The visibility of variable which write after volatile variable write

The visibility of variable which write after volatile variable write - java

public class Test {
private static volatile boolean flag = false;
private static int i = 1;
public static void main(String[] args) {
new Thread(() -> {
try {
TimeUnit.SECONDS.sleep(1);
} catch (InterruptedException e) {
e.printStackTrace();
}
flag = true;
i += 1;
}).start();
new Thread(() -> {
while (!flag) {
if (i != 1) {
System.out.println(i);
}
}
System.out.println(flag);
System.out.println(i);
}).start();
}
}
Variable i is written after volatile variable flag, but the code output true 2. It seems the modify of i by the first thread is visible to the second thread.
According to my understanding, variable I should be written before flag, then the second thread can be aware of the change.

Accordingly to the language standard (§17.4):
A field may be declared volatile, in which case the Java Memory Model
ensures that all threads see a consistent value for the variable
So informally, all threads will have a view of the must update value of that variable.
However, the volatile clause not only implies ensure visibility guarantee of the target variable but also full volatile visibility guarantee, namely:
Actually, the visibility guarantee of Java volatile goes beyond the
volatile variable itself. The visibility guarantee is as follows:
If Thread A writes to a volatile variable and Thread B subsequently
reads the same volatile variable, then all variables visible to Thread
A before writing the volatile variable, will also be visible to Thread
B after it has read the volatile variable.
If Thread A reads a
volatile variable, then all all variables visible to Thread A when
reading the volatile variable will also be re-read from main memory.
According to my understanding, variable I should be written before
flag, then the second thread can be aware of the change.
"All variables visible to the Thread A before writing the volatile variable", it does not refer to operation over those variables.

Your code suffers from a data-race.
A data race is when there are 2 memory actions to the same address which are not ordered by a happens before relation, and at least one of these actions is a write.
In this case the write to i is the problem.
The write to i, is after the write to the volatile variable flag and hence there is no happens before relation between writing the i and reading i.
If you would write i before you write to the flag, there would be the following happens before relation:
write of i happens before write of flag due to the program order rule
write of flag happens before read of flag due to volatile variable rule (on the hardware level this is a task for cache coherence).
the read of flag happens before the read of i due to program order rule.
Because the happens before relation is transitive, the write of i happens before the read if i.
So like you already indicated, if you move the write of i in front of the write of the flag; the data race is gone.

The memory model defines guarantees, however anything may happen on top of them.
On x86, all writes have release semantics, and as soon as you write to a variable, its updated value will be visible as soon as possible from other threads.
So the fact that actions before writing to a volatile variable happen-before actions after reading to it, does not prevent actions after writing to it to become visible after reading it.

Related

Doesn't "volatile" ensure that other threads see a consistent value for the variable? [duplicate]

How do atomic / volatile / synchronized work internally?
What is the difference between the following code blocks?
Code 1
private int counter;
public int getNextUniqueIndex() {
return counter++;
}
Code 2
private AtomicInteger counter;
public int getNextUniqueIndex() {
return counter.getAndIncrement();
}
Code 3
private volatile int counter;
public int getNextUniqueIndex() {
return counter++;
}
Does volatile work in the following way? Is
volatile int i = 0;
void incIBy5() {
i += 5;
}
equivalent to
Integer i = 5;
void incIBy5() {
int temp;
synchronized(i) { temp = i }
synchronized(i) { i = temp + 5 }
}
I think that two threads cannot enter a synchronized block at the same time... am I right? If this is true then how does atomic.incrementAndGet() work without synchronized? And is it thread-safe?
And what is the difference between internal reading and writing to volatile variables / atomic variables? I read in some article that the thread has a local copy of the variables - what is that?

