Comparing two JSONs - java

What's the best way to compare two JSON strings in Java? I want to be able to print out only the difference in key/values pairs.
I'm using gson library to convert it to a map and do assert but it displays both JSONs:
Type type = new TypeToken<Map<String, String>>() {}.getType();
Gson gson = new Gson();
Map<String, String> mapExpected = gson.fromJson(expectedJson, type);
Map<String, String> mapResponse = gson.fromJson(jsonResponse, type);
Assert.assertEquals(mapExpected, mapResponse);
Is there a better way to do this?

If you just wanted to compare simple equality, Jackson would make it easy; and just in case this might help it'd be:
JsonNode tree1 = objectMapper.readTree(json1);
JsonNode tree2 = objectMapper.readTree(json2);
if (!tree1.equals(tree2)) { // handle diffing
}
Now; since all JsonNode objects properly implement equality checks (so that ordering of keys does not matter etc), you could use this for recursive diffing to see where and how contents differ. For ObjectNodes you could get key names, remove same (tree1.getFieldNames().removeAll(tree2.getFieldNames()) and so on.

It is tricky, but it can be done.
I would implement a Pair class that holds both String (key and value), with its corresponding equals() and hashcode();
Then put all elements from Map A as Pair in a Set (setA) and all elements from Map B in another Set (setB)
Then calculate
Set<Pair> setA_B = setA.removeAll(setB);
Set<Pair> setB_A = setB.removeAll(setA);
Set<Pair> result = setA_B.addAll(setB_A);
In result there are only the elements that do not match. If all elements match (both original maps are equal) then result is empty.

Using SJuan76's solution, I was able to get just the difference in Key value pairs.
Type type = new TypeToken<Map<String, String>>() {}.getType();
Gson gson = new Gson();
Map<String, String> mapExpected = gson.fromJson(expectedJson, type);
Map<String, String> mapResponse = gson.fromJson(jsonResponse, type);
Set<SimpleEntry<String,String>> expectedSet = new HashSet<SimpleEntry<String, String>>();
Set<SimpleEntry<String, String>> tmpExpectedSet = new HashSet<SimpleEntry<String, String>>();
Set<SimpleEntry<String, String>> responseSet = new HashSet<SimpleEntry<String, String>>();
for (String key : mapExpected.keySet()) {
expectedSet.add(new SimpleEntry<String, String>(key, mapExpected.get(key)));
tmpExpectedSet.add(new SimpleEntry<String, String>(key, mapExpected.get(key)));
}
for (String key : mapResponse.keySet())
responseSet.add((new SimpleEntry<String, String>(key, mapResponse.get(key))));
expectedSet.removeAll(responseSet);
responseSet.removeAll(tmpExpectedSet);
expectedSet.addAll(responseSet);
if (!expectedSet.isEmpty()) {
for (SimpleEntry<String, String> diff : expectedSet)
log.error(diff.getKey() + ":" + diff.getValue());
}

Related

How can I convert a 'Collection<Map<String,String>>' to 'Map<String,String>'?

I want to convert from Collection<Map<String,String>> to Map<String,String>.
When I tried to do this way,
Map<String,String> m = (Map<String,String>)map.values();
where,
map is of type Map<String,Map<String,String>>
I'm getting
java.lang.ClassCastException: java.util.TreeMap$Values cannot be cast to java.util.Map
What is it trying to say? I'm not able to get it and how do I correctly convert from Collection<Map<String,String>> to Map<String,String>?
You can use this small snippet to put all the values into a single map:
Map<String, String> result = new TreeMap<>();
for(Map<String, String> value : map.values()) {
result.putAll(value);
}
Though this will just overwrite duplicate keys with a new value if there are any.
As long as it's collection then you should think as it's collection of objects.
Then proceed the iteration, for each object, you shall put it in the map
public Map<String, String> getMapsFromArrayOfMaps( Collection<Map<String,String>> maps ) {
Map<String, String> result = new HashMap<>();
maps.forEach(map->result.putAll(map));
return result ;
}

