We Keep Coding

java.lang.NumberFormatException error after inputting a number [duplicate]

This question already has answers here:
Scanner is skipping nextLine() after using next() or nextFoo()?
(24 answers)
Closed 2 years ago.
I am feeling quite stupid at this point for not being able to figure out something that is most likely a simple fix. I keep getting the error "Exception in thread "main" java.lang.NumberFormatException: For input string: ""
at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:68)
at java.base/java.lang.Integer.parseInt(Integer.java:662)
at java.base/java.lang.Integer.parseInt(Integer.java:770)
at searchSorting.main(searchSorting.java:15)" after inputting how many numbers I want to input. Others solutions to this problem just don't seem to apply to me somehow. Thanks for the help
import java.util.Scanner;
import java.util.Arrays;
public class searchSorting
{
public static void main (String[]args)
{
String line;
int number, search, item, array[], first, last, middle;
Scanner in = new Scanner(System.in);
System.out.print("How many numbers you want to input?: ");
number = in.nextInt();
array = new int [number];
item = Integer.parseInt(in.nextLine());
double[] values = new double[item];
for (int i = 0; i < values.length; i++) {
System.out.print("Input number " + i + ": ");
values[i] = Double.parseDouble(in.nextLine());
}
for (int index = 0; index < 5; index++)
System.out.print(values[index] + " ");
in.nextLine();
Arrays.sort(values);
System.out.println("Sorted number is: " + Arrays.toString(values));
System.out.println("Enter the number you are looking for?");
search = in.nextInt();
first = 0;
last = (item - 1);
middle = (first + last)/2;
while( first <= last )
{
if ( array[middle] < item )
first = middle + 1;
else if ( array[middle] == item )
{
System.out.println(item + " found at location " + (middle + 1) + ".");
break;
}
else
{
last = middle - 1;
}
middle = (first + last)/2;
}
if ( first > last )
System.out.println(item + " is not found.\n");
}}

For more info check out Scanner and Integer documentation, it's an excellent resource.
Edit: Try removing line 15 and replacing item with number in the next line

You call this:
number = in.nextInt();
Assuming the user types 123 and ENTER, this call consumes the 123 and leaves the input stream positioned before the end-of-line character.
The next relevant code is
item = Integer.parseInt(in.nextLine());
The nextLine call advances the input stream past the end-of-line, returning all characters it passed on the way. Since the ENTER key was pressed immediately after 123, the returned value is the emoty string. Which is not an integer.
You need to review your strategy of sometimes scanning numbers (nextInt) and sometimes scanning rest-of-linr (nextLine). Mixing the two needs to be done quite carefully. You might be better advised to stick to the numerical methods (nextInt/nextDouble).
For example, replacing this
item = Integer.parseInt(in.nextLine());
by this
item = in.nextInt();
automatically handles the line-ending.
From discussion in comments:
I am still confused as to why it's having me input
the value a second time on the next line
Making assumptions about how you modified the code since your initial question: it's because you've written code that reads the number twice:
System.out.print("How many numbers you want to input?: ");
number = in.nextInt(); // **** first input ****
array = new int [number];
item = in.nextDouble(); // **** second input ****
double[] values = new double[item];
Each time you call for in.nextSomething() the Scanner is going to read more input. It should likely just be this:
System.out.print("How many numbers you want to input?: ");
number = in.nextInt();
array = new int [number];
double[] values = new double[number];

Non duplicates numbers in user input

I am trying to work out how to create an input validation where it won't let you enter the same number twice as well as being inside a range of numbers and that nothing can be entered unless it's an integer. I am currently creating a lottery program and I am unsure how to do this. Any help would be much appreciated. My number range validation works but the other two validations do not. I attempted the non duplicate number validation and i'm unsure how to do the numbers only validation. Can someone show me how to structure this please.
This method is in my Player class
public void choose() {
int temp = 0;
for (int i = 0; i<6; i++) {
System.out.println("Enter enter a number between 1 & 59");
temp = keyboard.nextInt();
keyboard.nextLine();
while ((temp<1) || (temp>59)) {
System.out.println("You entered an invalid number, please enter a number between 1 and 59");
temp = keyboard.nextInt();
keyboard.nextLine();
}
if (i > 0) {
while(temp == numbers[i-1]) {
System.out.println("Please enter a different number as you have already entered this");
temp = keyboard.nextInt();
keyboard.nextLine();
}
}
numbers[i] = temp;
}
}