You are specifically asking about how they internally work, so here you are:
No synchronization
private int counter;
public int getNextUniqueIndex() {
return counter++;
}
It basically reads value from memory, increments it and puts back to memory. This works in single thread but nowadays, in the era of multi-core, multi-CPU, multi-level caches it won't work correctly. First of all it introduces race condition (several threads can read the value at the same time), but also visibility problems. The value might only be stored in "local" CPU memory (some cache) and not be visible for other CPUs/cores (and thus - threads). This is why many refer to local copy of a variable in a thread. It is very unsafe. Consider this popular but broken thread-stopping code:
private boolean stopped;
public void run() {
while(!stopped) {
//do some work
}
}
public void pleaseStop() {
stopped = true;
}
Add volatile to stopped variable and it works fine - if any other thread modifies stopped variable via pleaseStop() method, you are guaranteed to see that change immediately in working thread's while(!stopped) loop. BTW this is not a good way to interrupt a thread either, see: How to stop a thread that is running forever without any use and Stopping a specific java thread.
AtomicInteger
private AtomicInteger counter = new AtomicInteger();
public int getNextUniqueIndex() {
return counter.getAndIncrement();
}
The AtomicInteger class uses CAS (compare-and-swap) low-level CPU operations (no synchronization needed!) They allow you to modify a particular variable only if the present value is equal to something else (and is returned successfully). So when you execute getAndIncrement() it actually runs in a loop (simplified real implementation):
int current;
do {
current = get();
} while(!compareAndSet(current, current + 1));
So basically: read; try to store incremented value; if not successful (the value is no longer equal to current), read and try again. The compareAndSet() is implemented in native code (assembly).
volatile without synchronization
private volatile int counter;
public int getNextUniqueIndex() {
return counter++;
}
This code is not correct. It fixes the visibility issue (volatile makes sure other threads can see change made to counter) but still has a race condition. This has been explained multiple times: pre/post-incrementation is not atomic.
The only side effect of volatile is "flushing" caches so that all other parties see the freshest version of the data. This is too strict in most situations; that is why volatile is not default.
volatile without synchronization (2)
volatile int i = 0;
void incIBy5() {
i += 5;
}
The same problem as above, but even worse because i is not private. The race condition is still present. Why is it a problem? If, say, two threads run this code simultaneously, the output might be + 5 or + 10. However, you are guaranteed to see the change.
Multiple independent synchronized
void incIBy5() {
int temp;
synchronized(i) { temp = i }
synchronized(i) { i = temp + 5 }
}
Surprise, this code is incorrect as well. In fact, it is completely wrong. First of all you are synchronizing on i, which is about to be changed (moreover, i is a primitive, so I guess you are synchronizing on a temporary Integer created via autoboxing...) Completely flawed. You could also write:
synchronized(new Object()) {
//thread-safe, SRSLy?
}
No two threads can enter the same synchronized block with the same lock. In this case (and similarly in your code) the lock object changes upon every execution, so synchronized effectively has no effect.
Even if you have used a final variable (or this) for synchronization, the code is still incorrect. Two threads can first read i to temp synchronously (having the same value locally in temp), then the first assigns a new value to i (say, from 1 to 6) and the other one does the same thing (from 1 to 6).
The synchronization must span from reading to assigning a value. Your first synchronization has no effect (reading an int is atomic) and the second as well. In my opinion, these are the correct forms:
void synchronized incIBy5() {
i += 5
}
void incIBy5() {
synchronized(this) {
i += 5
}
}
void incIBy5() {
synchronized(this) {
int temp = i;
i = temp + 5;
}
}

Declaring a variable as volatile means that modifying its value immediately affects the actual memory storage for the variable. The compiler cannot optimize away any references made to the variable. This guarantees that when one thread modifies the variable, all other threads see the new value immediately. (This is not guaranteed for non-volatile variables.)
Declaring an atomic variable guarantees that operations made on the variable occur in an atomic fashion, i.e., that all of the substeps of the operation are completed within the thread they are executed and are not interrupted by other threads. For example, an increment-and-test operation requires the variable to be incremented and then compared to another value; an atomic operation guarantees that both of these steps will be completed as if they were a single indivisible/uninterruptible operation.
Synchronizing all accesses to a variable allows only a single thread at a time to access the variable, and forces all other threads to wait for that accessing thread to release its access to the variable.
Synchronized access is similar to atomic access, but the atomic operations are generally implemented at a lower level of programming. Also, it is entirely possible to synchronize only some accesses to a variable and allow other accesses to be unsynchronized (e.g., synchronize all writes to a variable but none of the reads from it).
Atomicity, synchronization, and volatility are independent attributes, but are typically used in combination to enforce proper thread cooperation for accessing variables.
Addendum (April 2016)
Synchronized access to a variable is usually implemented using a monitor or semaphore. These are low-level mutex (mutual exclusion) mechanisms that allow a thread to acquire control of a variable or block of code exclusively, forcing all other threads to wait if they also attempt to acquire the same mutex. Once the owning thread releases the mutex, another thread can acquire the mutex in turn.
Addendum (July 2016)
Synchronization occurs on an object. This means that calling a synchronized method of a class will lock the this object of the call. Static synchronized methods will lock the Class object itself.
Likewise, entering a synchronized block requires locking the this object of the method.
This means that a synchronized method (or block) can be executing in multiple threads at the same time if they are locking on different objects, but only one thread can execute a synchronized method (or block) at a time for any given single object.