Storing multiple datatypes in a single HashMap

I want to put an array of int and a String into a HashMap. Is this possible? what is the proper way to that?
This is my HashMap:
Map<String, String> stringMap = new HashMap<>();
stringMap.put("Text","fish" );
stringMap.put("Diet","false");
stringMap.put("CookingTime", "60");
stringMap.put("OptionId", [7,8,8]);
I know this line is wrong - how do I store an array in a HashMap?
stringMap.put("OptionId", [7,8,8]);
You can instantiate an array in java by doing
someMap.put("OptionId", new int[]{7,8,8});
Otherwise you will need a function that returns those values in an array.
For your case: if you want to create a HashMap of multiple datatypes you can use
HashMap<String, Object> map = new HashMap<String, Object>();
You can then put anything you want in
map.put("key1", "A String");
map.put("key2", new int[]{7,8,8});
map.put("key3", 123);
Except now the tricky part is you don't know what is what so you need to use instanceof to parse the map unless you know what type of object is at a key then you can just cast it to that type.
if(map.get("key1") instanceof String)
String s = (String) map.get("key1"); // s = "A String"
or
int[] arr = (int[]) map.get("key2"); // arr = {7,8,8}

How to add a value to a list of values for a single key in a hashmap (Java)

I have written this:
HashMap<String, String> map1 = new HashMap<String, String>();
Map<String, ArrayList<String>> map2 = new HashMap<String, ArrayList<String>>();
i am trying to allow more then 1 value for each key in a hashmap. so if the first key is '1', i want to allow '1' to be paired with values '2' and '3'.
so it be like:
1 --> 2
|--> 3
but when I do:
map2.put(key, value);
it gives error that says "incompatible types" and it can not be converted to ArrayList and it says the error is at the value part of the line.
If you are using Java 8, you can do this quite easily:
String key = "someKey";
String value1 = "someValue1";
String value2 = "someValue2";
Map<String, List<String>> map2 = new HashMap<>();
map2.computeIfAbsent(key, k -> new ArrayList<>()).add(value1);
map2.computeIfAbsent(key, k -> new ArrayList<>()).add(value2);
System.out.println(map2);
The documentation for Map.computeIfAbsent(...) has pretty much this example.
In map2 you need to add ArrayList (you declared it as Map<String, ArrayList<String>> - the second one is the value type) only, that's why it gives you incompatible types.
You would need to do initialize the key with an ArrayList and add objects to it later:
if (!map2.containsKey(key)) {
map2.put(key, new ArrayList<String>());
}
map2.get(key).add(value);
Or you could use Multimap from guava, then you can just map2.put and it won't overwrite your values there but add to a list.
You are little bit away from what you are trying to do.
Map<String, ArrayList<String>> map2 = new HashMap<String, ArrayList<String>>();
this will allow only String as key and an ArrayList as value. So you have to try something like:
ArrayList<String> value=new ArrayList<String>();
value.add("2");
value.add("3");
map2.put("1", value);
When retrieving you also have to follow ans opposite procedure.
ArrayList<String> valueTemp=map2.get("1");
then you can iterate over this ArrayList to get those values ("2" and "3");
Try like this. //use list or set.. but set avoids duplicates
Map<String, Set<String>> map = new HashMap<>();
Set<String> list = new HashSet<>();
// add value to the map
Boolean b = map.containsKey(key);
if (b) {
map.get(key).addAll(list);
} else
map.put(key, list);
}
You can not add different values in same key in Map. Map is override the value in that key. You can do like this way.
Map<String, ArrayList<String>> map = new HashMap<String, ArrayList<String>>();
ArrayList<String> list=new ArrayList<String>();
list.add("2");
list.add("3");
map.put("1", list);
first add value in array list then put into map.
It is all because standard Map implementations in java stores only single pairs (oneKey, oneValue). The only way to store multiple values for a particular key in a java standard Map is to store "collection" as value, then you need to access this collection (from Map) by key, and then use this collection "value" as regular collection, in your example as ArrayList. So you do not put something directly by map.put (except from creating the empty collection), instead you take the whole collection by key and use this collection.
You need something like Multimap, for example:
public class Multimap<T,S> {
Map<T, ArrayList<S>> map2 = new HashMap<T, ArrayList<S>>();
public void add(T key, S value) {
ArrayList<T> currentValuesForGivenKey = get(key);
if (currentValuesForGivenKey == null) {
currentValuesForGivenKey = new ArrayList<T>();
map2.get(key, currentValuesForGivenKey);
}
currentValuesForGivenKey.add(value);
}
public ArrayList<S> get(T key) {
ArrayList<String> currentValuesForGivenKey = map2.get(key);
if (currentValuesForGivenKey == null) {
currentValuesForGivenKey = new ArrayList<S>();
map2.get(key, currentValuesForGivenKey);
}
return currentValuesForGivenKey;
}
}
then you can use it like this:
Multimap<String,String> map2 = new Multimap<String,String>();
map2.add("1","2");
map2.add("1","3");
map2.add("1","4");
for (String value: map2.get("1")) {
System.out.println(value);
}
will print:
2
3
4
it gives error that says "incompatible types" and it can not be converted to ArrayList and it says the error is at the value part of the line.
because, it won't automatically convert to ArrayList.
You should add both the values to list and then put that list in map.

