Unknown inline modifier Java regex - java

i am parsing some text files in which the escape character is ? - There is also 4 escaped characters : + ' : ? . I think the clear escaping was working fine ( might be wrong tho ) until i added spring batch. Now when i try to launch the parsing of the file, this is failing and i don't get why.
Here is the error :
java.util.regex.PatternSyntaxException: Unknown inline modifier near index 6
(\?)(?|:|\+|')
And there is the code
private String regex = "(\\?)(?|:|\\+|')";
private String clearEscaping(String s){
return s.replaceAll(regex, "$2");
}
Can someone explain me why this is not working ? And how should i fix the issue ? Is there any more efficient way to do the escape clearing ?

Thanks to anubhava to point out that my regex was wrong in the 1st place & giving me the fix.
Thanks to Wiktor Stribiżew, for the complete solution & make it clear !
=> I changed my regex to "(\\\\?)([?:+'])"

Related

Jenkins Console section: What Java regex will trigger on string ERROR but not on string %%ERRORLEVEL%%?

I am using the Jenkins console sections plugin [1] on a windows server. It is excellent in order to make a nice left navbar on my logs.
Positively, I would like any error message to cause a section header, eg;
Assert-PathExstsNotTooLong : ERROR, The path does not exist: E:\P...
...
Oops! Error, please do not do that.
Negatively, I would like to be able to avoid having spelled-out execution templates cause a new section header, eg the below.
[workspace] $ cmd.exe /C " c:\Windows\Microsoft.NET\Framework64\v4.0.30319\MSBuild.exe /p:Configuration=Debug /p:VisualStudioVersion=12.0 "E:\Program Files (x86)\Jenkins\jobs\M.sln"
Using references here on SO [2] and on the tester you recommended [3], I came up with the following, but it is not working?
^(?=(.*([Ee][Rr][Rr][Oo][Rr] ).*))(?!(%%ERRORLEVEL%%))
Using Regex101's amazing tester, with JS flavor, I used the above as input and had these test strings and outputs. The second line of match info perhaps explains my issue but I do not understand it.
test-strings =
help error you should see me
i am %%errorlevel%% again
i am not a section
match-info;
1. `help error you should see me`
2. `error `
Any tips?
thank you!
1.[] ;This plugin uses Java Regex, per its docs ; ; ; ; X.Collapsing Console Sections Plugin - Jenkins - Jenkins Wiki ; ; https://wiki.jenkins-ci.org/display/JENKINS/Collapsing+Console+Sections+Plugin
2.[] ; An example regex on characters, not strings, to avoid; ; ; ; X.java - Regular expression include and exclude special characters - Stack Overflow ; ; Regular expression include and exclude special characters
3.[] ; ; ; ; ; X.Online regex tester and debugger: JavaScript, Python, PHP, and PCRE ; ; https://www.regex101.com/#javascript
(I can't add comments yet, otherwise I'd ask directly, but your example of a spelled-out message template doesn't include the text %%ERRORLEVEL%%, but I assume that it's meant to be a string with %%ERRORLEVEL%% somewhere in the middle of it. Also, as the example isn't quite right, I can't tell exactly what you mean by "not working")
Your problem is that your regex matches ERROR_ (with a space) anywhere in the text, except where the text is exactly %%ERRORLEVEL%%. I think that instead you could write:
^(?=(.*([Ee][Rr][Rr][Oo][Rr])))(?!.*(%%ERRORLEVEL%%)).*
Do you really need to only match ERROR_ (with a space) as opposed to ERROR (whether or not it has a space)? If the former, then you are already excluding %%ERRORLEVEL%%, and you could just use .*(?i:ERROR ).* as the full regex.
The Collapsing Console Sections Plugin uses Java regular expressions, so you can use (?i:ERROR) to match ERROR case-insensitively.
You need a trailing .* before and after your negative-lookahead atom for %%ERRORLEVEL%%, otherwise it will only exclude an exact match
The documentation for the plugin doesn't say whether the pattern has to match a line completely, or if it just matches text within the line. If it matches the line completely, the leading ^ is unnecessary, but won't be doing any harm.
You've got capturing brackets around ERROR and %%ERRORLEVEL%%. If you're not doing anything with that text, then those brackets are unnecessary.
The following regex will match any line with any of ERROR, Error, error etc in it, except lines with any of %%ERRORLEVEL%%, %%ErrorLevel%%, %%errorlevel%% etc.
^(?=.*(?i:ERROR))(?!.*(?i:%%ERRORLEVEL%%)).*

