How to extend Spring oidcUser to use customUserDetails - java

This is my first Question ever here on SO, it was helpfull and saved me lots of time, but now I can't find any solution to my problem.
As I'm rather new to spring and espacially to spring-security, I'm stuck with something that might be easy if i had more knowledge.
I have an existing Application that uses a local user database. It uses a custom UserDetails implementation that works if used with user:password authentification through a login form.
Here is the current setup:
public class SecurityContext extends WebSecurityConfigurerAdapter {
....
#Autowired
public void configureGlobal(final AuthenticationManagerBuilder auth) throws Exception {
auth.authenticationProvider(authenticationProvider()).userDetailsService(userDetailsService());
}
#Bean
public AuthenticationProvider authenticationProvider() {
DaoAuthenticationProvider result = new DaoAuthenticationProvider();
result.setUserDetailsService(userDetailsService());
result.setPasswordEncoder(passwordEncoder());
return result;
}
#Override
#Bean
public GatesUserDetailsService userDetailsService() {
GatesUserDetailsService result = new GatesUserDetailsService();
result.setClientService(clientService);
result.setAccountService(accountService);
result.setCardService(cardService);
result.setPersonService(personService);
result.setAccountPropertyService(accountPropertyService);
result.setLoginAttemptService(loginAttemptService);
return result;
}
Now I want to use SSO from an external IDP that speaks OpenIdConnect.
Going through the documentation I was able to get this up and running in a "default" manner. That is, at the and of my process a get a user that is an Instance of OidcUser. I need that user to be either extended or incorporate the existing userDetails.
The documentation (Spring Boot and OAuth2) recommends to
Implement and expose OAuth2UserService to call the Authorization
Server as well as your database. Your implementation can delegate to
the default implementation, which will do the heavy lifting of calling
the Authorization Server. Your implementation should return something
that extends your custom User object and implements OAuth2User.
I was able to introduce my own Oauth2UserService that gets called right at the and of the authentification by setting:
#Override
protected void configure(final HttpSecurity http) throws Exception {
http.exceptionHandling()
.accessDeniedHandler(accessDeniedHandler())
.and()
.oauth2Login()
.failureHandler(authenticationFailureHandler())
.successHandler(authenticationSuccessHandler())
.userInfoEndpoint()
.userService(this.oauth2UserService())
.oidcUserService(this.oidcUserService());}
private OAuth2UserService<OidcUserRequest, OidcUser> oidcUserService() {
final OidcUserService delegate = new OidcUserService();
return (userRequest) -> {
OidcUser oidcUser = delegate.loadUser(userRequest);
//..DO some additional Stuff check against external Server
//Here I could load my custom userDetails
GatesUserDetails userDetails = (GatesUserDetails) userDetailsService.loadUserByUsername("131:" + username);
....
But I have now Idea how to make my customUser a vaild return to my function.
I tried to implement the OidcUser Interface in my userDetails, but still it does not work.
Any hint (even to a more understandable doc) would be highly appreciated.
EDIT
To clarify things, I implemented the oidcUser Interface as stated in the docs along with the necessary implementations (getAttribute, getAttributes, getAuthorities) but still I could not use this as the return type would still be our GatesUserDetails, no way (for me) to cast it to oidcUser

Have the same problem with spring-security-oauth2-client-5.6.2, after hours google and debugger it solved.
First, make sure your UserInfo entrypoint is correct in case you own the
Auth server.
Plus requested scopes contains any of profiles not
only openid.
Logic found here: OidcUserService::shouldRetrieveUserInfo
private boolean shouldRetrieveUserInfo(OidcUserRequest userRequest) {
// Auto-disabled if UserInfo Endpoint URI is not provided
ProviderDetails providerDetails = userRequest.getClientRegistration().getProviderDetails();
if (StringUtils.isEmpty(providerDetails.getUserInfoEndpoint().getUri())) {
return false;
}
// The Claims requested by the profile, email, address, and phone scope values
// are returned from the UserInfo Endpoint (as described in Section 5.3.2),
// when a response_type value is used that results in an Access Token being
// issued.
// However, when no Access Token is issued, which is the case for the
// response_type=id_token,
// the resulting Claims are returned in the ID Token.
// The Authorization Code Grant Flow, which is response_type=code, results in an
// Access Token being issued.
if (AuthorizationGrantType.AUTHORIZATION_CODE
.equals(userRequest.getClientRegistration().getAuthorizationGrantType())) {
// Return true if there is at least one match between the authorized scope(s)
// and accessible scope(s)
return this.accessibleScopes.isEmpty()
|| CollectionUtils.containsAny(userRequest.getAccessToken().getScopes(), this.accessibleScopes);
}
return false;
}
Hope this could help someone.

