public void rotateImage90(){
this.redisplayImage();
for (int x = 0; x < this.image.length; x++)
for (int y = 0; y < this.image[0].length; y++){
this.image[x][y] = this.image[this.image.length-1-x][y];
}
}
I dont know what to do from here to rotate an image 90 degrees. Please help if u can
Here is one way to do it. There may be better ways using an AffineTransForm. This method does not explicitly rotate the source image but rotates the target graphics context, and then writes the image to that.
read in the source image. In this case into buf.
extract the dimensions.
create the target rotated BufferedImage (output) reversing the source dimensions and copying the image type (JPEG, PNG, etc).
Now get the graphics context for the output image.
Since you want to rotate about the center, translate to the target center anchors and then rotate in radians to 90 degrees (Math.PI/2).
Now get ready to write the source image (buf) into the rotated context of (output). However, the anchors need to be retranslated to the starting position for the source file (buf). So translate back but reverse the width and height anchors to match the width and height of the source file.
then draw the original image (buf) into the context rotated buffered image (output).
And write the rotated image (output) to the file system
try {
BufferedImage buf =
ImageIO.read(new File("f:/sourceImage.jpg"));
int width = buf.getWidth();
int height = buf.getHeight();
BufferedImage output = new BufferedImage(height, width, buf.getType());
Graphics2D g2d = (Graphics2D)output.getGraphics();
g2d.translate(height/2., width/2.);
g2d.rotate(Math.PI/2);
g2d.translate(-width/2., -height/2.);
g2d.drawImage(buf, 0,0,width, height,null);
ImageIO.write(output, "JPEG", new File("f:/rotatedImage.jpg"));
} catch (Exception e) {
e.printStackTrace();
}
Related
I create an image that is an extract of a PDF and i make an OCR with tesseract on it. Everything works good until a decide to change the dpi of my image. I was excpecting to have an error by doing this and i tried to rescale my image in order to make my OCR work well again.
I have no idea about how I can rescale my image. I know there is some methods with the BufferedImage class but i can't find a way to dynamicly rescale it.
I don't know if I'm clear but imagine a 300 dpi image. If I want to change it to 600 I have to rescale my image to make my OCR work again, my question here is how can I rescale it dynamicly ? Is there a sort of a ratio between the original dpi and the new one that i can use to get a new width and height? Or something else?
To help you understand me here is my code:
public double ratioDPI() {
int ratio = 0;
int minimal_dpi = 300;
int dpi = ERXProperties.intForKey("dpi.image");
return ratio = (dpi/minimal_dpi);
}
public BufferedImage rescale(BufferedImage img) {
int width_img = img.getWidth();
int height_img = img.getHeight();
double factor_width = ERXProperties.doubleForKey("factor.size.width.image.republique.francaise");
double factor_height = ERXProperties.doubleForKey("factor.size.height.image.republique.francaise");
return (BufferedImage) img.getScaledInstance((int)(width_img*ratio), (int)(height_img*ratio), BufferedImage.SCALE_SMOOTH);
}
If you change the DPI of an image, you change the size when outputting it to a printer, for example. If you increase the DPI from 300 to 600, the image in the output only takes up half the width and half the height. If you resize the picture now it only takes up more memory, the quality of the picture would not be better.
For scaling it is best to use AffineTransform, so you can filter the image bilinear so that the pixelation is not so noticeable:
A scaling function:
public static BufferedImage scale(BufferedImage source, double scale, boolean bilinearFiltering){
try{
BufferedImage destination = new BufferedImage((int)(source.getWidth() * scale), (int)(source.getHeight() * scale), source.getType());
AffineTransform at = new AffineTransform();
at.scale(scale, scale);
AffineTransformOp scaleOp = new AffineTransformOp(at, getInterpolationType(bilinearFiltering));
return scaleOp.filter(source, destination);
}
catch (Exception e) {
e.printStackTrace();
return null;
}
}
private static int getInterpolationType(boolean bilinearFiltering){
return bilinearFiltering ? AffineTransformOp.TYPE_BILINEAR : AffineTransformOp.TYPE_NEAREST_NEIGHBOR;
}
Maybe that's a solution for you.
I am trying to get the value of the White Colored pixel from a GrayScale image and replace it with another Color but when I run my code, the whole GrayScale image is transfered to another Color. Can anyone please tell me where is fault in the code or how can I get my desired results??
