How correctly detect device is tablet or phone - java

I can detect device type from attrs resources:
<bool name="isTablet">false</bool>
// xlarge and sw600dp = tablet
// normal = phone
if(getResources().getBoolean(R.bool.isTablet)) {
// is tablet
}
But some smaller tablets are detected as phones.

I think you can use TelephonyManager class.
TelephonyManager manager = (TelephonyManager)getApplicationContext().getSystemService(Context.TELEPHONY_SERVICE);
if (Objects.requireNonNull(manager).getPhoneType() == TelephonyManager.PHONE_TYPE_NONE){
//Tablet
}
else{
//Mobile Device
}

Related

How to get IMEI in Android Version 10 or 11? [duplicate]

I am getting the IMEI ID null from the telephonymanager. What to do?
is there any workaround for that?
Android Q has restricted to access for both IMEI and serial no. It is available only for platform and apps with special carrier permission. Also the permission READ_PRIVILEGED_PHONE_STATE is not available for non platform apps.
If you try to access it throws below exception
java.lang.SecurityException: getImeiForSlot: The user 10180 does not meet the requirements to access device identifiers.
Please refer documentation:
https://developer.android.com/preview/privacy/data-identifiers#device-ids
Also refer Issue
I am late to post answer. I still believe my answer will help someone.
Android 10 Restricted developer to Access IMEI number.
You can have a alternate solution by get Software ID. You can use software id as a unique id. Please find below code as i use in Application.
public static String getDeviceId(Context context) {
String deviceId;
if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null) {
deviceId = mTelephony.getDeviceId();
} else {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
}
}
return deviceId;
}
This just would not work as of Android Q. Third party apps can not use IMEI nor the serial number of a phone and other non-resettable device identifiers.
The only permissions that are able to use those is READ_PRIVILEGED_PHONE_STATE and that cannot be used by any third party apps - Manufacture and Software Applications. If you use that method you will get an error Security exception or get null .
You can still try to get a unique id by using:
import android.provider.Settings.Secure;
private String android_id = Secure.getString(getContext().getContentResolver(),Secure.ANDROID_ID);
The best way to get the IMEI number is as follows:
public static String getIMEIDeviceId(Context context) {
String deviceId;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q)
{
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (context.checkSelfPermission(Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return "";
}
}
assert mTelephony != null;
if (mTelephony.getDeviceId() != null)
{
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O)
{
deviceId = mTelephony.getImei();
}else {
deviceId = mTelephony.getDeviceId();
}
} else {
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
Log.d("deviceId", deviceId);
return deviceId;
}
Just copy the method and use it. It will definitely. However, you might know you can't get IMEI in android Q (version 10). In this code, you can get a unique identifier (alternative id) through any device or any API level.
It works 100%
Thank You!!
And Enjoy Coding :)
As the best practices suggest. " you can avoid using hardware identifiers, such as SSAID (Android ID) and IMEI, without limiting required functionality."
Rather go for an instance ID such as String uniqueID = UUID.randomUUID().toString(); or FirebaseInstanceId.getInstance().getId();
Not sure about IMEI number, but you can get the simSerialNumber and other carrier info this way.
getSimSerialNumber() needs privileged permissions from Android 10 onwards, and third party apps can't register this permission.
See : https://developer.android.com/about/versions/10/privacy/changes#non-resettable-device-ids
A possible solution is to use the TELEPHONY_SUBSCRIPTION_SERVICE from Android 5.1, to retrieve the sim serial number. Steps below:
Check for READ_PHONE_STATE permission.
Get Active subscription list.( Returns the list of all active sim cards)
Retrieve the sim details from Subscription Object.
if ( isPermissionGranted(READ_PHONE_STATE) ) {
String simSerialNo="";
