I'm trying to code based on the manual operation. For manual, I have a URL and when I paste the URL to the Chrome browser, the browser automatically downloads the PDF file from that URL and save to folder "download" without prompting any user input. With Code, I'm able to accomplish the same thing as the manual operation. However I would like the code to save the PDF into specific folder instead of default folder "download". Is it possible to do that?
public static void browseURL() {
try {
String url ="mycompanyURL";
System.out.println("url " + url );
Desktop desktop = Desktop.getDesktop();
URI uri = new URI (url);
desktop.browse(uri);
}catch(Exception err) {
System.out.println("exception " + err.getMessage());
}
}
When I had to do that in old versions of Java, I used the following snippet (pure Java, source: Baeldung).
public void streamFromUrl(String downloadUrl, String filePath) throws IOException {
File file = new File(filePath);
try (BufferedInputStream in = new BufferedInputStream(new URL(downloadUrl).openStream());
FileOutputStream fileOutputStream = new FileOutputStream(file)) {
byte[] dataBuffer = new byte[1024];
int bytesRead;
while ((bytesRead = in.read(dataBuffer, 0, 1024)) != -1) {
fileOutputStream.write(dataBuffer, 0, bytesRead);
}
}
}
The above opens an input stream on the URL, and outputs the bytes of such stream into a file output stream (where the file is wherever you wish).
Alternatively, there are many libraries doing that in one/two liners (the article I posted shows some of those alternatives).
Also, starting from more recent versions of Java, there are other shorter options:
public void streamFromUrl(String downloadUrl, String filePath) throws IOException {
try (InputStream in = new URL(downloadUrl).openStream()) {
Files.copy(in, Paths.get(new File(filePath)), StandardCopyOption.REPLACE_EXISTING);
}
}
Depending on the version of Java you have, you may pick one of those. Generally speaking, I suggest you reading through the Baeldung's article and check the one that best suits for you.
Here you go. Handles redirects and so on can use and modify as you wish. Have fun with it. All in native Java. Did write this to download some media easily. This can also download media like images, videos and documents.
import java.io.IOException;
import java.net.URI;
import java.net.http.HttpClient;
import java.net.http.HttpRequest;
import java.net.http.HttpRequest.Builder;
import java.net.http.HttpResponse.BodyHandlers;
import java.nio.file.Files;
import java.nio.file.Path;
public class Downloader {
public static void download(String url) {
final HttpClient hc = HttpClient.newHttpClient();
final Builder requestBuilder = HttpRequest.newBuilder().version(HttpClient.Version.HTTP_1_1);
Path path = Path.of("myfilepath");
handleGet(hc, "myfile.pdf", "myurl.com", path, requestBuilder);
}
private static void handleGet(
final HttpClient hc,
final String fileName,
final String url,
final Path filePath,
final Builder requestBuilder
) {
final HttpRequest request = requestBuilder.uri(URI.create(url)).build();
hc.sendAsync(request, BodyHandlers.ofInputStream())
.thenApply(resp -> {
int sc = resp.statusCode();
System.out.println("STATUSCODE: "+sc+" for url '"+url+"'");
if(sc >= 200 && sc < 300) return resp;
if(sc == 302) {
System.out.println("Handling 302...");
String newUrl = resp.headers().firstValue("location").get();
handleGet(hc, fileName, newUrl, filePath, requestBuilder);
}
return resp;
})
.thenAccept(resp -> {
int sc = resp.statusCode();
if(sc >= 200 && sc < 300) {
try {
System.out.println("Im fine here");
Files.copy(resp.body(), filePath);
} catch (IOException e) {
throw new RuntimeException(e);
}
} else {
System.err.println("STATUSCODE: "+ sc +" for file "+ fileName);
}
}).join();
}
}
Related
I'm trying to write a simple http server, using com.sun.net.httpserver class. I send html file (index.html) to browser on startup, but I don't know how to include an external css file. It works when css code is placed inside html file. I know, that browser should send a request, asking server for css file, but I'm not sure how to receive this request and send back this file to browser. I attach a fragment of my code below, if it could be helpful.
