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Hangman game: How to find the word?

I have to create a hangman game. I am stuck in the last step. In fact, when the user finds the word my input asks yet a letter.
Here an example: (the word to find is "non")
Enter your letter please : n
n _ n
Enter your letter please : o
n o n
Enter your letter please :
n o n
My problem is probably my wordFind, I don't understand how to manipulate this ?
String[] words = {"yess", "non"};
String wordRandom = words[(int) (Math.random() * words.length)];
boolean[] letterGuess = new boolean [wordRandom.length()];
boolean wordFind = false;
int numberAttempt = 5;
while(numberAttempt > 0 && !wordFind){
System.out.println("Number of attempt(s) " + numberAttempt);
for(int i=0; i < wordRandom.length(); i++){
if(letterGuess[i]){
System.out.print(wordRandom.charAt(i));
}
else{
System.out.print("- ");
}
}
System.out.println(" ");
System.out.print("Enter your letter please : ");
char letter = input.next().charAt(0);
int letterFound = 0;
boolean alreadyFound = false;
for(int i=0; i < wordRandom.length(); i++){
if(wordRandom.charAt(i) == letter){
if(letterGuess[i]){
alreadyFound = true;
}
letterGuess[i] = true;
letterFound++;
}
}
if(alreadyFound){
System.out.println("Letter already proposed and it has been found ! ");
} else{
if(letterFound == 1){
System.out.println("The letter is correct ! ");
}
else if(letterFound > 0){
System.out.println("The letter is " + letterFound + " times in the word ! ");
}
else{
numberAttempt--;
System.out.println("The letter is not in the word ! ");
}
}
}

You need to add a solved condition like this
boolean wordFind = false;
int numberAttempt = 5;
boolean solved = false;
while(numberAttempt > 0 && !wordFind && !solved){
after you update letterFound, set solved
letterFound++;
if (letterfound == wordRandom.length()) {
solved = true
}
Then at the end after the while loop, if solved is true, congratulate the user.

You can create a variable int amountCorrect = 0; and use that as a check. Every time the user gets a right letter, add to amountCorrect the number of letters there are. At the beginning of the while loop, create a boolean check that checks if the amountCorrect variable is the same as the length of the wordRandom. I know your code is kind of long, so I put a comment next to the lines where I added code:
String[] words = { "yess", "non" };
String wordRandom = words[(int) (Math.random() * words.length)];
boolean[] letterGuess = new boolean[wordRandom.length()];
boolean wordFind = false;
int numberAttempt = 5;
int amountCorrect = 0; // The amountCorrect variable
while (numberAttempt > 0 && !wordFind) {
System.out.println("Number of attempt(s) " + numberAttempt);
// This is the boolean check
if (amountCorrect == wordRandom.length()) {
System.out.println("You Win!");
break;
}
for (int i = 0; i < wordRandom.length(); i++) {
if (letterGuess[i]) {
System.out.print(wordRandom.charAt(i));
} else {
System.out.print("- ");
}
}
System.out.println(" ");
System.out.print("Enter your letter please : ");
char letter = input.next().charAt(0);
int letterFound = 0;
boolean alreadyFound = false;
for (int i = 0; i < wordRandom.length(); i++) {
if (wordRandom.charAt(i) == letter) {
if (letterGuess[i]) {
alreadyFound = true;
}
letterGuess[i] = true;
letterFound++;
// add to amountCorrect
amountCorrect++;
}
}
if (alreadyFound) {
System.out.println("Letter already proposed and it has been found ! ");
} else {
if (letterFound == 1) {
System.out.println("The letter is correct ! ");
}
else if (letterFound > 0) {
System.out.println("The letter is " + letterFound + " times in the word ! ");
}
else {
numberAttempt--;
System.out.println("The letter is not in the word ! ");
}
}
}

Stuck in logic for movie guess game in java (by udacity)

