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Creating query exception in JPA while creting custom query method

JPA repository throwing Error for custom query method:
org.h2.jdbc.JdbcSQLException: Table "NBMRBANKDTLSENTITY" not found; SQL statement:
select NBMRBankDtlsEntity from NBMRBankDtlsEntity where NBMRBankDtlsEntity.ipphId = ? [42102-191]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:345)
Class :
#Repository
public interface NBMRBankDtlsRepository extends JpaRepository<NBMRBankDtlsEntity, Long> {
#Query(value ="select n from NBMRBankDtlsEntity n where n.ipphId = :ipphId",nativeQuery = true)
Optional<NBMRBankDtlsEntity> findByIPPHId(#Param("ipphId") Long ipphId);
}

The error message tells you: Table "NBMRBANKDTLSENTITY" not found. Therefore it probably doesn't exist. To fix this you'll have to create the table, manually through a script or through hibernates schema creation feature.

I am already creating a table also inserting the record, After that only i am calling this custom query method.
I have found the issue as i am using nativeQuery = true so it is expecting normal sql query to query DB directly not the java query which is creating issue. Now after changing below it works fine ,
#Query(value = "SELECT * from NB_MR_BANK_DTLS WHERE IPPH_ID = :ipphId",nativeQuery = true)
For java query we can use directly as it internally converts to SQL while querying the DB,
#Query(value = "select p from NBMRBankDtlsEntity p WHERE p.ipphId = :ipphId")

QueryDSL - order by count as alias

I'm using queryDSL to get users with some additional data from base:
public List<Tuple> getUsersWithData (final SomeParam someParam) {
QUser user = QUser.user;
QRecord record = QRecord.record;
JPQLQuery = query = new JPAQuery(getEntityManager());
NumberPath<Long> cAlias = Expressions.numberPath(Long.class, "cAlias");
return query.from(user)
.leftJoin(record).on(record.someParam.eq(someParam))
.where(user.active.eq(true))
.groupBy(user)
.orderBy(cAlias.asc())
.list(user, record.countDistinct().as(cAlias));
}
Despite it's working as desired, it generates two COUNT() in SQL:
SELECT
t0.ID
t0.NAME
to.ACTIVE
COUNT(DISTINCT (t1.ID))
FROM USERS t0 LEFT OUTER JOIN t1 ON (t1.SOME_PARAM_ID = ?)
WHERE t0.ACTIVE = true
GROUP BY t0.ID, to.NAME, t0.ACTIVE
ORDER BY COUNT(DISTINCT (t1.ID))
I want to know if it's possible to get something like this:
SELECT
t0.ID
t0.NAME
to.ACTIVE
COUNT(DISTINCT (t1.ID)) as cAlias
FROM USERS t0 LEFT OUTER JOIN t1 ON (t1.SOME_PARAM_ID = ?)
WHERE t0.ACTIVE = true
GROUP BY t0.ID, to.NAME, t0.ACTIVE
ORDER BY cAlias
I failed to understand this from documentation, please, give me some directions if it's possible.

QVehicle qVehicle = QVehicle.vehicle;
NumberPath<Long> aliasQuantity = Expressions.numberPath(Long.class, "quantity");
final List<QuantityByTypeVO> quantityByTypeVO = new JPAQueryFactory(getEntityManager())
.select(Projections.constructor(QuantityByTypeVO.class, qVehicle.tipo, qVehicle.count().as(aliasQuantity)))
.from(qVehicle)
.groupBy(qVehicle.type)
.orderBy(aliasQuantity.desc())
.fetch();
select
vehicleges0_.type as col_0_0_, count(vehicleges0_.pk) as col_1_0_
from vehicle vehicleges0_
group by vehicleges0_.type
order by col_1_0_ desc;
I did something like that, but I did count first before ordering. Look the query and the select generated.

That's a restriction imposed by SQL rather than by queryDSL.
You may try to run your suggested query in a DB console - I think it won't execute, at least not on every DB.
But I don't think this duplicated COUNT() really creates any performance overhead.

Native query with named parameter fails with "Not all named parameters have been set"

I want to execute a simple native query, but it does not work:
#Autowired
private EntityManager em;
Query q = em.createNativeQuery("SELECT count(*) FROM mytable where username = :username");
em.setProperty("username", "test");
(int) q.getSingleResult();
Why am I getting this exception?
org.hibernate.QueryException: Not all named parameters have been set: [username]

Named parameters are not supported by JPA in native queries, only for JPQL. You must use positional parameters.
Named parameters follow the rules for identifiers defined in Section 4.4.1. The use of named parameters applies to the Java Persistence query language, and is not defined for native queries. Only positional parameter binding may be portably used for native queries.
So, use this
Query q = em.createNativeQuery("SELECT count(*) FROM mytable where username = ?1");
q.setParameter(1, "test");
While JPA specification doesn't support named parameters in native queries, some JPA implementations (like Hibernate) may support it
Native SQL queries support positional as well as named parameters
However, this couples your application to specific JPA implementation, and thus makes it unportable.