private void startServer()
{
try
{
server = HttpServer.create(new InetSocketAddress(8000), 0);
}
catch (IOException e)
{
System.err.println("Exception in class : " + e.getMessage());
}
server.createContext("/", new indexHandler());
server.setExecutor(null);
server.start();
}
private static class indexHandler implements HttpHandler
{
public void handle(HttpExchange httpExchange) throws IOException
{
Headers header = httpExchange.getResponseHeaders();
header.add("Content-Type", "text/html");
sendIndexFile(httpExchange);
}
}
static private void sendIndexFile(HttpExchange httpExchange) throws IOException
{
File indexFile = new File(getIndexFilePath());
byte [] indexFileByteArray = new byte[(int)indexFile.length()];
BufferedInputStream requestStream = new BufferedInputStream(new FileInputStream(indexFile));
requestStream.read(indexFileByteArray, 0, indexFileByteArray.length);
httpExchange.sendResponseHeaders(200, indexFile.length());
OutputStream responseStream = httpExchange.getResponseBody();
responseStream.write(indexFileByteArray, 0, indexFileByteArray.length);
responseStream.close();
}
There is no built-in method for handling static content. You have two options.
Either use a light-weight webserver for static content like nginx, but than distribution of your application will be more difficult.
Or create your own file serving classes. For that, you have to create a new context in your web server:
int port = 8080;
HttpServer server = HttpServer.create(new InetSocketAddress(port), 0);
// ... more server contexts
server.createContext("/static", new StaticFileServer());
And than create the class that will serve your static files.
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.OutputStream;
import com.sun.net.httpserver.HttpExchange;
import com.sun.net.httpserver.HttpHandler;
#SuppressWarnings("restriction")
public class StaticFileServer implements HttpHandler {
#Override
public void handle(HttpExchange exchange) throws IOException {
String fileId = exchange.getRequestURI().getPath();
File file = getFile(fileId);
if (file == null) {
String response = "Error 404 File not found.";
exchange.sendResponseHeaders(404, response.length());
OutputStream output = exchange.getResponseBody();
output.write(response.getBytes());
output.flush();
output.close();
} else {
exchange.sendResponseHeaders(200, 0);
OutputStream output = exchange.getResponseBody();
FileInputStream fs = new FileInputStream(file);
final byte[] buffer = new byte[0x10000];
int count = 0;
while ((count = fs.read(buffer)) >= 0) {
output.write(buffer, 0, count);
}
output.flush();
output.close();
fs.close();
}
}
private File getFile(String fileId) {
// TODO retrieve the file associated with the id
return null;
}
}
For the method getFile(String fileId); you can implement any way of retrieving the file associated with the fileId. A good option is to create a file structure mirroring the URL hierarchy. If you don't have many files, than you can use a HashMap to store valid id-file pairs.
I am using below code, its not working.
when i use imageUrl on browser its redirect somewhere then its working.
But i have n number of facebook id only and every time redirected url is different.
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.URL;
public class SaveImageFromUrl {
public static void main(String[] args) throws Exception {
String imageUrl = "http://graph.facebook.com/67563683055/picture?type=square";
String destinationFile = "C:\\Users\\emtx\\Desktop\\Nxg-pic.png";
saveImage(imageUrl, destinationFile);
}
public static void saveImage(String imageUrl, String destinationFile) throws IOException {
URL url = new URL(imageUrl);
InputStream is = url.openStream();
OutputStream os = new FileOutputStream(destinationFile);
byte[] b = new byte[2048];
int length;
while ((length = is.read(b)) != -1) {
os.write(b, 0, length);
}
is.close();
os.close();
}
}
In addition to Phsemos answer, you can also disable the redirection with the redirect parameter and use the following API call to get the real URL as JSON:
https://graph.facebook.com/67563683055/picture?type=square&redirect=false
This is how the JSON looks like:
{
"data": {
"is_silhouette": false,
"url": "https://scontent.xx.fbcdn.net/hprofile-xaf1/v/t1.0-1/c44.44.544.544/s50x50/316295_10151906553973056_2129080216_n.jpg?oh=04888b6ef5d631447227b42d82ebd35d&oe=57250EA4"
}
}
Address you are using redirects you to other location. Since URL class doesn't redirects you automatically what you get is
headers containing information about redirection (like Location which points you to new address),
and possibly body (but in this case it is empty).
