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Splitting String according to multiple String in java

I just beginning to learn java, so please don't mind.
I have string
String test="John Software_Engineer Kartika QA Xing Project_Manager Mark CEO Celina Assistant_Developer";
I want to splitting based of position of Company={"Software_Engineer", "QA","Project_Manager","CEO ","Assistant_Developer"};
EDITED:
if above is difficulties then is it possible??? Based or {AND, OR)
String value="NA_USA >= 15 AND NA_USA=< 30 OR NA_USA!=80"
String value1="EUROPE_SPAIN >= 5 OR EUROPE_SPAIN < = 30 "
How to split and put in hashtable in java. finally how to access it from the end. this is not necessary but my main concern is how to split.
Next EDIT:
I got solution from this, it is the best idea or not????
String to="USA AND JAPAN OR SPAIN AND CHINA";
String [] ind= new String[]{"AND", "OR"};
for (int hj = 0; hj < ind.length; hj++){
to=to.replaceAll(ind[hj].toString(), "*");
}
System.out.println(" (=to=) "+to);
String[] partsparts = to.split("\\*");
for (int hj1 = 0; hj1 < partsparts.length; hj1++){
System.out.println(" (=partsparts=) "+partsparts[hj1].toString());
}
and
List<String> test1=split(to, '*', 1);
System.out.println("-str333->"+test1);
New EDIT:
If I have this type of String how can you splitting:
final String PLAYER = "IF John END IF Football(soccer) END IF Abdul-Jabbar tennis player END IF Karim -1996 * 1974 END IF";
How can i get like this: String [] data=[John , Football(soccer) ,Abdul-Jabbar tennis player, Karim -1996 * 1974 ]
Do you have any idea???

This will split your string for you and store it in a string array(Max size 50).
private static String[]split = new String[50];
public static void main(String[] args) {
String test="John -Software_Engineer Kartika -QA Xing -Project_Manager Mark -CEO Celina -Assistant_Developer";
for (String retval: test.split("-")){
int i = 0;
split[i]=retval;
System.out.println(split[i]);
i++;
}
}

You can make a string with Name:post and space. then it will be easy get desire value.
String test="John:Software_Engineer Kartika:QA Xing:Project_Manager"

I am unable to comment as my reputation is less. Hence i am writing over here.
Your first Question of String splitting could be generalized as positional word splitting. If it is guaranteed that you require all even positioned string, you could first split the string based on the space and pull all the even position string.
On your Second Question on AND & OR split, you could replace all " AND " & " OR " with single String " " and you could split the output string by single space string " ".
On your third Question, replace "IF " & " END" with single space string " " and I am not sure whether last IF do occurs in your string. If so you could replace it too with empty string "" and then split the string based on single space string " ".
First classify your input string based on patterns and please devise an algorithm before you work on Java.
I would suggest you to use StringBuffer or StringBuilder instead of using String directly as the cost is high for String Operation when compared to the above to.

try this
String[] a = test.replaceAll("\\w+ (\\w+)", "$1").split(" ");
here we first replace word pairs with the second word, then split by space

You can take a set which have all positions Like
Set<String> positions = new HashSet<String>();
positions.add("Software_Engineer");
positions.add("QA");
String test="John Software_Engineer Kartika QA Xing Project_Manager Mark CEO Celina Assistant_Developer";
List<String> positionsInString = new ArrayList<String>();
Iterator<String> iterator = positions.iterator();
while (iterator.hasNext()) {
String position = (String) iterator.next();
if(test.contains(position)){
positionsInString.add(position);
break;
}
}

Last two letters of a user inputted string using substring (Java)

I'm writing a program that generates star wars names. The user inputs their first, last, mother's maiden name, birth city, and first car and the program gives a star wars name. I need the last two characters* of the user inputted last name. I know I can use substring, but I cannot get anything to work. The best I have is:
lastname.substring(lastname.length() -2)
which gives the first two letters of the last name, and not the last. Also, I cannot use lastname.substr(-2) because substr for some reason won't work (not sure why, this would be much easier).
Thanks for any help.
*EDIT: I hope I didn't confuse anyone, I need the last two characters of the last name.
Actually I see my problem now: my original last name variable is
String lastname = console.nextLine().substring(0,2).trim().toUpperCase();
which keeps the first two letters, so the reason I was getting the first two letters was because of this. I understand now. Is there a way to get the last two letters from this same variable?

