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Java 8 UTF-16 isn't default charset but UTF-8

I been doing some coding with String in Java8,Java 11 but this question is based on Java 8. I have this little snippet.
final char e = (char)200;//È
I just thought that the characters between 0.255[Ascii+extended Ascii] would always fit in a byte just because 2^8=256 but this seems not to be true i have try on the website https://mothereff.in/byte-counter and states that the character is taking 2 bytes can somebody please explain to me.
Another question in a lot of post states that Java is UTF-16 but in my machine running Windows 7 is returning UTF-8 in this snippet.
String csn = Charset.defaultCharset().name();
Is this platform depent?
Other questions i have try this snippet.
final List<Charset>charsets = Arrays.asList(StandardCharsets.ISO_8859_1,StandardCharsets.US_ASCII,StandardCharsets.UTF_16,StandardCharsets.UTF_8);
charsets.forEach(a->print(a,"È"));
System.out.println("getBytes");
System.out.println(Arrays.toString("È".getBytes()));
charsets.forEach(a->System.out.println(a+" "+Arrays.toString(sb.toString().getBytes(a))));
private void print(final Charset set,final CharSequence sb){
byte[] array = new byte[4];
set.newEncoder()
.encode(CharBuffer.wrap(sb), ByteBuffer.wrap(array), true);
final String buildedString = new String(array,set);
System.out.println(set+" "+Arrays.toString(array)+" "+buildedString+"<<>>"+buildedString.length());
}
And prints
run:
ISO-8859-1 [-56, 0, 0, 0] È//PERFECT USING 1 BYTE WHICH IS -56
US-ASCII [0, 0, 0, 0] //DONT GET IT SEE THIS ITEM FOR LATER
UTF-16 [-2, -1, 0, -56] È<<>>1 //WHAT IS -2,-1 BYTE USED FOR? I HAVE TRY WITH OTHER EXAMPLES AND THEY ALWAYS APPEAR AM I LOSING TWO BYTES HERE??
UTF-8 [-61, -120, 0, 0] 2 È //SEEMS TO MY CHARACTER NEEDS TWO BYTES?? I THOUGHT THAT CODE=200 WOULD REQUIRE ONLY ONE
getBytes
[-61, -120]//OK MY UTF-8 REPRESENTATION
ISO-8859-1 [-56]//OK
US-ASCII [63]//OK BUT WHY WHEN I ENCODE IN ASCCI DOESNT GET ANY BYTE ENCODED?
UTF-16 [-2, -1, 0, -56]//AGAIN WHAT ARE -2,-1 IN THE LEADING BYTES?
UTF-8 [-61, -120]//OK
I have try
System.out.println(new String(new byte[]{-1,-2},"UTF-16"));//SIMPLE "" I AM WASTING THIS 2 BYTES??
In resume.
Why UTF-16 always has two leading bytes are they wasted? new byte[]{-1,-2}
Why when i encode "È" i dont get any bytes in ASCCI Charset but when i do È.getBytes(StandardCharsets.US_ASCII) i get {63}?
Java uses UTF-16 but in my case UTF-8 is platform depend??
Sorry if this post is confussing
Environment
Windows 7 64 Bits Netbeans 8.2 with Java 1.8.0_121

First question
For your first question: those bytes are the BOM code and they specify the byte order (whether the least or most significant comes first) of multibyte encoding such as UTF-16.
Second question
Every ASCII character can be encoded as a single byte in UTF-8. But ASCII is not an 8-bit encoding, it uses 7 bits for every character. And in fact, all Unicode character with code points >= 128 require at least two bytes. (The reason is that you need a way to distinguish between 200 and a multibyte code point whose first byte happens to be 200. UTF-8 solves this by using the bytes >= 128 to represent multibyte codepoints.)
'È' is not an ASCII character, so it cannot be represented in ASCII. This explains the second output: 63 is ASCII for the character '?'. And indeed, the Javadoc for the getBytes(Charset) method specifies that unmappable input is mapped to "the default replacement byte array", in this case '?'. On the other hand, to obtain the first ASCII byte array you used the CharsetEncoder directly, which is a more low-level API and does not perform such automatic replacements. (When you would have checked the result of the encode method, you would have found it to have returned a CoderResult instance representing an error.)
Third question
Java 8 Strings use UTF-16 internally, but when communicating with other software, different encodings may be expected, such as UTF-8. The Charset.defaultCharset() method returns the default character set of the virtual machine, which depends on the locale and character set of the operating system, not on the encoding used internally by Java strings.