You may want to create method like (based on: http://www.mkyong.com/java/java-httpurlconnection-follow-redirect-example/)
public static String getFinalLocation(String address) throws IOException{
URL url = new URL(address);
HttpURLConnection conn = (HttpURLConnection)url.openConnection();
int status = conn.getResponseCode();
if (status != HttpURLConnection.HTTP_OK)
{
if (status == HttpURLConnection.HTTP_MOVED_TEMP
|| status == HttpURLConnection.HTTP_MOVED_PERM
|| status == HttpURLConnection.HTTP_SEE_OTHER)
{
String newLocation = conn.getHeaderField("Location");
return getFinalLocation(newLocation);
}
}
return address;
}
and change your
URL url = new URL(imageUrl);
to
URL url = new URL(getFinalLocation(imageUrl));
I have a URL i.e http://downloadplugins.verify.com/Windows/SubAngle.exe .
If I paste it on the tab and press enter then the file (SubAngle.exe) is getting downloaded and saved in the download folder. This is a manual process. But it can be done with java code.
I wrote the code for getting the absolute path with the help of the file name i.e SubAngle.exe.
Requirement:- With the help of the URL file gets downloaded,Verify the file has been downloaded and returns the absolute path of the file.
where locfile is "http://downloadplugins.verify.com/Windows/SubAngle.exe"
public String downloadAndVerifyFile(String locfile) {
File fileLocation = new File(locfile);
File fileLocation1 = new File(fileLocation.getName());
String fileLocationPath = null;
if(fileLocation.exists()){
fileLocationPath = fileLocation1.getAbsolutePath();
}
else{
throw new FileNotFoundException("File with name "+locFile+" may not exits at the location");
}
return fileLocationPath;
}
easy and general function that im using:
import org.apache.commons.io.FileUtils;
public static void downLoadFile(String fromFile, String toFile) throws MalformedURLException, IOException {
try {
FileUtils.copyURLToFile(new URL(fromFile), new File(toFile), 60000, 60000);
} catch (FileNotFoundException e) {
e.printStackTrace();
System.out.println("exception on: downLoadFile() function: " + e.getMessage());
}
}
Instead of writing this huge code, go for Apache's commons.io
Try this:
URL ipURL = new URL("inputURL");
File opFile = new File("outputFile");
FileUtils.copyURLToFile(ipURL, opFile);
Code to DownloadFile from URL
import java.net.*;
import java.io.*;
public class DownloadFile {
public static void main(String[] args) throws IOException {
InputStream in = null;
FileOutputStream out = null;
try {
// URL("http://downloadplugins.verify.com/Windows/SubAngle.exe");
System.out.println("Starting download");
long t1 = System.currentTimeMillis();
URL url = new URL(args[0]);
// Open the input and out files for the streams
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
in = conn.getInputStream();
out = new FileOutputStream("YourFile.exe");
// Read data into buffer and then write to the output file
byte[] buffer = new byte[8192];
int bytesRead;
while ((bytesRead = in.read(buffer)) != -1) {
out.write(buffer, 0, bytesRead);
}
long t2 = System.currentTimeMillis();
System.out.println("Time for download & save file in millis:"+(t2-t1));
} catch (Exception e) {
// Display or throw the error
System.out.println("Erorr while execting the program: "
+ e.getMessage());
} finally {
// Close the resources correctly
if (in != null) {
in.close();
}
if (out != null) {
out.close();
}
}
}
}
Configure the value of fileName properly to know where the file is getting stored.
