Whenever I need to open the logisim-evolution.jar file, I need to type the command:
java -jar logisim-evolution.jar
I would like to add an entry for that program in /bin to be able to open it through the dmenu. How can I do that?
You're better off making a .sh launcher that runs java -jar logisim-evolution.jar and put it in /bin
#Federico klez Culloca
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So, I am trying to run a program from jar files. It uses javaswing and has a gui.
The program runs fine in netbeans and in eclipse.
When I try to run it from the exported jar file it says this:
Unable To Install Java
There are errors in the following switches:
"C:\Users\CNC Department\Desktop\ValveConversion.jar";.
Check that the commands are valid and try again.[java installation not complete
Now, I also tried doing it from the command prompt. Here is what came up:
[cmd prompt attempt][1] [1]: https://i.stack.imgur.com/7reZ3.png
So, I reinstalled the java JDK, java SDK, netbeans and eclipse. The issue is still occurring in both command prompt and from running the jar file directly.
What am I doing incorrectly here? What do you recommend that I do to get this to run from a .jar file?
You need to set the java path
Open a cmd with elevated privileges and run this command to set the JAVA_HOME environment variable using setx command:
setx JAVA_HOME -m "C:\Program Files\Java\jdk-11.0.2"
Then restart the cmd and run java -version to check if it's all ok.
For reference setx command documentation
Or simply use the following snippet if you prefer to use java without setting the PATH variable:
"C:\Program Files\Java\jdk-11.0.2\bin\java" -jar "C:\Users\CNC Department\Desktop\ValveConversion.jar"
I have a bat file I run through command prompt to deploy a java app locally for local testing on my machine:
start java -server -AnotherParameter -AnotherParameter -jar path\to\jar\appName-version.jar
exit
To run this bat file, I use the following command:
start batFileName.bat
However, the next time the version changes on this jar, the bat file will not work, because the version is out of sync. This results in myself having to change my bat file each time the version is updated.
Is there a way to pass in a the version when I run the start command through command prompt to use as the jar name? This way when I run my bat file, I can just pass in the name of the jar at that time to run the java application? If so how would I pass that version into the bat file and how would I use that parameter?
In your script, replace the version part of the jar file name with an argument replacement parameter:
start java -server -AnotherParameter -AnotherParameter -jar path\to\jar\appName-%1.jar
Do not start the program using java -jar . Change the start up script
include the folder where you jar file is present into class path with wild card, like:
java -cp path\to\jar*
call the main class in your jar file. I suppose the main class does not change so often as versions of the jar file?
The whole command line will look like this:
java -cp path\to\jar* com.something.foo.bar.Main
JVM will load your jar whatever its name is, and will find the main class and will start it if it has "main" method.
I have java installed but when I try to open it in terminal it doesn't work
I type
java -jar Minecraft.jar
the output I get is
unable to get access to jar file Minecraft.jar
How I could fix this so I can next time just click the app. My operating system is Linux
Minecraft.jar file must be in your current working directory, which seems not being the case. So you either change your working directory to where Minecraft.jar resides or give full path to it
java --jar /your/valid/full/path/to/Minecraft.jar
give the full path to jar or go to directory and run command java -jar Minecraft.jar.
I have to get some kinks out of a shell script for work, and one of the line looks like this:
-cp: this is the classpath
This is the set of classes that are used when running a specific class.
In your example; OrganT.Tune.Mix OrganT must be a class in the classpath (in this case, inside the OrganT.jar
Read the documentation, can be found here
Just a hint - under linux and mac you can use the
man <command goes here>
comman in the terminal/shell to display all parameters and usage information available for the specific command.
-cp stands for classpath. The CLASSPATH variable is one way to tell applications, including the JDK tools, where to look for user classes.
java -classpath .;YourJarFile.jar
I think you want to run a script for including the class path and execute the jar.
To do this in any text editor type java -jar YourJarFile.jar and save it, with extention (anyName.sh) assuming you have got linux flavour. Make it executable using the command chmod 775 anyName.sh
For windows type java -jar YourJarFile.jar, and save it with extention (anyName.bat)
I have a homework assignment in Java that is tested using the commands:
make
./<program_name> <arguments>
my make file compiles my java program successfully, but how can the program be run without using the command:
java <program_name>
I have investigated how to convert a .jar into an .exe but I am convinced that is not the answer I am looking for.
I believe the test is run on a Linux machine. Is there something I can include in the make file to cause the command
./<program_name>
to run a compiled java class?
Without converting the java program in a native executable file, that will be different for linux, for windows and any other platform (so you will loose Java portability), the only thing you can do is to create a launch script.
On *nix system you can create a bash script and on windows a batch script. Then in this script you have to call java <program_name>.
With the script you are now able to launch your application with a single command.
For example on unix you can create myapp.sh:
#!/bin/bash
java -classpath bin com.test.YourApp $*
and make this script runnable with command
chmod a+x myapp.sh
in this example when you write myapp.sh command you launch your Java class com.test.YourApp using the folder bin as classpath.