Let's back up a bit…
Java's text datatypes use the UTF-16 character encoding of the Unicode character set. (As do, VB4/5/6/A/Script, JavaScript, .NET, ….) You can see this in the various operations you do with the string API: indexing, length, ….
Libraries support converting between the text datatypes and byte arrays using various encodings. Some of them are categorized as "Extended ASCII", but stating that is a very poor substitute for naming the character encoding actually being used.
Some operating systems allow the user to designate a default character encoding. (Most users don't know or care, though.) Java attempts to pick this up. It is only useful when the program understands that input from the user is that character encoding or that output should be. This century, users dealing in text files prefer to use a specific encoding, communicate them unchanged across systems, don't appreciate lossy conversions and therefore don't have any use for this concept. From a program's point of view, it is never what you want unless it is exactly what you want.
Where a conversion would be lossy, you have the choice of a replacement character (such a '?'), omitting it, or throwing an exception.
A character encoding is a map between a codepoint (integer) of a character set and one or more code units, according to the definition of the encoding. A code unit is a fixed size and the number of code units needed for a codepoint, might vary by codepoint.
In libraries, it is not generally useful to have an array of code units so they take the further step of converting to/from an array of bytes. byte values do range from -128 to 127, however, that's the Java interpretation as two's complement 8-bit integers. As the bytes are understood to be encoding text, the values would be interpret according to the rules of the character encoding.
Because some Unicode encodings, have code units more than one byte long, byte order becomes important. So, at the byte array level, there is UTF-16 Big Endian and UTF-16 Little Endian. When communicating a text file or stream, you would send the bytes and well as having a shared knowledge of the encoding. This "metadata" is required for understanding. So, UTF-16BE or UTF-16LE, for example. To make that a bit easier, Unicode allows some metadata beginning of the file or stream to indicate the byte order. It is called the byte-order mark (BOM) So, the external metadata can share the encoding (say, UTF-16), while the internal metadata shares the byte order. Unicode allows the BOM to be present even when byte order is not relevant, such as UTF-8. So, if the understanding is that the bytes are text encoded with any Unicode encoding and a BOM is present, then it's a very simple matter to figure out which Unicode encoding it is and what the byte order is, if relavent.
1) You are seeing the BOM in some of your Unicode encoding outputs.
2) È is not in the ASCII character set. What would want to happen in this case? I often prefer an exception.
3) The system you were using, for your account, at the time of your tests, may have had UTF-8 as the default character encoding, Is that important to the way you want and have encoded your text files on that system?

When I assign char (from literal or otherwise), what "java internal encoding is UTF16" means here? In what encoding is it stored in char?

//non-utf source file encoding
char ch = 'ё'; // some number within 0..65535 is stored in char.
System.out.println(ch); // the same number output to
"java internal encoding is UTF16". Where does it meanfully come to play in that?
Besides, I can perfectly put into char one utf16 codeunit from surrogate range (say '\uD800') - making this char perfectly invalid Unicode. And let us stay within BMP, so to avoid thinking that we might have 2 chars (codeunits) for a supplementary symbol (thinking this way sounds to me that "char internally uses utf16" is complete nonsense). But maybe "char internally uses utf16" makes sense within BMP?
I could undersand it if were like this: my source code file is in windows-1251 encoding, char literal is converted to number according to windows-1251 encoding (what really happens), then this number is automatically converted to another number (from windows-1251 number to utf-16 number) - which is NOT taking place (am I right?! this I could understand as "internally uses UTF-16"). And then that stored number is written to (really it is written as given, as from win-1251, no my "imaginary conversion from internal utf16 to output\console encoding" taking place), console shows it converting from number to glyph using console encoding (what really happens)
So this "UTF16 encoding used internally" is NEVER USED ANYHOW ??? char just stores any number (in [0..65535]), and besides specific range and being "unsigned" has NO DIFFERENCE FROM int (in scope of my example of course)???
P.S. Experimentally, code above with UTF-8 encoding of source file and console outputs
й
1081
with win-1251 encoding of source file and UTF-8 in console outputs
�
65533
Same output if we use String instead of char...
String s = "й";
System.out.println(s);
In API, all methods taking char as argument usually never take encoding as argument. But methods taking byte[] as argument often take encoding as another argument. Implying that with char we don't need encoding (meaning that we know this encoding for sure). But **how on earth do we know in what encoding something was put into char???
If char is just a storage for a number, we do need to understand what encoding this number originally came from?**
So char vs byte is just that char has two bytes of something with UNKNOWN encoding (instead of one byte of UNKNOWN encoding for a byte).
Given some initialized char variable, we don't know what encoding to use to correctly display it (to choose correct console encoding for output), we cannot tell what was encoding of source file where it was initialized with char literal (not counting cases where various encodings and utf would be compatilble).
Am I right, or am I a big idiot? Sorry for asking in latter case :)))
SO research shows no direct answer to my question:
In what encoding is a Java char stored in?
What encoding is used when I type a character?
To which character encoding (Unicode version) set does a char object
correspond?