Source: http://www.devmanuals.com/tutorials/java/corejava/files/java-read-large-file-efficiently.html
The source was modified to replace local file with http URL
Output:
java DownloadFile http://download.springsource.com/release/TOOLS/update/3.7.1.RELEASE/e4.5/springsource-tool-suite-3.7.1.RELEASE-e4.5.1-updatesite.zip
Starting download
Time for download & save file in millis:100184
I have created zip file using java as below snippet
import java.io.*;
import java.util.zip.*;
public class ZipCreateExample {
public static void main(String[] args) throws IOException {
System.out.print("Please enter file name to zip : ");
BufferedReader input = new BufferedReader
(new InputStreamReader(System.in));
String filesToZip = input.readLine();
File f = new File(filesToZip);
if(!f.exists()) {
System.out.println("File not found.");
System.exit(0);
}
System.out.print("Please enter zip file name : ");
String zipFileName = input.readLine();
if (!zipFileName.endsWith(".zip"))
zipFileName = zipFileName + ".zip";
byte[] buffer = new byte[18024];
try {
ZipOutputStream out = new ZipOutputStream
(new FileOutputStream(zipFileName));
out.setLevel(Deflater.DEFAULT_COMPRESSION);
FileInputStream in = new FileInputStream(filesToZip);
out.putNextEntry(new ZipEntry(filesToZip));
int len;
while ((len = in.read(buffer)) > 0) {
out.write(buffer, 0, len);
}
out.closeEntry();
in.close();
out.close();
} catch (IllegalArgumentException iae) {
iae.printStackTrace();
System.exit(0);
} catch (FileNotFoundException fnfe) {
fnfe.printStackTrace();
System.exit(0);
} catch (IOException ioe) {
ioe.printStackTrace();
System.exit(0);
}
}
}
Now I want when I click on the zip file it should prompt me to type password and then decompress the zip file.
Please any help,How should I go further?
Try the following code which is based on Zip4j:
import net.lingala.zip4j.core.ZipFile;
import net.lingala.zip4j.exception.ZipException;
import net.lingala.zip4j.model.ZipParameters;
import net.lingala.zip4j.util.Zip4jConstants;
import org.apache.commons.io.FilenameUtils;
import java.io.File;
public class Zipper
{
private String password;
private static final String EXTENSION = "zip";
public Zipper(String password)
{
this.password = password;
}
public void pack(String filePath) throws ZipException
{
ZipParameters zipParameters = new ZipParameters();
zipParameters.setCompressionMethod(Zip4jConstants.COMP_DEFLATE);
zipParameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_ULTRA);
zipParameters.setEncryptFiles(true);
zipParameters.setEncryptionMethod(Zip4jConstants.ENC_METHOD_AES);
zipParameters.setAesKeyStrength(Zip4jConstants.AES_STRENGTH_256);
zipParameters.setPassword(password);
String baseFileName = FilenameUtils.getBaseName(filePath);
String destinationZipFilePath = baseFileName + "." + EXTENSION;
ZipFile zipFile = new ZipFile(destinationZipFilePath);
zipFile.addFile(new File(filePath), zipParameters);
}
public void unpack(String sourceZipFilePath, String extractedZipFilePath) throws ZipException
{
ZipFile zipFile = new ZipFile(sourceZipFilePath + "." + EXTENSION);
if (zipFile.isEncrypted())
{
zipFile.setPassword(password);
}
zipFile.extractAll(extractedZipFilePath);
}
}
FilenameUtils is from Apache Commons IO.
Example usage:
public static void main(String[] arguments) throws ZipException
{
Zipper zipper = new Zipper("password");
zipper.pack("encrypt-me.txt");
zipper.unpack("encrypt-me", "D:\\");
}
Standard Java API does not support password protected zip files. Fortunately good guys have already implemented such ability for us. Please take a look on this article that explains how to create password protected zip.
