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How can I recursively FTP a directory structure using Jsch? [duplicate]

This question already has answers here:
Transfer folder and subfolders using ChannelSftp in JSch?
(3 answers)
Closed 5 years ago.
I'm trying to traverse a directory and upload all contents and directories in the same structure.
This is an example structure:
Dir1/
....Dir1_1/
....Dir1_2/
........Dir1_2_1/
............file.txt
Dir2/
....file.txt
....file2.txt
Dir3/
Dir4/
index.html
index.css
example.file
I've tried the following:
private void ftpFiles(File[] files, ChannelSftp channelSftp) throws SftpException, FileNotFoundException {
for (File file : files) {
System.out.println("Uploading: " + file.getName());
if (file.isDirectory()) {
System.out.println(file.getName() + " is a directory");
SftpATTRS attrs;
try {
channelSftp.stat(file.getName());
} catch (Exception e) {
System.out.println(file.getName() + " does not exist. Creating it...");
channelSftp.mkdir(file.getName());
}
channelSftp.cd(file.getName());
this.ftpFiles(file.listFiles(), channelSftp);
} else {
channelSftp.put(new FileInputStream(file), file.getName());
}
}
}
I'm taking an array of top level files, and recursively going down each one.
The problem is once I hit the first directory and cd into it, all further files and directories are inside of this.
Example: /Dir1/Dir1_1/Dir1_2/Dir1_2_1/Dir2/Dir3/Dir4/...etc
How can I do a ../ with my channel while calling this recursively?

Maybe something like (pseudo code):
List<Files> directories = new ArrayList<> ();
if (file is directory) directories.add(file);
else dowloadFile();
for (File f : directories) {
cd(f);
ftpFiles(listFiles());
cd(..);
}

None of the properties file is getting loaded in Servlet Application [duplicate]

This question already has answers here:
Where to place and how to read configuration resource files in servlet based application?
(6 answers)
Closed 5 years ago.
I'm preparing a servlet application and none of the properties file is getting loaded in application. Even though all the property files are residing in the same location.
Code:
Properties prop = new Properties();
InputStream input = getClass().getClassLoader().getResourceAsStream("ldap.properties");;
try{
logger.debug("Loading Properties File");
//input = new FileInputStream("ldap.properties");
// load a properties file
prop.load(input);
logger.debug("Retry Count is: " + Integer.parseInt(prop.getProperty("retry")));
System.out.println("Retry Count is: " + Integer.parseInt(prop.getProperty("retry")));
logger.debug("downTimeValue is: " + Integer.parseInt(prop.getProperty("downTimeValue")));
retry = Integer.parseInt(prop.getProperty("retry"));
downTimeValue = Integer.parseInt(prop.getProperty("downTimeValue"));
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (input != null) {
try {
input.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
Error:
[#|2018-01-22T15:34:27.313+0530|SEVERE|oracle-glassfish3.1.2|javax.enterprise.system.std.com.sun.enterprise.server.logging|_ThreadID=64;_ThreadName=Thread-2;|log4j:WARN No appenders could be found for logger (com.amdocs.LDAPKit).|#]
[#|2018-01-22T15:34:27.314+0530|SEVERE|oracle-glassfish3.1.2|javax.enterprise.system.std.com.sun.enterprise.server.logging|_ThreadID=64;_ThreadName=Thread-2;|log4j:WARN Please initialize the log4j system properly.|#]
[#|2018-01-22T15:34:27.314+0530|SEVERE|oracle-glassfish3.1.2|javax.enterprise.system.std.com.sun.enterprise.server.logging|_ThreadID=64;_ThreadName=Thread-2;|log4j:WARN See http://logging.apache.org/log4j/1.2/faq.html#noconfig for more info.|#]
[#|2018-01-22T16:02:37.033+0530|WARNING|oracle-glassfish3.1.2|javax.enterprise.system.container.web.com.sun.enterprise.web|_ThreadID=67;_ThreadName=Thread-2;|StandardWrapperValve[com.amdocs.LDAPKit]: PWC1406: Servlet.service() for servlet com.amdocs.LDAPKit threw exception
java.lang.NullPointerException
at java.util.Properties$LineReader.readLine(Properties.java:434)
at java.util.Properties.load0(Properties.java:353)
at java.util.Properties.load(Properties.java:341)
at com.amdocs.LDAPKit.doPost(LDAPKit.java:133)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:688)