Related

Spring boot WebSecurityConfigurerAdapter basic authentication user password validation issue

I'm writing a simple REST API using Spring Boot and I want to enable basic authentication. Therefore I have used the WebSecurityConfigurerAdapter as shown below. For simplicity, I just want to check only the password (pwd123) and allow any user to log in. Please refer to the code below.
#EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
#Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.authenticationProvider(new AuthenticationProvider() {
#Override
public Authentication authenticate(Authentication authentication) throws AuthenticationException {
if (authentication == null || authentication.getCredentials() == null) {
throw new BadCredentialsException("Bad credentials");
}
if (authentication.getCredentials().equals("pwd123")) {
return new UsernamePasswordAuthenticationToken(authentication.getName(),
authentication.getCredentials().toString(),
Collections.emptyList());
}
return null;
}
#Override
public boolean supports(Class<?> authentication) {
return authentication.equals(UsernamePasswordAuthenticationToken.class);
}
});
}
#Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests().anyRequest().authenticated()
.and().httpBasic();
}
}
Assume user_A has accessed the REST API with a valid password, i.e pwd123, and then do the send API call with a wrong password. However the user is allowed to access the API which is the problem.
When I do the debugging I realized that authenticationIsRequired function in BasicAuthenticationFilter class which is in Spring Security, returns false in such scenario. Please refer that code.
private boolean authenticationIsRequired(String username) {
// Only reauthenticate if username doesn't match SecurityContextHolder and user
// isn't authenticated (see SEC-53)
Authentication existingAuth = SecurityContextHolder.getContext().getAuthentication();
if (existingAuth == null || !existingAuth.isAuthenticated()) {
return true;
}
// Limit username comparison to providers which use usernames (ie
// UsernamePasswordAuthenticationToken) (see SEC-348)
if (existingAuth instanceof UsernamePasswordAuthenticationToken && !existingAuth.getName().equals(username)) {
return true;
}
// Handle unusual condition where an AnonymousAuthenticationToken is already
// present. This shouldn't happen very often, as BasicProcessingFitler is meant to
// be earlier in the filter chain than AnonymousAuthenticationFilter.
// Nevertheless, presence of both an AnonymousAuthenticationToken together with a
// BASIC authentication request header should indicate reauthentication using the
// BASIC protocol is desirable. This behaviour is also consistent with that
// provided by form and digest, both of which force re-authentication if the
// respective header is detected (and in doing so replace/ any existing
// AnonymousAuthenticationToken). See SEC-610.
return (existingAuth instanceof AnonymousAuthenticationToken);
}
Please let me know what is missing in my implementation
As mentioned in the comments, instead of providing a custom AuthenticationProvider you can try providing a custom UserDetailsService. Here's the complete configuration:
#EnableWebSecurity
public class SecurityConfiguration {
#Bean
public SecurityFilterChain securityFilterChain(HttpSecurity http) throws Exception {
http
.authorizeRequests((authorizeRequests) -> authorizeRequests
.anyRequest().authenticated()
)
.httpBasic(Customizer.withDefaults());
return http.build();
}
#Bean
public UserDetailsService userDetailsService() {
return (username) -> new User(username, "{noop}pwd123", AuthorityUtils.createAuthorityList("ROLE_USER"));
}
}
When you evolve to looking up the user via a third-party service, you can add the code to do this in the custom UserDetailsService (a lambda function or an actual class that implements the interface) and continue returning a org.springframework.security.core.userdetails.User.
Note: I don't actually recommend plain-text passwords in production. You would replace {noop}pwd123 with something like {bcrypt}<bcrypt encoded password here>.
As suggested in the comments and answers, even if you use the InMemoryUserDetailsManager the problem does not get resolved, which means, once the user is authenticated with the correct user name and password, his password is not validated in the subsequent REST API calls,i.e. can use any password. This is because of the functionality in BasicAuthenticationFilter class where it skips users who are having a valid JSESSION cookie.
To fix the issue, we should configure http to create state-less sessions via
http .sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS).and()
in configure function of the WebSecurityConfigurerAdapter
Please refer Why BasicAuthenticationFilter in spring security matches only username and not the password