So if the name was Michael, you just want Micha?
Try:
String trimmedLastName = lastName.substring(0, lastName.length() - 2);
For example:
String lastName = "Michael";
String trimmedLastName = lastName.substring(0, lastName.length() - 2);
System.out.println(trimmedLastName); // prints Micha
The reason mine works and yours doesn't is because the first parameter of substring is where to start. So I start from the first letter, and end on the second last letter (not inclusive).
What yours does is start on the second last letter, and continue on until the end of the string.
However, if you wanted just el from Michael, you could do this:
String lastName = "Michael";
String trimmedLastName = lastName.substring(lastName.length() - 2);
System.out.println(trimmedLastName); // prints el

Try this out,
lastname.substring(lastname.length() -3,lastname.length() -1);

If you need the different ways, here:
StringBuffer myString = new StringBuffer(inputString);
myString.revert();
StringBuffer userInput = new StringBuffer(myString.subString(2));
String result = userInput.revert();
Have a nice day.

Because String is immutable so when you call subString it doesn't change the value of lastname.
I think you should do:
String genName = lastname.subString(lastname.lengh()-2);

lastname.substring(lastname.length() - 2) should return the last 2 letters.
lastname.substring(0, 2) returns the first two.
substring(index) is includive
substring(index1, index2) is inclusive, exclusive respectively.

Regex to parse multiline data

I have a following data from a file and I would like to see if I can do a regex parsing here
Name (First Name) City Zip
John (retired) 10007
Mark Baltimore 21268
....
....
Avg Salary
70000 100%
Its not a big file and the entire data from the file is available in a String object with a new line characters (\n) (String data = "data from the file")
I am trying to get name, city, zip and then the salary, percentage details
data inside () considered part of Name field.
For Name field space is considered valid and there are no space for other fields.
'Avg Salary' is available only at the end of the file
Will it be easy to do this via regex parsing in Java?

If the text file is space-aligned, you can (and probably should) extract the fields based on the number of characters. So, you take the first n characters in each line as first name, the next m characters as City, and so on.
This is one code to extract using the above method, by calculating the field length of the fields automatically, assuming we know the header.
String data = "data from the file";
// This is just to ensure we have enough space in the array
int numNewLines = data.length()-data.replace("\n","").length();
String[][] result = new String[numNewLines][3];
String[] lines = data.split("\n");
int avgSalary = 0;
int secondFieldStart = lines[0].indexOf("City");
int thirdFieldStart = lines[0].indexOf("Zip");
for(int i=1; i<lines.length; i++){
String line = lines[i].trim();
if(line.equals("Avg Salary")){
avgSalary = Integer.parseInt(lines[i+1].substring(0,secondFieldStart).trim());
break;
}
result[i-1][0] = line.substring(0,secondFieldStart).trim(); // First Name
result[i-1][1] = line.substring(secondFieldStart,thirdFieldStart).trim(); // City
result[i-1][2] = line.substring(thirdFieldStart).trim(); // Zip
}
Using regex will be possible, but it will be more complicated. And regex won't be able to differentiate person's name and city's name anyway:
Consider this case:
John Long-name Joe New York 21003
How would you know the name is John Long-name Joe instead of John Long-name Joe New if you don't know that the length of the first field is at most 20 characters? (note that length of John Long-name Joe is 19 characters, leaving one space between it and New in New York)
Of course if your fields are separated by other characters (like tab character \t), you can split each line based on that. And it's easy to modify the code above to accommodate that =)
Since the solution I proposed above is simpler, I guess you might want to try it instead =)