In most cases it is best to think of a char just as a certain character (independent of any encoding), e.g. the character 'A', and not as a 16-bit value in some encoding. Only when you convert between char or a String and a sequence of bytes does the encoding play a role.
The fact that a char is internally encoded as UTF-16 is only important if you have to deal with it's numeric value.
Surrogate pairs are only meaningful in a character sequence. A single char can not hold a character value outside the BMP. This is where the character abstraction breaks down.

Unicode is system of expressing textual data as codepoints. These are typically characters, but not always. A Unicode codepoint is always represented in some encoding. The common ones are UTF-8, UTF-16 and UTF-32, where the number indicates the number of bits in a codeunit. (For example UTF-8 is encoded as 8-bit bytes, and UTF-16 is encoded as 16-bit words.)
While the first version of Unicode only allowed code points in the range 0hex ... FFFFhex, in Unicode 2.0, they changed the range to 0hex to 10FFFFhex.
So, clearly, a Java (16 bit) char is no longer big enough to represent every Unicode code point.
This brings us back to UTF-16. A Java char can represent Unicode code points that are less or equal to FFFFhex. For larger codepoints, the UTF-16 representation consists of 2 16-bit values; a so-called surrogate pair. And that will fit into 2 Java chars. So in fact, the standard representation of a Java String is a sequence of char values that constitute the UTF-16 representation of the Unicode code points.
If we are working with most modern languages (including CJK with simplified characters), the Unicode code points of interest are all found in code plane zero (0hex through FFFFhex). If you can make that assumption, then it is possible to treat a char as a Unicode code point. However, increasingly we are seeing code points in higher planes. A common case is the code points for Emojis.)
If you look at the javadoc for the String class, you will see a bunch of methods line codePointAt, codePointCount and so on. These allow you to handle text data properly ... that is to deal with the surrogate pair cases.
So how does this relate to UTF-8, windows-1251 and so on?
Well these are 8-bit character encodings that are used at the OS level in text files and so on. When you read a file using a Java Reader your text is effectively transcoded from UTF-8 (or windows-1251) into UTF-16. When you write characters out (using a Writer) you transcode in the other direction.
This doesn't always work.
Many character encodings such as windows-1251 are not capable of representing the full range of Unicode codepoints. So, if you attempt to write (say) a CJK character via a Writer configured a windows-1251, you will get ? characters instead.
If you read an encoded file using the wrong character encoding (for example, if you attempt to read a UTF-8 file as windows-1251, or vice versa) then the trancoding is liable to give garbage. This phenomenon is so common it has a name: Mojibake).
You asked:
Does that mean that in char ch = 'й'; literal 'й' is always converted to utf16 from whatever encoding source file was in?
Now we are (presumably) talking about Java source code. The answer is that it depends. Basically, you need to make sure that the Java compiler uses the correct encoding to read the source file. This is typically specified using the -encoding command line option. (If you don't specify the -encoding then the "platform default converter" is used; see the javac manual entry.)
Assuming that you compile your source code with the correct encoding (i.e. matching the actual representation in the source file), the Java compiler will emit code containing the correct UTF-16 representation of any String literals.
However, note that this is independent of the character encoding that your application uses to read and write files at runtime. That encoding is determined by what your application selects or the execution platform's default encoding.

