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I NEED HELP ABOUT THİS QUESTİONS / JAVA ARRAYS [closed]

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49 5 8 14 3 7 6 21
It gives the rank of the smallest number whose remainder is 0 after dividing by 7 in the above given index.
create the algorithm.
I WAS TRY BUT I FAİLED.. I'M YET NEW TO JAVA ..

Here's some hints:
To test if an integer named x is divisible by 7:
if (x % 7 == 0) {
// x is divisible by 7
}
To enumerate all the items in an array name arr
for (int i = 0; i < arr.length; i++) {
}

Store the result in the variable [closed]

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Store the result in the variable
How do I store the result of number % 4 = 0 in a variable?
Like this: number1 = (number2 % 4 = 0)

Not sure what do you want exactly. Here are some hints for you:
int quotient = divisor / divider;
int remainder = divisor % divider;
boolean isDivisibleByFour = number % 4 == 0; // true or false

Do while loop nested in for loop wont iterate [closed]

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I need to enter N which is a number of numbers for which I need to see if they can be divided by 3. Afterwards I need to display what % of numbers from the N I can divide. Numbers need to go from 15 to 62 and they need to loop until I enter the right value each time, but they don't. Instead, they just repeat the for loop regardless of my input. Here is the code:
System.out.println("Enter N number of numbers");
int N = TextIO.getlnInt();
int number;
int counterOfDivisible = 0;
for(int i = 0; i < N ; i++) {
do {
System.out.println("Please enter a number from the 15-62 span");
number = TextIO.getlnInt();
} while (number<15 && number>62);
if(number%3==0)
counterOfDivisible++;
}
System.out.println("% of numbers from the N that can be divided by 3 is " + (counterOfDivisible*100.0)/N + "%");

number can never be <15 and >62 at the same time. Think about your condition.

Thank you all for the quick reply, first time here. Quite silly mistake on my behalf.
This seems to do the trick i was aiming for.
do {
System.out.println("Please enter a number from the 15-62 span");
number = TextIO.getlnInt();
} while (number < 15 || number > 62);

Remove random index from an arrayList [closed]

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I have an ArrayList of 4 items. I need to remove one item randomly and display the updated ArrayList. However my random keeps targeting the second and third element on the array list. As far as I understand my random would count like this: 0 1 2 3. Shouldn't that be enough to cover my 4 elements? Why does it keep targeting the same indexes? I have tried increasing the random number (4) + 1, but that puts me out of bounds.
Random rand = new Random();
Scanner input = new Scanner(System.in);
int numberOfGuests = 4;
ArrayList<String> guestList = new ArrayList<>(4);
System.out.println("Enter 4 guests:");
for(int i = 1; i <=numberOfGuests; i++){
System.out.printf("guest%d: ", i);
guestList.add(input.nextLine());
}
System.out.println("Guest List: " + guestList);
String remove = guestList.remove(rand.nextInt(4));
System.out.printf("%s can't come%n" , remove);
System.out.println("Guest List: " + guestList);

yoy check when you user random number generation the rage is set to length of array minus one such as in your case
String remove = guestList.remove(rand.nextInt(3));

Random Array Error [closed]

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Why does the program show java.lang.ArrayIndexOutOfBoundsException: 11?
The program needs to print 11 numbers. 9 numbers should be random.
It prints 11 numbers but it has an error.
public class Main {
public static void main(String[] args) {
Random random = new Random();
int[] Cnum = new int[11];
Cnum[0]=0;
Cnum[1]=9;
System.out.print(Cnum[0]);
System.out.print(Cnum[1]);
for(int a = 2; 2 < 10; a++){
Cnum[a]=random.nextInt(9);
System.out.print(Cnum[a]);
}
}
}
The output should be (x is random) :
09xxxxxxxxx
But the output it does is:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 11
at CellphoneNumberGenerator.Main.main(Main.java:17)
09505423220

for(int a=2;2<10;a++)
That is basically a while(True) (infinite) loop because 2 is always less than 10. Perhaps you meant:
for(int a= 2; a<10; a++)

In your for cycle the condition is wrong.
You have 2 < 10 instead of a < 10