(The link was dead, latest archived version: https://web.archive.org/web/20161029174700/http://java.sys-con.com/node/1258827)
Sample code below will zip and password protect your file.
This REST service accepts bytes of the original file. It zips the byte array and password protects it. Then it sends bytes of password protected zipped file as response. The code is a sample of sending and receiving binary bytes to and from a REST service, and also of zipping a file with password protect. The bytes are zipped from stream, so no files are ever stored on the server.
Uses JAX-RS API using Jersey API in java
Client is using Jersey-client API.
Uses zip4j 1.3.2 open source library, and apache commons io.
#PUT
#Path("/bindata/protect/qparam")
#Consumes(MediaType.APPLICATION_OCTET_STREAM)
#Produces(MediaType.APPLICATION_OCTET_STREAM)
public Response zipFileUsingPassProtect(byte[] fileBytes, #QueryParam(value = "pass") String pass,
#QueryParam(value = "inputFileName") String inputFileName) {
System.out.println("====2001==== Entering zipFileUsingPassProtect");
System.out.println("fileBytes size = " + fileBytes.length);
System.out.println("password = " + pass);
System.out.println("inputFileName = " + inputFileName);
byte b[] = null;
try {
b = zipFileProtected(fileBytes, inputFileName, pass);
} catch (IOException e) {
e.printStackTrace();
return Response.status(Status.INTERNAL_SERVER_ERROR).build();
}
System.out.println(" ");
System.out.println("++++++++++++++++++++++++++++++++");
System.out.println(" ");
return Response.ok(b, MediaType.APPLICATION_OCTET_STREAM)
.header("content-disposition", "attachment; filename = " + inputFileName + ".zip").build();
}
private byte[] zipFileProtected(byte[] fileBytes, String fileName, String pass) throws IOException {
ByteArrayInputStream inputByteStream = null;
ByteArrayOutputStream outputByteStream = null;
net.lingala.zip4j.io.ZipOutputStream outputZipStream = null;
try {
//write the zip bytes to a byte array
outputByteStream = new ByteArrayOutputStream();
outputZipStream = new net.lingala.zip4j.io.ZipOutputStream(outputByteStream);
//input byte stream to read the input bytes
inputByteStream = new ByteArrayInputStream(fileBytes);
//init the zip parameters
ZipParameters zipParams = new ZipParameters();
zipParams.setCompressionMethod(Zip4jConstants.COMP_DEFLATE);
zipParams.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_NORMAL);
zipParams.setEncryptFiles(true);
zipParams.setEncryptionMethod(Zip4jConstants.ENC_METHOD_STANDARD);
zipParams.setPassword(pass);
zipParams.setSourceExternalStream(true);
zipParams.setFileNameInZip(fileName);
//create zip entry
outputZipStream.putNextEntry(new File(fileName), zipParams);
IOUtils.copy(inputByteStream, outputZipStream);
outputZipStream.closeEntry();
//finish up
outputZipStream.finish();
IOUtils.closeQuietly(inputByteStream);
IOUtils.closeQuietly(outputByteStream);
IOUtils.closeQuietly(outputZipStream);
return outputByteStream.toByteArray();
} catch (ZipException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
IOUtils.closeQuietly(inputByteStream);
IOUtils.closeQuietly(outputByteStream);
IOUtils.closeQuietly(outputZipStream);
}
return null;
}
Unit test below:
#Test
public void testPassProtectZip_with_params() {
byte[] inputBytes = null;
try {
inputBytes = FileUtils.readFileToByteArray(new File(inputFilePath));
} catch (IOException e) {
e.printStackTrace();
}
System.out.println("bytes read into array. size = " + inputBytes.length);
Client client = ClientBuilder.newClient();
WebTarget target = client.target("http://localhost:8080").path("filezip/services/zip/bindata/protect/qparam");
target = target.queryParam("pass", "mypass123");
target = target.queryParam("inputFileName", "any_name_here.pdf");
Invocation.Builder builder = target.request(MediaType.APPLICATION_OCTET_STREAM);
Response resp = builder.put(Entity.entity(inputBytes, MediaType.APPLICATION_OCTET_STREAM));
System.out.println("response = " + resp.getStatus());
Assert.assertEquals(Status.OK.getStatusCode(), resp.getStatus());
byte[] zipBytes = resp.readEntity(byte[].class);
try {
FileUtils.writeByteArrayToFile(new File(responseFilePathPasswordZipParam), zipBytes);
} catch (IOException e) {
e.printStackTrace();
}
}
Feel free to use and modify. Please let me know if you find any errors. Hope this helps.
