How to use Jackson Mixin to map JsonNode into an object? - java

Given is a JsonNode with several levels of depth. From this node a few properties (not all) are to be used to build an object from a 3rd-party class. The class has a no-arg constructor as well as getter and setter.
With the help of a Mixin I want to achieve a mapping between the deeper nested properties of the JsonNode and the shallow properties of the object. Unfortunately, I could not find a relevant example besides this, but the example is too simplistic and I could not implement it for my requirement (maybe I am just not capable or patient enough to test all possibilities - then I apologize).
Here an excerpt of the JsonNode:
{
"datasource": {
"jdbcUrl": "jdbc:h2:mem:example-db",
"driverClassName": "org.h2.Driver",
"username": "sa",
"password": "let-me-in",
"hikari": {
"maximum-pool-size": 10
}
}
}
And here a simplified notion of the class to map to:
public class HikariConfig {
private String jdbcUrl;
private String driverClassName;
private volatile String username;
private volatile String password;
private volatile int maxPoolSize;
//...
}
As you can see from the maxPoolSize property, this value has to be mapped from nested with property name "maximum-pool-size" to shallow with property name "maxPoolSize". Since no special settings regarding visibility seem to be required, the following code should be sufficient for deserialization:
HikariConfig config = new ObjectMapper()
.addMixIn(HikariConfig.class, HikariConfigMixin.class)
.readerFor(HikariConfig.class)
.readValue(jsonNode);
What I need now is a working Mixin class. If I wanted to map into a own object, then I could simply avoid mixin and use records like this:
#JsonIgnoreProperties(ignoreUnknown = true)
private record ConfigData(Datasource datasource) {
private record Datasource(
String jdbcUrl,
String driverClassName,
String username,
String password,
Hikari hikari) {
private record Hikari(
#JsonProperty("maximum-pool-size") Integer maxPoolSize) { }
}
}
But of course that does not work here.
My question therefore:
Can somebody please tell me how to declare a Mixin that does a proper mapping? Preferably with annotations, perhaps using `#JsonPath` somehow?
Many thanks for any help

Related

Make Spring Boot JSON enum deserialization strict, so it does not silently convert invalid values into null

I am using Java Spring Boot #RestController with an object containing enum fields.
Spring automagically deserializes the JSON to the MyRequest object.
#RestController
public class MyController {
#PostMapping(path = "/operation")
public ResponseEntity<MyResponse> operation(#Valid #RequestBody MyRequest request) {
...
}
}
public class MyRequest {
private MyEnum1 field1;
private MyEnum2 field2;
private MyEnum3 field3;
private MyEnum4 field4;
private MyEnum5 field5;
private MyEnum6 field6;
... // really a lot of various enum fields!
}
public enum MyEnum1 {
VAL1, VAL2, VAL3;
}
The problem is that if the JSON contains completely invalid value of the enum field, the deserializer silently converts them to null, without any exception.
{
"field1": "BLAHBLAH",
...
}
This is user-unfriendly and treacherous.
I know that I may write custom JSON deserializers for each enum, but the solution is cumbersome and non-elegant.
Is there a way to globally set the JSON enum deserializer to a "strict mode", so if the value is invalid it throws an exception? If so, how and where?
That feature should be disabled by default.
But if you want to set it explicitly you can do it like this:
in your properties:
spring.jackson.deserialization.read-unknown-enum-values-as-null=false
or as an alternative in a configuration class (actually any bean would work, just make sure it happens early):
#Autowired
public void configureJackson(ObjectMapper objectMapper) {
objectMapper.disable(DeserializationFeature.READ_UNKNOWN_ENUM_VALUES_AS_NULL);
}
Because it should actually be like this by default, I am wondering why it is not for you. Do you enable it somewhere? Which Spring Boot version are you using?