Will String.getBytes("UTF-16") return the same result on all platforms?

I need to create a hash from a String containing users password. To create the hash, I use a byte array which I get by calling String.getBytes(). But when I call this method with specified encoding, (such as UTF-8) on a platform where this is not the default encoding, the non-ASCII characters get replaced by a default character (if I understand the behaviour of getBytes() correctly) and therefore on such platform, I will get a different byte array, and eventually a different hash.
Since Strings are internally stored in UTF-16, will calling String.getBytes("UTF-16") guarantee me that I get the same byte array on every platform, regardless of its default encoding?

Yes. Not only is it guaranteed to be UTF-16, but the byte order is defined too:
When decoding, the UTF-16 charset interprets the byte-order mark at the beginning of the input stream to indicate the byte-order of the stream but defaults to big-endian if there is no byte-order mark; when encoding, it uses big-endian byte order and writes a big-endian byte-order mark.
(The BOM isn't relevant when the caller doesn't ask for it, so String.getBytes(...) won't include it.)
So long as you have the same string content - i.e. the same sequence of char values - then you'll get the same bytes on every implementation of Java, barring bugs. (Any such bug would be pretty surprising, given that UTF-16 is probably the simplest encoding to implement in Java...)
The fact that UTF-16 is the native representation for char (and usually for String) is only relevant in terms of ease of implementation, however. For example, I'd also expect String.getBytes("UTF-8") to give the same results on every platform.

It is true, java uses Unicode internally so it may combine any script/language. String and char use UTF-16BE but .class files store there String constants in UTF-8. In general it is irrelevant what String does, as there is a conversion to bytes specifying the encoding the bytes have to be in.
If this encoding of the bytes cannot represent some of the Unicode characters, a placeholder character or question mark is given. Also fonts might not have all Unicode characters, 35 MB for a full Unicode font is a normal size. You might then see a square with 2x2 hex codes or so for missing code points. Or on Linux another font might substitute the char.
Hence UTF-8 is a perfect fine choice.
String s = ...;
if (!s.startsWith("\uFEFF")) { // Add a Unicode BOM
s = "\uFEFF" + s;
}
byte[] bytes = s.getBytes(StandardCharsets.UTF_8);
Both UTF-16 (in both byte orders) and UTF-8 always are present in the JRE, whereas some Charsets are not. Hence you can use a constant from StandardCharsets not needing to handle any UnsupportedEncodingException.
Above I added a BOM for Windows Notepad esoecially, to recognize UTF-8. It certainly is not good practice. But as a small help here.
There is no disadvantage to UTF16-LE or UTF-16BE. I think UTF-8 is a bit more universally used, as UTF-16 also cannot store all Unicode code points in 16 bits. Text is Asian scripts would be more compressed, but already HTML pages are more compact in UTF-8 because of the HTML tags and other latin script.
For Windows UTF-16LE might be more native.
Problem with placeholders for non-Unicode platforms, especially Windows, might happen.

I just found this:
https://github.com/facebook/conceal/issues/138
which seems to answer negatively your question.
As per Jon Skeet's answer: the specification is clear. But I guess Android/Mac implementations of Dalvik/JVM don't agree.

Java - UTF8/16 is a Charset Name or Character Encoding?

The application I am developing will be used by folks in Western & Eastern Europe as well in the US. I am encoding my input and decoding my output with UTF-8 character set.
My confusion is becase when I use this method String(byte[] bytes, String charsetName), I provide UTF-8 as the charsetname when it really is an character encoding. And my default econding is set in Eclipse as Cp1252.
Does this mean if, in the US in my Java application, I create an Output text file using Cp1252 as my charset encoding and UTF-8 as my charset name, will the folks in Europe be able to read this file in my Java application and vice versa?