Spring Boot LDAP check if a user belongs to a specific group

I'm building an application which will allow only a specific set of users in my org. to login. Only those users that belong to a particular AD Group can login. Eg: GDL - MyTeam is a GDL, only who's members I want to allow to get in.
I checked out Atlassian's tutorial, and confluent's tutorial as well as Megha's answer here.
What is different in my case, compared to other stack overflow questions is that I'm using ActiveDirectoryLdapAuthenticationProvider as can be seen in my code snippet below. That is the one to be dictating the terms.
However, My application would still allow any user in the org to get in to my application. I'm really not able to understand what criteria is it using to allow anyone.
I'm a totally newbie to ldiff syntax and filtering ldap using Java. Combine with springboot, I really don't know if I should use group search base or user search base. I just want people of my GDL to be able to get in. Rest should receive an authentication failure.
Here is my code file for reference:
#Override
public void configure(AuthenticationManagerBuilder auth) throws Exception {
configureLdap(auth);
configureActiveDirectory(auth);
}
private void configureLdap(AuthenticationManagerBuilder auth) throws Exception {
auth
.ldapAuthentication()
.contextSource(contextSource())
.userSearchFilter("(&(objectClass=user)(sAMAccountName=*)(memberOf=cn=GDL-MyTeam,ou=users,dc=myCompany,dc=com)))")
.passwordCompare()
.passwordEncoder(passwordEncoder())
.passwordAttribute("userPassword");
}
private void configureActiveDirectory(AuthenticationManagerBuilder auth) {
ActiveDirectoryLdapAuthenticationProvider adProvider = activeDirectoryLdapAuthenticationProvider();
if (adProvider != null) {
auth.authenticationProvider(adProvider);
auth.eraseCredentials(false);
}
}
#Bean(BeanIds.AUTHENTICATION_MANAGER)
#Override
public AuthenticationManager authenticationManagerBean() throws Exception {
return super.authenticationManagerBean();
}
#Bean
public LdapContextSource contextSource() {
LdapContextSource contextSource = new LdapContextSource();
contextSource.setUrl(ldapUrls); //mycompany.com:389
contextSource.setBase(ldapBaseDn); //dc=myCompany,dc=com
contextSource.setUserDn(env.getProperty(ldapSecurityPrincipal));
contextSource.setPassword(env.getProperty(ldapPrincipalPassword));
contextSource.setReferral("follow");
contextSource.afterPropertiesSet();
return contextSource;
}
#Bean
protected ActiveDirectoryLdapAuthenticationProvider activeDirectoryLdapAuthenticationProvider() {
ActiveDirectoryLdapAuthenticationProvider provider = new ActiveDirectoryLdapAuthenticationProvider("myCompany.com", ldapUrls,
ldapBaseDn);
provider.setConvertSubErrorCodesToExceptions(true);
provider.setUseAuthenticationRequestCredentials(true);
provider.setUserDetailsContextMapper(new CustomUserDetailsContextMapper());
return provider;
}
#Bean
public LdapTemplate ldapTemplate() {
LdapTemplate template = new LdapTemplate();
template.setContextSource(contextSource());
template.setIgnoreNameNotFoundException(true);
template.setIgnorePartialResultException(true);
return template;
}
I believe this filter is the place where I have specified the correct matching criteria, but for some reason it's allowing everyone and not just My team's specific GDL.
.userSearchFilter("(&(objectClass=user)(sAMAccountName=*)(memberOf=cn=GDL-MyTeam,ou=users,dc=myCompany,dc=com)))")
Can anyone please provide guidance as to where I am going wrong.
Thanks a ton!
EDIT:
I figured out that ActiveDirectoryLdapAuthenticationProvider is dictating the terms. I believe this is the place where I need to put in the search filter. If I put in the exact same filter as the other answers
In order to perform this operation a successful bind must be completed on the connection., data 0, v3839]; remaining name '/'
But I really don't understand what to put in here. Suggestions please?
I wonder if this might be the issue:
.userSearchFilter("(&(objectClass=user)(sAMAccountName=*)(memberOf=cn=GDL-MyTeam,ou=users,dc=myCompany,dc=com)))")
You use sAMAccountName=* (with the *). Looks like wild card to me, meaning anyone?. What if you replace that with {1} like in
.userSearchFilter("(&(objectClass=user)(sAMAccountName={1})(memberOf=cn=GDL-MyTeam,ou=users,dc=myCompany,dc=com)))")