volatile:
volatile is a keyword. volatile forces all threads to get latest value of the variable from main memory instead of cache. No locking is required to access volatile variables. All threads can access volatile variable value at same time.
Using volatile variables reduces the risk of memory consistency errors, because any write to a volatile variable establishes a happens-before relationship with subsequent reads of that same variable.
This means that changes to a volatile variable are always visible to other threads. What's more, it also means that when a thread reads a volatile variable, it sees not just the latest change to the volatile, but also the side effects of the code that led up the change.
When to use: One thread modifies the data and other threads have to read latest value of data. Other threads will take some action but they won't update data.
AtomicXXX:
AtomicXXX classes support lock-free thread-safe programming on single variables. These AtomicXXX classes (like AtomicInteger) resolves memory inconsistency errors / side effects of modification of volatile variables, which have been accessed in multiple threads.
When to use: Multiple threads can read and modify data.
synchronized:
synchronized is keyword used to guard a method or code block. By making method as synchronized has two effects:
First, it is not possible for two invocations of synchronized methods on the same object to interleave. When one thread is executing a synchronized method for an object, all other threads that invoke synchronized methods for the same object block (suspend execution) until the first thread is done with the object.
Second, when a synchronized method exits, it automatically establishes a happens-before relationship with any subsequent invocation of a synchronized method for the same object. This guarantees that changes to the state of the object are visible to all threads.
When to use: Multiple threads can read and modify data. Your business logic not only update the data but also executes atomic operations
AtomicXXX is equivalent of volatile + synchronized even though the implementation is different. AmtomicXXX extends volatile variables + compareAndSet methods but does not use synchronization.
Related SE questions:
Difference between volatile and synchronized in Java
Volatile boolean vs AtomicBoolean
Good articles to read: ( Above content is taken from these documentation pages)
https://docs.oracle.com/javase/tutorial/essential/concurrency/sync.html
https://docs.oracle.com/javase/tutorial/essential/concurrency/atomic.html
https://docs.oracle.com/javase/8/docs/api/java/util/concurrent/atomic/package-summary.html

I know that two threads can not enter in Synchronize block at the same time
Two thread cannot enter a synchronized block on the same object twice. This means that two threads can enter the same block on different objects. This confusion can lead to code like this.
private Integer i = 0;
synchronized(i) {
i++;
}
This will not behave as expected as it could be locking on a different object each time.
if this is true than How this atomic.incrementAndGet() works without Synchronize ?? and is thread safe ??
yes. It doesn't use locking to achieve thread safety.
If you want to know how they work in more detail, you can read the code for them.
And what is difference between internal reading and writing to Volatile Variable / Atomic Variable ??
Atomic class uses volatile fields. There is no difference in the field. The difference is the operations performed. The Atomic classes use CompareAndSwap or CAS operations.
i read in some article that thread has local copy of variables what is that ??
I can only assume that it referring to the fact that each CPU has its own cached view of memory which can be different from every other CPU. To ensure that your CPU has a consistent view of data, you need to use thread safety techniques.
This is only an issue when memory is shared at least one thread updates it.

