fileName = filePath.substring(filePath.lastIndexOf('/')+1);
logger.info( " File Name :" +fileName);
fio = new FileIO(directory,fileName);
fio.mkDir();
byte[] buffer = new byte[1024];
OutputStream fosForZip = fio.createOutputStream();
ZipOutputStream zos = new ZipOutputStream(fosForZip);
InputStream fis = null;
for (int i=0; i < filePathArr.length; i++) {
srcFileName = filePathArr[i].substring(filePathArr[i].lastIndexOf('/')+1);
srcFio = new FileIO(directory,srcFileName);
if (srcFio.isFileExist()) {
cont=true;
logger.info(" adding into zip file " +srcFileName);
fis = srcFio.createInputStream();
BufferedInputStream bis = new BufferedInputStream(fis);
zos.putNextEntry(new ZipEntry(srcFileName));
int length;
while ((length = bis.read(buffer)) != -1) {
zos.write(buffer, 0, length);
}
zos.closeEntry();
// close the InputStream
bis.close();
srcFio.closeInputStream(fis);
} else {
logger.info(srcFileName + " file does not exist on shared drive");
cont =false;
break;
}
}
FileIO.closeOutputStream(zos);
if (!cont){
standardReportsForm.setMissingFileName(srcFileName);
request.getSession().getAttribute("fetchReports");
standardReportsForm.setFetchedReports((List<ReportDetails>)request.getSession().getAttribute("fetchReports"));
return mapping.findForward("fetchReport");
}
} else {
filePath = filePathArr[0];
fileName = filePath.substring(filePath.lastIndexOf('/')+1);
}
if (basePath.startsWith("smb")) {
SmbFile smbFile = new SmbFile(basePath+filePath,SMBHelper.getInstance().createAuthFromSmbLocation(basePath));
if(smbFile.exists())
{
is = new SmbFileInputStream(smbFile);
cont=true;
}
} else {
File file=new File(basePath+filePath);
if(file.exists())
{
is = new FileInputStream(file);
cont=true;
}
}
if(cont)
{
fos=response.getOutputStream();
setContentType(response, fileName);
//fos.write (baos.toByteArray());
ByteArrayOutputStream bos = new ByteArrayOutputStream();
byte[] buf = new byte[1024];
for (int readNum; (readNum = is.read(buf)) != -1;) {
bos.write(buf, 0, readNum);
}
byte[] bytes = bos.toByteArray();
fos.write(bytes);
fos.flush();
fos.close();
} else {
standardReportsForm.setMissingFileName(fileName);
request.getSession().getAttribute("fetchReports");
standardReportsForm.setFetchedReports((List<ReportDetails>)request.getSession().getAttribute("fetchReports"));
return mapping.findForward("fetchReport");
}
}catch(SQLException sx) {
logger.error(" error log SQLException " ,sx);
failureList.add(new UROCException(UROCMessages.getMessage("ERR_CONN_EXEC"), sx));
} catch(NamingException ne) {
logger.info("RMI error is "+ne);
failureList.add(new UROCException(UROCMessages.getMessage("ERR_NAMING_EXEC"), ne));
} catch(Exception e) {
logger.error(" error log Exception " ,e);
failureList.add(new UROCException(UROCMessages.getMessage("ERR_GEN_EXEC", new String[] {"General Exception"}), e));
} finally {
SQLHelper.closeConnection(connection, failureList, logger);
}
return null;
}
yah you can use java code to unzip the file.here is the example
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
public class UnzipUtility {
public String zipFilePath= "D:/javatut/corejava/src/zipfile.zip";
public String destDir = "D:/javatut/corejava";
private static final int BUFFER_SIZE = 4096;
/**
* #param args
* #throws IOException
*/
public static void main(String[] args) throws IOException {
UnzipUtility uu = new UnzipUtility();
uu.unzip(uu.zipFilePath, uu.destDir);
}
public void unzip(String zipFilePath,String destDir)throws IOException{
File destDirectory = new File(destDir);
if(!destDirectory.exists()){
destDirectory.mkdir();
}
ZipInputStream zipIn = new ZipInputStream(new FileInputStream(zipFilePath));
ZipEntry zipEntry = zipIn.getNextEntry();
while(zipEntry!=null){
String filePath=destDir+File.separator+zipEntry.getName();
if(!zipEntry.isDirectory()){
extractFile(zipIn,filePath);
}
else{
File dir = new File(filePath);
dir.mkdir();
}
zipIn.closeEntry();
zipEntry = zipIn.getNextEntry();
}
zipIn.close();
}
private void extractFile(ZipInputStream zipIn, String filePath) throws FileNotFoundException {
BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(filePath));
byte[] bytesIn = new byte[BUFFER_SIZE];
int read = 0;
try {
while ((read = zipIn.read(bytesIn)) != -1) {
bos.write(bytesIn, 0, read);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
bos.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
thank you.......
please follow this path and (clear) automatic files viewer
chrome://settings/onStartup/Advanced/Downloads/automatic file viewer (clear)