Check if a string ends in is valid or not in java using regex

I have the following requirement where in I need to do few things only if the given string ends in "Y" or "Years" or "YEARS".
I tried doing it using regex like this.
String text=1.5Y;
if(Pattern.matches("Y$",text) || Pattern.matches("YEARS$",text) || Pattern.matches("Years",text))
{
//do
}
However this is getting failed.
Can someone point me where I have gone wrong or suggest me any other feasible method.
EDIT:
Thanks.That helps.
Finally I have used "(?i)^.*Y(ears)?$| (?i)^.*M(onths)?$".
But I want to make more changes to make it perfect.
Let's say I have many strings.
Ideally only strings like 1.5Y or 0.5-3.5Y or 2.5/2.5-4.5Y should pass if check.
It can be number of years(Ex:2.5y) or the period of years(2.5-3.5y) or the no of years/period of years(Ex.2.5/3.5-4.5Y) nothing more.
More Examples:
--------------
Y -should fail;
MY - should fail;
1.5CY - should fail;
1.5Y-2.5Y should fail;
1.5-2.5Y should pass;
1.5Y/2.5-3.5Y should fail;
1.5/2.5-3.5Y should pass;
You don't need a regex here:
if(text.endsWith("Y") || ...)
matches method attempts to match full input so use:
^.*Y$
for your first pattern.
btw you can use a single regex for all 3 cases:
if (text.matches( "(?i)^.*Y(ears)?$" ) ) {...}
(?i) does ignore case match.
.*(?:Y|YEARS|Years)$
You can directly use this .Match matches from beginning.So yours is failing.
You can simply use the regex pattern:
if (Pattern.matches(".*(Y|YEARS|Years)$",text)) {/*do something*/}
/((?!0)\d+|0)(.\d+)?(?:years|year|y)/gi
https://regex101.com/r/gJ6xD2/2
var text = "1.6y 1.5years 1year 1.5h";
text.match(/((?!0)\d+|0)(\.\d+)?(?:years|year|y)/gi);
Result["1.6y", "1.5years", "1year"]
(?=^(0\.\d+|[1-9](?:\d+)?(?:\.\d+)?)(?:(\s+)?[\/-](\s+)?(?:0\.\d+|[1-9](?:\d+)?(?:\.\d+)?))*(?:\s+)?(?:y(?:(ea)?rs|ears?)?|m(?:onths?)?)$).*
https://regex101.com/r/kL7rQ1/3
Only thing I wasn't sure "2.3 - 4 / 6.2 y" format is acceptable or not, so I've included it.

Parametric string replacement

I am running in to bit of a trouble trying to use parametric replacement.
In my properties file I have the following entry
tpi.message=This is a test message. Generated for ? on ? .
The text above is displayed on the web and in the report therefore I need to replace ? with parameters.
However, I can't use replace* method because ? is special character for regex. I also don't want to use String.format method.
I know it is possible to replace ? but I don't remember how.
Your help is appreciated.
You can do it like this:
String message = "This is a test message. Generated for ? on ?";
message = message.replaceFirst("\\?", "Bob").replaceFirst("\\?", "Tuesday");
System.out.println(message); // This is a test message. Generated for Bob on Tuesday

Java: How to spit the line in between two pattern in Java

I am facing some problem with getting the text matching with the two patterns,Please help me out,Here is my question and my requirement :
Line : selenium.TypeKeys("name=email", "raj#ymail.com");
My requirement is to Get the name=email from the above line,
Thanks
This should give you the value between " and ,.
line.substring(line.indexOf("(\""), line.indexOf(","));

Regex submitting with empty string

I have the following REGEX that I'm serving up to java via an xml file.
[a-zA-Z -\(\) \-]+
This regex is used to validate server side and client side (via javascript) and works pretty well at allowing only alphabetic content and a few other characters...
My problem is that it will also allow zero lenth strings / empty through.
Does anyone have a simple and yet elegant solution to this?
I already tried...
[a-zA-Z -\(\) \-]{1,}+
but that didn;t seem to work.
Cheers!
UPDATE FOLLOWING INVESTIGATION
It appears the code I provided does in fact work...
String inputStr = " ";
String pattern = "[a-zA-Z -\\(\\) \\-]+";
boolean patternMatched = java.util.regex.Pattern.matches(pattern, inputStr);
if ( patternMatched ){
out.println("Pattern MATCHED");
}else{
out.println("NOT MATCHED");
}
After looking at this more closely I think the problem may well be within the logic of some of my java bean coding... It appears the regex is dropped out at the point where the string parse should take place, thereby allowing empty strings to be submitted... And also any other string... EEJIT that I am...
Cheers for the help in peer reviewing my initial stupid though....!
Have you tried this:
[a-zA-Z -\(\) \-]+

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