The server I am sending a POST request to requires extra parameters in the Content-Disposition field that are easily added in C# code, but I am struggling to replicate this functionality in Java.
The working C# code:
using (var content = new MultipartFormDataContent()) {
var fileContent = new ByteArrayContent(System.IO.File.ReadAllBytes("filepath"));
fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "file",
FileName = "file.zip.encrypted",
};
fileContent.Headers.ContentDisposition.Parameters.Add(new NameValueHeaderValue("Type", "CSV"));
fileContent.Headers.ContentDisposition.Parameters.Add(new NameValueHeaderValue("Token", jwt));
content.Add(fileContent);
var requestUri = "url";
var result = client.PostAsync(requestUri, content).Result;
When I print the above request headers the Content-Disposition header looks like:
Content-Disposition: form-data; name=file; filename=file.zip.encrypted; Type=CSV; Token=jwt
Attempting to replicate this POST request in Java Apache Http:
File file = new File("filepath");
String headerValue = "form-data; name=file; filename=\"file.zip.encrypted\"; Type=\"CSV\"; Token=\""+jwtToken+"\"";
try (CloseableHttpClient client2 = HttpClients.createDefault()) {
HttpPost post2 = new HttpPost(url);
HttpEntity entity = MultipartEntityBuilder.create().addPart("file", new FileBody(file)).build();
post2.setHeader("Content-Disposition", headerValue);
post2.setEntity(entity);
try (CloseableHttpResponse response2 = client2.execute(post2)) {
System.out.println(response2.toString());
}
}
However, when I print the Headers in this request, only the name and filename fields are captured, and not the other parameters required in the Content-Disposition header. This is leading to Internal Server Error responses, as the Header does not contain the required parameters. (tried with and without the added quotes around field values)
Content-Disposition: form-data; name="file"; filename="file.zip.encrypted"
Any help getting the C# POST request behavior replicated in Java would be greatly appreciated, thanks!
Related
I using Okhttp3 for download file from server in android application. my link is http://www.webweb.infinityfreeapp.com/lichi/download.php?path=Add.jpg it download file in firefox, chorme smoothly, while in okhttp3 response string shows
<html><body><script>document.cookie="_test=9e105a99e90025d241c180c29fad3231 ; expires=Thu, 31-Dec-37 23:55:55 GMT; path=/" ;document.location.href="http://www.webweb.infinityfreeapp.com/lichi/download.php?path=Add.jpg&i=1";</script></body></html>
but i feel response string has Add.jpg file data. so, what can i change in okhttp3 code or php code that i gather App.jpg data in response string of okhttp3
Php Code
if(isset($_GET['path']))
{
$url = $_GET['path'];
$type = "application/pdf";
$completePath = "http://www.webweb.infinityfreeapp.com/lichi/";
$visibleName = "$url";
$completePath .= $url;
// Force download
header("Content-disposition: attachment; filename=$visibleName");
header("Content-Type: application/force-download");
header("Content-Transfer-Encoding: $type\n");
// header("Content-Length: ".filesize($completePath));
header("Pragma: no-cache");
header("Cache-Control: must-revalidate, post-check=0, pre-check=0, public");
header("Expires: 0");
readfile($completePath);
die();
}
I comment Content-Length because it crash system in uncomment
Java code
OkHttpClient client = new OkHttpClient();
String url = "http://www.webweb.infinityfreeapp.com/lichi/download.php?path=Add.jpg";
Call call = client.newCall(new Request.Builder().url(url).get().build());
Response response = call.execute();
if (response.code() == 200 || response.code() == 201) {
Headers responseHeaders = response.headers();
for (int i = 0; i < responseHeaders.size(); i++)
Log.d(LOG_TAG, responseHeaders.name(i) + ": " + responseHeaders.value(i));
String str = response.body().string();
}
Here str contain above html file information instead Add.jpg file data. so please give answer
good question
Autually if we send a get request to
http://www.webweb.infinityfreeapp.com/lichi/download.php?path=Add.jpg
we get the right resutl just like
<html><body><script>document.cookie="_test=9e105a99e90025d241c180c29fad3231 ; expires=Thu, 31-D...";</script></body></html> .
we can get a file in browser, because browser can parse html ，
when browser get the string result which is a html page, it create another request with a new Header （Cookie=_test=9e105a99e90025d241c180c29fad3231), and with the Cookie, we get an image file from server.
Thanks for quick and good solution.
i just add header as:-
.header("Cookie", "_test=9e105a99e90025d241c180c29fad3231")
and send again with above code, actual result come
I am creating a java process to download WebEx recordings using their NBR API's NBRFileOpenService call. It returns a multipart response with the recording file contents attached. I have it somewhat working with the code below. However, when the recording file is large enough, I get OutOfMemoryError exception.
It is quite common for the recordings to be large and if the API only returned the file alone, I could just stream the download, however I'm not so sure how I can safely handle the multipart response. So I'm wondering if there is any way to read the file metadata as well as save the binary content to a file without holding the entire response in memory.