They're encodings. It's a pity that Java uses "charset" all over the place when it really means "encoding", but that's hard to fix now :( Annoyingly, IANA made the same mistake.
Actually, by Unicode terminology they're probably most accurately character encoding schemes:
A character encoding form plus byte serialization. There are seven character encoding schemes in Unicode: UTF-8, UTF-16, UTF-16BE, UTF-16LE, UTF-32, UTF-32BE, and UTF-32LE.
Where a character encoding form is:
Mapping from a character set definition to the actual code units used to represent the data.
Yes, the fact that Unicode only defines seven character encoding forms makes this even more confusing. Fundamentally, all most developers need to know is that a "charset" in Java terminology is a mapping between text data (String, char[]) and binary data (byte[]).

I think those two things are not directly related.
The Eclipse setting decide how your eclipse editor will save the text file (typically source code) you created/edited. You can use other editors and therefore the file maybe saved in some other encoding scheme. As long as your java compiler has no problem compiling your source code you're safe.
The
java String(byte[] bytes, String charsetName)
is your own application logic that deals with how do you want to interpret some data your read either from a file or network. Different charsetName (essentially different character encoding scheme) may have different interpretation on the byte array.

A "charset" does implies the set of characters that the text uses. For UTF-8/16, the character set happens to be "all" characters. For others, not necessarily. Back in the days, everybody were inventing their own character sets and encoding schemes, and the two were almost 1-to-1 mapping, therefore one name can be used to refer to both character set and encoding scheme.

Java safeguards for when UTF-16 doesn't cut it

My understanding is that Java uses UTF-16 by default (for String and char and possibly other types) and that UTF-16 is a major superset of most character encodings on the planet (though, I could be wrong). But I need a way to protect my app for when it's reading files that were generated with encodings (I'm not sure if there are many, or none at all) that UTF-16 doesn't support.
So I ask:
Is it safe to assume the file is UTF-16 prior to reading it, or, to maximize my chances of not getting NPEs or other malformed input exceptions, should I be using a character encoding detector like JUniversalCharDet or JCharDet or ICU4J to first detect the encoding?
Then, when writing to a file, I need to be sure that a characte/byte didn't make it into the in-memory object (the String, the OutputStream, whatever) that produces garbage text/characters when written to a string or file. Ideally, I'd like to have some way of making sure that this garbage-producing character gets caught somehow before making it into the file that I am writing. How do I safeguard against this?
Thanks in advance.

Java normally uses UTF-16 for its internal representation of characters. n Java char arrays are a sequence of UTF-16 encoded Unicode codepoints. By default char values are considered to be Big Endian (as any Java basic type is). You should however not use char values to write strings to files or memory. You should make use of the character encoding/decoding facilities in the Java API (see below).
UTF-16 is not a major superset of encodings. Actually, UTF-8 and UTF-16 can both encode any Unicode code point. In that sense, Unicode does define almost any character that you possibly want to use in modern communication.
If you read a file from disk and asume UTF-16 then you would quickly run into trouble. Most text files are using ASCII or an extension of ASCII to use all 8 bits of a byte. Examples of these extensions are UTF-8 (which can be used to read any ASCII text) or ISO 8859-1 (Latin). Then there are a lot of encodings e.g. used by Windows that are an extension of those extensions. UTF-16 is not compatible with ASCII, so it should not be used as default for most applications.
So yes, please use some kind of detector if you want to read a lot of plain text files with unknown encoding. This should answer question #1.
As for question #2, think of a file that is completely ASCII. Now you want to add a character that is not in the ASCII. You choose UTF-8 (which is a pretty safe bet). There is no way of knowing that the program that opens the file guesses correctly guesses that it should use UTF-8. It may try to use Latin or even worse, assume 7-bit ASCII. In that case you get garbage. Unfortunately there are no smart tricks to make sure this never happens.
Look into the CharsetEncoder and CharsetDecoder classes to see how Java handles encoding/decoding.

Whenever a conversion between bytes and characters takes place, Java allows to specify the character encoding to be used. If it is not specified, a machine dependent default encoding is used. In some encodings the bit pattern representing a certain character has no similarity with the bit pattern used for the same character in UTF-16 encoding.
To question 1 the answer is therefore "no", you cannot assume the file is encoded in UTF-16.
It depends on the used encoding which characters are representable.