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Passing two variables to one method to get two results

I am trying to pass two variables along to a method and have the method give me back two independent results.
int numX = 5;
int numY = 3;
System.out.println(displayTwiceTheNumber(numX, numY));
}
public static int displayTwiceTheNumber(int numX, int numY) {
int numW, numZ;
numW, numZ = 2 * (numX, numY);
return numW numZ;
}
Java takes it that at numW, numZ = 2 * (numX, numY); that I am trying to redefine numX and numY. How do I phrase the last block to take two variables and give two results?

A single int function can only return 1 int at a time.
If you want to return 2 values, consider calling the function twice or creating a custom object to be used.

You need to change the return type of the function. Currently, the return type is int, so you have to return one integer.
To return two integer, you should consider returning an array or a list or something similar.
public static int[] displayTwiceTheNumber(int numX, int numY){
//your code that do something
int[] ret = {numW, numZ};
return ret;
}
Or knowing that this function would change the value of numW and numZ, you could declare those as global variable. Now, when you call this function, those variable will be changed. Then, you can use numW and numZ subsequently.
public int numW;
public int numZ;
public static void displayTwiceTheNumber(int numX, int numY){
//your code that do something and modifies numW and numZ
}
public static void anotherfunction(){
//after calling displayTwiceTheNumber, numW and numZ would have the appropriate value
//you can now just use numW and numZ directly
}

Overview: Use a tuple. In this example I use an tuple to return more than one result. Tuple means to return more than one result type. In this example I return a tuple of two integer types. My class TupleCustom contains one method function1 which receives two parameters of type integer: x and y. I create a tuple of type integer and return the tuple as a variable. Internally, the precomiler converts the tuple json than back to a tuple with variable Item1, Item2...ItemN in the unit test method.
public class TupleCustom
{
public async Task<Tuple<int, int>> Function1(int x, int y)
{
Tuple<int, int> retTuple = new Tuple<int, int>(x, y);
await Task.Yield();
return retTuple;
}
}
public class TestSuite
{
private readonly ITestOutputHelper output;
public TestSuite(ITestOutputHelper output)
{
this.output = output;
}
[Fact]
public async Task TestTuple()
{
TupleCustom custom = new TupleCustom();
Tuple<int, int> mytuple = await custom.Function1(1,2);
output.WriteLine($" Item1={mytuple.Item1} Item2={mytuple.Item2} ");
}

When I have this problem I create a private utility class for handling the return values. By doing it this way, you can pass various types in the argument list. Aspects of the class can be tailored to your requirements.
public static void main(String [] args) {
int numX = 5;
double numY = 3.0;
Nums n = displayTwiceTheNumber(numX, numY);
System.out.println(n.numX);
System.out.println(n.numY);
}
public static Nums displayTwiceTheNumber(int numX, double numY) {
int numW;
double numZ;
// do something with arguments.
// in this case just double them and return.
return new Nums(2*numX, 2*numY);
}
private static class Nums {
int numX;
double numY;
public Nums(int nx, double ny) {
this.numX = nx;
this.numY = ny;
}
public String toString() {
return "(" + numX + ", " + numY +")";
}
}
Prints
10
6.0

Void method for println vs. println with return method

While I was writing a calculator app, I just couldn't figure out what the best way to do this is:
private void calculate(String command) {
System.out.print("value1: ");
int value1 = reader.readInteger();
System.out.print("value2: ");
int value2 = reader.readInteger();
if (command.equals("sum"))
System.out.println("sum of the values " + sum(value1 + value2));
}
private int sum(int value1, int value2) {
return value1 + value2;
}
or
private void calculate(String command) {
System.out.print("value1: ");
int value1 = reader.readInteger();
System.out.print("value2: ");
int value2 = reader.readInteger();
if (command.equals("sum"))
sum();
}
private void sum(int value1, int value2) {
System.out.println("sum of the values " + value1 + value2);
}
The second one makes the calculate() method cleaner, but is it generally preferred to use return methods or void(just for the printline)?

In general, it's better to return value - then you can test your method and reuse it in more complex calculations.
One of the good approaches is to define some calculate method which calculates and returns value, and define void show method which will accept as argument value to show on the screen and properly show it.

I think you should take a look at command pattern if you will extend this to other commands.
It will reduce your if statements in future when you want extend this calculate method.
command-pattern with calculator

Better way is the returning value. If you named the method sum, you expect to get value of sum.
You might create a method showResult(). You expect to get a information message.
public int getSum() {
return this.sum;
}
public void showResult() {
System.out.println("sum = " + this.sum); // add some description
}
private void calculate() {
this.sum = reader.readInteger() + reader.readInteger();
}

Why am I getting a "; expected" error?

public class homework
{
public static void intPow(int a, int b)
{
Math.pow(a,b);
}
public static void main(String args[])
{
intPow();
}
}
I'm trying to learn how to create a method, but I keep getting 10 ; expected errors. I know this code isn't correct, but I can't seem to find how to create a method correctly. In this case I'm trying to create a method that returns a^b.