Java Spring authenticate user based on token

Looking to protect pages in a basic java spring application based on a token. After the token is consumed I would need the application to know the token was valid at some point and then put some time to live on that session. Below is the controller I have to consume the token.
#RequestMapping(value = "/login", method = RequestMethod.GET)
public String login(ModelMap model, #RequestParam(value = "token", required = false) String token) {
if(token==null) {
return "redirect:403";
} else if(token.isEmpty()) {
return "redirect:403";
} else {
//perform token WS call to validate the token
return "redirect:home";
}
}
#RequestMapping(value = "/403", method = RequestMethod.GET)
public ModelAndView accesssDenied(Principal user) {
ModelAndView model = new ModelAndView();
model.addObject("msg",
"You do not have permission to access this page!");
model.setViewName("403");
return model;
}
After performing some check on the token how can I protect all of the subsequent pages? Id also like to be able to secure api calls as well. Can anyone point me in the direction of the spring component?
I think you should take a look at Spring Security instead of rolling your own solution - it is built for handling authentication.
What you especially should look at is session management which sounds like what you're trying to do here.
Depending on how your users get their token you might have to implement your own authentication manager and/or login flow, though the default ones cover a lot of common cases too.
Once you have Spring Security set up and your session management working you would protect URLs either by annotating the controller methods:
#RequestMapping("/api/protected")
#PreAuthorize("hasRole('ROLE_USER')")
public String myProtectedController(Authentication authentication, Model model) {
// User will be authenticated here
}
or by registering them into the HTTP security configuration:
#Configuration
public class SecurityConfig extends WebSecurityConfigurationAdapter {
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
// Everyone can acess /login
.antMatchers("/login").permitAll()
// Only authorized users can access URLs under /api/
.antMatchers("/api/**").access("hasRole('ROLE_USER')")
}
}
Of course, in your case you might use something other than ROLE_USER since you may or may not have actual users but something else in your session that you can use.