I am making a movie guessing game(much like hangman but doesn't contain the stick figure and stuff) on Java that takes input from the user, letter by letter. I am stuck where I want the letter entered to replace all instances of that letter in the title of the movie. My code is not working completely.
Later, I am gonna apply the logic that stops the user from entering the same letter again. But at the moment I need to fix this particular issue. Any help?
This is the game process function in my game class.
public void GameProcess(char[] dashedarray) {
Scanner input = new Scanner(System.in);
char guess;
int i = 0;
int spaces = 0;
int correct = 0;
int wrong = 0;
boolean run = true;
while (run) {
if (dashedarray[i] == ' ') {
spaces++;
i++;
continue;
} else {
System.out.println("Enter your guess.");
guess = input.next().charAt(0);
for (int j = 0; j < dashedarray.length; j++) {
if (dashedarray[j] != ' ') {
if (moviename.charAt(i) == guess) {
dashedarray[i] = guess;
correct++;
}
else if(moviename.charAt(j) == guess) {
dashedarray[j] = guess;
correct++;
}
}
else
{
wrong++;
}
}
i++;
PrintArray(dashedarray);
if (correct == (moviename.length() - spaces)) {
System.out.println("You have won.");
break;
} else if (wrong == 10) {
System.out.println("You have lost.");
break;
}
System.out.println("The number of wrong guesses is " + wrong + ".");
}
}

You don't need i at all. spaces is to count the number of spaces in your answer, which does not need to be guessed. You should do that outside of the loop.
Scanner input = new Scanner(System.in);
char guess;
int i = 0;
int spaces = 0;
int correct = 0;
int wrong = 0;
boolean run = true;
for (int i = 0; i < dashedarray.length; i++) {
spaces++;
}
while (run) {
System.out.println("Enter your guess.");
guess = input.next().charAt(0);
boolean match = false;
for (int j = 0; j < dashedarray.length; j++) {
if (dashedarray[j] != ' ') {
if(moviename.charAt(j) == guess) {
dashedarray[j] = guess;
correct++;
match = true;
}
}
}
// It matched nothing, this input is wrong.
if (!match) {
wrong++;
}
PrintArray(dashedarray);
if (correct == (moviename.length() - spaces)) {
System.out.println("You have won.");
break;
} else if (wrong == 10) {
System.out.println("You have lost.");
break;
}
System.out.println("The number of wrong guesses is " + wrong + ".");
}

Java battleship program not printing board correctly

I am having a problem with my java battleship program not printing the coordinates that the user enters. When the user guesses a spot on the board its supposed to update the space with an "X" if its a hit, if not then the board remains the same. But when a user guesses wrong on my program, it prints everything except the space where the user guessed. I believe that my else statement where the board updates is the problem, but any modification I did resulted in the board not printing anything.
import java.util.Random;
import java.util.Scanner;
class Battleship {
public static char randChar(){
final String alphabet = "ABCDE";
final int N = alphabet.length();
char rand;
Random r = new Random();
rand = alphabet.charAt(r.nextInt(N));
return rand;
}
public static void main (String[] args) throws java.lang.Exception {
char[] letters = {' ', 'A', 'B', 'C', 'D', 'E'};
int[] numbers ={1, 2, 3, 4, 5};
int[][] ships = new int[7][2];
char colGuess;
int rowGuess;
Boolean boardFlag=false;
Scanner scan = new Scanner(System.in);
//creates the board
for (int i = 0 ; i <= 5 ; i++) {
for (int j = 0 ; j <= 5 ; j++) {
if (i == 0) {
System.out.print(letters[j] + " ");
}
else if (j == 0) {
System.out.print(numbers[i - 1]);
}
else {
System.out.print(letters[j] + "" + numbers[i-1]);
}
System.out.print(" ");
}
System.out.println();
}
//assigns ships to random spots
assignShips(ships);
System.out.println("Enter your guess for the column:");
colGuess = scan.next().charAt(0);
//converts to uppercase
colGuess = Character.toUpperCase(colGuess);
System.out.println("Enter your guess for the row:");
rowGuess = scan.nextInt();
//shows player what they entered
System.out.println("you entered: " + (char) colGuess + rowGuess);
//calls method to check for a hit
fire(colGuess, rowGuess, ships);
boardFlag = fire(colGuess, rowGuess, ships);
System.out.println(boardFlag);
//updates the board
for (int i = 0 ; i <= 5 ; i++) {
for (int j = 0 ; j <= 5 ; j++) {
if (i == 0) {
System.out.print(letters[j] + " ");
}
else if (j == 0) {
System.out.print(numbers[i - 1]);
}
else {
if(letters[j] == colGuess && numbers[i - 1] == rowGuess) {
if(boardFlag==true) {
System.out.print(" " + "X");
}
}
else {
System.out.print(letters[j] + "" + numbers[i - 1]);
}
}
System.out.print(" ");
}
System.out.println();
}
}
public static void assignShips(int[][] ships) {
Random random = new Random();
for(int ship = 0; ship < 7; ship++) {
ships[ship][0] = randChar();
ships[ship][1] = random.nextInt(5);
//gives location of ships, for testing purposes
System.out.print("Ship:" + (ship+1)+ " is located at"+(char)ships[ship][0]+ships[ship][1]+"\n");
}
}
//checks user input to see if we have a hit
public static Boolean fire(char colGuess, int rowGuess, int[][] ships) {
Boolean hitFlag=false;
for(int ship = 0; ship < ships.length; ship++){
if(colGuess ==ships[ship][0] && rowGuess == ships[ship][1]){
hitFlag=true;
}
}
if(hitFlag == true) {
System.out.println("we hit em at "+(char)colGuess+rowGuess+" chief!");
}
else {
System.out.println("sorry chief we missed em");
}
return hitFlag;
}
}