API Response Format:
------=_Part_674_458057647.1593732813745
Content-Type: text/xml; charset=UTF-8
Content-Transfer-Encoding: binary
Content-Id: <AD79B5747EFC01CDDA9A281BA8CDEF0C>
[SOAP RESPONSE]
------=_Part_674_458057647.1593732813745
Content-Type: application/octet-stream
Content-Transfer-Encoding: binary
Content-Id: <C498AB4664B57130F869695A1C5B584E>
[FILE METADATA]
------=_Part_674_458057647.1593732813745
Content-Type: application/octet-stream
Content-Transfer-Encoding: binary
Content-Id: <003D9EBA1E491CE2E9E5903C996EFD4C>
[BINARY FILE CONTENT]
------=_Part_674_458057647.1593732813745--
My Code:
public void retrieveRecordingFile(String uri, String recordId, String serviceType) throws Exception {
HttpClient httpClient = generateHttpClient();
HttpPost httpPost = new HttpPost(uri);
httpPost.addHeader("Content-Type", ContentType.APPLICATION_XML.getMimeType());
httpPost.addHeader("SOAPAction", "NBRFileOpenService");
String requestXml = buildNBRDownloadFileXml(recordId, serviceType);
HttpEntity httpEntity = new ByteArrayEntity(requestXml.getBytes(Charset.forName("UTF-8")));
httpPost.setEntity(httpEntity);
HttpResponse httpResponse = httpClient.execute(httpPost);
if (httpResponse.getStatusLine().getStatusCode() == 200) {
MimeMultipart mimeMultipart = new MimeMultipart(new ByteArrayDataSource(httpResponse.getEntity().getContent(), "multipart/form-data"));
String filename = null;
File targetFile = null;
for (int i = 0; i < mimeMultipart.getCount(); i++) {
if (i == 1) {
filename = retrieveFileName(mimeMultipart.getBodyPart(i).getInputStream());
} else if (i == 2) {
targetFile = new File(DOWNLOAD_DIR + filename);
FileUtils.copyInputStreamToFile(mimeMultipart.getBodyPart(i).getInputStream(), targetFile);
}
}
}
}
Any help is truly appreciated.
I am facing an issue with Windows Computer Vision API. If I send a request with contentType = application/json and image URL in JSON request body things work fine but on sending a binary image(base 64 encoded) with contentType = application/octet-stream it gives me ImageFormatInvalid in the response.
Any help is much appreciated. Thank you!
Code:
final String binaryData = "data:image/jpeg;base64, /9............
ByteArrayEntity requestEntity = new ByteArrayEntity(binaryData.getBytes(),
ContentType.APPLICATION_OCTET_STREAM);
request.setEntity(requestEntity);
HttpResponse response = httpClient.execute(request);
HttpEntity entity = response.getEntity();
Response: InvalidImageFormat
It seems I was generating the binary incorrectly.
Worked when made changes as below:
byte[] decodedString = Base64.decodeBase64(binaryData);
ByteArrayEntity requestEntity = new
ByteArrayEntity(decodedString,ContentType.APPLICATION_OCTET_STREAM);
request.setEntity(requestEntity);
I am using rest template for creating HTTP post request . But request contain by default added Accept-char header with huge Content . Please suggest how to exclude addition of that header. Below is the code i am using:
HttpHeader header= new HttpHeader();
RestTemplate template = new RestTemplate();
header.setContentType("application/xml");
String body=" content of body ";
HttpEntity<string> request=new HttpEntity<string> (body,header);
template.postForObject(URL,request,String.class);
This should remove 'Accept-Charset' header:
StringHttpMessageConverter stringHttpMessageConverter = new StringHttpMessageConverter(StandardCharsets.UTF_8);
stringHttpMessageConverter.setWriteAcceptCharset(false);
restTemplate.getMessageConverters().add(0, stringHttpMessageConverter);
The goal is to send an email with inline image. Everything is working well, except the image is not appearing in the email.
My approach is based on this Jersey-example of Mailgun's User Guide.
public static ClientResponse SendInlineImage() {
Client client = Client.create();
client.addFilter(new HTTPBasicAuthFilter("api",
"YOUR_API_KEY"));
WebResource webResource =
client.resource("https://api.mailgun.net/v3/YOUR_DOMAIN_NAME" +
"/messages");
FormDataMultiPart form = new FormDataMultiPart();
form.field("from", "Excited User <YOU#YOUR_DOMAIN_NAME>");
form.field("to", "baz#example.com");
form.field("subject", "Hello");
form.field("text", "Testing some Mailgun awesomness!");
form.field("html", "<html>Inline image here: <img src=\"cid:test.jpg\"></html>");
File jpgFile = new File("files/test.jpg");
form.bodyPart(new FileDataBodyPart("inline",jpgFile,
MediaType.APPLICATION_OCTET_STREAM_TYPE));
return webResource.type(MediaType.MULTIPART_FORM_DATA_TYPE).
post(ClientResponse.class, form);
}
However, I need to use Spring's RestTemplate.
This is what I've got so far:
RestTemplate template = new RestTemplate();
MultiValueMap<String, Object> map = new LinkedMultiValueMap<>();
// ... put all strings in map (from, to, subject, html)
HttpHeaders headers = new HttpHeaders();
// ... put auth credentials on header, and content type multipart/form-data
template.exchange(MAILGUN_API_BASE_URL + "/messages", HttpMethod.POST,
new HttpEntity<>(map, headers), String.class);
The remaining part is to put the *.png file into the map. Not sure how to do that. Have tried reading all its bytes via ServletContextResource#getInputStream, but without success: Image is not appearing in the resulting e-mail.
Am I missing something here?
This turned out to be a case where everything was set up correctly, but only a small detail prevented it from working.
map.add("inline", new ServletContextResource(this.servletContext,
"/resources/images/email-banner.png"));
For Mailgun you need to use the map-key "inline". Also, the ServletContextResource has a method getFilename(), which is used to resolve against the image tag. Thus, the image tag should have the following content id:
<img src="cid:email-banner.png"/>