This is the code...
public class gray {
public static void main (String args[])throws IOException{
int width;
int height;
BufferedImage myImage = null;
File f = new File("E:\\eclipse\\workspace\\Graphs\\src\\ColorToGray\\1.png");
myImage = ImageIO.read(f);
width = myImage.getWidth();
height = myImage.getHeight();
BufferedImage image = new BufferedImage(width,height,BufferedImage.TYPE_INT_ARGB);
int pixels[];
pixels = new int[width * height];
myImage.getRGB(0, 0, width, height, pixels, 0, width);
for (int i = 0; i < pixels.length; i++) {
if (pixels[i] == 0xFFFFFF) {
pixels[i] = 0x000000FF;
}
}
File f2 = new File("E:\\eclipse\\workspace\\Graphs\\src\\ColorToGray\\out 1.png");
image.setRGB(0, 0, width, height, pixels, 0, width);
ImageIO.write( image, "jpg", f2);
}
}
Image Before:
Image Before Output
Image After:
Image After Output
I looked into it, and found a bunch of problems.
First of all, when specifying the filename to save, you supply a ".png" extension, but when you call the ImageIO.write() function, you specify file type "jpg". That tends not to work very well. If you try to open up the resulting file, most programs will give you a "this is not a valid .PNG file" error. Windows explorer tries to be smart, and re-interprets the .PNG as a .JPG, but this spared you from the chance of discovering your mistake.
This takes care of the strange redness problem.
However, if you specify "png" in ImageIO.write(), you still don't get the right image. One would expect an image that looks mostly like the original, with just a few patches of blue there where bright white used to be, but instead what we get is an overall brighter version of the original image.
I do not have enough time to look into your original image to find out what is really wrong with it, but I suspect that it is actually a bright image with an alpha mask that makes it look less bright, AND there is something wrong with the way the image gets saved that strips away alpha information, thus the apparent added brightness.
So, I tried your code with another image that I know has no tricks in it, and still your code did not appear to do anything. It turns out that the ARGB format of the int values you get from myImage.getRGB(); returns 255 for "A", which means that you need to be checking for 0xFFFFFFFF, not 0x00FFFFFF.
And of course when you replace a value, you must replace it with 0xFF0000FF, specifying a full alpha value. Replacing a pixel with 0x000000FF has no visible effect, because regardless of the high blue value, alpha is zero, so the pixel would be rendered transparent.
double degPi = degrees * Math.PI / 180;
double a = Math.cos(degPi)*tImgCover.getScaledHeight();
double b = Math.sin(degPi)*tImgCover.getScaledWidth();
double c = -Math.sin(degPi) * tImgCover.getScaledHeight();
double d = Math.cos(degPi)* tImgCover.getScaledWidth();
double e = absX;
double f = absY;
contentByte.addImage(imgae, a, b, c, d, e, f);/*add image*/
How to rotate around the image center by itext?
If we have an Image image and coordinates x, y, we can draw the image without rotation with its lower left corner at the given coordinates like this
contentByte.addImage(image, image.getWidth(), 0, 0, image.getHeight(), x, y);
A bitmap image from the resources has a size of 1x1 with the coordinate origin at its lower left. Thus, this operation stretches the image to its correct size and moves it so its lower left is at the given coordinates.
If we want to draw the same image as if the one drawn above was rotated around its center by an angle rotate, therefore, we can do this by moving the 1x1 image so that the origin is in its center, stretch it to its correct size, rotate it, and then move the origin (which still is at the center of the rotated image) to the center of the unrotated image. These operations are easier to express using AffineTransform instances (from package com.itextpdf.awt.geom) instead number tupels. Thus:
// Draw image as if the previous image was rotated around its center
// Image starts out being 1x1 with origin in lower left
// Move origin to center of image
AffineTransform A = AffineTransform.getTranslateInstance(-0.5, -0.5);
// Stretch it to its dimensions
AffineTransform B = AffineTransform.getScaleInstance(image.getWidth(), image.getHeight());
// Rotate it
AffineTransform C = AffineTransform.getRotateInstance(rotate);
// Move it to have the same center as above
AffineTransform D = AffineTransform.getTranslateInstance(x + image.getWidth()/2, y + image.getHeight()/2);
// Concatenate
AffineTransform M = (AffineTransform) A.clone();
M.preConcatenate(B);
M.preConcatenate(C);
M.preConcatenate(D);
//Draw
contentByte.addImage(image, M);
(AddRotatedImage.java test method testAddRotatedImage)
For example drawing both images using
int x = 200;
int y = 300;
float rotate = (float) Math.PI / 3;
results in something like this:
With a Flip
The OP asked in a comment
how to add rotate and flip image?