The reason its not showing up when you miss is because your net telling it to print anything.
if(letters[j] == colGuess && numbers[i-1] == rowGuess){
if(boardFlag==true) {
System.out.print(" "+"X");
}
}
Your only handling the coordinate the user input if they hit. To fix this you would need an else statement after your if(boardFlag == true)to handle printing if you miss.

The problem is in your update board portion of the code because you don't do anything if the guessed location isn't a hit.
if(letters[j]==colGuess && numbers[i-1]==rowGuess && boardFlag) {
System.out.print(" "+"X");
} else {
System.out.print(letters[j]+""+numbers[i-1]);
}
Full Update Portion:
//updates the board
for (int i = 0 ; i <= 5 ; i++){
for (int j = 0 ; j <= 5 ; j++){
if (i == 0) {
System.out.print(letters[j]+" ");
} else if (j == 0){
System.out.print(numbers[i-1] );
} else {
if(letters[j]==colGuess && numbers[i-1]==rowGuess && boardFlag){
System.out.print(" "+"X");
} else {
System.out.print(letters[j]+""+numbers[i-1]);
}
}
System.out.print(" ");
}
System.out.println();
}

This block (old version):
if(hitFlag==true){
System.out.println("we hit em at "+(char)colGuess+rowGuess+" chief!");
} else {
System.out.println("sorry chief we missed em");
}
Should be (new version):
if(hitFlag==true){
System.out.println("we hit em at "+(char)colGuess+rowGuess+" chief!");
} else {
System.out.println("sorry chief we missed em at " + (char)colGuess+rowGuess);
}
this will print:
sorry chief we missed em at D3 //D3 is a random possible set of coordinates
Rather than:
sorry chief we missed em //Old version
So all you have to add is (char)colGuess+rowGuess, which prints the coordinates of your previous guess.
Comment if you have any questions!

How to store user input for continued use?

How can I repeat this program but keep the user input when it is displayed to them a second time or the third time etc. The program asks them where they want to sit, then the display shows them an X in place of where they said. I want the X to stay for the next time it asks for their input until the user decides to quit the program by choosing "2".
import java.util.Scanner;
import java.util.Arrays;
class AirplaneSeating {
static Scanner inNum = new Scanner(System.in);
static Scanner inStr = new Scanner(System.in);
static void option() {
String[][] seatingChart = new String[10][4];
int rows = 10;
int columns = 4;
seatingChart = new String[rows][columns];
for(int i = 0; i < rows; i++) {
for(int j = 0; j < columns; j++) {
seatingChart[i][j] = "" + ((char)('A' + i)) + ((char)('1' + j));
}
}
for(int i = 0; i < rows ; i++) {
for(int j = 0; j < columns ; j++) {
System.out.print(seatingChart[i][j] + " ");
}
System.out.println("");
}
System.out.println("What seat would you like to reserve? ");
String str = inStr.nextLine();
System.out.println("You chose: " + str);
for(int i = 0; i < rows ; i++) {
for(int j = 0; j < columns ; j++) {
if(seatingChart[i][j].equals(str)) {
System.out.print("X" + " ");
} else {
System.out.print(seatingChart[i][j] + " ");
}
}
System.out.println("");
}
}
public static void main(String[] args) {
int choice;
do {
System.out.println("Choose from one of the following options:");
System.out.println("\tl. Choose a seat to reserve: ");
System.out.println("\t2. Quit");
System.out.print("Enter 1 or 2: ");
choice = inNum.nextInt();
switch(choice) {
case 1:
option();
break;
case 2:
System.out.println("\nGoodbye!");
break;
default:
System.out.println(choice + " is not an option. Please choose 1, 2, 3, 4, or 5.");
}
}while(choice !=2);
}
}