Synchronized Vs Atomic Vs Volatile:
Volatile and Atomic is apply only on variable , While Synchronized apply on method.
Volatile ensure about visibility not atomicity/consistency of object , While other both ensure about visibility and atomicity.
Volatile variable store in RAM and it’s faster in access but we can’t achive Thread safety or synchronization whitout synchronized keyword.
Synchronized implemented as synchronized block or synchronized method while both not. We can thread safe multiple line of code with help of synchronized keyword while with both we can’t achieve the same.
Synchronized can lock the same class object or different class object while both can’t.
Please correct me if anything i missed.

A volatile + synchronization is a fool proof solution for an operation(statement) to be fully atomic which includes multiple instructions to the CPU.
Say for eg:volatile int i = 2; i++, which is nothing but i = i + 1; which makes i as the value 3 in the memory after the execution of this statement.
This includes reading the existing value from memory for i(which is 2), load into the CPU accumulator register and do with the calculation by increment the existing value with one(2 + 1 = 3 in accumulator) and then write back that incremented value back to the memory. These operations are not atomic enough though the value is of i is volatile. i being volatile guarantees only that a SINGLE read/write from memory is atomic and not with MULTIPLE. Hence, we need to have synchronized also around i++ to keep it to be fool proof atomic statement. Remember the fact that a statement includes multiple statements.
Hope the explanation is clear enough.

The Java volatile modifier is an example of a special mechanism to guarantee that communication happens between threads. When one thread writes to a volatile variable, and another thread sees that write, the first thread is telling the second about all of the contents of memory up until it performed the write to that volatile variable.
Atomic operations are performed in a single unit of task without interference from other operations. Atomic operations are necessity in multi-threaded environment to avoid data inconsistency.

When Java refresh Thread Cache to actual copy

I read few articles on volatile Thread cache and found either it is too much brief without examples, so it is very difficult for beginner to understand.
Please help me in understanding below program,
public class Test {
int a = 0;
public static void main(String[] args) {
final Test t = new Test();
new Thread(new Runnable(){
public void run() {
try {
Thread.sleep(3000);
} catch (Exception e) {}
t.a = 10;
System.out.println("now t.a == 10");
}
}).start();
new Thread(new Runnable(){
public void run() {
while(t.a == 0) {}
System.out.println("Loop done: " + t.a);
}
}).start();
}
}
When I make a variable volatile and run my program then it stops after some time but when I remove volatile to a variable, then it goes on and my program is not stopping.
What I knew about volatile is "when variable is declared as volatile then thread will directly read/write to variable memory instead of read/write from local thread cache.
if not declared volatile then one can see delay in updation of actual value."
Also, as per my understanding of refreshing the cached copy, I thought program will stop in some time but then why in above program it is continuing to run and not updating.
So when is Thread referring to its local cache starts referring to main copy or refresh its value with main copy value?
Please correct me if I am wrong in my understanding....
Please explain me with some small code snippet or link.

when variable is declared as volatile then thread will directly read/write to variable memory instead of read/write from local thread cache. if not declared volatile then one can see delay in updation of actual value.
To begin with, the above statements are false. There are many more phenomena going on at the level of machine code which have nothing to do with any "thread-local variable caches". In fact, this concept is hardly applicable at all.
To give you something specific to focus on, the JIT compiler will be allowed to transform your code
while(t.a == 0) {}
into
if (t.a == 0) while (true) {}
whenever t.a is not volatile. The Java Memory Model allows any variable accessed in a data race to be treated as if the accessing thread was the only thread in existence. Since obviously this thread is not modifying t.a, its value can be considered a loop invariant and the check doesn't have to be repeated... ever.

This may or may not be necessarily what is happening, but volatile also prevents certain reordering by the compiler.
For instance your code here
while(t.a == 0) {}
System.out.println("Loop done: " + t.a);
Can be reordered to
if(t.a == 0){
while(true){
}
}
System.out.println("Loop done: " + t.a);
This is called hoisting and is perfectly legal. Declaring it volatile will prevent this sort of ordering.

If a variable is not declared volatile, whether it will be read from the cache or from the main copy is not predictable.
The cache has a limited size and the variable can get evicted from it for various reasons, like other variables occupying the cache. When this happens the main copy is read.