Do it as follows:
import java.util.Arrays;
import java.util.Scanner;
public class Main {
static int[] numbers = new int[6];
static Scanner keyboard = new Scanner(System.in);
public static void main(String args[]) {
// Test
choose();
System.out.println(Arrays.toString(numbers));
}
static void choose() {
int temp;
boolean valid;
for (int i = 0; i < 6; i++) {
// Check if the integer is in the range of 1 to 59
do {
valid = true;
System.out.print("Enter in an integer (from 1 to 59): ");
temp = keyboard.nextInt();
if (temp < 1 || temp > 59) {
System.out.println("Error: Invalid integer.");
valid = false;
}
for (int j = 0; j < i; j++) {
if (numbers[j] == temp) {
System.out.println("Please enter a different number as you have already entered this");
valid = false;
break;
}
}
numbers[i] = temp;
} while (!valid); // Loop back if the integer is not in the range of 1 to 100
}
}
}
A sample run:
Enter in an integer (from 1 to 59): 100
Error: Invalid integer.
Enter in an integer (from 1 to 59): -1
Error: Invalid integer.
Enter in an integer (from 1 to 59): 20
Enter in an integer (from 1 to 59): 0
Error: Invalid integer.
Enter in an integer (from 1 to 59): 4
Enter in an integer (from 1 to 59): 5
Enter in an integer (from 1 to 59): 20
Please enter a different number as you have already entered this
Enter in an integer (from 1 to 59): 25
Enter in an integer (from 1 to 59): 6
Enter in an integer (from 1 to 59): 23
[20, 4, 5, 25, 6, 23]

For testing a value is present in the numbers array use Arrays.asList(numbers).contains(temp)
May better if you use an ArrayList for storing numbers.

I would rewrite the method recursively to avoid multiple loops.
If you are not familiar with recursively methods it is basically a method that calls itself inside the method. By using clever parameters you can use a recursively method as a loop. For example
void loop(int index) {
if(index == 10) {
return; //End loop
}
System.out.println(index);
loop(index++);
}
by calling loop(1) the numbers 1 to 9 will be printed.
In your case the recursively method could look something like
public void choose(int nbrOfchoices, List<Integer> taken) {
if(nbrOfChoices < 0) {
return; //Terminate the recursively loop
}
System.out.println("Enter enter a number between 1 and 59");
try {
int temp = keyboard.nextInt(); //Scanner.nextInt throws InputMismatchException if the next token does not matches the Integer regular expression
} catch(InputMismatchException e) {
System.out.println("You need to enter an integer");
choose(nbrOfChoices, taken);
return;
}
if (value < 1 || value >= 59) { //Number not in interval
System.out.println("The number " + temp + " is not between 1 and 59.");
choose(nbrOfChoices, taken);
return;
}
if (taken.contains(temp)) { //Number already taken
System.out.println("The number " + temp + " has already been entered.");
choose(nbrOfChoices, taken);
return;
}
taken.add(temp);
choose(nbrOfChoices--, taken);
}
Now you start the recursively method by calling choose(yourNumberOfchoices, yourArrayList taken). You can also easily add two additonal parameters if you want to be able to change your number interval.

What you want to do is use recursion so you can ask them to provide input again. You can define choices instead of 6. You can define maxExclusive instead 59 (60 in this case). You can keep track of chosen as a Set of Integer values since Sets can only contain unique non-null values. At the end of each choose call we call choose again with 1 less choice remaining instead of a for loop. At the start of each method call, we check if choices is < 0, if so, we prevent execution.
public void choose(Scanner keyboard, int choices, int maxExclusive, Set<Integer> chosen) {
if (choices <= 0) {
return;
}
System.out.println("Enter enter a number between 1 & " + (maxExclusive - 1));
int value = keyboard.nextInt();
keyboard.nextLine();
if (value < 1 || value >= maxExclusive) {
System.out.println("You entered an invalid number.");
choose(keyboard, choices, maxExclusive, chosen);
return;
}
if (chosen.contains(value)) {
System.out.println("You already entered this number.");
choose(keyboard, choices, maxExclusive, chosen);
return;
}
chosen.add(value);
choose(keyboard, --choices, maxExclusive, chosen);
}
choose(new Scanner(System.in), 6, 60, new HashSet<>());

