How can I output the points that are colinear? - java

THE PROBLEM: Write a program that reads N points in a plane and outputs any group of four or more colinear points
What I did: I calculated the slope of every 2 points and then put them in a hashmap to see which one is the max.
What I need to do: I need to output the points that are colinear from the initial 2D array. I found the number of points that are colinear with the hashmap.
import java.util.*;
public class app {
public static int maxPoints(int[][] points) {
int ans = 1;
int n = points.length;
for (int i = 0; i < n; i++) {
HashMap<String, Integer> map = new HashMap<>();
int OLP = 0;
int max = 0;
for (int j = i + 1; j < n; j++) {
if (points[i][0] == points[j][0] && points[i][1] == points[j][1]) {
OLP++;
continue;
}
int dy = points[j][1] - points[i][1];
int dx = points[j][0] - points[i][0];
int g = gcd(Math.abs(dy), Math.abs(dx));
int num = dy / g;
int deno = dx / g;
if (num == 0)
deno = 1;
if (deno == 0)
num = 1;
if ((num < 0 && deno < 0) || deno < 0) {
num *= -1;
deno *= -1;
}
map.put(createString(deno, num), map.getOrDefault(createString(deno, num), 0) + 1);
max = Math.max(max, map.get(createString(deno, num)));
}
ans = Math.max(ans, 1 + OLP + max);
}
return ans;
}
public static int gcd(int a, int b) {
if (a == 0)
return b;
if (b == 0)
return a;
int max = Math.max(a, b);
int min = Math.min(a, b);
return gcd(max % min, min);
}
public static String createString(int a, int b) {
return Integer.toString(a) + " " + Integer.toString(b);
}
public static void main(String[] args) {
int[][] points = { { 1, 1 }, { 2, 2 }, { 3, 3 }, { 4, 4 }, { 5, 4 } };
System.out.println("max Points are: " + maxPoints(points));
}}

Related

How can I use values stored in an array to another method to do a calculation?