Spring Security LDAP and Remember Me

I'm building an app with Spring Boot that has integration with LDAP. I was able to connect successfully to LDAP server and authenticate user. Now I have a requirement to add remember-me functionality. I tried to look through different posts (this) but was not able to find an answer to my problem. Official Spring Security document states that
If you are using an authentication provider which doesn't use a
UserDetailsService (for example, the LDAP provider) then it won't work
unless you also have a UserDetailsService bean in your application
context
Here the my working code with some initial thoughts to add remember-me functionality:
WebSecurityConfig
import com.ui.security.CustomUserDetailsServiceImpl;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.access.event.LoggerListener;
import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
import org.springframework.security.config.annotation.method.configuration.EnableGlobalMethodSecurity;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.ldap.authentication.ad.ActiveDirectoryLdapAuthenticationProvider;
import org.springframework.security.ldap.userdetails.UserDetailsContextMapper;
import org.springframework.security.web.authentication.RememberMeServices;
import org.springframework.security.web.authentication.rememberme.TokenBasedRememberMeServices;
#Configuration
#EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
String DOMAIN = "ldap-server.com";
String URL = "ldap://ds.ldap-server.com:389";
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.csrf().disable()
.authorizeRequests()
.antMatchers("/ui/**").authenticated()
.antMatchers("/", "/home", "/UIDL/**", "/ui/**").permitAll()
.anyRequest().authenticated()
;
http
.formLogin()
.loginPage("/login").failureUrl("/login?error=true").permitAll()
.and().logout().permitAll()
;
// Not sure how to implement this
http.rememberMe().rememberMeServices(rememberMeServices()).key("password");
}
#Override
protected void configure(AuthenticationManagerBuilder authManagerBuilder) throws Exception {
authManagerBuilder
.authenticationProvider(activeDirectoryLdapAuthenticationProvider())
.userDetailsService(userDetailsService())
;
}
#Bean
public ActiveDirectoryLdapAuthenticationProvider activeDirectoryLdapAuthenticationProvider() {
ActiveDirectoryLdapAuthenticationProvider provider = new ActiveDirectoryLdapAuthenticationProvider(DOMAIN, URL);
provider.setConvertSubErrorCodesToExceptions(true);
provider.setUseAuthenticationRequestCredentials(true);
provider.setUserDetailsContextMapper(userDetailsContextMapper());
return provider;
}
#Bean
public UserDetailsContextMapper userDetailsContextMapper() {
UserDetailsContextMapper contextMapper = new CustomUserDetailsServiceImpl();
return contextMapper;
}
/**
* Impl of remember me service
* #return
*/
#Bean
public RememberMeServices rememberMeServices() {
// TokenBasedRememberMeServices rememberMeServices = new TokenBasedRememberMeServices("password", userService);
// rememberMeServices.setCookieName("cookieName");
// rememberMeServices.setParameter("rememberMe");
return rememberMeServices;
}
#Bean
public LoggerListener loggerListener() {
return new LoggerListener();
}
}
CustomUserDetailsServiceImpl
public class CustomUserDetailsServiceImpl implements UserDetailsContextMapper {
#Autowired
SecurityHelper securityHelper;
Log ___log = LogFactory.getLog(this.getClass());
#Override
public LoggedInUserDetails mapUserFromContext(DirContextOperations ctx, String username, Collection<? extends GrantedAuthority> grantedAuthorities) {
LoggedInUserDetails userDetails = null;
try {
userDetails = securityHelper.authenticateUser(ctx, username, grantedAuthorities);
} catch (NamingException e) {
e.printStackTrace();
}
return userDetails;
}
#Override
public void mapUserToContext(UserDetails user, DirContextAdapter ctx) {
}
}
I know that I need to implement UserService somehow, but not sure how that can be achieved.
There are two issues to configuration of the RememberMe features with LDAP:
selection of the correct RememberMe implementation (Tokens vs. PersistentTokens)
its configuration using Spring's Java Configuration
I'll take these step by step.
The Token-based remember me feature (TokenBasedRememberMeServices) works in the following way during authentication:
user gets authenticated (agaisnt AD) and we currently know user's ID and password
we construct value username + expirationTime + password + staticKey and create an MD5 hash of it
we create a cookie which contains username + expiration + the calculated hash
When user wants to come back to the service and be authenticated using the remember me functionality we:
check whether the cookie exists and isn't expired
populate the user ID from the cookie and call the provided UserDetailsService which is expected to return information related to the user's ID, including the password
we then calculate the hash from the returned data and verify that the hash in the cookie matches with the value we calculated
if it matches we return the user's Authentication object
The hash checking process is required in order to make sure that nobody can create a "fake" remember me cookie, which would let them impersonate another user. The problem is that this process relies on possibility of loading password from our repository - but this is impossible with Active Directory - we cannot load plaintext password based on username.
This makes the Token-based implementation unsuitable for usage with AD (unless we start creating some local user store which contains the password or some other secret user-based credential and I'm not suggesting this approach as I don't know other details of your application, although it might be a good way to go).
The other remember me implementation is based on persistent tokens (PersistentTokenBasedRememberMeServices) and it works like this (in a bit simplified way):
when user authenticates we generate a random token
we store the token in storage together with information about user's ID associated with it
we create a cookie which includes the token ID
When user wants to authenticate we:
check whether we have the cookie with token ID available
verify whether the token ID exists in database
load user's data based on information in the database
As you can see, the password is no longer required, although we now need a token storage (typically database, we can use in-memory for testing) which is used instead of the password verification.
And that gets us to the configuration part. The basic configuration for persistent-token-based remember me looks like this:
#Override
protected void configure(HttpSecurity http) throws Exception {
....
String internalSecretKey = "internalSecretKey";
http.rememberMe().rememberMeServices(rememberMeServices(internalSecretKey)).key(internalSecretKey);
}
#Bean
public RememberMeServices rememberMeServices(String internalSecretKey) {
BasicRememberMeUserDetailsService rememberMeUserDetailsService = new BasicRememberMeUserDetailsService();
InMemoryTokenRepositoryImpl rememberMeTokenRepository = new InMemoryTokenRepositoryImpl();
PersistentTokenBasedRememberMeServices services = new PersistentTokenBasedRememberMeServices(staticKey, rememberMeUserDetailsService, rememberMeTokenRepository);
services.setAlwaysRemember(true);
return services;
}
This implementation will use in-memory token storage which should be replaced with JdbcTokenRepositoryImpl for production. The provided UserDetailsService is responsible for loading of additional data for the user identified by the user ID loaded from the remember me cookie. The simpliest implementation can look like this:
public class BasicRememberMeUserDetailsService implements UserDetailsService {
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
return new User(username, "", Collections.<GrantedAuthority>emptyList());
}
}
You could also supply another UserDetailsService implementation which loads additional attributes or group memberships from your AD or internal database, depending on your needs. It could look like this:
#Bean
public RememberMeServices rememberMeServices(String internalSecretKey) {
LdapContextSource ldapContext = getLdapContext();
String searchBase = "OU=Users,DC=test,DC=company,DC=com";
String searchFilter = "(&(objectClass=user)(sAMAccountName={0}))";
FilterBasedLdapUserSearch search = new FilterBasedLdapUserSearch(searchBase, searchFilter, ldapContext);
search.setSearchSubtree(true);
LdapUserDetailsService rememberMeUserDetailsService = new LdapUserDetailsService(search);
rememberMeUserDetailsService.setUserDetailsMapper(new CustomUserDetailsServiceImpl());
InMemoryTokenRepositoryImpl rememberMeTokenRepository = new InMemoryTokenRepositoryImpl();
PersistentTokenBasedRememberMeServices services = new PersistentTokenBasedRememberMeServices(internalSecretKey, rememberMeUserDetailsService, rememberMeTokenRepository);
services.setAlwaysRemember(true);
return services;
}
#Bean
public LdapContextSource getLdapContext() {
LdapContextSource source = new LdapContextSource();
source.setUserDn("user#"+DOMAIN);
source.setPassword("password");
source.setUrl(URL);
return source;
}
This will get you remember me functionality which works with LDAP and provides the loaded data inside RememberMeAuthenticationToken which will be available in the SecurityContextHolder.getContext().getAuthentication(). It will also be able to re-use your existing logic for parsing of LDAP data into an User object (CustomUserDetailsServiceImpl).
As a separate subject, there's also one problem with the code posted in the question, you should replace the:
authManagerBuilder
.authenticationProvider(activeDirectoryLdapAuthenticationProvider())
.userDetailsService(userDetailsService())
;
with:
authManagerBuilder
.authenticationProvider(activeDirectoryLdapAuthenticationProvider())
;
The call to userDetailsService should only be made in order to add DAO-based authentication (e.g. against database) and should be called with a real implementation of the user details service. Your current configuration can lead to infinite loops.
It sounds like you are missing an instance of UserService that your RememberMeService needs a reference to. Since you are using LDAP, you'd need an LDAP version of UserService. I'm only familiar with JDBC/JPA implementations, but looks like org.springframework.security.ldap.userdetails.LdapUserDetailsManager is what you are looking for. Then your config would look something like this:
#Bean
public UserDetailsService getUserDetailsService() {
return new LdapUserDetailsManager(); // TODO give it whatever constructor params it needs
}
#Bean
public RememberMeServices rememberMeServices() {
TokenBasedRememberMeServices rememberMeServices = new TokenBasedRememberMeServices("password", getUserDetailsService());
rememberMeServices.setCookieName("cookieName");
rememberMeServices.setParameter("rememberMe");
return rememberMeServices;
}