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP_MR1) {
SubscriptionManager subsManager = (SubscriptionManager) context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE);
List<SubscriptionInfo> subsList = subsManager.getActiveSubscriptionInfoList();
if (subsList!=null) {
for (SubscriptionInfo subsInfo : subsList) {
if (subsInfo != null) {
simSerialNo = subsInfo.getIccId();
}
}
}
} else {
TelephonyManager tMgr = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
simSerialNo = tMgr.getSimSerialNumber();
}
}
Check if this helps
you can change other way, i use uuid to replace devices id.
String uniquePseudoID = "35" +
Build.BOARD.length() % 10 +
Build.BRAND.length() % 10 +
Build.DEVICE.length() % 10 +
Build.DISPLAY.length() % 10 +
Build.HOST.length() % 10 +
Build.ID.length() % 10 +
Build.MANUFACTURER.length() % 10 +
Build.MODEL.length() % 10 +
Build.PRODUCT.length() % 10 +
Build.TAGS.length() % 10 +
Build.TYPE.length() % 10 +
Build.USER.length() % 10;
String serial = Build.getRadioVersion();
String uuid = new UUID(uniquePseudoID.hashCode(), serial.hashCode()).toString();
AppLog.d("Device ID",uuid);
If your app targets Android 10 or higher, a SecurityException occurs.
Following modules are affected...
Build
getSerial()
TelephonyManager
getImei()
getDeviceId()
getMeid()
getSimSerialNumber()
getSubscriberId()
So you cant get IMEI no for android 10 , You have to used another unique identifier for this like Android ID
It unique 64 bit hex no for device
private String android_id = Secure.getString(getContext().getContentResolver(),
Secure.ANDROID_ID);
According to google docs.
Restriction on non-resettable device identifiers
Starting in Android 10, apps must have the READ_PRIVILEGED_PHONE_STATE privileged permission in order to access the device's non-resettable identifiers, which include both IMEI and serial number.
Caution: Third-party apps installed from the Google Play Store cannot
declare privileged permissions.
So, Instead of imei you can get Android unique ID.
String imei = "";
TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
if (checkSelfPermission(Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
try {
imei = telephonyManager.getImei();
} catch (Exception e) {
e.printStackTrace();
imei = Settings.Secure.getString(this.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
} else {
if (ActivityCompat.checkSelfPermission(MainActivity.this, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
imei = telephonyManager.getDeviceId();
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
}
Targeting Android Q, third party apps can't access IMEI at all. Android Q doc is misleading while stating
Starting in Android Q, apps must have the READ_PRIVILEGED_PHONE_STATE
privileged permission in order to access the device's non-resettable
identifiers, which include both IMEI and serial number.
https://developer.android.com/preview/privacy/data-identifiers#device-ids
But when I actually tried to implement it, I am receiving this exception:
java.lang.SecurityException: getDeviceId: The user 10132 does not meet the requirements to access device identifiers.
Someone had reported this on google's issue tracker where a Googler said that this is intended behaviour and IMEI on Q+ is only available for system level apps.
Status: Won't Fix (Intended Behavior) This is Working As Intended.
IMEI is a personal identifier and this is not given out to apps as a
matter of policy. There is no workaround.
https://issuetracker.google.com/issues/129583175#comment10
They mentioned:
If your app is the device or profile owner app, you need only the READ_PHONE_STATE permission to access non-resettable device identifiers, even if your app targets Android 10 or higher.
I tried deploying via EMM as device owner app but not success.
If you needed, you can try to install a work profile in to the mobile phone and include your app in the same package or vice versa.
I tried and it works, it's simple if yo follow this repo: https://github.com/googlesamples/android-testdpc
When you install the Work Profile your app is installed in this profile and you will have acces to the IMEI.
And now there is another example fixed yesterday to Android 10:
https://github.com/android/enterprise-samples/pull/29