Java - POJO Serialization Jackson 2.0

I've been scanning stack overflow all day and have not come across a viable solution for my problem.
I have a pojo that has primitive types and nested objects. For example...
#JsonIgnoreProperties({"duration", "errorCode", "haveFieldsChanged",
"serviceRequestToken", "storedProcDuration"}) // Abstract Base Class
properties
class Bus extends AbstractBaseClass implements Serializable{
#JsonIgnore
private static final long serialVersionId = 1;
#JsonProperty("name")
String name;
#JsonProperty("id")
int id;
#JsonProperty("students")
List<Student> students; // Nested Objects
#JsonProperty("employer")
Employer employer; //Nested object
// Getters and setters - none are annotated
#JsonRootName(value = "student")
class Student implements Serializable{
// student fields
}
#JsonRootName(value = "statusType")
class Employer implements Serializable{
#JsonProperty("id")
int id;
}
When I serialize my Bus object, jackson has no problem creating the proper structure for name, id, and my list of students. However, it will skip over Employer entirely leaving it absent from the json. See below.
{
"name":"Sean",
"id": 1,
"students":[student objects...]
}
I have tried #JsonProperty, #JsonSerialize(as = Employer.class), I tried building map for the employer object. I feel like I have exhausted most options. Is there something I am missing?
I ran into stack overflow exceptions trying some other annotations. I appreciate any help I can get.
The reason I added #JsonProperty to the fields is to help drive deserialization. I think this may be the root cause for serialization, but I am not certain.
Serialization Implementation
private String serializeBus(Bus bus) throws Exception {
ObjectMapper mapper = new ObjectMapper();
mapper.setVisibility(PropertyAccessor.ALL, Visibility.NONE);
mapper.setVisibility(PropertyAccessor.FIELD, Visibility.ANY);
String json = null;
try {
json = mapper.writeValueAsString(bus);
} catch (JsonProcessingException e) {
logger.error("Error serializing bus");
throw new Exception(e);
}
return json;
}
Thank you!
So, if it is not feasible for you to share code, then I put your example above in a little sandbox project: https://github.com/mle-enso/stackoverflow
It currently runs with Spring Boot 2.1 but also downgrading the managed Jackson version(s) to 2.6.1 has no negative impact.
Maybe you could try this project with a simple mvn clean verify or a manual test run of de.mle.stackoverflow.jackson.BusSerializerTest to dig further into this issue here.