static void diceRoll(int[] val) {
for (int i=0;i<6;i++) {
int roll1 = (int) ((Math.random() * 1000 % 6 + 1));
int roll2 = (int) ((Math.random() * 1000 % 6 + 1));
int roll3 = (int) ((Math.random() * 1000 % 6 + 1));
int roll4 = (int) ((Math.random() * 1000 % 6 + 1));
int total =0;
if ((roll1 < roll2) && (roll1 < roll3) && (roll1 < roll4)) {
total= roll2 + roll3 + roll4;
} else if ((roll2 < roll1) && (roll2 < roll3) && (roll2 < roll4)) {
total= roll1 + roll3 + roll4;
} else if ((roll3 < roll1) && (roll3 < roll2) && (roll3 < roll4)) {
total = roll1 + roll2 + roll4;
} else if ((roll4 < roll1) && (roll4 < roll2) && (roll4 < roll3)) {
total = roll1 + roll2 + roll3;
}
}
}
static void calculateBonus(int[] bonusVal){
int bonus=0;
int[] val= new int[6];
for (int i=0;i<6;i++)
for(int j=0;j<6;j++)
if (val[i] > 10 && val[i] != 11) {
bonusVal[j] = (val[i] - 10) / 2;
} else if (val[i] < 10) {
bonusVal[j] = ((val[i] / 2) - 5);
} else if (val[i] == 10 || val[i] == 11) {
bonusVal[j] = 0;
}
}
public static void main(String[]args){
Scanner sc = new Scanner(System.in);
//Declaring variables
int level;
String choice = null;
//Getting the Level value
System.out.println("Enter the Level value :");
level = sc.nextInt();
while ((level<=0)||(level>20)){
System.out.println("Invalid input.Please enter a number between 1-20.");
System.out.println("Enter the Level value : ");
level = sc.nextInt();
}
do{
int[] val= new int[6];
int _str= val[0];
int con= val[1];
int dex= val[2];
int _int= val[3];
int wis= val[4];
int _cha= val[5];
int [] bonusVal=new int[6];
int bonus1= bonusVal[0];
int bonus2= bonusVal[1];
int bonus3= bonusVal[2];
int bonus4= bonusVal[3];
int bonus5= bonusVal[4];
int bonus6= bonusVal[5];
//Printing the Level
System.out.println("\n\n\n\n\nLevel : [ "+level+" ]");
//Displaying out put
System.out.println("_Str : ["+_str+" ]"+"["+bonus1+"]");
System.out.println("Dex : ["+dex+" ]"+"["+bonus2+"]");
System.out.println("Con : ["+con+" ]"+"["+bonus3+"]");
System.out.println("Int : ["+_int+" ]"+"["+bonus4+"]");
System.out.println("Wis : ["+wis+" ]"+"["+bonus5+"]");
System.out.println("_Cha : ["+_cha+" ]"+"["+bonus6+"]");
//Calculating the Hit points
double hp = (((Math.random()*1000 %6+1)+bonus3)*level);
//Print the Hit points
System.out.println("HP : ["+hp+"]");
//Give the chance to re-roll or continue
System.out.println("Type r if you want to re-roll or any other character if you want to continue :");
choice = sc.next();
}
while (choice.equals("r"));;
}
}
I think i had made mistakes in the second method .I want to figure out how can i use above stored values in the array to calcuate bonus and store the values for bonus in another array.This is the program i have so far.I still didnt got the output i neede.I need to get 6 values from dice roll method and store them in an array.and then i want to call the values to calculate bonus and store those bonus values in another array.
I think you want to do something like below. I haven't compiled the code, let me know if you face any issues in compiling.
static int[] calculateBonus(int[] val) {
int[] bonusVal = new int[val.length];
for(int j=0; j < val.length; j++) {
if (val[j] > 10 && val[j] != 11) {
bonus[j] = (val[j] - 10) / 2;
} else if (val[j] < 10) {
bonus[j] = ((val[j] / 2) - 5);
} else if (val[j] == 10 || val[j] == 11) {
bonus[j] = 0;
}
}
return bonusVal;
}
You need to return an array from the first method to start with, right now it doesn't work with an array at all.
Change it to the below to return an array and have a new array variable
static int[] diceRoll() {
final int rolls = 6;
int[] result = new int[rolls];
//the for loop...
at the end of the for loop you store the value in the array and then at the end return the array so the end of the method will look like
result[i] = total;
}
return result;
}
The calculateBonus will use this returned array as input and it will also work internally with an array and not an int as you have now. I also added that it will return an array.
static int[] calculateBonus(int[] val){
int count = val.length;
int[] bonus = new int[count];
for(int j=0;j<count;j++) {
if (val[j] > 10 && val[j] != 11) {
bonus[j] = (val[j] - 10) / 2;
} else if (val[j] < 10) {
bonus[j] = ((val[j] / 2) - 5);
} else if (val[j] == 10 || val[j] == 11) {
bonus[j] = 0;
}
}
return bonus;
}
A simple run
public static void main(String[] args) {
int[] values = diceRoll();
int[] bonus = calculateBonus(values);
for(int i=0; i<bonus.length; i++) {
System.out.println(bonus[i]);
}
}
Update
Below is a new version of the two methods that addresses the questions I asked in the comment and also clean up the code some.
Main difference is that I use a ArrayList in the diceRole method and that calculateBonus now uses double.
static int[] diceRoll() {
int[] result = new int[6];
for (int i=0;i<6;i++) {
List<Integer> list = new ArrayList<>();
for (int j = 0; j < 4; j++) {
list.add(new Integer((int) ((Math.random() * 1000 % 6 + 1))));
}
Collections.sort(list); //list is now in ascending order
int total =0;
for (int j = 1; j < list.size(); j++) {
total += list.get(j).intValue();
}
result[i] = total;
}
return result;
}
static double[] calculateBonus(int[] val) {
int count = val.length;
double[] bonus = new double[count];
for(int j=0;j<count;j++) {
double value = 0.0;
if (val[j] > 11) {
value = (val[j] - 10.0) / 2.0;
} else if (val[j] < 10.0) {
value = ((val[j] / 2.0) - 5.0);
}
bonus[j] = value;
}
return bonus;
}