Edit 1 - Using QueryParam but you may use HeaderParam for PUT instead to hide passwd from plain sight. Modify the test method accordingly.
Edit 2 - REST path is filezip/services/zip/bindata/protect/qparam
filezip is name of war. services is the url mapping in web.xml. zip is class level path annotation. bindata/protect/qparam is the method level path annotation.
In new version of Zip4j, class Zip4jConstants was removed. Use EncryptionMethod and AesKeyStrength class instead. Documentation : https://github.com/srikanth-lingala/zip4j
ZipParameters zipParameters = new ZipParameters();
zipParameters.setEncryptFiles(true);
zipParameters.setEncryptionMethod(EncryptionMethod.AES);
zipParameters.setAesKeyStrength(AesKeyStrength.KEY_STRENGTH_256);
List<File> filesToAdd = Arrays.asList(
new File("somefile"),
new File("someotherfile")
);
ZipFile zipFile = new ZipFile("filename.zip", "password".toCharArray());
zipFile.addFiles(filesToAdd, zipParameters);
There is no default Java API to create a password protected file. There is another example about how to do it here.
Library Zip4J seems to be the preferred answer.
In case the privacy of the password is highly recommended, one might close a security gap in class ZipFile, which carries the password in plain text, even after the ZipFile is closed. Following method destroys the password.
public static void destroyZipPassword(ZipFile zip) throws DestroyFailedException
{
try
{
Field fdPwd = ZipFile.class.getDeclaredField("password");
fdPwd.setAccessible(true);
char[] password = (char[]) fdPwd.get(zip);
Arrays.fill(password, (char) 0);
}
catch (Exception e)
{
e.printStackTrace();
throw new DestroyFailedException(e.getMessage());
}
}
I am using Jsoup Java HTML parser to fetch images from a particular URL. But some of the images are throwing a status 502 error code and are not saved to my machine. Here is the code snapshot i have used:-
String url = "http://www.jabong.com";
String html = Jsoup.connect(url.toString()).get().html();
Document doc = Jsoup.parse(html, url);
images = doc.select("img");
for (Element element : images) {
String imgSrc = element.attr("abs:src");
log.info(imgSrc);
if (imgSrc != "") {
saveFromUrl(imgSrc, dirPath+"/" + nameCounter + ".jpg");
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
log.error("error in sleeping");
}
nameCounter++;
}
}
And the saveFromURL function looks like this:-
public static void saveFromUrl(String Url, String destinationFile) {
try {
URL url = new URL(Url);
InputStream is = url.openStream();
OutputStream os = new FileOutputStream(destinationFile);
byte[] b = new byte[2048];
int length;
while ((length = is.read(b)) != -1) {
os.write(b, 0, length);
}
is.close();
os.close();
} catch (IOException e) {
log.error("Error in saving file from url:" + Url);
//e.printStackTrace();
}
}
I searched on internet about status code 502 but it says error is due to bad gateway. I don't understand this. One of the possible things i am thinking that this error may be because of I am sending get request to images in loop. May be webserver is not able handle to this much load so denying the request to the images when previous image is not sent.So I tried to put sleep after fetching every image but no luck :(
Some advices please
Here's a full code example that works for me...
