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Perlin Noise repeating pattern

My problem that my perlin noise is repeating itself very obviously in very small spaces. Here is an image of what it going on. I know that this does happen after a certain point with all perlin noise, but it seems to be happening almost immediately with mine. I believe that it is caused by my really awful pseudorandom gradient generator, but Im not sure. My code is below.
As a side note, my perlin noise seems to generate very small values, between -.2 and positive .2 and I think this is also caused by my pseudorandom gradient generator.
If anyone has any advice on improving this part of my code, please feel free to tell me. Any ideas would be helpful right now.
Thanks to everyone in advance!
public class Perlin {
int[] p = new int[255];
public Perlin() {
for(int i = 0; i < p.length; i++)
p[i] = i;
shuffle(p);
}
int grads[][] = {
{1,0},{0,1},{-1,0},{0,-1},
{1,1},{-1,1},{1,-1},{-1,-1}
};
public double perlin (double x, double y) {
int unitX = (int)Math.floor(x) & 255; // decide unit square
int unitY = (int)Math.floor(y) & 255; // decide unit square
double relX = x-Math.floor(x); // relative x position
double relY = y-Math.floor(y); // relative y position
// bad pseudorandom gradient -- what i think is causing the problems
int units = unitX+unitY;
int[] gradTL = grads[p[(units)]%(grads.length)];
int[] gradTR = grads[p[(units+1)]%(grads.length)];
int[] gradBL = grads[p[(units+1)]%(grads.length)];
int[] gradBR = grads[p[(units+2)]%(grads.length)];
// distance from edges to point, relative x and y inside the unit square
double[] vecTL = {relX,relY};
double[] vecTR = {relX-1,relY};
double[] vecBL = {relX,relY-1};
double[] vecBR = {relX-1,relY-1};
// dot product
double tl = dot(gradTL,vecTL);
double tr = dot(gradTR,vecTR);
double bl = dot(gradBL,vecBL);
double br = dot(gradBR,vecBR);
// perlins fade curve
double u = fade(relX);
double v = fade(relY);
// lerping the faded values
double x1 = lerp(tl,tr,u);
double y1 = lerp(bl,br,u);
// ditto
return lerp(x1,y1,v);
}
public double dot(int[] grad, double[] dist) {
return (grad[0]*dist[0]) + (grad[1]*dist[1]);
}
public double lerp(double start, double end, double rate){
return start+rate*(end-start);
}
public double fade(double t) {
return t*t*t*(t*(t*6-15)+10);
}
public void shuffle(int[] p) {
Random r = new Random();
for(int i = 0; i < p.length; i++) {
int n = r.nextInt(p.length - i);
// do swap thing
int place = p[i];
p[i] = p[i+n];
p[i+n] = place;
}
}
}
A side note on my gradient generator, I know Ken Perlin used 255 because he was using bits, I just randomly picked it. I dont think it has any effect on the patterns if it is changed.

Your intuition is correct. You calculate:
int units = unitX+unitY;
and then use that as the base of all your gradient table lookups. This guarantees that you get the same values along lines with slope -1, which is exactly what we see assuming (0, 0) is the upper-left corner.
I would suggest using a real hash function to combine your coordinates: xxHash, Murmur3, or even things like CRC32 (which isn't meant to be a hash) would be much better than what you're doing. You could also implement Perlin's original hash function, although it has known issues with anisotropy.