After many tries I found that you should use createNativeQuery And you can send parameters using # replacement
In my example
String UPDATE_lOGIN_TABLE_QUERY = "UPDATE OMFX.USER_LOGIN SET LOGOUT_TIME = SYSDATE WHERE LOGIN_ID = #loginId AND USER_ID = #userId";
Query query = em.createNativeQuery(logQuery);
query.setParameter("userId", logDataDto.getUserId());
query.setParameter("loginId", logDataDto.getLoginId());
query.executeUpdate();

You are calling setProperty instead of setParameter. Change your code to
Query q = em.createNativeQuery("SELECT count(*) FROM mytable where username = :username");
em.setParameter("username", "test");
(int) q.getSingleResult();
and it should work.

I use EclipseLink. This JPA allows the following way for the native queries:
Query q = em.createNativeQuery("SELECT * FROM mytable where username = ?username");
q.setParameter("username", "test");
q.getResultList();

Use set Parameter from query.
Query q = (Query) em.createNativeQuery("SELECT count(*) FROM mytable where username = ?1");
q.setParameter(1, "test");

This was a bug fixed in version 4.3.11
https://hibernate.atlassian.net/browse/HHH-2851
EDIT:
Best way to execute a native query is still to use NamedParameterJdbcTemplate
It allows you need to retrieve a result that is not a managed entity ; you can use a RowMapper and even a Map of named parameters!
private NamedParameterJdbcTemplate namedParameterJdbcTemplate;
#Autowired
public void setDataSource(DataSource dataSource) {
this.namedParameterJdbcTemplate = new NamedParameterJdbcTemplate(dataSource);
}
final List<Long> resultList = namedParameterJdbcTemplate.query(query,
mapOfNamedParamters,
new RowMapper<Long>() {
#Override
public Long mapRow(ResultSet rs, int rowNum) throws SQLException {
return rs.getLong(1);
}
});

convert a sql query into jpql (JPA)

I have a JPA annotated model classes called LeadGeneration and Lead. I need to get a resultset from the above two classes with JPQL. I have done an SQL equivivalent of the result set I want. Please tell me how to convert this SQL to JPQL. Have to give generated_employee_id and status as parameters.
SELECT *
FROM lead_generation lg, lead l
WHERE lg.lg_code = l.lead_generation AND lg.generated_employee_id = '111' AND l.status ='CONVERTED_LEAD'
AND (first_appointment_date between DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() );

in other ways,you can using nativeQuery,like this:
#Query(value="SELECT * FROM lead_generation lg, lead l WHERE lg.lg_code = l.lead_generation AND lg.generated_employee_id = ?1 AND l.status ='CONVERTED_LEAD' AND (first_appointment_date between DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )",nativeQuery=true)
List<User> findLeadGeneration(Integer id);

Make sure lead_generation has collections of lead. Each object "." variable must be setter and getter of object.
SELECT * FROM lead_generation lg INNER_JOIN lg.leads l WHERE lg.generated_employee_id = :id AND l.status= :status AND (lead_generation.first_appointment_date BETWEEN :min ANd :max)
Query query = em.createQuery("SELECT * FROM lead_generation lg INNER_JOIN lg.leads l WHERE lg.generated_employee_id = :id AND l.status= :status AND (lead_generation.first_appointment_date BETWEEN :min ANd :max)");
query.setParameter("id", "111");
query.setParameter("status", "CONVERTED_LEAD");
query.setParameter("min", DATE_FORMAT(NOW() ,'%Y-%m-01'));
query.setParameter("max", NOW());
List<lead_generation> lead_generations = (List<lead_generation>) query.getResultList();

OpenJPA: how to construct a GROUP BY query with a group count

In JPQL I want to construct the equivalent query to this:
select *, count(*) as finger_count from page_delta_summary
where delta_history_id = ? and change_type = ? group by fingerprint;
where fingerprint is a varchar field in table page_delta_summary. What I have is this:
select d, count(d) as finger_count from PageDeltaSummary d
where d.deltaHistoryId = :deltaHistoryId and d.type = :pageDeltaType
GROUP BY d.fingerprint"
where PageDeltaSummary is my entity. But I'm getting the following exception:
org.apache.openjpa.persistence.ArgumentException: Your query on type "class com.su3analytics.sitedelta.model.PageDeltaSummary" with filter "select d, count(d) from PageDeltaSummary d where d.deltaHistoryId = :deltaHistoryId and d.type = :pageDeltaType GROUP BY d.fingerprint" is invalid. Your select and having clauses must only include aggregates or values that also appear in your grouping clause.
The query works fine if I remove either count(d) as finger_count or the GROUP BY.
Any suggestions?
Thanks

Your original SQL query doesn't make sense, therefore you can't convert in into JPQL.
I guess you want to get count of page_delta_summary rows satisfying where conditions for each fingerprint. If so, the SQL query looks like this:
select fingerprint, count(*) as finger_count from page_delta_summary
where delta_history_id = ? and change_type = ? group by fingerprint;
and JPQL - like this:
select d.fingerprint, count(d) from PageDeltaSummary d
where d.deltaHistoryId = :deltaHistoryId and d.type = :pageDeltaType
GROUP BY d.fingerprint
These queries return pairs <fingerprint, finger_count> instead of full page_delta_summary rows (or entities).