Spring Secuiry Database Authentication casting Spring User to Domain User

I've been having some trouble figuring this one out.
I've got an multitenant system where users are organized into organizations. Within that organization the usernames must be unique. Otherwise, two organizations can have the same user name.
I've got spring security hooked up with the jdbc-user-service and all that works fine. My problems start when I'm trying to get the current user.
I took a look at a link that leverages spring 3 and the Principal object as a method parameter. This works great, except a Principal doesn't have enough information! First, usernames aren't unique in my usecase, also having easy access to the organization that the user belongs to would be great.
A little more searching dug up this awesome answer. The problem with this is the same problem as before. It relies on the Principal object, which just doesn't have enough info.
(here's the magic)
#Override
public Object resolveArgument(MethodParameter methodParameter,
ModelAndViewContainer mavContainer,
NativeWebRequest webRequest,
WebDataBinderFactory binderFactory) throws Exception {
if (this.supportsParameter(methodParameter)) {
Principal principal = webRequest.getUserPrincipal();
return (User) ((Authentication) principal).getPrincipal();
} else {
return WebArgumentResolver.UNRESOLVED;
}
}
Is there a good way to override the User object to use my own? Am i stuck writing a custom UserDetailService? Is there a better approach than continuing to walk down this path?
Thanks
Make your User object inherit UserDetails(or use a wrapper) and use it as principal.
e.g.
public class MyCustomUser implements UserDetails {
// ..
}
Make a custom UserDetailsService that returns your User object:
#Service
public class MyCustomUserDetailsServiceImpl implements UserDetailsService {
#Autowired
private MyCustomUserDAO userDAO;
#Override
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
return userDAO.getByUsername(username);
}
}
Now you can extract your user:
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
Object principal = auth.getPrincipal();
MyCustomUser user = (MyCustomUser)principal;
user.myCustomMethod();

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