Java Methods vs constructors parameter comparison [duplicate] - java

This question already has answers here:
Methods vs Constructors in Java
(11 answers)
Closed 2 years ago.
actually i'm beginner my questions might be silly And my doubt is what was actual purpose of methods vs constructors in java,
we can pass values in both methods & constructor parameters,
which one is recommended and why??

A Java method is use to perform some action which is also know as Function. Where you can pass parameter. They must have return type.
A Constructor is special method use to initialise the object . Constructor must not have return type. Constuctor name must be same as class name.

Constructor is used to initialize an object whereas method is used to exhibits functionality of an object.
Constructors are invoked implicitly whereas methods are invoked explicitly.
Constructor does not return any value where the method may/may not return a value.
In case constructor is not present, a default constructor is provided by java compiler. In the case of a method, no default method is provided.
Constructor should be of the same name as that of class. Method name should not be of the same name as that of class.

Related

What are the benefits of a zero argument constructor? when is it ideal? [duplicate]

This question already has answers here:
Why do we need a default no argument constructor in Java?
(7 answers)
Closed 5 years ago.
Why would anyone want to define a zero argument constructor when a default parameterless constructor is created during compile time anyway? Are there any benefits to doing so? are there any cases where it is better to define a zero argument constructor within a class for the sole purpose of preventing the default from being created during compile time?
Simple: you define it when you need it.
For example to call another constructor with some default values which are then used by the other constructor to initialize fields of the class.
When you write down an "empty" constructor that does nothing besides calling the super constructor then sure - you wrote useless code that should go away.
A default constructor is added by java internally if user does not define any parametrised constructor. It initialises any uninitialised fields to their default values.
Like int to 0
string to null
object to null
It's needed if you want to execute an init-function as soon as a new object of the class is created. For Example:
public class Example {
public Example() {
init();
}
public void init() {
//do some Stuff
}
}
But Just defining it without doing anything is not sensefull.

No Param and Default constructors confusion [duplicate]

This question already has answers here:
Java default constructor
(13 answers)
Closed 6 years ago.
Here is a code with no param constructor
public class misc2 {
misc2(String x){
}
public static void main(String ... args){
misc2 m = new misc2(); // this throws a compilation error
}
}
My question is why does it throw a compilation error, when Java automatically creates a default constructor, in this case misc2(){...}. if it is not defined already.
Also, now if I add a no param constructor misc2(){...}, which one is actually called by the JVM. Is it the default param or the no param. The second question is because if Java already creates a default constructor with no parameters already, the what is the need to explicitly create a constructor in some cases in the Java program?
Java creates a default constructor if and only if no other explicit constructor is provided.
From the docs:
You don't have to provide any constructors for your class, but you must be careful when doing this. The compiler automatically provides a no-argument, default constructor for any class without constructors.
See: https://docs.oracle.com/javase/tutorial/java/javaOO/constructors.html

What is a method signature? [duplicate]

This question already has answers here:
Definition of a method signature?
(7 answers)
Closed 7 years ago.
I read a book titled 'Object First with Java' and in page 7 the author mentioned that the method signature "provides information needed to invoke that method". And the the author gave the following example:
void moveHorizontal(int distance)
However, today when I was watching a video about C# on Pluralsight, the author said that "the return type of a method is not part of the method signature".
I'm confused now and would like know what is a method signature?
A method-signature is the part of the method based on which you overload / override it. It contains :
The method name.
The arguments passed to it.
It doesn't contain :
Scope / access modifier
return type.
Method signature is used in interfaces and in abstract classes, but we always define the method data type(return type). It will be something invaluable if the return type is not a part of the signature.

Checking for valid overloading [duplicate]

This question already has answers here:
Which overload will get selected for null in Java?
(3 answers)
Closed 8 years ago.
I want to know whether this is a valid overloading :
public class OverLoadingTest{
private void callFunction(Object object){
System.out.println("Printing Object");
}
private void callFunction(String string){
System.out.println("Printing String");
}
}
Further more, since someone asked me this question.
If I do like this,
OverLoadingTest test = new OverLoadingTest();
test.callFunction(null);
what will be printed ?
Of course my opinion is that it isn't valid overloading at all.
So no question of the second part.
Please tell me about this with some explanation.
The method with the least generic argument is called. So, in your case, it will be method accepting String
Note : If 2 classes are at the same level, then you will get an ambiguous call exception. For example if one method took String and another took Exception.
If more than one member method is both accessible and applicable to a method
invocation, it is necessary to choose one to provide the descriptor for
the run-time method dispatch.
The Java programming language uses the rule that the most specific method is chosen.
See more details in JSL 15.12.2.5
In your case, String method will be invoked, if argument is String or null and for other argument's types Object method will be invoked.
In your example, if you define one more method with argument type that is not String (e.g Integer), can't compile the source as it is ambiguous to be invoked between the methods with String and Integer as they are same level.

How does the special variable "this" know exactly which Object to refer to in a program in JAVA? [duplicate]

This question already has answers here:
Using the keyword "this" in java [duplicate]
(12 answers)
Closed 9 years ago.
If the special variable this refers to an Object in a variable/method that is being used. How does it know exactly which object it must refer to out of various objects in a program?
The mechanism is almost disappointingly simple.
Each instance method actually takes one more argument than you declare for it, and that extra argument is assigned to this. Java syntax just thinly disguises this. When you write
list.get(0);
you have actually written
get(list, 0);
in a slightly modified way. The Java runtime resolves which get method to call by inspecting the type of that first argument and locating the appropriate get method in its class.
this points to the current object instance that it is used in.
If you define a class A with a method() that contains a this reference then you create two instances of the class
A a1 = new A();
A a2 = new A();
If you call a1.method() then this will refer to a1, if you call a2.method() then this will refer to a2
A a = new A();
a.doSomething(i) // is same as calling doSomething(a, i).
So, internally this refers to "a". The first argument to the function will be the object (there will only be one method that will be used by all objects). So, argument o will be the current object which has called this function.
From JAVA LANGUAGE SPECIFICATION
The keyword this may be used only in the body of an instance method,
instance initializer, or constructor, or in the initializer of an
instance variable of a class. If it appears anywhere else, a
compile-time error occurs.
When used as a primary expression, the keyword this denotes a value
that is a reference to the object for which the instance method was
invoked (§15.12), or to the object being constructed.
The type of this is the class C within which the keyword this occurs.
At run time, the class of the actual object referred to may be the
class C or any subclass of C.
The keyword this is also used in a special explicit constructor
invocation statement, which can appear at the beginning of a
constructor body (§8.8.7).
You can also refer to Oracle Tutorials
Within an instance method or a constructor, this is a reference to the current object — the object whose method or constructor is being called. You can refer to any member of the current object from within an instance method or a constructor by using this.
Oracle Java Tutorials
this is a very important keyword that can differentiate between parent and child class objects. this refers to the present context in which object has too be referred to..!!

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