Finding the largest Odd Fibonacci number in the given ranges of values

Ex: n1=100, n2=250, out=233.
Here I have to find the largest odd fibonacci number in the given set of ranges. If an odd fibonacci number doesn't exist then it should return 0. I am getting output as 50 times 0's and then 10 times 233. Where is my mistake and how can I get the desired output?
public class Fibo {
public static void main(String[] args) {
try {
int n1 = 100;
int n2 = 250;
int res = 0;
if (n1 % 2 == 0) {
n1 += 1;
for (int i = n1; i < n2; i += 2) {
if (isPerfectSquare(5 * i * i + 4) || isPerfectSquare(5 * i * i - 4))
res = i;
System.out.println(res);
}
}
} catch(Exception ignored) {
System.out.println("0");
}
}
public static boolean isPerfectSquare(int num) {
double sqrt = Math.sqrt(num);
int x = (int)sqrt;
return Math.pow(sqrt, 2) == Math.pow(x, 2);
}
}
public class Fibonacci {
public static void main(String[] args) {
System.out.println("Enter the starting range");
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
System.out.println("Enter the ending range");
int r = sc.nextInt();
int res = 0;
for (int i = n; i <= r; i++) {
if (isPerfectSquare(5 * i * i + 4) || isPerfectSquare(5 * i * i - 4))
res = i;
}
System.out.println("The biggest odd number in the range is"+" "+res);
}
public static boolean isPerfectSquare(int num) {
double sqrt = Math.sqrt(num);
int x = (int)sqrt;
return Math.pow(sqrt, 2) == Math.pow(x, 2);
}
}
public static int getLargestOddFibonacciBetween(int lo, int hi) {
assert lo <= hi;
int f0 = 0;
int f1 = 1;
int res = -1;
while (f1 <= hi) {
int val = f0 + f1;
f0 = f1;
f1 = val;
if (val >= lo && val <= hi && isOdd(val))
res = val;
}
return res;
}
private static boolean isOdd(int val) {
return (val & 1) == 1;
}

splitting binary string such that it is a power of 5

I am trying to split a binary string such that it is a possible to cut string into smallest positive integer, each of them being the power of 5. If there is no such pieces return -1 instead.
public class Power {
public int numsOfWays(String s) {
long[] f = new long[s.length() + 1];
f[0] = 0;
for (int i = 1; i <= s.length(); ++i) {
f[i] = Integer.MAX_VALUE;
for (int j = 1; j <= i; ++j) {
if (s.charAt(j - 1) == '0') {
continue;
}
int num = Integer.parseInt(s.substring(j - 1, i), 2);
if (isPower(num)) {
f[i] = Math.min(f[i], f[j - 1] + 1);
}
}
}
return f[s.length()] == Integer.MAX_VALUE ? -1 : (int) f[s.length()];
}
private boolean isPower(long val) {
if (val == 0) {
return false;
}
int n = (int) (Math.log(val) / Math.log(5));
return Math.pow(5, n) == val;
}
public static void main(String[] args) {
Power b = new Power();
System.out.println(b.numsOfWays("111011100110101100101110111"));
}
}
I am getting this error :-
Exception in thread "main" java.lang.NumberFormatException: For input string: "11101110011010110010111011100000"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:583)
at abc.Power.numsOfWays(Power.java:13)
at abc.Power.main(Power.java:33)
The Problem is in Line 13 of your code:
The line:
int num = Integer.parseInt(s.substring(j - 1, i), 2);
has a problem because the value is too long for intto handle.
Change it to:
long num = Long.parseLong(s.substring(j - 1, i), 2);
and it should work.
EDIT: The Entire Code looks like this:
public class Power {
public int numsOfWays(String s) {
long[] f = new long[s.length() + 1];
f[0] = 0;
for (int i = 1; i <= s.length(); ++i) {
f[i] = Integer.MAX_VALUE;
for (int j = 1; j <= i; ++j) {
if (s.charAt(j - 1) == '0') {
continue;
}
long num = Long.parseLong(s.substring(j - 1, i), 2);
if (isPower(num)) {
f[i] = Math.min(f[i], f[j - 1] + 1);
}
}
}
return f[s.length()] == Integer.MAX_VALUE ? -1 : (int) f[s.length()];
}
private boolean isPower(long val) {
if (val == 0) {
return false;
}
int n = (int) (Math.log(val) / Math.log(5));
return Math.pow(5, n) == val;
}
public static void main(String[] args) {
Power b = new Power();
System.out.println(b.numsOfWays("111011100110101100101110111")); // 5
System.out.println(b.numsOfWays("11111111111111111111111111111111111111111111111111")); // 50
}
}
And the output is:
5
50