Marking a variable volatile is making sure changes to it are visible across threads.
In your code first thread changes the value of a and other thread sees this change and breaks out of loop.
Important point to note about volatile variable is value can change between last access and current access, even if compiler knows that its values is not being changed.
(as #Marko Topolnik said)
This stops the JIT compiler from doing optimizations like
while(t.a == 0) {}
into
if (t.a == 0) while (true) {}
knowing that a cant not change.
this talk offers very good explanation of these things. Jeremy Menson's talk on Java Memory Model#Google

Is a volatile boolean switch written to by only one thread thread-safe?

I have the following code:
public class Simulation
{
public static volatile boolean IS_EVEN_TICK;
}
and the following in another (runnable) class:
public void run()
{
while (true)
{
// flip the "even/uneven tick" switch
Simulation.IS_EVEN_TICK = !Simulation.IS_EVEN_TICK;
}
}
As far as I understand it this is generally not thread-safe, because the write to Simulation.IS_EVEN_TICK depends on the current value of that variable. However this thread is the only thread that ever writes to the variable, all other threads will only read the variable (if they access it at all).
Is the variable being volatile enough to make sure that all threads read the right value from it or do I need to synchronize the access to the variable nonetheless?

However this thread is the only thread that ever writes to the variable... Is the variable being volatile enough to make sure that all threads read the right value from it.
If there is only one writer then there is no race condition. You do not need to synchronize across the variable.
You might consider using an AtomicBoolean but it does not support a toggle() method so if you had multiple writers toggling the value, you would have to do something like the following:
private final AtomicBoolean isEvenTick = new AtomicBoolean();
...
boolean currentValue;
do {
currentValue = isEvenTick.get();
} while (!isEvenTick.compareAndSet(currentValue, !currentValue);

try to read specification and understand JMM, if your variable volatile it means that variable will be created directly in heap and no one processor does not copy that value to own cache.
Volatile fields are special fields which are used for communicating state between threads. Each read of a volatile will see the last write to that volatile by any thread; in effect, they are designated by the programmer as fields for which it is never acceptable to see a "stale" value as a result of caching or reordering

When to use volatile and synchronized

I know there are many questions about this, but I still don't quite understand. I know what both of these keywords do, but I can't determine which to use in certain scenarios. Here are a couple of examples that I'm trying to determine which is the best to use.
Example 1:
import java.net.ServerSocket;
public class Something extends Thread {
private ServerSocket serverSocket;
public void run() {
while (true) {
if (serverSocket.isClosed()) {
...
} else { //Should this block use synchronized (serverSocket)?
//Do stuff with serverSocket
}
}
}
public ServerSocket getServerSocket() {
return serverSocket;
}
}
public class SomethingElse {
Something something = new Something();
public void doSomething() {
something.getServerSocket().close();
}
}
Example 2:
public class Server {
private int port;//Should it be volatile or the threads accessing it use synchronized (server)?
//getPort() and setPort(int) are accessed from multiple threads
public int getPort() {
return port;
}
public void setPort(int port) {
this.port = port;
}
}
Any help is greatly appreciated.

A simple answer is as follows:
synchronized can always be used to give you a thread-safe / correct solution,
volatile will probably be faster, but can only be used to give you a thread-safe / correct in limited situations.
If in doubt, use synchronized. Correctness is more important than performance.
Characterizing the situations under which volatile can be used safely involves determining whether each update operation can be performed as a single atomic update to a single volatile variable. If the operation involves accessing other (non-final) state or updating more than one shared variable, it cannot be done safely with just volatile. You also need to remember that:
updates to non-volatile long or a double may not be atomic, and
Java operators like ++ and += are not atomic.
Terminology: an operation is "atomic" if the operation either happens entirely, or it does not happen at all. The term "indivisible" is a synonym.
When we talk about atomicity, we usually mean atomicity from the perspective of an outside observer; e.g. a different thread to the one that is performing the operation. For instance, ++ is not atomic from the perspective of another thread, because that thread may be able to observe state of the field being incremented in the middle of the operation. Indeed, if the field is a long or a double, it may even be possible to observe a state that is neither the initial state or the final state!