How to use spring data with couchbase without _class attribute

Is there a simple way to use spring data couchbase with documents that do not have _class attribute?
In the couchbase I have something like this in my sampledata bucket:
{
"username" : "alice",
"created" : 1473292800000,
"data" : { "a": 1, "b" : "2"},
"type" : "mydata"
}
Now, is there any way to define mapping from this structure of document to Java object (note that _class attribute is missing and cannot be added) and vice versa so that I get all (or most) automagical features from spring couchbase data?
Something like:
If type field has value "mydata" use class MyData.java.
So when find is performed instead of automatically adding AND _class = "mydata" to generated query add AND type = "mydata".
Spring Data in general needs the _class field to know what to instantiate back when deserializing.
It's fairly easy in Spring Data Couchbase to use a different field name than _class, by overriding the typeKey() method in the AbsctractCouchbaseDataConfiguration.
But it'll still expect a fully qualified classname in there by default
Getting around that will require quite a bit more work:
You'll need to implement your own CouchbaseTypeMapper, following the model of DefaultCouchbaseTypeMapper. In the super(...) constructor, you'll need to provide an additional argument: a list of TypeInformationMapper. The default implementation doesn't explicitly provide one, so a SimpleTypeInformationMapper is used, which is the one that puts FQNs.
There's an alternative implementation that is configurable so you can alias specific classes to a shorter name via a Map: ConfigurableTypeInformationMapper...
So by putting a ConfigurableTypeInformationMapper with the alias you want for specific classes + a SimpleTypeInformationMapper after it in the list (for the case were you serialize a class that you didn't provide an alias for), you can achieve your goal.
The typeMapper is used within the MappingCouchbaseConverter, which you'll also need to extend unfortunately (just to instantiate your typeMapper instead of the default.
Once you have that, again override the configuration to return an instance of your custom MappingCouchbaseConverter that uses your custom CouchbaseTypeMapper (the mappingCouchbaseConverter() method).
You can achive this e.g. by creating custom annotation #DocumentType
#DocumentType("billing")
#Document
public class BillingRecordDocument {
String name;
// ...
}
Document will look like:
{
"type" : "billing"
"name" : "..."
}
Just create following classes:
Create custom AbstractReactiveCouchbaseConfiguration or AbstractCouchbaseConfiguration (depends which varian you use)
#Configuration
#EnableReactiveCouchbaseRepositories
public class CustomReactiveCouchbaseConfiguration extends AbstractReactiveCouchbaseConfiguration {
// implement abstract methods
// and configure custom mapping convereter
#Bean(name = BeanNames.COUCHBASE_MAPPING_CONVERTER)
public MappingCouchbaseConverter mappingCouchbaseConverter() throws Exception {
MappingCouchbaseConverter converter = new CustomMappingCouchbaseConverter(couchbaseMappingContext(), typeKey());
converter.setCustomConversions(customConversions());
return converter;
}
#Override
public String typeKey() {
return "type"; // this will owerride '_class'
}
}
Create custom MappingCouchbaseConverter
public class CustomMappingCouchbaseConverter extends MappingCouchbaseConverter {
public CustomMappingCouchbaseConverter(final MappingContext<? extends CouchbasePersistentEntity<?>,
CouchbasePersistentProperty> mappingContext, final String typeKey) {
super(mappingContext, typeKey);
this.typeMapper = new TypeBasedCouchbaseTypeMapper(typeKey);
}
}
and custom annotation #DocumentType
#Persistent
#Inherited
#Retention(RetentionPolicy.RUNTIME)
#Target({ElementType.TYPE})
public #interface DocumentType {
String value();
}
Then create TypeAwareTypeInformationMapper which will just check if an entity is annoatated by #DocumentType if so, use value from that annotation, do the default if not (fully qualified class name)
public class TypeAwareTypeInformationMapper extends SimpleTypeInformationMapper {
#Override
public Alias createAliasFor(TypeInformation<?> type) {
DocumentType[] documentType = type.getType().getAnnotationsByType(DocumentType.class);
if (documentType.length == 1) {
return Alias.of(documentType[0].value());
}
return super.createAliasFor(type);
}
}
Then register it as following
public class TypeBasedCouchbaseTypeMapper extends DefaultTypeMapper<CouchbaseDocument> implements CouchbaseTypeMapper {
private final String typeKey;
public TypeBasedCouchbaseTypeMapper(final String typeKey) {
super(new DefaultCouchbaseTypeMapper.CouchbaseDocumentTypeAliasAccessor(typeKey),
Collections.singletonList(new TypeAwareTypeInformationMapper()));
this.typeKey = typeKey;
}
#Override
public String getTypeKey() {
return typeKey;
}
}
In your couchbase configuration class you just need to have :
#Override
public String typeKey() {
return "type";
}
Unfortunately for query derivation (n1ql) the _class or type are still using the class name.Tried spring couch 2.2.6 and it's minus point here.
#Simon, are you aware that something has changed and the support to have the possibility to have custom _class/type value in next release(s)?
#SimonBasle
Inside of class N1qlUtils and method createWhereFilterForEntity we have access to the CouchbaseConverter. On line:
String typeValue = entityInformation.getJavaType().getName();
Why not use the typeMapper from the converter to get the name of the entity when we want to avoid using the class name? Otherwise you have to annotate each method in your repository as follows:
#Query("#{#n1ql.selectEntity} WHERE `type`='airport' AND airportname = $1")
List<Airport> findAirportByAirportname(String airportName);
If createWhereFilterForEntity used the CouchbaseConverter we could avoid annotating with the #Query.

