Invalid Java statement [duplicate] - java

This question already has answers here:
Java: Not a statement
(2 answers)
Closed 2 years ago.
I want to know why the following is invalid in Java. Java compiler says that it is not a valid statement.
1+1;
I know the following works.
int i = 1+1;
Please explain why the second one is valid while the first is not. Thanks in advance.

Because you are doing nothing with 1+1. That is not a statement, it's an expression that returns a value that should be stored somewhere, like in the second example you give. If your statements have no effect, they are excluded from the language grammar.

The Java syntax needs the variable to be declared like the following
Class name = value;
You can't create a value without a variable definition and can't create a variable without a name and a class.

Related

How object class non Null works [duplicate]

This question already has an answer here:
Purpose of Objects.isNull(...) / Objects.nonNull(...)
(1 answer)
Closed 12 months ago.
Can someone explain the following code?
if (Objects.nonNull(department.getDepartmentName()) && !"".equalsIgnoreCase(department.getDepartmentName())) {
depDB.setDepartmentName(department.getDepartmentName());
}
The first stab at understanding how a piece of code works should be look at the documentation available.
In your context, code intends to check if department.getDepartmentName() is both not-null and an empty string, only then set it to some value.
On an additional note, double check is redundant.
"".equalsIgnoreCase(department.getDepartmentName())
checks both, if department.getDepartmentName() is not null and is blank string.

How to use var in Java [duplicate]

This question already has an answer here:
Any difference between `var x` and `int x`? [duplicate]
(1 answer)
Closed 1 year ago.
I am stuck on how to use var. Is there any difference between this two?
var input = (String) result.get("some field from DB");
String input = (String) result.get("some field from DB");
In java 10 and above when you use var you are allowing the compiler to attempt to decide what the variables type should be. In your example your casting a String so it will give that variable type String.
In your second example you are specifically telling the compiler that your variable is of type String.
The second is safer if you know what your variable type will be as it leaves no confusion down to the compile.

Error with Conditional Operator in Java [duplicate]

This question already has answers here:
Why can't I use the ternary ? operator to select between two function calls?
(4 answers)
Java: Ternary with no return. (For method calling)
(6 answers)
Closed 4 years ago.
c.getCollectibles()[i][j].isCollected() ? collectiblePanels[i][j].setSplash(c.getCollectibles()[i][j].getIcon()) : repaint();
I am writing a program in Java and have an error in my program. I am using a conditional operator. c.getCollectibles() returns a two-dimensional array of a Collectible class, and isCollected() is a non-static public method in the Collectible class that returns a boolean value.
collectiblePanels is a two-dimensional array of a class that contains a setSplash() method. The setSplash() method takes in the same type that getIcon() returns (the specifics are irrelevant to the error). Overall, setSplash() is void.
repaint() is a random void method. Again, specifics are irrelevant to the error.
The specific error is below:
The left-hand side of an assignment must be a variable
Syntax error on token "?", invalid AssignmentOperator
Syntax error on token ":", ; expected

Why the java array documentation doesn't show the field "length"? [duplicate]

This question already has answers here:
Where is array's length property defined?
(7 answers)
Closed 7 years ago.
I have seen some examples of getting the length of an array using the field length, for example: array.length. I have always used this field but checking the array documentation I did not see that variable. Why is it that the documentation doesn't show it? It only shows a bunch of methods but I can't see the variable length. Is it in another class or what? I have seen questions like this before but the answers are not well explained so I can't understand them.
Because length is not actually a field. The compiler recognizes the identifier specially and translates it to an arraylength instruction rather than a getfield instruction.

Unfamiliar piece of enhanced for loop syntax [duplicate]

This question already has answers here:
"loop:" in Java code. What is this, and why does it compile?
(12 answers)
Closed 9 years ago.
I have the job of going through another's code and I'm trying to figure it all out when I came across this for loop.
//I don't understand the purpose of assetLoop
assetLoop: for (AssetObject asset : assets) {
//Some code
}
I've never seen this syntax and I can't find any reference to it anywhere through my google searches. Can anyone tell me what assetLoop: is doing? Or simply give me the name of this concept so I can do some non-mindless googling and read about it? :)
This is called a label.
It allows you to write break assetLoop from a nested loop to break out of the outer loop.
It's essentially a limited form of goto, and is rarely used.
It's a label. You can put them on any statement. break assetLoop; will break out of that loop, even if the break statement is within another for, while, do-while or switch statement. Similarly continure assetLoop; will jump to the next iteration of the loop.

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