For this you simply insert a mirroring affine transformation into the sequence of transformations above.
Unfortunately the OP did not mention which he meant a horizontal or a vertical flip. But as changing the rotation angle accordingly transforms one in the other, that isn't really necessary, either.
// Draw image as if the previous image was flipped and rotated around its center
// Image starts out being 1x1 with origin in lower left
// Move origin to center of image
AffineTransform A = AffineTransform.getTranslateInstance(-0.5, -0.5);
// Flip it horizontally
AffineTransform B = new AffineTransform(-1, 0, 0, 1, 0, 0);
// Stretch it to its dimensions
AffineTransform C = AffineTransform.getScaleInstance(image.getWidth(), image.getHeight());
// Rotate it
AffineTransform D = AffineTransform.getRotateInstance(rotate);
// Move it to have the same center as above
AffineTransform E = AffineTransform.getTranslateInstance(x + image.getWidth()/2, y + image.getHeight()/2);
// Concatenate
AffineTransform M = (AffineTransform) A.clone();
M.preConcatenate(B);
M.preConcatenate(C);
M.preConcatenate(D);
M.preConcatenate(E);
//Draw
contentByte.addImage(image, M);
(AddRotatedImage.java test method testAddRotatedFlippedImage)
The result with the same image as above:
With Interpolation
The OP asked in a yet another comment
How anti aliasing ?
The iText Image class knows an Interpolation property. By setting it to true (before adding the image to the document, obviously),
image.setInterpolation(true);
low resolution images are subject to interpolation when drawn.
E.g. using a 2x2 image with differently colored pixels instead of the image of Willi, you get the following results, first without interpolation, then with interpolation:
Confer the AddRotatedImage.java test testAddRotatedInterpolatedImage which adds this image:
Beware: iText Image property Interpolation effectively sets the Interpolate entry in the PDF image dictionary. The PDF specification notes in this context:
NOTE A conforming Reader may choose to not implement this feature of PDF, or may use any specific implementation of interpolation that it wishes.
Thus, on some viewers interpolation may occur differently than in your viewer, maybe even not at all. If you need a specific kind of interpolation on every viewer, upscale the image with the desired amount of interpolation / anti-aliasing before loading it into an iText Image.
public static BufferedImage rotateClockwise90( BufferedImage inputImage ){
int width = inputImage.getWidth();
int height = inputImage.getHeight();
BufferedImage returnImage = new BufferedImage( height, width , inputImage.getType() );
for( int x = 0; x < width; x++ ) {
for( int y = 0; y < height; y++ ) {
returnImage.setRGB( height-y-1, x, inputImage.getRGB( x, y ) );
}
}
return returnImage;
}
Currently I am saving a jtable as jpeg using the below method, when the dimension of the jtable became 2590, 126181, java.lang.OutOfMemoryError: Java heap space exception occurs at "BufferedImage constructor", when the size of the table is small the image gets saved successfully.
public BufferedImage saveComponentAsJPEG(JTable table, String filename) {
Dimension size = table.getSize();
BufferedImage myImage =
new BufferedImage(size.width, size.height,
BufferedImage.TYPE_INT_RGB);
Graphics2D g2 = myImage.createGraphics();
table.paint(g2);
return myImage;
}
How to save a jtable with bigger size in pdf or jpeg image?
Updated Info:
You asked how to "split the JTable into different small images":
As you go through my code below please read my comments, they help explain what is happening and will help you grasp a better understanding of how a JTable/JComponent can be painted to lots of small images. At the heart my code is similar to yours, but there are two key points:
1) Rather than create a single large BufferedImage, I create a single small image that is then used multiple times, therefore leaving a very small memory footprint.
2) With the single image, I use Graphics.translate() to paint a small part of the JTable each time.