I highly recommend to transform your project to a maven project so that it will handle dependencies and build your project.
After that, move your properties files to resources folder because getClass().getClassLoader().getResourceAsStream("ldap.properties"); looks for files in resources folder.
Your project structure should look like this

Java - How I can check if file is exist? [duplicate]

This question already has answers here:
How do I check if a file exists in Java?
(19 answers)
Closed 7 years ago.
I'm creating a file with writeToFile() function.
Before I call writeToFile() function, I want to check if the file already exist or not.
How can I do this?
code:
private void writeToFile(String data, String fileName) {
try {
OutputStreamWriter outputStreamWriter = new OutputStreamWriter(this.openFileOutput(fileName, Context.MODE_APPEND));
outputStreamWriter.write(data);
outputStreamWriter.close();
}
catch (IOException e) {
Log.e("Exception", "File write failed: " + e.toString());
}
}

You could utilize java.io.File and call the .exists() method to check if the file exists.
Use the following code to check if a file already exists.
if(file.exists() && !file.isDirectory()) {
// continue code
}

Using java.io.File
File f = new File(fileName);
if (f.exists()) {
// do something
}
This is a duplicate.

File file = new File("FileName");
if(file.exists()){
System.out.println("file is already there");
}else{
System.out.println("Not find file ");
}
The methods in the Path class are syntactic, meaning that they operate on the Path instance. But eventually you must access the file system to verify that a particular Path exists

NIO getParentFile().mkdir() [duplicate]

This question already has answers here:
Using Java nio to create a subdirectory and file
(3 answers)
Closed 8 years ago.
Is there a way to create a file and directory in one shot
as in below... (Using Java 7 and NIO... Paths and Files static methods ).
where you wouldn't have to type the Path and then file in separate lines ( of code ) ?
File file = new File("Library\\test.txt");
if (file.getParentFile().mkdir()) {
file.createNewFile();
} else {
throw new IOException("Failed to create directory " + file.getParent());
}
Basically looking for the equivalent approach to "getParentFile().mkdir()" off the Path ( and file ) entered in Java 7 NIO.
Thx

Actually realized it's accopmplished this way..
Path file = Paths.get("/Users/jokrasa/Documents/workspace_traffic/javaReviewFeb28/src/TEST/","testy.txt");
try {
Files.createDirectory(file.getParent());
Files.createFile(file);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
So you don't have to type it in twice actually...
Cheers !

Rename all files in a folder using java [duplicate]

This question already has answers here:
Rename a file using Java
(15 answers)
Closed 8 years ago.
How can we rename all files in a folder using java?
C:/temp/pictures/1.jpg
C:/temp/pictures/2.jpg
C:/temp/pictures/3.jpg
C:/temp/pictures/4.jpg
C:/temp/pictures/5.jpg
Rename to
C:/temp/pictures/landscape_1.jpg
C:/temp/pictures/landscape_2.jpg
C:/temp/pictures/landscape_3.jpg
C:/temp/pictures/landscape_4.jpg
C:/temp/pictures/landscape_5.jpg
Kind regards

Take a look at below code which check file in the folder and rename it.
File dir = new File("D:/xyz");
if (dir.isDirectory()) { // make sure it's a directory
for (final File f : dir.listFiles()) {
try {
File newfile =new File("newfile.txt");
if(f.renameTo(newfile)){
System.out.println("Rename succesful");
}else{
System.out.println("Rename failed");
}
} catch (Exception e) {
// TODO: handle exception
e.printStackTrace();
}
I Hope It Will Help You