comparing array strings

The user enters an array of numbers such as "123456789"
and then the user is supposed to enter a string of commands such as "PE"
and my program will check each character in the string.
P = Remove the last number entered, which is 9
E = Prints out the final result.
To this point everything was working fine.
But my problem is that I have to be able to read the command when the user inputs "P(any number)", and I have to place that number at the end of the array of numbers.
So if it was P(4), the result would be "1234567894".
How can I do this ?
This is what I have right now for P and E.
if (commandList.get(x).equals("P(")) {
JOptionPane.showMessageDialog(null, "HI");
}
else if (commandList.get(x).equals("P")) {
strList.remove(strList.size()-1);
x++;
}

As far as I understand, your problem is to extract the 'digit' from the string "P(digit)" ?
Well you have to parse the input string, e.g., by searching for bounding characters, here '(' and ')'. For example by something like that:
String s = "P(3)";
String number = s.substring(s.indexOf("(") + 1, s.indexOf(")"));
strList.append(number);
But this would also accept anything within the bracktes, e.g., "foooo" from "P(foooo)", and it would crash if ')' cannot be found, e.g., s = "P(123", and it would accept "P(3)blah54" which is strictly spoken invalid. To improve your parser, you can use regular expressions, e.g., to check if the input is exactly of the form "P(2)" for exactly a single digit, you can use
String s = "P(3)";
if (!s.matches("P\\(\\d\\)"))
throw new RuntimeException("invalid input format: " + s);
String number = s.substring(s.indexOf("(") + 1, s.indexOf(")"));
strList.append(number);
If you explicitly want to cast the digit to an int, you might have a look at Integer.parseInt(...), e.g.,
int i = Integer.parseInt(number);

closest thing to NSScanner in Java

I'm moving some code from objective-c to java. The project is an XML/HTML Parser. In objective c I pretty much only use the scanUpToString("mystring"); method.
I looked at the Java Scanner class, but it breaks everything into tokens. I don't want that. I just want to be able to scan up to occurrences of substrings and keep track of the scanners current location in the overall string.
Any help would be great thanks!
EDIT
to be more specific. I don't want Scanner to tokenize.
String test = "<title balh> blah <title> blah>";
Scanner feedScanner = new Scanner(test);
String title = "<title";
String a = feedScanner.next(title);
String b = feedScanner.next(title);
In the above code I'd like feedScanner.next(title); to scan up to the end of the next occurrence of "<title"
What actually happens is the first time feeScanner.next is called it works since the default delimiter is whitespace, however, the second time it is called it fails (for my purposes).

You can achieve this with String class (Java.lang.String).
First get the first index of your substring.
int first_occurence= string.indexOf(substring);
Then iterate over entire string and get the next value of substrings
int next_index=indexOf( str,fromIndex);
If you want to save the values, add them to the wrapper class and the add to a arraylist object.

This really is easier by just using String's methodsdirectly:
String test = "<title balh> blah <title> blah>";
String target = "<title";
int index = 0;
index = test.indexOf( target, index ) + target.length();
// Index is now 6 (the space b/w "<title" and "blah"
index = test.indexOf( target, index ) + target.length();
// Index is now at the ">" in "<title> blah"
Depending on what you want to actually do besides walk through the string, different approaches might be better/worse. E.g. if you want to get the blah> blah string between the <title's, a Scanner is convenient:
String test = "<title balh> blah <title> blah>";
Scanner scan = new Scanner(test);
scan.useDelimiter("<title");
String stuff = scan.next(); // gets " blah> blah ";

Maybe String.split is something for you?
s = "The almighty String is mystring is your String is our mystring-object - isn't it?";
parts = s.split ("mystring");
Result:
Array("The almighty String is ", " is your String is our ", -object - isn't it?)
You know that in between your "mystring" must be. I'm not sure for start and end, so maybe you need some s.startsWith ("mystring") / s.endsWith.