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some questions about java Scanner

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}
Why does the code on line 6 have the same effect on line 8? Is there no distinction between the starting point of this while loop?

Also, you should follow this tips to use the Scanner properly:
Mixing any nextXXX method with nextLine from the Scanner class for user input, will not ask you for input again but instead result in an empty line read by nextLine.
To prevent this, when reading user input, always only use nextLine. If you need an int, do
int value = Integer.parseInt(scanner.nextLine());
instead of using nextInt.
Assume the following:
Scanner sc = new Scanner(System.in);
System.out.println("Enter your age:");
int age = sc.nextInt();
System.out.println("Enter your name:");
String name = sc.nextLine();
System.out.println("Hello " + name + ", you are " + age + " years old");
When executing this code, you will be asked to enter an age, suppose you enter 20.
However, the code will not ask you to actually input a name and the output will be:
Hello , you are 20 years old.
The reason why is that when you hit the enter button, your actual input is
20\n
and not just 20. A call to nextInt will now consume the 20 and leave the newline symbol \n in the internal input buffer of System.in. The call to nextLine will now not lead to a new input, since there is still unread input left in System.in. So it will read the \n, leading to an empty input.
So every user input is not only a number, but a full line. As such, it makes much more sense to also use nextLine(), even if reading just an age. The corrected code which works as intended is:
Scanner sc = new Scanner(System.in);
System.out.println("Enter your age:");
// Now nextLine, not nextInt anymore
int age = Integer.parseInt(sc.nextLine());
System.out.println("Enter your name:");
String name = sc.nextLine();
System.out.println("Hello " + name + ", you are " + age + " years old");
The nextXXX methods, such as nextInt can be useful when reading multi-input from a single line. For example when you enter 20 John in a single line.

Strange output when I read from scanner

I'm trying to create a videoStore with the basic CRUD operation. For creating each movie I need to read the title, the year and the gender as below:
System.out.print("name: ");
name = in.nextLine();
System.out.print("year: ");
year = in.nextInt();
in.nextLine();
System.out.print("gender: ");
gender = in.next();
When I enter the addMovie option, I get this print on the console
(name: year:)
Can someone explain to me why it happens as above?
Here is the rest of the method:
static ArrayList<Movie> movies = new ArrayList<Movie>();
static Scanner in = new Scanner(System.in);
public static void InserirFilme() {
String name;
int year;
String gender;
boolean existe = false;
System.out.print("name: ");
name = in.nextLine();
System.out.print("year: ");
year = in.nextInt();
in.nextLine();
System.out.print("gender: ");
gender = in.next();
Movie movie = new Movie(name, year, gender);
for(Movie m: movies)
{
if(movie == m)
{
existe = true;
}
}
if(!existe)
{
movies.add(movie);
}
else
{
System.out.println("the movie already exists in the videoStore");
}
}

Calling next does not remove the line break, which means the next time you call InserirFilme the call to read the name can complete immediately. Use nextLine.
System.out.print("gender: ");
gender = in.nextLine();
(You probably mean "genre" instead of "gender" though)
Also, as mentioned in the comments, this check will never succeed:
if(movie == f)

You run this method in loop (right?)
The first call reads input correctly, but it leaves the linebreak in System.in after the last in.next().
On next call the name: is printed, then scanner reads an empty string from System.in because the linebreak already exists here.
And after thet the year: is printed on the same line because no new linebreaks are entered.
So you just have to insert another in.nextLine() after reading gender (or genre :) )
Or use nextLine() for read genre instead of next(), because genre might have more than one word.
But there are some disadvantages with using fake nextLine() to 'eat' linebreak - there might be another text which you doesn't process. It's a bad practice - to loose the data user entered.
It is better to read all the data from line, then validate/parse it, check isn't there some extra data, and if the data is invalid show notification and let him try to enter the right value.
Here are some examples how to deal with user input manually - https://stackoverflow.com/a/3059367/1916536. This is helpful to teach yourself.
Try to generalize user input operations:
name = validatedReader.readPhrase("name: ");
year = validatedReader.readNumber("year: ");
genre = validatedReader.readWord("genre: ");
where ValidatedReader is a custom wrapper for Scanner which could use your own validation rules, and could gently re-ask user after a wrong input.
It could also validate dates, phone numbers, emails, url's or so
For production purposes, it is better to use validation frameworks with configurable validation rules. There are a lot of validation frameworks for different purposes - Web, UI, REST etc...

when i enter the addMovie option, i get this print on the console (name: year:) can someone explain me why it happens i already searched a lot and i cant understand why :S
The way i understood your question is that you are getting the output (name: year: ) in a line and want it in seperate lines? In that case you simply can use System.out.println(String); instead of System.out.print(String). On the other hand you can also use "\n" whenever you want a linebreak within a String. Hope i could help you :).
Edit: If this was not an answer to your question, feel free to tell me and clarify your question :)

For String name you are using in.nextLine(); i.e the data entered on the entire line will be added to name string.
After "name: " is displayed, enter some text and press enter key, so that the year and gender fields will get correct values.
The code written is correct but you are not giving appropriate input through the scanner.
I recommend to use
String name = in.next();//instead of String name = in.nextLine();