plotting points along a straight line from a random start position

I am looking for some help with some game code i have inherited from a flight sim. The code below simulates bombs exploding on the ground, it works fine but i am trying to refine it.
At the moment it takes a random value for x and y as a start point and then adds another random value between -20 and 20 to this. It works ok, but doesn't simulate bombs dropping very well as the pattern does not lay along a straight line/
What i would like to achieve though is all x and y points after the first random values, to lay along a straight line, so that the effects called for all appear to lay in a line. It doesn't matter which way the line is orientated.
Thanks for any help
slipper
public static class BombUnit extends CandCGeneric
{
public boolean danger()
{
Point3d point3d = new Point3d();
pos.getAbs(point3d);
Vector3d vector3d = new Vector3d();
Random random = new Random();
Aircraft aircraft = War.GetNearestEnemyAircraft(this, 10000F, 9);
if(counter > 10)
{
counter = 0;
startpoint.set(point3d.x + (double)(random.nextInt(1000) - 500), point3d.y + (double)(random.nextInt(1000) - 500), point3d.z);
}
if(aircraft != null && (aircraft instanceof TypeBomber) && aircraft.getArmy() != myArmy)
{
World.MaxVisualDistance = 50000F;
counter++;
String s = "weapon.bomb_std";
startpoint.x += random.nextInt(40) - 20;
startpoint.y += random.nextInt(40) - 20;
Explosions.generate(this, startpoint, 7F, 0, 30F, !Mission.isNet());
startpoint.z = World.land().HQ(startpoint.x, startpoint.y);
MsgExplosion.send(this, s, startpoint, getOwner(), 0.0F, 7F, 0, 30F);
Engine.land();
int i = Landscape.getPixelMapT(Engine.land().WORLD2PIXX(startpoint.x), Engine.land().WORLD2PIXY(startpoint.y));
if(firecounter < 100 && i >= 16 && i < 20)
{
Eff3DActor.New(null, null, new Loc(startpoint.x, startpoint.y, startpoint.z + 5D, 0.0F, 90F, 0.0F), 1.0F, "Effects/Smokes/CityFire3.eff", 300F);
firecounter++;
}
super.setTimer(15);
}
return true;
}
private static Point3d startpoint = new Point3d();
private int counter;
private int firecounter;
public BombUnit()
{
counter = 11;
firecounter = 0;
Timer1 = Timer2 = 0.05F;
}
}

The code in the question is a mess, but ignoring this and trying to focus on the relevant parts: You can generate a random position for the first point, and a random direction, and then walk along this direction in several steps.
(This still raises the question of whether the direction is really not important. Wouldn't it matter if only the first bomb was dropped in the "valid" area, and the remaining ones outside of the screen?)
However, the relevant code could roughly look like this:
class Bombs
{
private final Random random = new Random(0);
int getScreenSizeX() { ... }
int getScreenSizeY() { ... }
// Method to drop a single bomb at the given position
void dropBombAt(double x, double y) { ... }
void dropBombs(int numberOfBombs, double distanceBetweenBombs)
{
// Create a random position in the screen
double currentX = random.nextDouble() * getScreenSizeX();
double currentY = random.nextDouble() * getScreenSizeY();
// Create a random step size
double directionX = random.nextDouble();
double directionY = random.nextDouble();
double invLength = 1.0 / Math.hypot(directionX, directionY);
double stepX = directionX * invLength * distanceBetweenBombs;
double stepY = directionY * invLength * distanceBetweenBombs;
// Drop the bombs
for (int i=0; i<numberOfBombs; i++)
{
dropBombAt(currentX, currentY);
currentX += stepX;
currentY += stepY;
}
}
}

I am assuming your startpoint is a StartPoint class with x,y,z coordinates as integers in it.
I hope I have understood your problem correctly. It looks like you either want to create a vertical explosion or a horizontal explosion. Since an explosion always occurs on ground, the z coordinate will be zero. Now you can vary one of x or y coordinate to give you a random explosion along a straight line. Whether you choose x or y could be fixed or could be randomized itself. A potential randomized solution below:
public boolean danger() {
// stuff
int orientation = Random.nextInt(2);
if(aircraft != null && (aircraft instanceof TypeBomber) && aircraft.getArmy() != myArmy)
{
// stuff
startPoint = randomizeStartPoint(orientation, startPoint);
// stuff
}
}
StartPoint randomizeStartPoint(int orientation, StartPoint startPoint) {
if(orientation == 0) {
startPoint.x += random.nextInt(40) - 20;
}
else {
startPoint.y += random.nextInt(40) - 20;
}
return startPoint;
}
In response to the image you uploaded, it seems that the orientation of the explosion need not necessarily be horizontal or vertical. So the code I posted above gives a limited solution to your problem.
Since you want any random straight line, your problem boils down to two sub parts:
1. Generate a random straight line equation.
2. Generate random point along this line.
Now, a straight line equation in coordinate geometry is y = mx + c where m is the slope and c is the constant where the line crosses the y-axis. The problem with c is that it gives rise to irrational coordinates. I am assuming you are looking for integer coordinates only, since this will ensure that your points are accurately plotted. (You could do with rational fractions, but then a fraction like 1/3 will still result in loss of accuracy). The best way to get rid of this irrational problem is to get rid of c. So now your straight line always looks like y = mx. So for step one, you have to generate a random m.
Then for step 2, you can either generate a random x or random y. It doesn't matter which one, since either one will result in random coordinates.
Here is a possible code for the solution:
int generateRandomSlope() {
return Random.nextInt(100); // arbitrarily chose 100.
}
int randomizeStartPoint(int m, StartPoint startPoint) { // takes the slope we generated earlier. without the slope, your points will never be on a straight line!
startPoint.x += random.nextInt(40) - 20;
startPoint.y += x * m; // because a line equation is y = mx
return startPoint;
}
public boolean danger() {
// stuff
int m = generateRandomSlope(); // you may want to generate this elsewhere so that it doesn't change each time danger() is called.
if(aircraft != null && (aircraft instanceof TypeBomber) && aircraft.getArmy() != myArmy)
{
// stuff
startPoint = randomizeStartPoint(m, startPoint);
// stuff
}
}
Again, this is not a complete or the best solution.