The synchronized keyword
synchronized indicates that a variable will be shared among several threads. It's used to ensure consistency by "locking" access to the variable, so that one thread can't modify it while another is using it.
Classic Example: updating a global variable that indicates the current time
The incrementSeconds() function must be able to complete uninterrupted because, as it runs, it creates temporary inconsistencies in the value of the global variable time. Without synchronization, another function might see a time of "12:60:00" or, at the comment marked with >>>, it would see "11:00:00" when the time is really "12:00:00" because the hours haven't incremented yet.
void incrementSeconds() {
if (++time.seconds > 59) { // time might be 1:00:60
time.seconds = 0; // time is invalid here: minutes are wrong
if (++time.minutes > 59) { // time might be 1:60:00
time.minutes = 0; // >>> time is invalid here: hours are wrong
if (++time.hours > 23) { // time might be 24:00:00
time.hours = 0;
}
}
}
The volatile keyword
volatile simply tells the compiler not to make assumptions about the constant-ness of a variable, because it may change when the compiler wouldn't normally expect it. For example, the software in a digital thermostat might have a variable that indicates the temperature, and whose value is updated directly by the hardware. It may change in places that a normal variable wouldn't.
If degreesCelsius is not declared to be volatile, the compiler is free to optimize this:
void controlHeater() {
while ((degreesCelsius * 9.0/5.0 + 32) < COMFY_TEMP_IN_FAHRENHEIT) {
setHeater(ON);
sleep(10);
}
}
into this:
void controlHeater() {
float tempInFahrenheit = degreesCelsius * 9.0/5.0 + 32;
while (tempInFahrenheit < COMFY_TEMP_IN_FAHRENHEIT) {
setHeater(ON);
sleep(10);
}
}
By declaring degreesCelsius to be volatile, you're telling the compiler that it has to check its value each time it runs through the loop.
Summary
In short, synchronized lets you control access to a variable, so you can guarantee that updates are atomic (that is, a set of changes will be applied as a unit; no other thread can access the variable when it's half-updated). You can use it to ensure consistency of your data. On the other hand, volatile is an admission that the contents of a variable are beyond your control, so the code must assume it can change at any time.

There is insufficient information in your post to determine what is going on, which is why all the advice you are getting is general information about volatile and synchronized.
So, here's my general advice:
During the cycle of writing-compiling-running a program, there are two optimization points:
at compile time, when the compiler might try to reorder instructions or optimize data caching.
at runtime, when the CPU has its own optimizations, like caching and out-of-order execution.
All this means that instructions will most likely not execute in the order that you wrote them, regardless if this order must be maintained in order to ensure program correctness in a multithreaded environment. A classic example you will often find in the literature is this:
class ThreadTask implements Runnable {
private boolean stop = false;
private boolean work;
public void run() {
while(!stop) {
work = !work; // simulate some work
}
}
public void stopWork() {
stop = true; // signal thread to stop
}
public static void main(String[] args) {
ThreadTask task = new ThreadTask();
Thread t = new Thread(task);
t.start();
Thread.sleep(1000);
task.stopWork();
t.join();
}
}
Depending on compiler optimizations and CPU architecture, the above code may never terminate on a multi-processor system. This is because the value of stop will be cached in a register of the CPU running thread t, such that the thread will never again read the value from main memory, even thought the main thread has updated it in the meantime.
To combat this kind of situation, memory fences were introduced. These are special instructions that do not allow regular instructions before the fence to be reordered with instructions after the fence. One such mechanism is the volatile keyword. Variables marked volatile are not optimized by the compiler/CPU and will always be written/read directly to/from main memory. In short, volatile ensures visibility of a variable's value across CPU cores.
Visibility is important, but should not be confused with atomicity. Two threads incrementing the same shared variable may produce inconsistent results even though the variable is declared volatile. This is due to the fact that on some systems the increment is actually translated into a sequence of assembler instructions that can be interrupted at any point. For such cases, critical sections such as the synchronized keyword need to be used. This means that only a single thread can access the code enclosed in the synchronized block. Other common uses of critical sections are atomic updates to a shared collection, when usually iterating over a collection while another thread is adding/removing items will cause an exception to be thrown.
Finally two interesting points:
synchronized and a few other constructs such as Thread.join will introduce memory fences implicitly. Hence, incrementing a variable inside a synchronized block does not require the variable to also be volatile, assuming that's the only place it's being read/written.
For simple updates such as value swap, increment, decrement, you can use non-blocking atomic methods like the ones found in AtomicInteger, AtomicLong, etc. These are much faster than synchronized because they do not trigger a context switch in case the lock is already taken by another thread. They also introduce memory fences when used.