Big integer multiplication in java

This is my own method and I am also using my own BigInt class I did everything but I cannot seem to find out where I am doing wrong if someone can help me, I will be really thankful.
public BigInt mul(BigInt o) {
int max = n.length > o.n.length ? n.length : o.n.length;
int[] newdigits = new int[n.length + o.n.length];
for (int i = 0; i < max; i++)
{
int carry = 0;
for (int i2 = 0; i2 < o.n.length || carry > 0; i2++)
{
int otherDigit = i2 >= o.n.length ? 0: o.n[i2];
int val = (n[i] * otherDigit) + carry;
newdigits[i + i2] += val % 10;
carry = val / 10;
}
}
return new BigInt(newdigits);
}
This is my code so far it works but in the result i get one extra zero, as an example: when i multiply 100*10 I get 01000 instead of 1000 and other issue is that when i multiply 9999*1999 I get this: 1817262619101 but the correct answer is 19988001.
Can some one help me on this?
Here is my BigInt class:
public class BigInt {
public static void main(String[] args) {
BigInt a = new BigInt(args.length == 2 ? args[0] : "9999");
BigInt b = new BigInt(args.length == 2 ? args[1] : "1999");
System.out.println(a + (a.equals(b) ? " equals " : " does not equal ") + b);
System.out.println(a + (a.compareTo(b) < 0 ? " < " : (a.compareTo(b) > 0 ? " > " : " = ")) + b);
System.out.println(a + " + " + b + " = " + a.add(b));
if (a.compareTo(b) >= 0) {
System.out.println(a + " - " + b + " = " + a.sub(b));
}
System.out.println(a + " * " + b + " = " + a.mul(b));
if (a.compareTo(b) >= 0) {
System.out.println(a + " / " + b + " = " + a.div(b));
}
}
}
final class BigInt implements Comparable<BigInt> {
int[] digits;
int size;
public BigInt() {
n = new int[1];
}
public BigInt(String s) {
n = new int[s.length()];
for (int i = 0; i < n.length; ++i) {
n[n.length - i - 1] = s.charAt(i) - '0';
}
n = trim(n);
}
private BigInt(int[] n) {
this.n = new int[n.length];
for (int i = 0; i < n.length; ++i) {
this.n[i] = n[i];
}
}
public BigInt add(BigInt o) {
return null;
}
public int compareTo(BigInt o) {
if (n.length < o.n.length) {
return -1;
}
else if (n.length > o.n.length) {
return +1;
}
for (int i = n.length-1; i >= 0; --i) {
if (n[i] < o.n[i]) {
return -1;
}
else if (n[i] > o.n[i]) {
return +1;
}
}
return 0;
}
public BigInt div(BigInt o) {
return null;
}
public boolean equals(Object o) {
if (o instanceof BigInt) {
if (n.length == ((BigInt)o).n.length) {
for (int i = 0; i < n.length; ++i) {
if (n[i] != ((BigInt)o).n[i]) {
return false;
}
}
return true;
}
}
return false;
}
public BigInt mul(BigInt o) {
int max = n.length > o.n.length ? n.length : o.n.length;
int[] newdigits = new int[n.length + o.n.length];
for (int i = 0; i < max; i++)
{
int carry = 0;
for (int i2 = 0; i2 < o.n.length || carry > 0; i2++)
{
int otherDigit = i2 >= o.n.length ? 0: o.n[i2];
int val = (n[i] * otherDigit) + carry;
newdigits[i + i2] += val % 10;
carry = val / 10;
}
}
return new BigInt(newdigits);
}
public BigInt sub(BigInt o) {
return null;
}
public String toString() {
String s = "";
for (int i : n) {
s = i + s;
}
return s;
}
private int[] trim(int[] nums) {
int size = nums.length;
for (int i = nums.length - 1; i > 0; --i) {
if (nums[i] != 0) {
break;
}
--size;
}
int[] res = new int[size];
for (int i = 0; i < size; ++i) {
res[i] = nums[i];
}
return res;
}
private int[] n;
}
Didn't feel like debugging your code, but here is how I'd implement that multiplication. It's a little less efficient, but easier to keep track of the carry.
public BigInt mul(BigInt o) {
int max = n.length > o.n.length ? n.length : o.n.length;
int[] newdigits = new int[n.length + o.n.length];
for (int i = 0; i < max; i++) {
for (int i2 = 0; i2 < max; i2++) {
int digit1 = i >= n.length ? 0 : n[i];
int digit2 = i2 >= o.n.length ? 0 : o.n[i2];
if (digit1 > 0 && digit2 > 0) {
int value = digit1 * digit2;
int pos = i + i2;
while (value > 0) {
int newDigit = (newdigits[pos] + value) % 10;
value = (newdigits[pos] + value) / 10;
newdigits[pos] = newDigit;
pos++;
}
}
}
}
return new BigInt(newdigits);
}
First, look the possible lengths:
[1] * [1] = [1] OR length(1) + length(1) -> length(1)
[9] * [9] = [8,1] OR length(1) + length(1) -> length(2)
One solution
Psudocode:
if (newdigits[ (length-1) ] == 0)
int[] newarray = new int[ (length-1) ]
copy newdigits to newarray
return newarray
You have to look at the carry of the largest digit before the earlier digits.
Secondly, you need to add the previous value you found to the val variable.
End of i=0:
[1, 9, 9, 7, 1, 0, 0, 0]
Adding during i=1:
[0, 1, 9, 9, 7, 1, 0, 0]
End of i=1:
[1, 10, 18, 16, 8, 1, 0, 0]
I suggest you try using Arrays.toString(newdigits) or use a debugger to catch these problems in the future.