Catmull Rom Spline implementation (LibGDX)

I want to generate a random spline across my screen.
Here is what I have so far:
public class CurvedPath {
Random rn;
CatmullRomSpline<Vector2> curve;
float[] xPts;
float[] yPts;
Vector2[] points;
public CurvedPath(){
points = new Vector2[10];
rn = new Random();
curve = new CatmullRomSpline<Vector2>(points,false);
for(int i = 0 ; i < 10; i++){
xPts[i] = rn.nextFloat()*SampleGame.WIDTH;
yPts[i] = SampleGame.HEIGHT*i/10;
}
}
}
I'm pretty confused on the documentation that has been provided on how to use the CatmullRomSpline object ( https://github.com/libgdx/libgdx/wiki/Path-interface-&-Splines )
Basically what I am trying to do here is generate 10 random points equally distributed across the height of my screen, and randomly placed along the width of the screen to create a randomized curved path.
So within the constructor's for loop you can see that I generate the x and y values of each control point for the spline.
How can I give input these points into the spline object and render it on the screen?
-thanks
update
Let me reword my question to be a little more specific..
I have my control points represented by xPts and yPts. Now I want to get the points that fall along the spline, how do I do this using these two vectors? The constructor for a CatmullRomSpline takes a Vector2, not two float[] 's

what you did. Fill with points:
curve = new CatmullRomSpline<Vector2>(points,false);
To get a point on the curve:
Vector2 point = new Vector2();
curve.valueAt(point, 0.5f);
valueAt() Parameter explanation:
1 (point) the point you are looking for is stored in the Vector2 object.
float between 0 and 1, 0 is the first point, 1 the last one. 0.5f is middle. This float represents the hole distance from first to last point.
Getting and render 100 points can look like this:
Vector2 point = new Vector2();
for (int i = 0; i <= 100; i++) {
curve.valueAt(point, i * 0.01f);
// draw using point.x and point.y
}
answer to you edited question:
for(int i = 0 ; i < 10; i++){
points[i].x = rn.nextFloat()*SampleGame.WIDTH;
points[i].y = SampleGame.HEIGHT*i/10;
}
curve = new CatmullRomSpline<Vector2>(points,false);

The process is also detailed here: https://github.com/libgdx/libgdx/wiki/Path-interface-&-Splines
/*members*/
int k = 100; //increase k for more fidelity to the spline
Vector2[] points = new Vector2[k];
/*init()*/
CatmullRomSpline<Vector2> myCatmull = new CatmullRomSpline<Vector2>(dataSet, true);
for(int i = 0; i < k; ++i)
{
points[i] = new Vector2();
myCatmull.valueAt(points[i], ((float)i)/((float)k-1));
}