Use BufferedReaders,BufferedWriters and a .txt file. They're pretty simple to use and allow you to save something in a text document which can later be accessed to reload previous information.

Checking for user input to be only integers in Java

I'm doing lottery game for my assignment (user inputs 6 number, i will generate 8 unique winning numbers and 2 last numbers are supplementary). I need help with user input checking if input numbers are from 1 to 45 and input must be int, when input is not integer it throws an error.
This programming way is procedure way, how can i change it into object oriented way? I know that I must make methods in another java file and then link it back to this main. Can you suggest me how to do it?
I have tried try and catch, if and else (for input check) but i don't know how to check user input when it's in array. Thank you for help.
Here is my code:
class Lottery {
public static void main ( String[] args ) {
System.out.println("\nWelcome to the Lottery game.");
System.out.println("You can enter numbers from 1 to 45.");
// User input into an array
int[] input = new int[6];
Scanner scanner = new Scanner(System.in);
System.out.println("\nPlease enter your 6 lucky numbers: ");
for(int j = 0; j < 6; j++) {
input[j]=scanner.nextInt();
}
int check = scanner.nextInt();
if(check < 0 && check > 45) {
System.out.println("\nERROR: Please enter only numbers from 1 to 45!");
}
// Printing out unique winning numbers from random generator
System.out.println("\nWinning numbers: ");
MultiRandomGenerator mrg = new MultiRandomGenerator();
int[] set;
set = mrg.getSet();
for (int i = 0; i < set.length; i++) {
System.out.print(set[i] + " ");
}
// Loops for counting how many numbers user has guessed right
int count = 0; // for 6 numbers
int scount = 0; // for 2 last supplementary numbers
for(int i = 0; i < input.length; i++) {
for(int k = 0; k < set.length; k++) {
if (k < 6) {
if (set[k] == input[i]) {
count++;
} else {
if (set[k] == input[i]) {
scount++;
}
}
}
}
}
System.out.print("\n\nYou guessed right " + count + " winning numbers.");
System.out.print("\nYou guessed right " + scount + " suplementary numbers.");
// If statments for printing out winning prizes
if (count == 6) {
System.out.println("\nYou have won 1st price!");
} if (count == 5 && scount == 1) {
System.out.println("\nYou have won 2st price!");
} if (count == 5) {
System.out.println("\nYou have won 3st price!");
} if (count == 4) {
System.out.println("\nYou have won 4st price!");
} if (count == 3 && scount == 1) {
System.out.println("\nYou have won 5st price!");
} if (count == 1 && scount == 2) {
System.out.println("\nYou have won 6st price!");
} else {
System.out.println("\nSorry, you didn't won anything.");
}
}
}

Sample code to go through array and find the invalid user input.
set = mrg.getSet();
String[] userDataStatus = new String[45];
for (int i = 0; i < set.length; i++)
{
try
{
String inputdata = set.get(i);
if(inputdata != null && inputdata.trim().length() > 0)
{
int currentNumber = Integer.parseInt(userdata);
userDataStatus[i] = "Y";//Y represent valid number
}
}
catch (NumberFormatException ex )
{
userDataStatus[i] = "N";//If it throws exception then save as 'N'
}
}
Use the above String array and display error messaage to users.

You can check in your loop, something like
int val;
try
{
input[j] = Integer.parseInt( scanner.nextString() );
}
catch (NumberFormatException ex )
{
}