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I am reading a CSV file using Java and wanted to write a regular expression to match below pattern. If it does not matches then output in the file. My issue is that i am not able to write the correct regex expression. Can someone help ?
Pattern = Name+" - "+NUMBER
Example:
Foo, Blah - 2345 = This should not output in the file
Some-Crap-Hello-1234 = this should output in the file
Some Name, Foo - 7898 = This should not output since the pattern matches with the last hyphen and space and number after that
Some Name - 1235 = This should output in the file since it has bunch of whitespaced before the hyphen
Foo, Blah - 11233 = This should not output in the file
Maybe this regex can help u
^[A-Za-z]+ - \d+$
For example, this pattern would match the following strings:
John - 123
Sarah - 4567
But not:
Sarah - 4567 other string here
Alexandra-9 (no space around the hyphen)
Alexandra - 9
Related
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I want to remove prefix and suffix in a String and extract the middle portion of the string.
For eg: Consider the Strings - "www.hello.com" and "www.test.com"
Here prefix - "www." and suffix - ".com". I want to extract the middle words - hello and test.
Currently i have achieved this using String.replace() method in Java.
str.replace("www.","").replace(".com","");
I want know is there any regular expression available to achieve it in a single method in java.
You could use a regex for that, it would work in the same way. Your regex would simply contain a capture group with both the prefix and the suffix in an OR operation.
(www\.|\.com)
You could then use this like you did with the replace.
String test = "www.test.com";
String output = test.replaceAll("(www\\.|\\.com)","")
P.S. this code is untested. Please don't just copy and paste it expecting everything to work.
(?<=www.)(.*)(?=.com)
This uses the lookbehind and lookahead feature of regex
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In a file there are 1000 of lines. I want to empty the line which has particular keyword.
For Example:
Input:
Danny akdfkldnklnflnwklfnlwen
I am sam
asndklfnklnfkldn DANNYkandfnkldnfkldnfklnskln
He is very well mannered.
klansdfnmkldnfkldnfklnsd_danny
Output Should be:
I am sam
He is very well mannered.
The line with keyword Danny should be entirely deleted to get the desired output.
Thanks for your help.
I have tried this http://rubular.com/r/bF0RzeaFYW
But it is not case sensitive.
The easiest option would be to:
Read the file one line at a time.
Use the .contains() method.
If the condition holds, then do nothing
Else, write the output to another file.
If you want to do the whole thing with a regular expression, you could find this expression: ^.*?danny.*?$ and replace it with an empty string. Example here.
Note: You will need to provide the following flags to the engine:
Multi line
Case Insensitive
From the command line: grep -vi danny input.txt
The -v flag removes all lines matching the pattern -- in this case "danny". The -i flag makes it case-insensitive.
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I want to get a value in a edi file having below format
\nRJCK3:0*20180105*U*127.35
\nRJCK3:0*20180105*B*127.35
I want a value U in 1st case, which comes between 2nd & 3rd star after RJC*K3, and want B in second string
Precisely, want to fetch a single character from a string, where that character will comes between 2nd & 3rd star(*) of a RJC*K3(static value).
You can use a classic Pattern matching way :
String str1 = "\\nRJC*K3:0*20180105*U*127.35";
Matcher m = Pattern.compile("RJC\\*K3.*\\*(\\w)\\*.*").matcher(str1);
String res1 = m.find() ? m.group(1) : "";
System.out.println(res1); // U
But if there is always the same amount of * before the letter you want, you cn easily split and take the 3rd part :
String str2 = "\\nRJC*K3:0*20180105*G*127.35";
String res2 = str2.split("\\*")[3];
System.out.println(res2); // G
There is no need to fight with edi files, you can use available libraries.
Please take a look at https://github.com/imsweb/x12-parser/
RJCloop.getSegment("RJC").getElementValue("RJC02")
can get you the value needed.
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I am trying to use java's string.replaceAll() or replaceFirst() method in order to edit data read from a pdf document. A line of data that could be returned is:
21/1**E (6-11) 4479 77000327633 (U)
I wish to only store the 77000327633 into a variable for working with and looking for the correct regex that will capture ONLY this 11 digit number. I've tried searching around for a regex but nothing seems to give me my desired outcome.
It could be done like this:
String value = "21/1**E (6-11) 4479 77000327633 (U)";
Pattern pattern = Pattern.compile(".* (\\d{11}) .*");
System.out.println(pattern.matcher(value).replaceAll("$1"));
Output:
77000327633
NB: This assumes that your number has 11 digits and that there is a space before and after.
NB2: It is not meant to be perfect it is only to show the idea which is here to define a global pattern with a group and replace everything by the content of the group
This is it : (.*)[ ]([0-9])*[ ](.*)
Can access to your value using $2
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I have string in following format:
String s = " some text....
[[Category:Anarchism| ]]
[[Category:Political culture]]
[[Category:Political ideologies]]
[[Category:Far-left politics]]
... some more text"
I want to extract all the categories from this text. [Anarchism,Political culture ....,Far-left politics]
Also, is there a good tutorial where I can learn about this regex pattern matching stuff..
Thanks
You can use the following regex to get categories:
\[\[Category:(.+)\]\]
Then you can access to your groups to get the category values.
Remember to add backslash to backslashes if you use on java strings:
\\[\\[Category:(.+)\\]\\]
You can see it working:
Assuming you don't want to select the word "Category" itself, the regex would be:
(?<=Category:).*?(?=])
I'll break this down a bit for you.
The first bit in brackets looks for Category, without actually selecting it.
Next .+? looks for 1-infinity characters (other than a newline), but stops as soon as the next part is matched:
The final brackets tells it to look for a ], but without actually selecting it.
The results would be the bits below highlighted in blue.