XmlElement ignored by Jackson during serialization

i'm using Jersey to build a REST service and as Json Processor i set Jackson in my application.
#javax.ws.rs.ApplicationPath("/")
public class MyApplication extends ResourceConfig {
public MyApplication() {
packages("controller");
register(JacksonFeature.class);
}
I implement a ContextResolver for Jacksons ObjectMapper (as it's suggested in this post Configure Jersey/Jackson to NOT use #XmlElement field annotation for JSON field naming) which creates an ObjectMapper that doesn't fail on unknown properties during deserialization:
#Provider
public class MyJsonObjectMapperProvider implements ContextResolver<ObjectMapper> {
#Override
public ObjectMapper getContext(Class<?> type)
{
System.out.println("mapper!!!");
ObjectMapper result = new ObjectMapper();
result.configure(DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES, false);
return result;
}
}
and then i register this class in my application inserting register(MyJsonObjectMapperProvider.class) in the class MyApplication shown above. I obtain what i want, in sense that if there are unknown properties in the json the object mapper doesn't fail.
My problem is another; i have this class that i use to map a specified Json, in order to deserialize it and subsequently serialize it:
public class Version {
private String status;
private String updated;
private String id;
private List<Link> links;
#XmlElement(name = "media-types")
private List<MediaTypes> media_types;
//constructor + getter and setter
}
The problem is about the element media_types and the use of the annotation #XmlElement. Before i insert the ContextResolver to personalize ObjectMapper all works fine, in fact after serialization i obtain a json in which the element/attribute media_types has as name media-types; on the contrary with ContextResolver this element doesn't change it's name and has media_types. I think that, during serialization, the annotation XmlElement doesn't work, but i'm not sure that this is the correct reason.
Another attempt i try to do is to put #JsonProperty("media-types") annotation instead of #XmlElement annotation but with no result; in fact with this annotation i obtain also a Processing Exception.
The last attempt (in addition to what has been suggested by the previous post) was that of insert these lines of code in the ContextResolver:
AnnotationIntrospector intr = new AnnotationIntrospector.Pair(new JaxbAnnotationIntrospector(),new JacksonAnnotationIntrospector());
// usually we use same introspector(s) for both serialization and deserialization:
result.getDeserializationConfig().withAnnotationIntrospector(intr);
result.getSerializationConfig().withAnnotationIntrospector(intr);
in order to use both JaxbAnnotation and JacksonAnnotation but the name of the field in question remain media_types.
I hope i was clear in explain my problem and thanks you in advance for your help!

Jackson JSON library: how to instantiate a class with abstract fields that can't access its concrete representation?

This is the same questions than :
Jackson JSON library: how to instantiate a class that contains abstract fields
Nevertheless its solution is not possible since my abstract class is in another project than the concrete one.
Is there a way then ?
EDIT
My architecture is as follows:
public class UserDTO {
...
private LanguageDTO lang;
}
I send that object user :
restTemplate.postForObject(this.getHttpCore().trim() + "admin/user/save/1/" + idUser, userEntity, UserDTO.class);
Then I am supposed to receive it in the function :
#RequestMapping(value = "/save/{admin}/{idUser}", method = RequestMethod.POST)
public String saveUserById(#RequestBody final UserEntity user, #PathVariable Integer idUser, #PathVariable boolean admin)
with UserEntity defined as :
public class UserEntity extends AbstractUserEntity {
...
}
public abstract class AbstractUserEntity {
...
private AbstractLanguageEntity lang;
}
I would like to know how I can specify that lang should be instantiate as LanguageEntity whereas abstract classes are in another project.
This could work assuming you can configure how the object get serialized. See the example here. Look under "1.1. Global default typing" to set the defaults to include extra information in your JSON string, basically the concrete Java type that must be used when deserializing.
Since it seems you need to do this for your Spring servlet, you would have to pass a Spring message converter as mentioned here
Then inside your custom objectMapper, you can do the necessary configuration:
public class JSONMapper extends ObjectMapper {
public JSONMapper() {
this.enableDefaultTyping();
}
}
You could probably also make it work with Mix-ins, which allow you to add annotations to classes already defined. You can see and example here. This will also need to be configured inside the objectMapper.
If you need the same functionality on your client side (REST template), you can pass the object mapper as shown here.
The easiest way to solve that issue is to add getters et setters in UserEntity but specifying a concrete class :
public LanguageEntity getLang() {
return (LanguageEntity) lang;
}
public void setLang(LanguageEntity language){
this.lang = language
}
If all that you want to achieve is to note that LanguageEntity is the implementation of AbstractLanguageEntity, you can register this mapping via module:
SimpleModule myModule = new SimpleModule())
.addAbstractTypeMapping(AbstractLanguageEntity.class,
LanguageEntity.class);
ObjectMapper mapper = new ObjectMapper()
.registerMdoule(myModule);

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