I hope it will help , upvote if yes
import java.util.ArrayList;
import java.util.Scanner;
public class Test {
private ArrayList<String> choose() {
Scanner scanner = new Scanner(System.in);
ArrayList<String> alreadyEntered = new ArrayList<>(6); // using six because your loop indicated me that you're taking six digits
for(int i = 0 ; i < 6 ; ++i){ // ++i is more efficient than i++
System.out.println("Enter a number between 1 & 59");
String digit;
digit = scanner.nextLine().trim();
if(digit.matches("[1-5][0-9]|[0-9]" && !alreadyEntered.contains(digit))// it checks if it is a number as well as if it is in range as well if it is not already entered, to understand this learn about regular expressions
alreadyEntered.add(digit);
else {
System.out.println("Invalid input, try again");
--i;
}
}
return alreadyEntered // return or do whatever with the numbers as i am using return type in method definition i am returning
}
scanner.close();
}
using arraylist of string just to make things easy otherwise i would have to to some parsing from integer to string and string to integer

Bingo game Java

I'm trying to write a java code with(bingo game),(bullseye game)
the rules are simple:
computer picks 4 numbers
user input 4 numbers
must check the user input is between 1 to 10
If the user input exists in the computer randomized numbers it will be 1 bulls
If a number exist in the same location of the computer randomized number it will show 1 "eye"
Max limit is 20 tries until the user is considered "failed"; I need to print each round how many bulls were and how many eye were by the user input;
Example:
if the pc randomizing 1 4 6 7
and the user type 3 4 1 7
the output will be 3 bulls and 2 eyes.
my code prints 0 and 0 at the end.
Thanks for the help!
Here is my code:
import java.util.Random;
import java.util.Scanner;
public class ArraysEx1 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
Random r = new Random();
int[] pcGuess = new int[4];
int[] playerGuess = new int[4];
int countGuess = 0, bulls = 0, eye = 0;
final int maxGuess = 20;
System.out.println("Please press enter to begin");
in.nextLine();
boolean areNumbersCorrect = true; // a boolean value to define if the user input are correct (values between 1 to 10)
for (; countGuess < maxGuess; countGuess++) {
System.out.println("Please enter 4 numbers between 1-10");
for (int i = 0; i < playerGuess.length; i++) {
playerGuess[i] = in.nextInt();
pcGuess[i] = r.nextInt(10)+1;
if (playerGuess[i] < 0 || playerGuess[i] > 10) { // an if statement to check if the user input are correct
areNumbersCorrect = false;
do { // do while loop if the boolean is not true. (force the user to enter correct values)
System.out.println("Please try again");
for (int j = 0; j < playerGuess.length; j++) {
playerGuess[j] = in.nextInt();
if (playerGuess[j] > 0 && playerGuess[j] < 10) {
areNumbersCorrect = true;
continue;
}
}
} while (!areNumbersCorrect); // end of do while loop
}
for (int j=pcGuess.length; j>0; j--) { // for loop to check each number from the user and computer.
if (playerGuess[i] == pcGuess[i]) {
eye++; // if the user number exist in the same location evaluate eye++
if (playerGuess[i]%pcGuess[j]== 0) {
bulls++; // if the user number exist in the randomized number but not in the same location evaluate bulls++
}
}
}
System.out.println(
eye+" Hits!(same pc number and location)"+" And: "+bulls+" Numbers exist");
} if(eye==4&&bulls==4) {
break;
}
}
System.out.println("It took you: "+countGuess+" Times to guess the numbers");
}
}