Note: In your first example, the field serverSocket is actually never initialized in the code you show.
Regarding synchronization, it depends on whether or not the ServerSocket class is thread safe. (I assume it is, but I have never used it.) If it is, you don't need to synchronize around it.
In the second example, int variables can be atomically updated so volatile may suffice.

volatile solves “visibility” problem across CPU cores. Therefore, value from local registers is flushed and synced with RAM. However, if we need consistent value and atomic op, we need a mechanism to defend the critical data. That can be achieved by either synchronized block or explicit lock.

What is the difference between atomic / volatile / synchronized?

How do atomic / volatile / synchronized work internally?
What is the difference between the following code blocks?
Code 1
private int counter;
public int getNextUniqueIndex() {
return counter++;
}
Code 2
private AtomicInteger counter;
public int getNextUniqueIndex() {
return counter.getAndIncrement();
}
Code 3
private volatile int counter;
public int getNextUniqueIndex() {
return counter++;
}
Does volatile work in the following way? Is
volatile int i = 0;
void incIBy5() {
i += 5;
}
equivalent to
Integer i = 5;
void incIBy5() {
int temp;
synchronized(i) { temp = i }
synchronized(i) { i = temp + 5 }
}
I think that two threads cannot enter a synchronized block at the same time... am I right? If this is true then how does atomic.incrementAndGet() work without synchronized? And is it thread-safe?
And what is the difference between internal reading and writing to volatile variables / atomic variables? I read in some article that the thread has a local copy of the variables - what is that?

You are specifically asking about how they internally work, so here you are:
No synchronization
private int counter;
public int getNextUniqueIndex() {
return counter++;
}
It basically reads value from memory, increments it and puts back to memory. This works in single thread but nowadays, in the era of multi-core, multi-CPU, multi-level caches it won't work correctly. First of all it introduces race condition (several threads can read the value at the same time), but also visibility problems. The value might only be stored in "local" CPU memory (some cache) and not be visible for other CPUs/cores (and thus - threads). This is why many refer to local copy of a variable in a thread. It is very unsafe. Consider this popular but broken thread-stopping code:
private boolean stopped;
public void run() {
while(!stopped) {
//do some work
}
}
public void pleaseStop() {
stopped = true;
}
Add volatile to stopped variable and it works fine - if any other thread modifies stopped variable via pleaseStop() method, you are guaranteed to see that change immediately in working thread's while(!stopped) loop. BTW this is not a good way to interrupt a thread either, see: How to stop a thread that is running forever without any use and Stopping a specific java thread.
AtomicInteger
private AtomicInteger counter = new AtomicInteger();
public int getNextUniqueIndex() {
return counter.getAndIncrement();
}
The AtomicInteger class uses CAS (compare-and-swap) low-level CPU operations (no synchronization needed!) They allow you to modify a particular variable only if the present value is equal to something else (and is returned successfully). So when you execute getAndIncrement() it actually runs in a loop (simplified real implementation):
int current;
do {
current = get();
} while(!compareAndSet(current, current + 1));
So basically: read; try to store incremented value; if not successful (the value is no longer equal to current), read and try again. The compareAndSet() is implemented in native code (assembly).
volatile without synchronization
private volatile int counter;
public int getNextUniqueIndex() {
return counter++;
}
This code is not correct. It fixes the visibility issue (volatile makes sure other threads can see change made to counter) but still has a race condition. This has been explained multiple times: pre/post-incrementation is not atomic.
The only side effect of volatile is "flushing" caches so that all other parties see the freshest version of the data. This is too strict in most situations; that is why volatile is not default.
volatile without synchronization (2)
volatile int i = 0;
void incIBy5() {
i += 5;
}
The same problem as above, but even worse because i is not private. The race condition is still present. Why is it a problem? If, say, two threads run this code simultaneously, the output might be + 5 or + 10. However, you are guaranteed to see the change.
Multiple independent synchronized
void incIBy5() {
int temp;
synchronized(i) { temp = i }
synchronized(i) { i = temp + 5 }
}
Surprise, this code is incorrect as well. In fact, it is completely wrong. First of all you are synchronizing on i, which is about to be changed (moreover, i is a primitive, so I guess you are synchronizing on a temporary Integer created via autoboxing...) Completely flawed. You could also write:
synchronized(new Object()) {
//thread-safe, SRSLy?
}
No two threads can enter the same synchronized block with the same lock. In this case (and similarly in your code) the lock object changes upon every execution, so synchronized effectively has no effect.
Even if you have used a final variable (or this) for synchronization, the code is still incorrect. Two threads can first read i to temp synchronously (having the same value locally in temp), then the first assigns a new value to i (say, from 1 to 6) and the other one does the same thing (from 1 to 6).
The synchronization must span from reading to assigning a value. Your first synchronization has no effect (reading an int is atomic) and the second as well. In my opinion, these are the correct forms:
void synchronized incIBy5() {
i += 5
}
void incIBy5() {
synchronized(this) {
i += 5
}
}
void incIBy5() {
synchronized(this) {
int temp = i;
i = temp + 5;
}
}