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.Authenticator;
import java.net.HttpURLConnection;
import java.net.InetSocketAddress;
import java.net.MalformedURLException;
import java.net.Proxy;
import java.net.SocketAddress;
import java.net.URL;
public class DownloadImage {
public static void main(String[] args) {
// URLs for Images we wish to download
String[] urls = {
"http://cdn.sstatic.net/stackoverflow/img/apple-touch-icon.png",
"http://www.google.co.uk/images/srpr/logo3w.png",
"http://i.microsoft.com/global/en-us/homepage/PublishingImages/sprites/microsoft_gray.png"
};
for(int i = 0; i < urls.length; i++) {
downloadFromUrl(urls[i]);
}
}
/*
Extract the file name from the URL
*/
private static String getOutputFileName(URL url) {
String[] urlParts = url.getPath().split("/");
return "c:/temp/" + urlParts[urlParts.length-1];
}
/*
Assumes there is no Proxy server involved.
*/
private static void downloadFromUrl(String urlString) {
InputStream is = null;
FileOutputStream fos = null;
try {
URL url = new URL(urlString);
System.out.println("Reading..." + url);
HttpURLConnection conn = (HttpURLConnection)url.openConnection(proxy);
is = conn.getInputStream();
String filename = getOutputFileName(url);
fos = new FileOutputStream(filename);
byte[] readData = new byte[1024];
int i = is.read(readData);
while(i != -1) {
fos.write(readData, 0, i);
i = is.read(readData);
}
System.out.println("Created file: " + filename);
}
catch (MalformedURLException e) {
e.printStackTrace();
}
catch (IOException e) {
e.printStackTrace();
}
finally {
if(is != null) {
try {
is.close();
} catch (IOException e) {
System.out.println("Big problems if InputStream cannot be closed");
}
}
if(fos != null) {
try {
fos.close();
} catch (IOException e) {
System.out.println("Big problems if FileOutputSream cannot be closed");
}
}
}
System.out.println("Completed");
}
}
You should see the following ouput on your console...
Reading...http://cdn.sstatic.net/stackoverflow/img/apple-touch-icon.png
Created file: c:/temp/apple-touch-icon.png
Completed
Reading...http://www.google.co.uk/images/srpr/logo3w.png
Created file: c:/temp/logo3w.png
Completed
Reading...http://i.microsoft.com/global/en-us/homepage/PublishingImages/sprites/microsoft_gray.png
Created file: c:/temp/microsoft_gray.png
Completed
So that's a working example without a Proxy server involved.
Only if you require authentication with a proxy server here's an additional Class that you'll need based on this Oracle technote
import java.net.Authenticator;
import java.net.PasswordAuthentication;
public class ProxyAuthenticator extends Authenticator {
private String userName, password;
public ProxyAuthenticator(String userName, String password) {
this.userName = userName;
this.password = password;
}
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication(userName, password.toCharArray());
}
}
And to use this new Class you would use the following code in place of the call to openConnection() shown above
...
try {
URL url = new URL(urlString);
System.out.println("Reading..." + url);
Authenticator.setDefault(new ProxyAuthenticator("username", "password");
SocketAddress addr = new InetSocketAddress("proxy.server.com", 80);
Proxy proxy = new Proxy(Proxy.Type.HTTP, addr);
HttpURLConnection conn = (HttpURLConnection)url.openConnection(proxy);
...
Your problem sounds like HTTP communication issues, so you are probably better off trying to use a library to handle the communication side of things. Take a look at Apache Commons HttpClient.
Some notes about your code example. You haven't used a URLConnection object so it's not clear what the behaviour will be in regards to the Web/Proxy servers and closing resources cleanly, etc. The HttpCommon library mentioned will help in this aspect.
There also seems to be some examples of doing what you want using J2ME libararies. Not something I have used personally but may also help you out.