Maze, optimal path finding using stacks

i have a program that generates a random maze. In the maze a red dot is displayed and the red dot flashes on by each block in the maze. all the blocks in the maze are == 1 and if the red dot goes through that block, it increments ++. the red dot goes in the direction towards the lowest number, that way it wont stay in an infinite loop by a dead end. once it reaches the end, ive solved the maze.
This is where im stumped, im trying to print the red dot to find the optimal route all the way back to the beginning where it started. I used a stack class that i made to record all the y and x components of where the red dot traveled. im able to traceback every where the red dot has gone but that isnt the optimal solution.
My question is how could i print the red dot tracing back in only the optimal path. My idea of solving this would be to check and see if the coordinates of a stack where visited before, if so..find the last case where it was visited and print the red dot up until that point. that way itll never deal with the dead ends it traveled.
the method solve() is what contains the traceback and solving technique for the red dot to travel through the maze and back.
Im not the greatest programmer and im still learning how to use stacks, ive been stumped for hours and dont know how to approach this. Please be kind and explain how you would do it using the stack i made. Thank you
import java.awt.*;
import java.awt.event.*;
import java.awt.Graphics;
import javax.swing.*;
public class mazedfs extends JFrame implements KeyListener
{
/* default values: */
private static int bh = 16; // height of a graphical block
private static int bw = 16; // width of a graphical block
private int mh = 41; // height and width of maze
private int mw = 51;
private int ah, aw; // height and width of graphical maze
private int yoff = 40; // init y-cord of maze
private Graphics g;
private int dtime = 40; // 40 ms delay time
byte[][] M; // the array for the maze
public static final int SOUTH = 0;
public static final int EAST = 1;
public static final int NORTH = 2;
public static final int WEST = 3;
public static boolean showvalue = true; // affects drawblock
// args determine block size, maze height, and maze width
public mazedfs(int bh0, int mh0, int mw0)
{
bh = bw = bh0; mh = mh0; mw = mw0;
ah = bh*mh;
aw = bw*mw;
M = new byte[mh][mw]; // initialize maze (all 0's - walls).
this.setBounds(0,0,aw+10,10+ah+yoff);
this.setVisible(true);
this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
try{Thread.sleep(500);} catch(Exception e) {} // Synch with system
this.addKeyListener(this);
g = getGraphics(); //g.setColor(Color.red);
setup();
}
public void paint(Graphics g) {} // override automatic repaint
public void setup()
{
g.setColor(Color.green);
g.fill3DRect(0,yoff,aw,ah,true); // fill raised rectangle
g.setColor(Color.black);
// showStatus("Generating maze...");
digout(mh-2,mw-2); // start digging!
// digout exit
M[mh-1][mw-2] = M[mh-2][mw-1] = 1;
drawblock(mh-2,mw-1);
solve(); // this is the function you will write for parts 1 and 2
play(); // for part 3
}
public static void main(String[] args)
{
int blocksize = bh, mheight = 41, mwidth = 41; // need to be odd
if (args.length==3)
{
mheight=Integer.parseInt(args[0]);
mwidth=Integer.parseInt(args[1]);
blocksize=Integer.parseInt(args[2]);
}
mazedfs W = new mazedfs(blocksize,mheight,mwidth);
}
public void drawblock(int y, int x)
{
g.setColor(Color.black);
g.fillRect(x*bw,yoff+(y*bh),bw,bh);
g.setColor(Color.yellow);
// following line displays value of M[y][x] in the graphical maze:
if (showvalue)
g.drawString(""+M[y][x],(x*bw)+(bw/2-4),yoff+(y*bh)+(bh/2+6));
}
void drawdot(int y, int x)
{
g.setColor(Color.red);
g.fillOval(x*bw,yoff+(y*bh),bw,bh);
try{Thread.sleep(dtime);} catch(Exception e) {}
}
/////////////////////////////////////////////////////////////////////
/* function to generate random maze */
public void digout(int y, int x)
{
M[y][x] = 1; // digout maze at coordinate y,x
drawblock(y,x); // change graphical display to reflect space dug out
int dir = (int)(Math.random()*4);
for (int i=0;i<4;i++){
int [] DX = {0,0,2,-2};
int [] DY = {-2,2,0,0};
int newx = x + DX[dir];
int newy = y + DY[dir];
if(newx>=0 && newx<mw && newy>=0 && newy<mh && M[newy][newx]==0)
{
M[y+DY[dir]/2][x+DX[dir]/2] = 1;
drawblock(y+DY[dir]/2,x+DX[dir]/2);
digout(newy,newx);
}
dir = (dir + 1)%4;}
} // digout
/* Write a routine to solve the maze.
Start at coordinates x=1, y=1, and stop at coordinates
x=mw-1, y=mh-2. This coordinate was especially dug out
after the program called your digout function (in the "actionPerformed"
method).
*/
public void solve()
{
int x=1, y=1;
Stack yourstack = null;
drawdot(y,x);
while(y!=mh-2 || x!=mw-2 && M[y][x]!=0){
int min = 0x7fffffff;
int DX = 0;
int DY = 0;
if (y-1>0 && min>M[y-1][x] && M[y-1][x]!=0){
min = M[y-1][x];
DX = 0;
DY = -1;
}//ifNORTH
if (y+1>0 && min>M[y+1][x] && M[y+1][x]!=0){
min = M[y+1][x];
DY = 1;
DX = 0;
}//ifSOUTH
if (x-1>0 && min>M[y][x-1] && M[y][x-1]!=0){
min = M[y][x-1];
DX = -1;
DY = 0;
}//ifWEST
if (x+1>0 && min>M[y][x+1] && M[y][x+1]!=0){
min = M[y][x+1];
DX = 1;
DY = 0;
}//ifEAST
M[y][x]++;
drawblock(y,x);
x = x+DX;
y = y+DY;
drawdot(y,x);
yourstack = new Stack(y,x,yourstack); // creates new stack for each coordinate travelled
}//while
while(yourstack != null){
yourstack = yourstack.tail;
drawdot(yourstack.y,yourstack.x); // this will traceback every box ive been through
}//while
} // solve
class Stack{
int x;
int y;
Stack tail;
public Stack(int a, int b, Stack t){
y = a;
x=b;
tail=t;
}
}//stackclass
///////////////////////////////////////////////////////////////
/// For part three (save a copy of part 2 version first!), you
// need to implement the KeyListener interface.
public void play() // for part 3
{
// code to setup game
}
// for part 3 you may also define some other instance vars outside of
// the play function.
// for KeyListener interface
public void keyReleased(KeyEvent e) {}
public void keyTyped(KeyEvent e) {}
public void keyPressed(KeyEvent e) // change this one
{
int key = e.getKeyCode(); // code for key pressed
System.out.println("YOU JUST PRESSED KEY "+key);
}
} // mazedfs
////////////
// define additional classes (stack) you may need here.

