I have a class:
#Getter
#Setter
#Entity(name = "car")
public class CarEntity {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id", nullable = false)
private UUID id;
#OneToMany(cascade = CascadeType.ALL, mappedBy = "car")
private List<WheelEntity> wheels;
private String number;
}
And a query finding an entity by one of its parameters and fetching nested collection:
#Query("SELECT c FROM car c WHERE c.number=:loanContract")
Optional<CarEntity> findByNumber(#Param("number") String number);
Everything works fine in runtime, but when I try to test it, the nested collection in the entity read from database is always null. I'm using Junit5 and H2 in-memory database.
Related
In my spring boot project, I have one LineItem entity below is the code
#Entity
#Table(name = "scenario_lineitem")
#Data
#NoArgsConstructor
public class LineItem implements Cloneable {
private static Logger logger = LoggerFactory.getLogger(GoogleConfigConstant.class);
#Id
#GeneratedValue(strategy = IDENTITY)
private BigInteger lineItemId;
#Column
private String name;
#OneToMany(fetch = FetchType.LAZY, cascade = { CascadeType.ALL, CascadeType.PERSIST, CascadeType.MERGE })
#JoinColumn(name = "line_item_meta_id")
private List<QuickPopValue> quickPopValues;
}
Another entity is
#Entity
#Table(name = "quick_pop_value")
#Data
#NoArgsConstructor
public class QuickPopValue implements Cloneable {
#Id
#GeneratedValue(strategy = IDENTITY)
#Column(name = "quick_pop_value_id", columnDefinition = "bigint(20)", unique = true, nullable = false)
private BigInteger quickPopValueId;
#Column(name = "column_name")
private String columnName;
#Column(name = "value")
private String value;
#Column(name = "formula", columnDefinition = "longtext")
private String formula;
}
Now I am trying to delete QuickPopValue one by one but it's not getting deleted and not getting any exception as well.
Below is the delete code :
List<QuickPopValue> quickPopValues = sheetRepository.findByColumnName(columnName);
for (QuickPopValue qpValue : quickPopValues) {
quickPopValueRepository.delete(qpValue);
}
Such behavior occurs when deleted object persisted in the current session.
for (QuickPopValue qpValue : quickPopValues) {
// Here you delete qpValue but this object persisted in `quickPopValues` array which is
quickPopValueRepository.delete(qpValue);
}
To solve this you can try delete by id
#Modifying
#Query("delete from QuickPopValue t where t.quickPopValueId = ?1")
void deleteQuickPopValue(Long entityId);
for (QuickPopValue qpValue : quickPopValues) {
quickPopValueRepository.deleteQuickPopValue(qpValue.getQuickPopValueId());
}
I try to save object Run to database. I defined relation between Run and City. One city could have many runs. I got problem with city_id. Is null.
Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement] with root cause
java.sql.SQLIntegrityConstraintViolationException: Column 'city_id' cannot be null
My entieties and controller:
City
#Entity
#Getter
#Setter
#Builder
#NoArgsConstructor
#AllArgsConstructor
#Table(name = "cities")
public class City {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "city_id")
private long id;
#OneToMany(mappedBy = "city", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
private List<Run> runs = new ArrayList<>();
private String name;
}
Run
#Entity
#Builder
#Getter
#Setter
#NoArgsConstructor
#AllArgsConstructor
#Table(name = "runs")
public class Run {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
#Column(name = "name_run")
private String nameRun;
#Column(name = "distance")
private double distance;
#Column(name = "date")
private Date date;
#Column(name = "my_time")
private String myTime;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "city_id", nullable = false)
#OnDelete(action = OnDeleteAction.CASCADE)
#JsonIgnore
private City city;
}
Controller
#CrossOrigin
#RestController
#RequestMapping("/api/")
public class RunController {
private RunRepository runRepository;
private RunService runService;
public RunController(RunRepository runRepository, RunService runService) {
this.runRepository = runRepository;
this.runService = runService;
}
#GetMapping("runs")
public ResponseEntity<List<Run>> getRuns() {
return runService.getRuns();
}
#PostMapping("runs")
public ResponseEntity addRun(#RequestBody Run run) {
return new ResponseEntity<>(runRepository.save(run), HttpStatus.OK);
}
}
I would like to save the run in DB.
My test request looks like :
{
"nameRun": "test",
"distance":"5.0",
"date":"2020-12-12",
"myTime":"50:40",
"city":"test1"
}
Result from evaluate expresion in Intelijj:
Why the City = null? Is here error in mapping?
Can you try with this json but you need to pass city id in json.
{
"nameRun": "test",
"distance": "5.0",
"date": "2020-12-12",
"myTime": "50:40",
"city": {
"id": 1,
"name": "test1"
}
}
Thanks
First of all, use Long for id please. It is better to add #Entity annotation too.
#Entity
public class City {
#Id
#GeneratedValue
private Long id;
#OneToMany(mappedBy = "city", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
private List<Run> runs = new ArrayList<>();
}
#Entity
public class Run {
#Id
#GeneratedValue
private Long id;
#ManyToOne(fetch = FetchType.LAZY)
private City city;
}
You need to set city_id when you save Run.
The simplest way to do that is just create a fake transient City and set id to it.
City city = new City();
city.setId(1L);
Run run = new Run();
run.setCity(city);
repository.save(run);
Obviously you should have a city with id 1L in the database.
Other options are
Use something like session.load() Hibernate analogue with Spring repository to create City without loading it from datatbase.
Load City entity entirely by id.
if you wanna save any run class,
Run run = new Run();
City city = new City();
city.getRuns().add(run);
runRepository.save(run);
if you wanna save any run class, first you need to insert to (Arraylist) runs variable of city class like city.getRuns().add(run) after filling run then you can runRepository.save(run).