How to get device id or IMEI programmatically in android Q? [duplicate]

I am getting the IMEI ID null from the telephonymanager. What to do?
is there any workaround for that?
Android Q has restricted to access for both IMEI and serial no. It is available only for platform and apps with special carrier permission. Also the permission READ_PRIVILEGED_PHONE_STATE is not available for non platform apps.
If you try to access it throws below exception
java.lang.SecurityException: getImeiForSlot: The user 10180 does not meet the requirements to access device identifiers.
Please refer documentation:
https://developer.android.com/preview/privacy/data-identifiers#device-ids
Also refer Issue
I am late to post answer. I still believe my answer will help someone.
Android 10 Restricted developer to Access IMEI number.
You can have a alternate solution by get Software ID. You can use software id as a unique id. Please find below code as i use in Application.
public static String getDeviceId(Context context) {
String deviceId;
if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null) {
deviceId = mTelephony.getDeviceId();
} else {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
}
}
return deviceId;
}
This just would not work as of Android Q. Third party apps can not use IMEI nor the serial number of a phone and other non-resettable device identifiers.
The only permissions that are able to use those is READ_PRIVILEGED_PHONE_STATE and that cannot be used by any third party apps - Manufacture and Software Applications. If you use that method you will get an error Security exception or get null .
You can still try to get a unique id by using:
import android.provider.Settings.Secure;
private String android_id = Secure.getString(getContext().getContentResolver(),Secure.ANDROID_ID);
The best way to get the IMEI number is as follows:
public static String getIMEIDeviceId(Context context) {
String deviceId;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q)
{
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (context.checkSelfPermission(Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return "";
}
}
assert mTelephony != null;
if (mTelephony.getDeviceId() != null)
{
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O)
{
deviceId = mTelephony.getImei();
}else {
deviceId = mTelephony.getDeviceId();
}
} else {
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
Log.d("deviceId", deviceId);
return deviceId;
}
Just copy the method and use it. It will definitely. However, you might know you can't get IMEI in android Q (version 10). In this code, you can get a unique identifier (alternative id) through any device or any API level.
It works 100%
Thank You!!
And Enjoy Coding :)
As the best practices suggest. " you can avoid using hardware identifiers, such as SSAID (Android ID) and IMEI, without limiting required functionality."
Rather go for an instance ID such as String uniqueID = UUID.randomUUID().toString(); or FirebaseInstanceId.getInstance().getId();
Not sure about IMEI number, but you can get the simSerialNumber and other carrier info this way.
getSimSerialNumber() needs privileged permissions from Android 10 onwards, and third party apps can't register this permission.
See : https://developer.android.com/about/versions/10/privacy/changes#non-resettable-device-ids
A possible solution is to use the TELEPHONY_SUBSCRIPTION_SERVICE from Android 5.1, to retrieve the sim serial number. Steps below:
Check for READ_PHONE_STATE permission.
Get Active subscription list.( Returns the list of all active sim cards)
Retrieve the sim details from Subscription Object.
if ( isPermissionGranted(READ_PHONE_STATE) ) {
String simSerialNo="";
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP_MR1) {
SubscriptionManager subsManager = (SubscriptionManager) context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE);
List<SubscriptionInfo> subsList = subsManager.getActiveSubscriptionInfoList();
if (subsList!=null) {
for (SubscriptionInfo subsInfo : subsList) {
if (subsInfo != null) {
simSerialNo = subsInfo.getIccId();
}
}
}
} else {
TelephonyManager tMgr = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
simSerialNo = tMgr.getSimSerialNumber();
}
}
Check if this helps
you can change other way, i use uuid to replace devices id.
String uniquePseudoID = "35" +
Build.BOARD.length() % 10 +
Build.BRAND.length() % 10 +
Build.DEVICE.length() % 10 +
Build.DISPLAY.length() % 10 +
Build.HOST.length() % 10 +
Build.ID.length() % 10 +
Build.MANUFACTURER.length() % 10 +
Build.MODEL.length() % 10 +
Build.PRODUCT.length() % 10 +
Build.TAGS.length() % 10 +
Build.TYPE.length() % 10 +
Build.USER.length() % 10;
String serial = Build.getRadioVersion();
String uuid = new UUID(uniquePseudoID.hashCode(), serial.hashCode()).toString();
AppLog.d("Device ID",uuid);
If your app targets Android 10 or higher, a SecurityException occurs.
Following modules are affected...
Build
getSerial()
TelephonyManager
getImei()
getDeviceId()
getMeid()
getSimSerialNumber()
getSubscriberId()
So you cant get IMEI no for android 10 , You have to used another unique identifier for this like Android ID
It unique 64 bit hex no for device
private String android_id = Secure.getString(getContext().getContentResolver(),
Secure.ANDROID_ID);
According to google docs.
Restriction on non-resettable device identifiers
Starting in Android 10, apps must have the READ_PRIVILEGED_PHONE_STATE privileged permission in order to access the device's non-resettable identifiers, which include both IMEI and serial number.
Caution: Third-party apps installed from the Google Play Store cannot
declare privileged permissions.
So, Instead of imei you can get Android unique ID.
String imei = "";
TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
if (checkSelfPermission(Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
try {
imei = telephonyManager.getImei();
} catch (Exception e) {
e.printStackTrace();
imei = Settings.Secure.getString(this.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
} else {
if (ActivityCompat.checkSelfPermission(MainActivity.this, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
imei = telephonyManager.getDeviceId();
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
}
Targeting Android Q, third party apps can't access IMEI at all. Android Q doc is misleading while stating
Starting in Android Q, apps must have the READ_PRIVILEGED_PHONE_STATE
privileged permission in order to access the device's non-resettable
identifiers, which include both IMEI and serial number.
https://developer.android.com/preview/privacy/data-identifiers#device-ids
But when I actually tried to implement it, I am receiving this exception:
java.lang.SecurityException: getDeviceId: The user 10132 does not meet the requirements to access device identifiers.
Someone had reported this on google's issue tracker where a Googler said that this is intended behaviour and IMEI on Q+ is only available for system level apps.
Status: Won't Fix (Intended Behavior) This is Working As Intended.
IMEI is a personal identifier and this is not given out to apps as a
matter of policy. There is no workaround.
https://issuetracker.google.com/issues/129583175#comment10
They mentioned:
If your app is the device or profile owner app, you need only the READ_PHONE_STATE permission to access non-resettable device identifiers, even if your app targets Android 10 or higher.
I tried deploying via EMM as device owner app but not success.
If you needed, you can try to install a work profile in to the mobile phone and include your app in the same package or vice versa.
I tried and it works, it's simple if yo follow this repo: https://github.com/googlesamples/android-testdpc
When you install the Work Profile your app is installed in this profile and you will have acces to the IMEI.
And now there is another example fixed yesterday to Android 10:
https://github.com/android/enterprise-samples/pull/29