when you trace your path back you currently just go back to your stack - but thats not the shortest path...
...whenever you can go back check the values of M around you:
byte valueOfFieldNorthOfXY = M[x][y-1]; //x/y is your current position
byte valueOfFieldWesthOfXY = M[x-1][y];
byte ...;
byte ...; //and so on...
while the first while-loop in your solve-methode simplay solves the maze by flooding it the second while-method is for going back...
and when i say flooding i mean: each time a field has been passed by the 'walker' the value of M[x][y] has been increased by 1 (when the 'walker' has walked 3x over field 5/6 then the value from M[5][6] = 3)
so when you go back from the end (#40/50) to the start (#1/1), you do this algorith:
1) i stand on x/y
2) i check the values north/east/south/west of me
2a) if i come from north, then i ignore the north field
2 ) ... and so on...
2d) if i come from west , then i ignore the west field
3) i pick that direction, where the value is the least
4) put the current field int your packPathStack and walk to
the 'best' direction
5) repeat (go back to Nr.1) until you are #1/1
example
? 4 ? //i'm standing at X (x/y)
2 x f //? are values from walls or not yet considerd
? ? ? //f is where i come from
--> i pick direction WEST(2) because thats less than NORTH(4)
implement this algorithm and you a NEW stack i call it yourPathBackStack
Stack yourPathBackStack = new Stack();
while(x != 1 && y != 1 ){ //x/y = 1/1 = start - do it until you are there (Nr. 5)
// 1) i stand on x/y
int x = yourPathBackStack.x;
int y = yourPathBackStack.y;
// 2) i check the values north/east/south/west of me
byte valueOfFieldNorthOfXY = ... ; //as seen above
// 2a) if i come from north, then i ignore the north field
if (yourstack.tail.x == x && yourstack.tail.y == y-1){
//check - i DO come from north
//make then valueOfFieldNorthOfXY very high
valueOfFieldNorthOfXY = 100; //it's the same as ignoring
}
// 2 ) ... and so on...
// 2d) if i come from west , then i ignore the west field
if (yourstack.tail.x == x-1 && ...// as seen above
// 3) i pick that direction, where the value is the least
int direction = NORTH; //lets simply start with north;
byte maxValue = 100;
if ( valueOfFieldNorthOfXY < maxValue ){ //First north
maxValue = valueOfFieldNorthOfXY;
direction = NORTH;
}
if ( valueOfFieldWestOfXY < maxValue ){ //Then east
maxValue = valueOfFieldWestOfXY ;
direction = WEST;
}
//then the also other directions
if ( value ... //as seen above
// 4) put the current field int your yourPathBackStack and walk to
// the 'best' direction
int newx = x;
int newy = y;
if (direction == NORTH){ //direction has been caclulated above
newy = newy - 1;
}
if (direc ... //with all other direction)
yourPathBackStack = new Stack(newx, newy, yourPathBackStack );
drawdot(yourPathBackStack.y,yourPathBackStack.x);
}