import java.util.ArrayList;
import java.util.Random;
import java.util.Scanner;
public class ArraysEx1 {
public static void main(String[] args) {
ArrayList<Integer> randNumbers = new ArrayList<>();
Random random = new Random();
String input;
int number;
Scanner sc = new Scanner(System.in);
do {
System.out.println("Please press enter to begin");
input = sc.nextLine();
}while (!input.equals(""));//loop while user doesn't press ENTER
for (int i = 0; i < 4; i++){
randNumbers.add(random.nextInt(10) + 1);//loop to fill the randNumbers arraylist with random numbers
}
/*
randNumbers.add(3);
randNumbers.add(2);
randNumbers.add(9);
randNumbers.add(9);
*/
System.out.println("My random numbers: " + randNumbers.toString());
int counter = 0;
int bulls = 0;
int eyes = 0;
do {
System.out.println("Please enter 4 numbers between 1-10");
number = sc.nextInt();
if (number > 0 && number <= 10){
//System.out.println("index of rand: " + randNumbers.indexOf(number));
//System.out.println("count: " + counter);
if (randNumbers.indexOf(number) == counter){
eyes++;
System.out.println("eyes++");
}else if (randNumbers.contains(number)){
bulls++;
System.out.println("bulls++");
}
counter++;
System.out.println("Number " + counter + " introduced. " + (4 - counter) + " more to go.");
}else {
System.out.println("Wrong number.");
}
}while (counter < 4);//loop for user to introduce valid numbers
System.out.println("You scored " + bulls + " bulls and " + eyes + " eyes.");
}
}
Try this piece of code. Note that I used ArrayList rather than an array, as it offers methods such as .contains() and .indexof().
WARNING: Code will fail if the randNumbers arraylist contains two numbers that are equals, such as the 3-2-9-9 array that is commented when you input 9-9-9-9 as your number guesses. This is because .indexof() method:
Returns the index of the first occurrence of the specified element
in this list, or -1 if this list does not contain the element.
Meaning the code fails to account the last 9 as it will compare the count index (3) to the first occurrence of 9 in the randNumbers, which is 2, making it false and not increasing eyes count.
Since I'm short on time, and this is an assigment you have and just copying it won't teach you much, I'll leave it to you to solve this specific case (I already told you what's wrong, won't be difficult to solve).

java array that accepts input of put name mark, quit and get name (not working)

im trying to write a program that will accept input of "put name mark", "get name mark" and "quit"
upon the user entering "put name mark" the program will prompt them to enter a student name and mark and then stores it at the next available array index.
the "get name" command will accept a name input from the user and they iterate through the array and display any mark matching the name entered.
the "quit" command will end the program and return the mean mark and the highest mark in the display.
the problem im having is that it dosent seem to be entering the loop when i type the required words in. it just jumps to where it asks the question again and wont even accept input
im still a beginner and ive been working on this program for 4 weeks so any help would be greatly appreciated.
package week14;
import java.util.Scanner;
public class week {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
//sets number of string inputs
{
String[] names = new String[50];
double[] scores = new double[50];
// Enter student name and score
System.out.print("please enter either: quit, put name mark, get name");
input.next();
if(input.next() == "put name mark" )
{
System.out.print("Enter Student Name");
names[50] = input.next();
System.out.print("Enter Score");
scores[50] = input.nextInt();
}
System.out.println("please enter either: quit, quit, put name mark, get name");
input.next();
if(input.next() == "get name")
{
System.out.print("please enter the name you would like to display the score for");
String get = input.next();
}
// Sort
for (int i = 50 - 1; i >= 1; i--) {
// Find the maximum in the scores[0..i]
double currentMax = scores[0];
int currentMaxIndex = 0;
for (int j = 1; j <= i; j++) {
if (currentMax < scores[j]) {
currentMax = scores[j];
currentMaxIndex = j;
}
}
// Swap scores[i] with scores[currentMaxIndex];
// Swap names[i] with names[currentMaxIndex] ;
if (currentMaxIndex != i) {
scores[currentMaxIndex] = scores[i];
scores[i] = currentMax;
String temp = names[currentMaxIndex];
names[currentMaxIndex] = names[i];
names[i] = temp;
}
if (input.equals("quit")){
System.out.print(names[i] + scores[i]);
System.out.println();
System.out.print(currentMax);
break;
}
}
}
}
}