No IMEI for Android Developers in Android 10

As Android is serious about security and trying to make new android versions more secure, its becoming tough for developers to keep up-to date with new security features and find old methods alternatives to make their app compatible with old features.
This question is about IMEI in New Android 10!
The old method was super easy to get IMEI number by using below code
String deviceId = "";
if (Build.VERSION.SDK_INT >= 26) {
if (telMgr.getPhoneType() == TelephonyManager.PHONE_TYPE_CDMA) {
deviceId = telMgr.getMeid();
} else if (telMgr.getPhoneType() == TelephonyManager.PHONE_TYPE_GSM) {
deviceId = telMgr.getImei();
} else {
deviceId = ""; // default!!!
}
} else {
deviceId = telMgr.getDeviceId();
}
In New Android 10 it is now restricted to get IMEI number. According to android documentation
apps must have the READ_PRIVILEGED_PHONE_STATE privileged permission in order to access the device's non-resettable identifiers, which include both IMEI and serial number.
The problem is that when we try to ask run time permissions with
android.Manifest.permission.READ_PRIVILEGED_PHONE_STATE
My compiler does not recognize this permissions and i got error on this line but when i ask this permission in manifest file it does recognize this line but through warning that this permission is only for system apps.
I want to make my app compatible with Android 10 and want to get IMEI. How can i get IMEI number in Android 10 without becoming device owner or profile owner ?
Only device owner apps can read unique identifiers or your app must be a system app with READ_PRIVILEGED_PHONE_STATE. You can't ask this permission for a normal app.
Android 10 Restricted developer to Access IMEI number.
You can have a alternate solution by get Software ID. You can use software id as a unique id. Please find below code as i use in Application.
public static String getDeviceId(Context context) {
String deviceId;
if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
deviceId = Settings.Secure.getString(context.getContentResolver(),Settings.Secure.ANDROID_ID);
}else {
final TelephonyManager mTelephony = (TelephonyManager)context.getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null) {
deviceId = mTelephony.getDeviceId();
} else {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
}
}
return deviceId;
}
To get a unique identifier you can use FirebaseInstanceId.getInstance().getId(); or String uniqueID = UUID.randomUUID().toString();. Have a look here for best practices https://developer.android.com/training/articles/user-data-ids#java