Slow map in java

I'm making a game in java, is a rpg, however, only with the map the game is slow.
The map is made ​​in TiledMap Editor, therefore, an XML that is read and loaded into an ArrayList. My PC is a dual-core 3.0, 4GB RAM, 1GB Video.
The do the rendering is done as follows:
//method of tileset class
public void loadTileset(){
positions = new int[1 + tilesX * tilesY][2];
int yy = 0;
int xx = 0;
int index = 0;
// save the initial x and y point of each tile in an array named positions
// positions[tileNumber] [0] - X position
// positions[tileNumber] [1] - Y position
for(int i = 1 ; i < positions.length; i++){
if(index == tilesX ){
yy += tileHeight;
xx = 0;
index = 0;
}
positions[i][0] = xx;
positions[i][1] = yy;
xx += tileWidth;
index++;
}
}
//method of map class
public void draw(Graphics2D screen){
//x and y position of each tile on the screen
int x = 0; int y = 0;
for(int j = 0; j < 20 ; j++){
for(int i = initialTile ; i < initialTile + quantTiles ; i++){
int tile = map[j][i];
if(tile != 0){
screen.drawImage(tileSet.getTileImage().getSubimage(tileSet.getTileX(tile), tileSet.getTileY(tile),tileSet.getTileWidth(), tileSet.getTileHeight()),x,y,null);
}
x += tileSet.getTileWidth();
}
x = 0;
y += tileSet.getTileHeight();
}
}
Am I doing something wrong?
Note: I'm new to the forum and to make matters worse I do not understand very much English, so excuse any mistake.

First of all, you should not create the subimages for the tiles during each call. Strictly speaking, you should not call getSubimage at all for images that you want to paint: It will make the image "unmanaged", and this can degrade rendering performance by an order of magnitude. You should only call getSubimage for images that you do not want to render - for example, when you are initially creating individual images for the tiles.
You obviously already have a TileSet class. You could add a bit of functionality to this class so that you can directly access images for the tiles.
Your current code looks like this:
screen.drawImage(
tileSet.getTileImage().getSubimage(
tileSet.getTileX(tile),
tileSet.getTileY(tile),
tileSet.getTileWidth(),
tileSet.getTileHeight()),
x,y,null);
You could change it to look like this:
screen.drawImage(tileSet.getTileImage(tile), x,y,null);
The getTileImage(int tile) method suggested here could then obtain tiles that have been stored internally.
I'll sketch a few lines of code from the tip of my head, you'll probably be able to transfer this into your TileSet class:
class TileSet
{
private Map<Integer, BufferedImage> tileImages;
TileSet()
{
....
prepareTileImages();
}
private void prepareTileImages()
{
tileImages = new HashMap<Integer, BufferedImage>();
for (int tile : allPossibleTileValuesThatMayBeInTheMap)
{
// These are the tiles that you originally rendered
// in your "draw"-Method
BufferedImage image =
getTileImage().getSubimage(
getTileX(tile),
getTileY(tile),
getTileWidth(),
getTileHeight());
// Create a new, managed copy of the image,
// and store it in the map
BufferedImage managedImage = convertToARGB(image);
tileImages.put(tile, managedImage);
}
}
private static BufferedImage convertToARGB(BufferedImage image)
{
BufferedImage newImage = new BufferedImage(
image.getWidth(), image.getHeight(),
BufferedImage.TYPE_INT_ARGB);
Graphics2D g = newImage.createGraphics();
g.drawImage(image, 0, 0, null);
g.dispose();
return newImage;
}
// This is the new method: For a given "tile" value
// that you found at map[x][y], this returns the
// appropriate tile:
public BufferedImage getTileImage(int tile)
{
return tileImages.get(tile);
}
}