You need to pass two int parameters into intPow():
public static void main(String args[])
{
int a = 2;
int b = 5;
intPow(a, b); //32
}
Furthermore, you should probably return an int from intPow() so you can play with it later:
public static int intPow(int a, int b) {
return Math.pow(a, b);
}
Then in main():
public static void main(String args[])
{
int a = 2;
int b = 5;
int power = intPow(a, b); //32
System.out.println(power);
}

pass two int values in intPow();
intPow(5,5);
And anyways the value would not be printed.
You need to use System.out.println() to print it.

Change
intPow();
to
intPow(2,3); // or any number

You declare intPow as a function that takes two parameters. But when you call it from main, you dont pass any. To fix this, change this line in main -
intPow();
to
intPow(1, 2);//or whatever other numbers you want.

public class homework
{
public static int intPow(int a, int b)
{
return Math.pow(a,b);
}
public static void main(String args[])
{
int a = 3;
int b = 4;
int result = intPow(a, b);
System.out.println(result);
}
}

If the goal is to create a method that returns a^b, the method should return a value. You probly need to convert to int though, because Math.pow works with doubles.
public static int intPow(int a, int b) {
return (int) Math.pow(a,b);
}
then call it using two parameters for a and b:
int result = intPow( 2, 3 );

Constructor undefined

I have a problem with my code, in that it keeps saying that the constructor is undefined. I already read somewhere that I need to declare the constructor with no arguments. I just don't know how to do that.
If someone could help, I am new at java and programming. My code is below:
import java.util.*;//import library
class Input
{
public Input (int size,int startV,int endingV)
{
//declarations of variables
double difference;
double[] array= new double[size];
array[0]=startV;
//calculating the difference to add on each number in the array
difference=(endingV-startV)/size;
for (int counter=1;counter<size;counter++) //for loop to fill the array
{
array[counter]=array[counter-1] + difference;
}
}
public Input enter(int size,int startV,int endingV)
{
//declarations of variables
double difference;
double[] array= new double[size];
array[0]=startV;
//calculating the difference to add on each number in the array
difference=(endingV-startV)/size;
for (int counter=1;counter<size;counter++) //for loop to fill the array
{
array[counter]=array[counter-1] + difference;
}
return this;
}
}
class Show
{
public Show (int size,double[] array)
{
for (int i=0;i<size;i++) //for loop to print the array
System.out.println("This is the array " + i+ ": " + array[i]);
}
public Show print(int size,double[] array)
{
for (int i=0;i<size;i++) //for loop to print the array
System.out.println("This is the array " + i+ ": " + array[i]);
return this;
}
}
public class Assignment2
{
public static void main(String[] args)
{
//declaring variables
int startV,endingV;
int size=0;
System.out.print("Give the size of the array:");//Print message on screen
size = new Scanner(System.in).nextInt();//asking for the size of array
double[] array= new double[size]; //creation of array
System.out.print("Give the starting value of the array:");
startV = new Scanner(System.in).nextInt();//asking for the starting value of array
System.out.print("Give the ending value of the array:");
endingV = new Scanner(System.in).nextInt();//asking for the last value of array
//calling the functions from the other classes
Input enter= new Input(size,startV,endingV);
Show print= new Show(size,array);
}
}

You're close:
You have a method:
public Method enter(int size,int startV,int endingV) {
to make it a constructor it's signature must be
public Method (int size,int startV,int endingV) {
and you then have to delete the return this; statement.
Remember, constructors don't have a return type and their name is identical to the name of the class. With this information, you'll also be able to fix the Method1 constructor.
Also, please respect the Java naming conventions and have variables start with a lower-case letter to improve the readability of your code.

You need to create a
public Method(size,startV,endingV)
not
public Method enter = (size, startV, endingV)
The first is a constructor the second is a method

For class Method
the default constructor will be
public Method(){}
For class Method1
the default constructor will be
public Method1(){}
in your classes there are no constructors as the
constructor name must be will the same as class name.
enter(int size,int startV,int endingV)
and
print(int size,double[] array)
can be two methods in your classes.
also your two constructor can be -
public Method(int size,int startV,int endingV){ /..../}
and
public Method1(int size,double[] array){ /..../}

Your constructor must have the same name than your class and has no return type. So for your class Method, your constructor will simply be :
public Method(int size, int startV, int endingV)
{
// code...
}
Please also note that constructors exist to initialize your instances of objects, if you want to create a method that does a specific calcul, then yes, you'll have to do :
public int enter(int size, int startV, int endingV)
{
int result = 0;
// code to calculate, for example result = size + startV + endingV ...
return result;
}