java multi mapping arraylist

Is it possible to map key to Multi Dimensional Array List. Some thing like following example..
Map<K,V>
Where K is key for list of alphabet and V is a multi dimensional array list or normal array list that stores list of word. Some thing like a application that reads a dictionary file. I want to see an example. Example can be anything related to Map and Multi Dimensional Array-list. Or is there any other efficient way to implement collection? I have never used such implementations so if there is already a thread related to mine QA please post the link.
You can always do Map<String, <List<String>>. e.g.
Map<String, List<String>> multimap = new HashMap<String, List<String>>();
String key = "asdf";
List<String> values = Arrays.asList("foo", "bar");
multimap.put(key, values);
You can also use the Multimap<String, String> interface in Google Guava - might be a better fit for your needs. It simplifies the coding somewhat -
Multimap<String, String> multimap = new ArrayListMultimap<String, String>();
String key = "asdf";
multimap.put(key, "foo");
multimap.put(key, "bar");
You can use Guava's Multimap's if you want to associate multiple values with a single key. You need ArrayListMultimap for your specific case.
Example
ListMultimap<String, String> dict= new ArrayListMultimap<String, String>();
dict.put("key 1", "value 1");
dict.put("key 1", "value 2");
dict.put("key 2", "value 1");
Following code without Google's Guava library. It is used for double value as key and sorted order
Map<Double,List<Object>> multiMap = new TreeMap<Double,List<Object>>();
for( int i= 0;i<15;i++)
{
List<Object> myClassList = multiMap.get((double)i);
if(myClassList == null)
{
myClassList = new ArrayList<Object>();
multiMap.put((double) i,myClassList);
}
myClassList.add("Value "+ i);
}
List<Object> myClassList = multiMap.get((double)0);
if(myClassList == null)
{
myClassList = new ArrayList<Object>();
multiMap.put( (double) 0,myClassList);
}
myClassList.add("Value Duplicate");
for (Map.Entry entry : multiMap.entrySet())
{
System.out.println("Key = " + entry.getKey() + ", Value = " +entry.getValue());
}