That's what i got for now maybe there are some errors if there is any problem say what's it and I'll fix it.
import java.util.Scanner;
public class Week
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in); //Scanner used to get input from the user
String[] names = new String[50]; //The array for names remember arrays index began with 0 not 1
int[] scores = new int[50]; //Again arrays began with 0 not 1 and the last is n-1
int last = 0; //Used to store the last added ID
String command; //The command from the user
boolean running = true; //Whenever the program is running or not
while(running)
{
System.out.println("please enter either: quit, put name mark, get name"); //Print the command list
command = input.nextLine(); //The next input line (This will make the Thread pause untill it get and input)
if(command.equals("put mark")) //If the command is "put mark"
{
if(last == 49) //Check because we can create and Exception by adding too much element to and array
System.out.println("Max number of people reached"); //So we can't add more people
else
{
System.out.println("Enter Student Name"); //Print the questin
names[last] = input.nextLine(); //The name
System.out.println("Enter Score"); //Ask for the score
scores[last] = input.nextInt(); //Get the score ,because score is a double we should use double so it can take numbers like 0.1
last++; //Increment last with 1
}
}else if(command.equals("get name"))
{
System.out.println("please enter the name you would like to display the score for");
String name = input.nextLine(); //Get the name
for(int i = 0; i < last; i++) //Loop untill we hit the last added name's ID
if(names[i].equals(name)) //Check if the names[i] is the name that we're searching for
System.out.println(name + " 's score is " + scores[i]); //If it's then we print it out
}else if(command.equals("quit"))
{
running = false; //The loop will never run again
//Implement sorting for youself I would use Map<K, V> but you didn't learned it so..
//In this case you have to make 1 loop to sort both of the arrays by sorting the second array
//and when you move anything must it in both arrays I can't help you to make this sorry
for(int i = 0; i < last; i++) //We print the sorted arrays of the people and their scores
System.out.println(names[i] + " 's score is " + scores[i]); //Let's print it
}
}
}
}

how to get a number to add like 12 is 3

i cant get the code right to ask for a number like 12 and then say the sum of the number is 3 in java netbeans
i got this so far
public class Exercise2_6 {
public static void main(String[] args) {
java.util.Scanner in = new java.util.Scanner( System.in );
System.out.println("Enter a number between 0 and 1000");
// Enter a number between 0 and 1000
Scanner input = new Scanner( System.in );
int x = in.nextInt( );
System.out.println(" The sum of the digits is "n" ");
System.out.println("n" = (in.nextInt( ) /100)); //this give you first digit
System.out.println("n" = in.nextInt( )%100); //this gives a number representing the remaining two digits
}
}
and it gives me back
run:
Enter a number between 0 and 1000
12
The sum of the digits is
Exception in thread "main" java.lang.RuntimeException: Uncompilable source code - not a statement
at Exercise2_6.main(Exercise2_6.java:55)
Java Result: 1
BUILD SUCCESSFUL (total time: 5 seconds)

Strings must be concatenated using the + operator.
Therefore, your statement of "n" = .... is not correct.
Replace
System.out.println("n" = (in.nextInt( ) /100)); //this give you first digit
System.out.println("n" = in.nextInt( )%100); //this gives a number representing the remaining two digits
with
System.out.println("n = " + in.nextInt()/100);
System.out.println("n = " + in.nextInt()%100);
However, the above statements will refer to TWO different ints, one for each time nextInt() is called. I don't know the purpose of your code but you should get into the practice of storing variables incase you need to use them again.
If you stored each int locally, for example
int n = in.nextInt();
you could then refer to it again later, for example by appending the above statements to
System.out.println("n = " + n/100); ....

This will probably not be the most efficient or 'correct' way of doing it, but I'm a complete noob myself. So, this is how I managed it. By using a while loop.
import java.util.Scanner;
public class SumOfDigits {
public static void main(String[] args) {
Scanner input = new Scanner (System.in);
int i, a = 0, x = 0;
System.out.println("Enter a number between 0 and 1000: ");
i = input.nextInt();
while(i != 0) {
a = i % 10;
i = i / 10;
x = x + a;
}
System.out.println("The sum of the digits in your number is: " + x);
}
}