The following code was tested with a large JComponents (2590 x 126181) and a tile size of 200x200, and the whole process did not exceed 60mb of memory:
//width = width of tile in pixels, for minimal memory usage try 200
//height = height of tile in pixels, for minimal memory usage try 200
//saveFileLocation = folder to save image tiles
//component = The JComponent to save as tiles
public static boolean saveComponentTiles(int width, int height, String saveFileLocation, JComponent component)
{
try
{
//Calculate tile sizes
int componentWidth = component.getWidth();
int componentHeight = component.getHeight();
int horizontalTiles = (int) Math.ceil((double)componentWidth / width); //use (double) so Math.ceil works correctly.
int verticalTiles = (int) Math.ceil((double)componentHeight / height); //use (double) so Math.ceil works correctly.
System.out.println("Tiles Required (H, W): "+horizontalTiles+", verticalTiles: "+verticalTiles);
//preset arguments
BufferedImage image;
//Loop through vertical and horizontal tiles
//Draw part of the component to the image
//Save image to file
for (int h = 0; h < verticalTiles; h++)
{
for (int w = 0; w < horizontalTiles; w++)
{
//check tile size, if area to paint is smaller than image then shrink image
int imageHeight = height;
int imageWidth = width;
if (h + 1 == verticalTiles)
{
imageHeight = componentHeight - (h * height);
}
if (w + 1 == horizontalTiles)
{
imageWidth = componentWidth - (w * width);
}
image = new BufferedImage(imageWidth, imageHeight, BufferedImage.TYPE_INT_ARGB);
Graphics g = image.getGraphics();
//translate image graphics so that only the correct part of the component is panted to the image
g.translate(-(w * width), -(h * height));
component.paint(g);
//In my example I am saving the image to file, however you could throw your PDF processing code here
//Files are named as "Image.[h].[w]"
//Example: Image 8 down and 2 accross would save as "Image.8.2.png"
ImageIO.write(image, "png", new File(saveFileLocation + "Image." + h +"."+ w + ".png"));
//tidy up
g.dispose();
}
}
return true;
}
catch (IOException ex)
{
return false;
}
}
Just call it like so:
boolean result = saveComponentTiles(200, 200, saveFileLocation, jTable1);
Also if you haven't done it already, you should only call the method from a different thread because it will hang your application when dealing with large components.
If you have not picked a PDF library yet, then I highly recommend looking at iText.
Original Post:
The process you are looking for is quite simple, however it may take some work.
You were on the right track thinking about parts, but as David
mentioned you shouldn't mess with the jTable, instead you will need a
to make use of the TiledImage class, or do something yourself with
RenderedImage and Rasters.
This sort of method basically uses HDD space instead of memory and
lets you create a large image in lots of smaller parts/tiles, then
when its done you can save it all to a single image file.
This answer may also help: https://stackoverflow.com/a/14069551/1270000
I am aware of BufferedImage.getSubimage However, it cant deal with cropping images that are smaller than the cropping size throwing the exception:
java.awt.image.RasterFormatException: (y + height) is outside raster
I want to be able to crop either a PNG/JPG/GIF to a certain size however if the image is smaller than the cropping area centre itself on a white background. Is there a call to do this? Or do I need to create an image manually to centre the image on if so, how would I go about this?
Thanks
You cannot crop an image larger, only smaller. So, you start with the goal dimension,let's say 100x100. And your BufferedImage (bi), let's say 150x50.
Create a rectangle of your goal:
Rectangle goal = new Rectangle(100, 100);
Then intersect it with the dimensions of your image:
Rectangle clip = goal.intersection(new Rectangle(bi.getWidth(), bi.getHeight());
Now, clip corresponds to the portion of bi that will fit within your goal. In this case 100 x50.
Now get the subImage using the value of clip.
BufferedImage clippedImg = bi.subImage(clip,1, clip.y, clip.width, clip.height);
Create a new BufferedImage (bi2), the size of goal:
BufferedImage bi2 = new BufferedImage(goal.width, goal.height);
Fill it with white (or whatever bg color you choose):
Graphics2D big2 = bi2.getGraphics();
big2.setColor(Color.white);
big2.fillRect(0, 0, goal.width, goal.height);
and draw the clipped image onto it.
int x = goal.width - (clip.width / 2);
int y = goal.height - (clip.height / 2);
big2.drawImage(x, y, clippedImg, null);