Unzip *.docx file in memory without write to disk - Java

I want to unzip *.docx file in memory without to write the output to the disk. I found the following implementation but it allows only to read the compressed files but not to see the directory structure. It is important for me to know the location of each file in the directory tree. can somebody give me a direction?
private static void UnzipFileInMemory() {
try {
ZipFile zf = new ZipFile("d:\\a.docx");
int i = 0;
for (Enumeration e = zf.entries(); e.hasMoreElements();) {
InputStream in = null;
try {
ZipEntry entry = (ZipEntry) e.nextElement();
System.out.println(entry);
in = zf.getInputStream(entry);
} catch (IOException ex) {
//Logger.getLogger(Tester.class.getName()).log(Level.SEVERE, null, ex);
} finally {
try {
in.close();
} catch (IOException ex) {
//Logger.getLogger(Tester.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
} catch (IOException ex) {
//Logger.getLogger(Tester.class.getName()).log(Level.SEVERE, null, ex);
}
}
Use ZipInputStream : zEntry in this example gives you file location.
import java.io.BufferedInputStream;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
public class unzip {
public static void main(String[] args) {
String filePath = "D:/Tmp/Tmp.zip";
String oPath = "D:/Tmp/";
new unzip().unzipFile(filePath, oPath);
}
public void unzipFile(String filePath, String oPath) {
FileInputStream fis = null;
ZipInputStream zipIs = null;
ZipEntry zEntry = null;
try {
fis = new FileInputStream(filePath);
zipIs = new ZipInputStream(new BufferedInputStream(fis));
while ((zEntry = zipIs.getNextEntry()) != null) {
try {
FileOutputStream fos = null;
String opFilePath = oPath + zEntry.getName();
fos = new FileOutputStream(opFilePath);
System.out.println(zEntry.getName());
fos.flush();
fos.close();
} catch (Exception ex) {
}
}
zipIs.close();
fis.close();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
You associate the zip format file as a virtual file system (FileSystem). For that java already has a protocol handler, for jar:file://.... So you have to prepend a File.toURI() with "jar:".
URI docxUri = ,,, // "jar:file:/C:/... .docx"
Map<String, String> zipProperties = new HashMap<>();
zipProperties.put("encoding", "UTF-8");
try (FileSystem zipFS = FileSystems.newFileSystem(docxUri, zipProperties)) {
Path documentXmlPath = zipFS.getPath("/word/document.xml");
Now you may use Files.delete() or Files.copy between real disk filesystem and zip.
When using XML:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(true);
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse(Files.newInputStream(documentXmlPath));
//Element root = doc.getDocumentElement();
You can then use XPath to find the places, and write the XML back again.
It even might be that you do not need XML but could replace place holders:
byte[] content = Files.readAllBytes(documentXmlPath);
String xml = new String(content, StandardCharsets.UTF_8);
xml = xml.replace("#DATE#", "2014-09-24");
xml = xml.replace("#NAME#", StringEscapeUtils.escapeXml("Sniper")));
...
content = xml.getBytes(StandardCharsets.UTF_8);
Files.delete(documentXmlPath);
Files.write(documentXmlPath, content);
For a fast development, rename a copy of the .docx to a name with the .zip file extension, and inspect the files.
Simply add a file checking code within your loop:
if (!entry.isDirectory()) // Alternatively: if(entry.getName().contains("."))
System.out.println(entry);

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