Java associative-array

How can I create and fetch associative arrays in Java like I can in PHP?
For example:
$arr[0]['name'] = 'demo';
$arr[0]['fname'] = 'fdemo';
$arr[1]['name'] = 'test';
$arr[1]['fname'] = 'fname';
Java doesn't support associative arrays, however this could easily be achieved using a Map. E.g.,
Map<String, String> map = new HashMap<String, String>();
map.put("name", "demo");
map.put("fname", "fdemo");
// etc
map.get("name"); // returns "demo"
Even more accurate to your example (since you can replace String with any object that meet your needs) would be to declare:
List<Map<String, String>> data = new ArrayList<>();
data.add(0, map);
data.get(0).get("name");
See the official documentation for more information
Java doesn't have associative arrays like PHP does.
There are various solutions for what you are doing, such as using a Map, but it depends on how you want to look up the information. You can easily write a class that holds all your information and store instances of them in an ArrayList.
public class Foo{
public String name, fname;
public Foo(String name, String fname){
this.name = name;
this.fname = fname;
}
}
And then...
List<Foo> foos = new ArrayList<Foo>();
foos.add(new Foo("demo","fdemo"));
foos.add(new Foo("test","fname"));
So you can access them like...
foos.get(0).name;
=> "demo"
You can accomplish this via Maps. Something like
Map<String, String>[] arr = new HashMap<String, String>[2]();
arr[0].put("name", "demo");
But as you start using Java I am sure you will find that if you create a class/model that represents your data will be your best options. I would do
class Person{
String name;
String fname;
}
List<Person> people = new ArrayList<Person>();
Person p = new Person();
p.name = "demo";
p.fname = "fdemo";
people.add(p);
Look at the Map interface, and at the concrete class HashMap.
To create a Map:
Map<String, String> assoc = new HashMap<String, String>();
To add a key-value pair:
assoc.put("name", "demo");
To retrieve the value associated with a key:
assoc.get("name")
And sure, you may create an array of Maps, as it seems to be what you want:
Map<String, String>[] assoc = ...
There is no such thing as associative array in Java. Its closest relative is a Map, which is strongly typed, however has less elegant syntax/API.
This is the closest you can get based on your example:
Map<Integer, Map<String, String>> arr =
org.apache.commons.collections.map.LazyMap.decorate(
new HashMap(), new InstantiateFactory(HashMap.class));
//$arr[0]['name'] = 'demo';
arr.get(0).put("name", "demo");
System.out.println(arr.get(0).get("name"));
System.out.println(arr.get(1).get("name")); //yields null
Well i also was in search of Associative array and found the List of maps as the best solution.
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class testHashes {
public static void main(String args[]){
Map<String,String> myMap1 = new HashMap<String, String>();
List<Map<String , String>> myMap = new ArrayList<Map<String,String>>();
myMap1.put("URL", "Val0");
myMap1.put("CRC", "Vla1");
myMap1.put("SIZE", "Vla2");
myMap1.put("PROGRESS", "Vla2");
myMap.add(0,myMap1);
myMap.add(1,myMap1);
for (Map<String, String> map : myMap) {
System.out.println(map.get("URL"));
}
//System.out.println(myMap);
}
}
Java equivalent of Perl's hash
HashMap<Integer, HashMap<String, String>> hash;
Java doesn't have associative arrays, the closest thing you can get is the Map interface
Here's a sample from that page.
import java.util.*;
public class Freq {
public static void main(String[] args) {
Map<String, Integer> m = new HashMap<String, Integer>();
// Initialize frequency table from command line
for (String a : args) {
Integer freq = m.get(a);
m.put(a, (freq == null) ? 1 : freq + 1);
}
System.out.println(m.size() + " distinct words:");
System.out.println(m);
}
}
If run with:
java Freq if it is to be it is up to me to delegate
You'll get:
8 distinct words:
{to=3, delegate=1, be=1, it=2, up=1, if=1, me=1, is=2}
Use ArrayList < Map < String, String > >
Here a code sample :
ArrayList<Map<String, String>> products = new ArrayList<Map<String, String>>();
while (iterator.hasNext()) {
Map<String, String> product = new HashMap<String, String>();
Element currentProduct = iterator.next();
product.put("id",currentProduct.get("id"));
product.put("name" , currentProduct.get("name") );
products.add(product );
}
System.out.println("products : " + products);
Output :
products : [{id=0001, name=prod1}, {id=0002, name=prod2}]
Associative arrays in Java like in PHP :
SlotMap hmap = new SlotHashMap();
String key = "k01";
String value = "123456";
// Add key value
hmap.put( key, value );
// check if key exists key value
if ( hmap.containsKey(key)) {
//.....
}
// loop over hmap
Set mapkeys = hmap.keySet();
for ( Iterator iterator = mapkeys.iterator(); iterator.hasNext();) {
String key = (String) iterator.next();
String value = hmap.get(key);
}
More info, see Class SoftHashMap : https://shiro.apache.org/static/1.2.2/apidocs/org/apache/shiro/util/SoftHashMap.html
Object[][] data = {
{"mykey1", "myval1"},
{"mykey2", "myval2"},
{new Date(), new Integer(1)},
};
Yes, this require iteration for searchting value by key, but if you need all of them, this will be the best choice.
In JDK 1.5 (http://tinyurl.com/3m2lxju) there is even a note: "NOTE: This class is obsolete. New implementations should implement the Map interface, rather than extending this class."
Regards, N.
Actually Java does support associative arrays they are called dictionaries!
Thinking more about it, I would like to throw out tuples as a more general-purpose way of dealing with this problem. While tuples are not native to Java, I use Javatuples to provide me the same functionality which would exist in other languages. An example of how to deal with the question asked is
Map<Pair<Integer, String>, String> arr = new HashMap<Pair<Integer, String>, String>();
Pair p1 = new Pair(0, "name");
arr.put(p1, "demo");
I like this approach because it can be extended to triples and other higher ordered groupings with api provided classes and methods.
Regarding the PHP comment 'No, PHP wouldn't like it'. Actually, PHP would keep on chugging unless you set some very restrictive (for PHP) exception/error levels, (and maybe not even then).
What WILL happen by default is that an access to a non existing variable/out of bounds array element 'unsets' your value that you're assigning to. NO, that is NOT null. PHP has a Perl/C lineage, from what I understand. So there are: unset and non existing variables, values which ARE set but are NULL, Boolean False values, then everything else that standard langauges have. You have to test for those separately, OR choose the RIGHT evaluation built in function/syntax.

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