Fibonacci Sequence return argument

I need to generate a program that generates the Fibonacci Sequence
Here is what I have so far:
import java.util.Scanner;
public class FibonacciRunner
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.println("Enter n:");
int n = in.nextInt();
EP64 fg = new EP64();
for (int i = 1; i <= n; i++)
System.out.println(fg.nextNumber());
}
}
public class EP64
{
public static void nextNumber(int n)
{
int fold1 = 1;
int fold2 = 1;
int fnew = fold1 + fold2;
fold1 = fnew;
}
}
I get an error on:
System.out.println(fg.nextNumber());
saying:
method nextNumber in class EP64 cannot be applied to given types:
required: int
found: no arguments
reason: actual and formal argument lists differ in length
and can someone also tell me if I am doing this program right? If not, help! I looked at other similar questions but I cannot make much sense of them
Thank you all!

method nextNumber in class EP64 cannot be applied to given types: required: int found: no arguments reason: actual and formal argument lists differ in length
Your
public static void nextNumber(int n)
^^^^^^^
says that any call to the method must provide an integer as argument. But here:
System.out.println(fg.nextNumber());
^^ you need to add an integer argument
you violate this by providing no argument.
As your code reads now, I'd probably drop the int n argument.
and can someone also tell me if I am doing this program right?
Naah, not really...
fold1 and fold2 should probably be member variables (so they don't get reset in every call to the method),
You're forgetting to update fold2 (you only update fold1),
Also, you probably want to return an int from the nextNumber method.
Read up on
Official Java Tutorial: Defining Methods

You are calling a static method to a object reference instead of the class itself.
And
Not passing any argument at all for nextNumber() method.
Make the method non-static as :
public void nextNumber(int n) {}
Pass arg to the method as :
for (int i = 1; i <= n; i++)
System.out.println(fg.nextNumber(n));
And also don't forget to return the processed number from your nextNumber method,which you collecting in System.out.println.

Your declaration of nextNumber says it takes an int argument, but you are calling it with no arguments.
Also, your code isn't going to do what you want. You probably should make fold1 and fold2 members of class EP64 and make the method an instance method rather than a static method. You also need to do fold2 = fold1; before you update fold1.
Finally, you need to declare nextNumber to return an int value, and then actually have it return an int value.

You have two problems. Firstly, your method doesn't return anything, i.e. it is void. You need to make it int and add a return fnew; at the end. The other problem is you are starting from scratch every time, it will return 2 each time. You need to make fold1 and fold2 fields by moving them above the nextNumber line. Oh, and drop the int n argument as it doesn't do anything.

I agree on the diagnostics of the other posts, but don't suggest a member variable, but a rename and local variables.
You can ask for the 5th Fibonacci-Number with 5 calls to
fib.next ();
or with a single call to
fib (5);
Since the fibonacci-sequence increases very rapidly, you have very few calls (54) before hitting the overflow boundary. So if you repeatedly recalc the same sequence, to print the sequence, it's not a big problem. A recursive solution would be fine.
Btw.: EP64 is a very bad name.

I think this is enough:
import java.util.Scanner;
public class Fibnocci
{
public static void main(String []abc)
{
int a=0,b=1,c;
Scanner in=new Scanner(System.in);
System.out.print("Enter the Range: ");
int n= in.nextInt();
System.out.print(a+" "+b);
for(int i=0;i<n-2;i++) //n-2 because we are showing 0,1 initially.
{
c=a+b;
System.out.print(" "+c);
a=b;
b=c;
}
}
}
If you want to call this as a method then:
import java.util.Scanner;
public class Fibnocci
{
public static void main(String []abc)
{
Scanner in=new Scanner(System.in);
System.out.print("Enter the Range: ");
int n= in.nextInt();
callFibonocci(n);
}
public static void callFibonocci(int n)
{
int a=0,b=1,c;
System.out.print(a+" "+b);
for(int i=0;i<n-2;i++) //n-2 because we are showing 0,1 initially.
{
c=a+b;
System.out.print(" "+c);
a=b;
b=c;
}
}
}
You can call this method out of the class;

// Fibnocci Using c#
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace CodeProject
{
class FibnocciSeries
{
public int[] FibonacciArray(int length)
{
int[] fseries = new int[length];
fseries[0] = 0;
fseries[1] = 1;
if (length == 0)
return null;
//Iterating through the loup to add adjacent numbers and create the memeber of series
for (int i = 2; i < length; i++)
{
fseries[i] = fseries[i - 1] + fseries[i - 2];
}
return fseries;
}
}
}
////////////////////
class Program
{
static void Main(string[] args)
{
FibnocciSeries fb = new FibnocciSeries();
Console.WriteLine("Please Enter Integer Length of Fibnocci series");
int length = Convert.ToInt32(Console.ReadLine());
int[] result = fb.FibonacciArray(length);
foreach(int i in result)
Console.Write(i.ToString()+ " ");
Console.ReadLine();
}
}
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