Android mobile usage history NetworkStatsManager

I'm making an App for Android 6.0 and I want to use the new class NetworkStatsManager for getting mobile data usage.
I added all permission I need in manifest and require the permission runtime.
When I call the method:
bucket = networkStatsManager.querySummaryForDevice(ConnectivityManager.TYPE_WIFI, "", fromDate.getTime(), toDate.getTime());
return the right value for WIFI usage.
But if i replace TYPE_WIFI with TYPE_MOBILE the result is always 0.
NetworkStats.Bucket bucket = null;
try {
bucket = networkStatsManager.querySummaryForDevice(ConnectivityManager.TYPE_MOBILE, "", fromDate.getTime(), toDate.getTime());
if(bucket == null){
Log.i("Info", "Error");
}else{
Log.i("Info", "Total: " + (bucket.getRxBytes() + bucket.getTxBytes()));
}
} catch (RemoteException e) {
e.printStackTrace();
}
I found a solution of this problem with hidden APIs (android statistic 3g traffic for each APP, how?) and when trying to retrieve mobile data usage information with TYPE_MOBILE was necessary to inform the SubscriberID, unlike when I tryed to get information TYPE WIFI.
Try this code
TelephonyManager tm = (TelephonyManager)getSystemService(TELEPHONY_SERVICE);
String subscriberID = tm.getSubscriberId();
NetworkStats networkStatsByApp = networkStatsManager.queryDetailsForUid(ConnectivityManager.TYPE_MOBILE, subscriberID, start, end, uid);
So when you are using TYPE_MOBILE, it's necessary to you use a valid subscriberID.
As a follow up to the accepted answer, I would also like to point out that in the following code,
TelephonyManager tm = (TelephonyManager)getSystemService(TELEPHONY_SERVICE);
String subscriberID = tm.getSubscriberId(); //subscriberID is usually the IMSI number (for GSM phones)
TelephonyManager tm contains the information about the default telephony service (SIM card) that is being used for making calls. So, if you are using a phone with Dual SIM cards and SIM 1 is being used for calls and SIM 2 is being used for Data, then TelephonyManager tm will hold information about SIM 1 and in your use case, where you are using NetworkStatsManager for getting Data usage stats, SIM 1 info will be of no use as it is not being used for consuming Data. So, you somehow need to fetch the TelephonyManager for SIM 2 so that you can use the correct subscriber Id of SIM 2 in networkStatsManager.querySummaryForDevice() to get the mobile data usage stats. So, how do you do this?
One way that I figured out is like this:
public void subscriberIdsOfDualSim(){
SubscriptionManager subscriptionManager = SubscriptionManager.from(this);
//we'll now get a List of information of active SIM cards
//for example, if there are 2 SIM slots and both the slots have 1 SIM card each, then the List size will be 2
List<SubscriptionInfo> activeSubscriptionInfoList = subscriptionManager.getActiveSubscriptionInfoList();
TelephonyManager manager = (TelephonyManager) this.getSystemService(Context.TELEPHONY_SERVICE);
for (SubscriptionInfo subscriptionInfo : activeSubscriptionInfoList) {
//loop through the SIM card info
//if there are 2 SIM cards, then we'll try to print the subscriberId of each of the SIM cards
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.N) {
//the following createForSubscriptionId() is available from API 24 :(
TelephonyManager manager1=manager.createForSubscriptionId(subscriptionInfo.getSubscriptionId());
String operatorName=manager1.getNetworkOperatorName();
String subscriberId=manager1.getSubscriberId(); //use this subscriberId to do NetworkStatsManager stuff
System.out.println("subscriberIdsOfDualSim: Carrier Name: "+operatorName+", subscriber id: "+subscriberId);
}
}
}
Notice that I have used createForSubscriptionId() method. One limitation of this method is that it can be used from API 24 (Android 7.0 Nougat) only.
So, if you are using both SIM 1 and SIM 2 for data consumption, then you can get the data usage info for each of the SIM cards by providing the subscriberId of each of them to networkStatsManager.querySummaryForDevice(). But, if you want to get correct mobile data consumption (both SIM 1 and SIM 2 inclusive) and you want to support phones below Nougat, then the good old getMobileRxBytes() and getMobileTxBytes() methods in TrafficStats class is what you may have to use.
Another follow up to the accepted answer and #Nandan, it's possible to obtain subscriber ids of both SIM cards using below code
SubscriptionManager subman = (SubscriptionManager)getSystemService(TELEPHONY_SUBSCRIPTION_SERVICE);
TelephonyManager telman = (TelephonyManager)getSystemService(TELEPHONY_SERVICE);
List<SubscriptionInfo> li = subman.getActiveSubscriptionInfoList();
for(SubscriptionInfo info : li){
int sid = info.getSubscriptionId(); //not the id we want
try{
Class c = Class.forName("android.telephony.TelephonyManager");
Method m = c.getMethod("getSubscriberId", new Class[]{int.class});
Object o = m.invoke(telman, new Object[]{sid});
String subid = (String)o; //id we want
Log.i("SubscriptionId", subid);
}
catch(Exception e){}
}
Credit to answer link https://stackoverflow.com/a/38071705/9038181

Android: How to get the Serial Number as shown in About Device, Status with Java

On my Android Tablet I go to Settings -> About Device -> Status
In this screen I find a serial number with a length of 11 characters.
I would like to read this serial number with Java.
Anyone an idea how to do that?
Use
String x = Build.SERIAL
For more details check this out.
This is the device serial number.
For MDN or MEID of the device depending on which radio the phone uses (GSM or CDMA), try
TelephonyManager tManager = (TelephonyManager)myActivity.getSystemService(Context.TELEPHONY_SERVICE);
String uid = tManager.getDeviceId();
and include the permission in the manifest file:
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
Very old question, but perhaps the solution from dev here still helps:
public static String getManufacturerSerialNumber() {
String serial = null;
try {
Class<?> c = Class.forName("android.os.SystemProperties");
Method get = c.getMethod("get", String.class, String.class);
serial = (String) get.invoke(c, "ril.serialnumber", "unknown");
} catch (Exception ignored) {}
return serial;
}
Try this:
TextView tv = (TextView)findViewById(R.id.text);
String serial = Build.SERIAL;
tv.setText(serial);

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