I know that two threads can not enter in Synchronize block at the same time
Two thread cannot enter a synchronized block on the same object twice. This means that two threads can enter the same block on different objects. This confusion can lead to code like this.
private Integer i = 0;
synchronized(i) {
i++;
}
This will not behave as expected as it could be locking on a different object each time.
if this is true than How this atomic.incrementAndGet() works without Synchronize ?? and is thread safe ??
yes. It doesn't use locking to achieve thread safety.
If you want to know how they work in more detail, you can read the code for them.
And what is difference between internal reading and writing to Volatile Variable / Atomic Variable ??
Atomic class uses volatile fields. There is no difference in the field. The difference is the operations performed. The Atomic classes use CompareAndSwap or CAS operations.
i read in some article that thread has local copy of variables what is that ??
I can only assume that it referring to the fact that each CPU has its own cached view of memory which can be different from every other CPU. To ensure that your CPU has a consistent view of data, you need to use thread safety techniques.
This is only an issue when memory is shared at least one thread updates it.

Synchronized Vs Atomic Vs Volatile:
Volatile and Atomic is apply only on variable , While Synchronized apply on method.
Volatile ensure about visibility not atomicity/consistency of object , While other both ensure about visibility and atomicity.
Volatile variable store in RAM and it’s faster in access but we can’t achive Thread safety or synchronization whitout synchronized keyword.
Synchronized implemented as synchronized block or synchronized method while both not. We can thread safe multiple line of code with help of synchronized keyword while with both we can’t achieve the same.
Synchronized can lock the same class object or different class object while both can’t.
Please correct me if anything i missed.

A volatile + synchronization is a fool proof solution for an operation(statement) to be fully atomic which includes multiple instructions to the CPU.
Say for eg:volatile int i = 2; i++, which is nothing but i = i + 1; which makes i as the value 3 in the memory after the execution of this statement.
This includes reading the existing value from memory for i(which is 2), load into the CPU accumulator register and do with the calculation by increment the existing value with one(2 + 1 = 3 in accumulator) and then write back that incremented value back to the memory. These operations are not atomic enough though the value is of i is volatile. i being volatile guarantees only that a SINGLE read/write from memory is atomic and not with MULTIPLE. Hence, we need to have synchronized also around i++ to keep it to be fool proof atomic statement. Remember the fact that a statement includes multiple statements.
Hope the explanation is clear enough.

The Java volatile modifier is an example of a special mechanism to guarantee that communication happens between threads. When one thread writes to a volatile variable, and another thread sees that write, the first thread is telling the second about all of the contents of memory up until it performed the write to that volatile variable.
Atomic operations are performed in a single unit of task without interference from other operations. Atomic operations are necessity in multi-threaded environment to avoid data inconsistency.

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Java is a programming language and computing platform first released by Sun Microsystems in 1995.