reducing using instance variable to decrease the use of memory

I'm trying to do the Algorithm programming assignment of Princeton , and I met a problem about the memory test. The assignment requires us run the percolation program N times and find the medium of the result, and I write a percolationtest.java and for each time, I create an instance variable, it worked, but use too much memory, and the instructor suggests me to use local variable, but I don't know how. Can some one help me and give me some advice, I really appreciate it.
public class PercolationStats {
private int N, T, totalSum;
private double []fraction;
private int []count;
public PercolationStats(int N, int T) {
if (N <= 0 || T <= 0)
throw new IllegalArgumentException();
else {
this.N = N;
this.T = T;
count = new int [T];
totalSum = N*N;
fraction = new double[T];
int randomX, randomY;
for (int i = 0; i < T; i++) {
Percolation perc = new Percolation(N);
while (true) {
if (perc.percolates()) {
fraction[i] = (double) count[i]/totalSum;
break;
}
randomX = StdRandom.uniform(1, N+1);
randomY = StdRandom.uniform(1, N+1);
if (perc.isOpen(randomX, randomY)) continue;
else {
perc.open(randomX, randomY);
count[i]++;
}
}
}
}
} // perform T independent experiments on an N-by-N grid
public double mean() {
double totalFraction = 0;
for (int i = 0; i < T; i++) {
totalFraction += fraction[i];
}
return totalFraction/T;
} // sample mean of percolation threshold
public double stddev() {
double u = this.mean();
double sum = 0;
for (int i = 0; i < T; i++) {
sum += (fraction[i] - u) * (fraction[i] - u);
}
return Math.sqrt(sum/(T-1));
} // sample standard deviation of percolation threshold
public double confidenceLo() {
double u = this.mean();
double theta = this.stddev();
double sqrtT = Math.sqrt(T);
return u-1.96*theta/sqrtT;
} // low endpoint of 95% confidence interval
public double confidenceHi() {
double u = this.mean();
double theta = this.stddev();
double sqrtT = Math.sqrt(T);
return u+1.96*theta/sqrtT;
} // high endpoint of 95% confidence interval
public static void main(String[] args) {
int N = 200;
int T = 100;
if (args.length == 1) N = Integer.parseInt(args[0]);
else if (args.length == 2) {
N = Integer.parseInt(args[0]);
T = Integer.parseInt(args[1]); }
PercolationStats a = new PercolationStats(N, T);
System.out.print("mean = ");
System.out.println(a.mean());
System.out.print("stddev = ");
System.out.println(a.stddev());
System.out.print("95% confidence interval = ");
System.out.print(a.confidenceLo());
System.out.print(", ");
System.out.println(a.confidenceHi());
}
}
public class Percolation {
private boolean[][] site;
private WeightedQuickUnionUF uf;
private int N;
public Percolation(int N) {
if (N < 1)
throw new IllegalArgumentException();
else {
site = new boolean[N + 2][N + 2];
for (int j = 1; j <= N; j++) {
site[0][j] = true;
site[N + 1][j] = true;
}
uf = new WeightedQuickUnionUF((N + 2) * (N + 2));
for (int i = 1; i <= N; i++) {
uf.union(0, i);
}
this.N = N;
}
}
public void open(int i, int j) {
if (i > N || i < 1 || j > N || j < 1)
throw new IndexOutOfBoundsException();
else {
if (!site[i][j]) {
site[i][j] = true;
if (site[i - 1][j]) {
uf.union((N + 2) * (i - 1) + j, (N + 2) * i + j);
}
if (site[i + 1][j]) {