You may instantiate Scanner Class differently for String and Integer type input. It works for me :)
Example:
static Scanner in1 = new Scanner(System.in);
static Scanner in2 = new Scanner(System.in);
Please use nextLine() for 'name' and 'gender'. It may contain more than one word. Let me know if it works.
Example:
System.out.print("name: ");
name = in1.nextLine();
System.out.print("year: ");
year = in2.nextInt();
System.out.print("gender: ");
gender = in1.nextLine();

scanner.nextLine() not working like I think it does

I am creating a random name generator for a fantasy table top game I play with my friends. Everything is working so for, except for when I go to scan a nextLine() for my description, the program doesn't wait for input, and instead goes back to the start of the while loop. What I want to do, is be able to type in a short sentence about the character they are interacting with, and have it set to the String value Description, later my goal is to print these values out in a text document as I create them for future use. My code for that section looks like as follows. Any help is greatly appreciated.
System.out.println("Male (m) Female (f) Quit (q)");
ui = UserInput.next();
while(!(ui.equals("q"))){
if(ui.equals("m")){
mName = maleNameGenerator(MS, SS, MaleNamesArray, SurnamesArray);
System.out.println(mName);
System.out.print("Location: ");
Location = UserInput.next();
System.out.print("Profession: ");
Profession = UserInput.next();
System.out.print("Description: ");
Description = UserInput.nextLine();
}
else if(ui.equals("f")){
fName = femaleNameGenerator(FS, SS, FemaleNamesArray, SurnamesArray);
System.out.println(fName);
}
else if(!(ui.equals("q"))){
System.out.println("Please input valid choice.");
}
System.out.println("Male (m) Female (f) Quit (q)");
ui = UserInput.next();
ui.toLowerCase();
}
UserInput.close();

The next() method leaves behind a newline character after taking input. In your code, the nextLine() method simply consumes this newline character and ignores the actual input. You can add another nextLine() to make sure the input is received.
...
System.out.print("Description: ");
UserInput.nextLine();
Description = UserInput.nextLine();
This problem can also occur when using other non-String type Scanner input methods (nextInt(), nextDouble(), etc). The explanation and solution would be the same.

InputMismatchException with Scanner

I have the following Java code:
Scanner input = new Scanner(System.in);
try {
System.out.println("Enter your name>>");
String name = input.next();
System.out.println("Enter your year of birth>>");
int age = input.nextInt();
System.out.println("Name: " + name);
System.out.println("Year of Birth: " + age);
System.out.println("Age: " + (2012 - age));
} catch (InputMismatchException err) {
System.out.println("Not a number");
}
When I enter a name with a space (e.g. "James Peterson"), I get the next line output correctly (Enter your year of birth) and then an InputMismatchException immediately. The code works with a single name without spaces. Is there something I'm missing?

System.out.println("Enter your name>>");
String name = input.next();
System.out.println("Enter your year of birth>>");
int age = input.nextInt();
Scanner, breaks its input into tokens using a delimiter pattern, which by default matches whitespace.
When you enter "James Peterson", Scanner#next() takes "James" as a token and assigns it to String name and then you do a Scanner#nextInt() which takes "Peterson" as the next token, but it is not something which can be cast to int and hence the InputMismatchException asnextInt() will throw an InputMismatchException if the next token does not match the Integer regular expression, or is out of range.

Actually the problem in your code has been clearly pointed out. In your case, there are two typical ways to achieve that:
One
Using useDelimiter method to delimite the input and after each input, you need to hit the Enter.
Sets this scanner's delimiting pattern to a pattern constructed from the specified String.
In your case, you need to
Scanner sc = new Scanner(System.in);
sc.setDelimiter("\\n");
// hit the "Enter" after each input for the field;
Two
Also you can achieve the same result using readLine
Advances this scanner past the current line and returns the input that was skipped. This method returns the rest of the current line, excluding any line separator at the end. The position is set to the beginning of the next line.
In this way, you can do
Scanner sc = new Scanner(System.in);
System.out.println("Enter your name>>");
String name = sc.nextLine();
...
System.out.println("Enter your year of birth>>");
int age = sc.nextInt();
P.S.
Actually you can achieve it in a more restrictive way, controlling the pattern using next(Pattern pattern), if you need it.
int age = sc.next(Pattern.compile("\\d+{1,3}"));
In this case, if the input DOES NOT match the pattern, it will throw InputMismatchException as you were trying to nextInt while the input is a string.
When I enter a name with a space (e.g. "James Peterson"), I get the next line output correctly (Enter your year of birth>>) and then an InputMismatchException immediately.

Getting accurate int and String input

I am having trouble reading in strings from the user after reading in an int. Essentially I have to get an int from the user and then several strings. I can successfully get the user's int. However, when I begin asking for strings (author, subject, etc...), my scanner "skips" over the first string input.
For example, my output looks like this:
Enter your choice:
2
Enter author:
Enter subject:
subject
As you can see, the user is never able to enter the author, and my scanner stores null into the author string.
Here is the code that produces the above output:
String author;
String subject;
int choice;
Scanner input = new Scanner(System.in);
System.out.println("Enter choice:");
choice = input.nextInt();
System.out.println("Enter author:");
author = input.nextLine();
System.out.println("Enter subject:");
subject = input.nextLine();
Any help would be greatly appreciated. Thank you!
-Preston Donovan

The problem is that when you use readLine it reads from the last read token to the end of the current line containing that token. It does not automatically move to the next line and then read the entire line.
Either use readLine consistently and parse the strings to integers where appropriate, or add an extra call to readLine:
System.out.println("Enter choice:");
choice = input.nextInt();
input.nextLine(); // Discard the rest of the line.
System.out.println("Enter author:");
author = input.nextLine();

This works perfectly.
Although while making previous programs like the one below it was not required. Can anyone explain this?
import java.util.Scanner;
public class Average Marks {
public static void main(String[] args) {
Scanner s = new Scanner ( System.in);
System.out.print("Enter your name: ");
String name=s.next();
System.out.print("Enter marks in three subjects: ");
int marks1=s.nextInt();
int marks2=s.nextInt();
int marks3=s.nextInt();
double average = ( marks1+marks2+marks3)/3.0;
System.out.println("\nName: "+name);
System.out.println("Average: "+average);