Also my samples are here. You can look at myclasses.
First class is called Patient .
#Data
#AllArgsConstructor
#NoArgsConstructor
#Entity
#ToString
#Table(name = "aapatient")
public class Patient {
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "AA_PATIENT_SEQ")
#SequenceGenerator(sequenceName = "AA_PATIENT_SEQ", allocationSize = 1, name = "AA_PATIENT_SEQ")
#Column(name = "patientid")
private Long patientid;
private String name;
private String lastname;
#OneToMany(mappedBy = "patient", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
private List<Problem> problems;
}
Second Class called Problem is this one.
#Data
#AllArgsConstructor
#NoArgsConstructor
#ToString
#Entity
#Table(name="aaproblem")
public class Problem{
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "AA_PATIENT_SEQ")
#SequenceGenerator(sequenceName = "AA_PATIENT_SEQ", allocationSize = 1, name = "AA_PATIENT_SEQ")
#Column(name = "problemid")
private Long problemid;
private String problemName;
private String problemDetail;
#Temporal(TemporalType.TIMESTAMP)
Date creationDate;
#NotNull
#ManyToOne(optional = true, fetch = FetchType.LAZY)
#JoinColumn(name = "patient_id")
private Patient patient;
}
I have two table with many-to-one relationship. Example is, I have Office table and Employee table. One Employee belong to one Office and one Office belong to many Employee.
Office
#Entity(name = "office")
#Table(name = "office", uniqueConstraints = {#UniqueConstraint(columnNames = {"id"})})
public class Office {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "office_name", nullable = false)
private String officeName;
}
Employee
#Entity(name = "employee")
#Table(name = "employee", uniqueConstraints = {#UniqueConstraint(columnNames = {"id"})})
public class Employee {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "employee_name", nullable = false)
private String employeeName;
#ManyToOne(cascade = CascadeType.PERSIST, fetch = FetchType.LAZY)
#JoinColumn(name = "office_id", referencedColumnName = "id", nullable = false)
#JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
private Office office;
}
OfficeDto
public class OfficeDto {
private Long id;
private String officeName;
}
EmployeeDto
public class EmployeeDto {
private Long id;
private String employeeName;
private OfficeDto office;
}
With above way of defining the entity and the DTO, when I do employee.findAll(), the JSON result is also include the detail of the office data.
Is there any way that I could achieve (objective):
When do saving new employee, I just have to mention the id of the office.
When do findAll employee, I could choose whether I want to gove the id only or also with the entire object to the client.
Because, with current situation, I think I need to define two employee DTO. First one is contain the entire office data (like the code of EmployeeDto) and the second one is replace private OfficeDto office with private int office.
The second problem you can solve by projection : https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#projections
Or just specific mapper to DTO, for mapping you can use mapstruct : http://mapstruct.org/documentation/installation/
For the first problem i found some answer in stack, but you need verify it : JPA many-to-one relation - need to save only Id
I have two entity classes.
Order.java
#Entity
#Table(name = "order_table")
public class Order implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#OneToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL, orphanRemoval = true)
#JoinColumn(name = "order_id", referencedColumnName = "id", nullable = false, insertable=false, updatable=false)
private Set<Item> items;
// getters & setters & toString
Item.java
#Entity
#Table(name = "item")
public class Item implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#Column(name = "order_id", nullable = false)
private Long orderId;
// getters & setters && toString
I created a test class like this:
#Test
public void createOrderWithItems() {
Item item = new Item();
item.setName("Iron Man");
Order order = new Order();
order.setName("Toy");
order.getItems().add(item);
Order created = service.createOrder(order);
Order orderById = service.getOrderById(order.getId());
System.out.println("Created Order: " + orderById);
Item itemById = service.getItemById(item.getId());
System.out.println("Created item: " + itemById);
Assert.notNull(created.getId(), "Order ID is Null");
}
Test is green but if you check output, you'll see that orderId field in the Item class is null.
Created Order: Order{id=1, name='Toy', items=[Item{id=2, name='Iron Man', orderId=null}]}
Created item: Item{id=2, name='Iron Man', orderId=null}
Does JPA not update this column in the db automatically? Is this column is redundant? If so, how can I retrieve this information from test code?
You need to set orderId explicitly.
item.setOrderId(order.getId());
order.getItems().add(item);
You can create a method addItem(Item item) in your Order class and hide this logic within it.
Cascading will create an entry in db but it won't initialize field. JPA annotations just indicate to JPA provider how to perform mapping between entity and table.
Moreover, check your annotations. #JoinColumn should be used in the entity which owns the relationship (the corresponding table has column as a foreign key). Check the top answer for this question for detailed explanations: What's the difference between #JoinColumn and mappedBy when using a JPA #OneToMany association
Suppose we have entity A that contains a list of entities with type B (with lazy initialization).
Entity B has one BLOB field and some other, that doesn't contain much data.
How can I, using hibernate criteria query, get entity A with it's fields and each A-entity with list of Bs, but every B-entity without the BLOB field ?
Also, I do not want to extract As and iterate them to get Bs. (I now, how to use 'Projections' to extract just Bs with required fields).
Here is some code sample:
A-entity:
#Entity
#Table(name = "A")
public class A implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#OneToMany(mappedBy = "order", fetch = FetchType.LAZY)
#Cascade(CascadeType.ALL)
private List<B> list = new LinkedList<>();
}
B-entity:
#Entity
#Table(name = "B")
public class B implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#Column(name = "data", nullable = false)
#Lob
private byte[] data;
#ManyToOne(targetEntity = A.class, fetch = FetchType.EAGER)
#JoinColumn(name = "A_id", nullable = false)
private A a;
}