uf.union((N + 2) * i + j, (N + 2) * (i + 1) + j);
}
if (site[i][j + 1]) {
uf.union((N + 2) * i + (j + 1), (N + 2) * i + j);
}
if (site[i][j - 1]) {
uf.union((N + 2) * i + (j - 1), (N + 2) * i + j);
}
}
}
}
public boolean isOpen(int i, int j) {
if (i > N || i < 1 || j > N || j < 1)
throw new IndexOutOfBoundsException();
else
return site[i][j];
}
public boolean isFull(int i, int j) {
if (i > N || i < 1 || j > N || j < 1)
throw new IndexOutOfBoundsException();
else
return site[i][j] && (i == 1 || uf.connected((N + 2) * i + j, 0));
}
public boolean percolates() {
for (int i = 1; i <= N; i++) {
if (this.isFull(N, i)) {
return true;
}
}
return false;
}
public static void main(String[] args) {
}
}
Added meanValue instance variable to keep mean value and replaced it in multiple places where you used to call mean() method which was over head to calculate again and again. Also modified "int[] count" as local variable which you were not using outside the constructor. post your "Percolation" and "StdRandom" classes for more optimization of code. you can run this code and test, it should reduce the runtime than yours.
public class PercolationStats {
private int N, T, totalSum;
private double []fraction;
private double meanValue;
public PercolationStats(int N, int T) {
if (N <= 0 || T <= 0)
throw new IllegalArgumentException();
else {
this.N = N;
this.T = T;
int [] count = new int [T];
totalSum = N*N;
fraction = new double[T];
int randomX, randomY;
for (int i = 0; i < T; i++) {
Percolation perc = new Percolation(N);
while (true) {
if (perc.percolates()) {
fraction[i] = (double) count[i]/totalSum;
break;
}
randomX = StdRandom.uniform(1, N+1);
randomY = StdRandom.uniform(1, N+1);
if (perc.isOpen(randomX, randomY)) continue;
else {
perc.open(randomX, randomY);
count[i]++;
}
}
}
}
}
// perform T independent experiments on an N-by-N grid
public double mean() {
double totalFraction = 0;
for (int i = 0; i < T; i++) {
totalFraction += fraction[i];
}
meanValue = totalFraction/T;
return meanValue;
} // sample mean of percolation threshold
public double stddev() {
double u = meanValue;
double sum = 0;
for (int i = 0; i < T; i++) {
sum += (fraction[i] - u) * (fraction[i] - u);
}
return Math.sqrt(sum/(T-1));
} // sample standard deviation of percolation threshold
public double confidenceLo() {
double u = meanValue;
double theta = this.stddev();
double sqrtT = Math.sqrt(T);
return u-1.96*theta/sqrtT;
} // low endpoint of 95% confidence interval
public double confidenceHi() {
double u = meanValue;
double theta = this.stddev();
double sqrtT = Math.sqrt(T);
return u+1.96*theta/sqrtT;
} // high endpoint of 95% confidence interval
public static void main(String[] args) {
int N = 200;
int T = 100;
if (args.length == 1) N = Integer.parseInt(args[0]);
else if (args.length == 2) {
N = Integer.parseInt(args[0]);
T = Integer.parseInt(args[1]); }
PercolationStats a = new PercolationStats(N, T);
System.out.print("mean = ");
System.out.println(a.mean());
System.out.print("stddev = ");
System.out.println(a.stddev());
System.out.print("95% confidence interval = ");
System.out.print(a.confidenceLo());
System.out.print(", ");
System.out.println(a.confidenceHi());
}
}

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