I usually use python/php but currently writing an Android app so playing with java at the moment.
I can't figure out why the following piece of my code doesn't work.
It's meant to take a long representing the time the last check occurred (last_check) and add a predefined number of minutes to it (CHECK_INTERVAL) which is currently set to 1 minute.
Log.i(this.toString(), "Last check: " + Long.toString(last_check));
long add_to_check = CHECK_INTERVAL * 60 * 1000;
long next = last_check + add_to_check;
Log.i(this.toString(), "Add to check: " + Long.toString(add_to_check));
Log.i(this.toString(), "Next check: " + Long.toString(next));
scheduleNextRun(next);
My expectation is that the first log will show the last_check time, the second log will show 60000 and the third log will show the sum of those two.
However, I am getting the same value for the first log and the third log - it's like my addition isn't working at all but I can't figure out why.
I thought I might have had issues with log vs int but have tried adding L to one of the variables and it doesn't make a difference.
FYI the second log is showing 60000 as expected.
thanks
Aaron
Is CHECK_INTERVAL 0? You wrote that "the second log is showing 60000 as expected" but perhaps CHECK_INTERVAL was 0 the first time this code ran, then initialized, then 1 on a later iteration when you're looking at that part of the log.
Are you initializing CHECK_INTERVAL to something non-zero but after this code runs? Do you have an initialization bug?
This problem will be easy to solve if you step through the code in the debugger and watch the results. If you're not using a debugger, do yourself a huge favor and get Android Studio (a wonderful tool built on IntelliJ IDEA) or Eclipse + ADT (a good tool).
Java initialization is defined in a way that's predictable, portable, and useful, but it can still be tricky. E.g. given
class Foo {
static final int A2 = A1 * 1000;
static final int A1 = 60;
}
The JVM first initializes all variables to default values, then runs the initialization expressions in order. Since A1 is 0 when A2's initializer runs, A2 will end up 0.
See Java Puzzlers for more subtle cases such as when one class's initialization code refers to a second class, causing the second class's initialization code to run, which then refers to values in the first class which haven't yet been initialized beyond their default values (0 and null). A class runs its initialization code on first demand, but nothing guarantees that it finishes initializing before those values are used.
Another tricky case happens when one class, C1, refers to a static final value from a second class, C2.A, then you edit the initialization code for A without recompiling class C1. Java has precise rules about when to cache such constants in the first class's .class file, but they aren't the ideal rules, and the compiler doesn't notice that it needs to recompile C1 for this!
BTW 1: If CHECK_INTERVAL is an int, the expression CHECK_INTERVAL * 60 * 1000 will compute an int value and wrap around within a 32-bit signed range. Still, 1 * 60 * 1000 will easily fit in an int.
BTW 2: The first arg to Log.i() is a tag. It's OK to pass in this.toString() [or toString() for short] but the idea is to pass in a constant tag like the current class name that you can use for log filtering.
[Added] Quick intro to Eclipse debugging
In the source code editor, double-click in the left margin to set a breakpoint. Then use the menus or toolbar to "debug as" a Java application rather than "run as". Eclipse will go into its "Debug perspective" (arrangement of views).
https://www.google.com/search?q=eclipse+debugger finds nice tutorials with step-by-step pictures (I checked the first 3; IBM's is the most concise and introduces more features) and videos. The Eclipse docs are good but harder to navigate.
It's all slicker in Android Studio.
Related
I have following code for studying.
My calculate function produces unexpected results when runs on aparapi.
Is there any problem with my code, or aparapi?
Results are;
Result Num Expected
2026982348 406816880 40681688012
2026982516 406816881 40681688180
2026982594 406816882 40681688258
2026982662 406816883 40681688326
2026982830 406816884 40681688494
2026982898 406816885 40681688562
2026982966 406816886 40681688630
2026983044 406816887 40681688708
2026983212 406816888 40681688876
2026983280 406816889 40681688944
2026983338 406816890 40681689002
2026983506 406816891 40681689170
2026983584 406816892 40681689248
2026983652 406816893 40681689316
2026983820 406816894 40681689484
2026983888 406816895 40681689552
2026983956 406816896 40681689620
2026984134 406816897 40681689798
2026984202 406816898 40681689866
2026984270 406816899 40681689934
Edit: If I set executionMode JTP or CPU, I get true results (result == expected) but on GPU mode there is a problem. I'm using late 2013 macbook pro retina with windows 10.
Edit2: Return line of my calculate method causes the problem. If I return Long.MAX_VALUE, it works. But (long) tc * 100 (or ((long) tc) * 100) not giving (eg. 40681688900)
I think you should review your code checking against Aparapi Java Kernel Guidelines, expecially paying attention to Other restrictions and Beware Of Side Effects sections.
Remember to keep your code as simpler as you can.
Looking to your code, in the calculate method you make wide use of the modulus (%) operator. I would suggest you to log each calculation in order to be able to compare what you get in JTP mode and what you get in GPU mode, in order to find out if there are some issues with this operator.
EDIT:
In your calculate method you use int variables to hold values, which may hold numbers till 2^31-1, namely 2147483647 as known as Integer.MAX_VALUE.
If you perform int value=2147483647; value++; you will get as a result -2147483648 as known as Integer.MIN_VALUE.
You can alternatively try your program with lower starting numbers or change your variable declarations to long, which may hold Long.MAX_VALUE, namely 2^63-1.
Both long and int values are supported by Aparapi.
Hi I'm the primary maintainer over at the new Aparapi.com and new github repository. We are much more active over at the new project home and even have about a dozen releases in maven central already. You might want to consider moving over to the new Aparapi.
With that said I am a developer at the new Aparapi and ran this test case and confirmed it is a legitimate Aparapi bug. I will look into what is causing the bug and hopefully can get a bug fix in for you before the next release. The issue has been reported here if you would like to track it. Remember this for the new Aparapi project so the bug fix is not likely to show up in the older Aparapi project.
I saw the following code in this commit for MongoDB's Java Connection driver, and it appears at first to be a joke of some sort. What does the following code do?
if (!((_ok) ? true : (Math.random() > 0.1))) {
return res;
}
(EDIT: the code has been updated since posting this question)
After inspecting the history of that line, my main conclusion is that there has been some incompetent programming at work.
That line is gratuitously convoluted. The general form
a? true : b
for boolean a, b is equivalent to the simple
a || b
The surrounding negation and excessive parentheses convolute things further. Keeping in mind De Morgan's laws it is a trivial observation that this piece of code amounts to
if (!_ok && Math.random() <= 0.1)
return res;
The commit that originally introduced this logic had
if (_ok == true) {
_logger.log( Level.WARNING , "Server seen down: " + _addr, e );
} else if (Math.random() < 0.1) {
_logger.log( Level.WARNING , "Server seen down: " + _addr );
}
—another example of incompetent coding, but notice the reversed logic: here the event is logged if either _ok or in 10% of other cases, whereas the code in 2. returns 10% of the times and logs 90% of the times. So the later commit ruined not only clarity, but correctness itself.
I think in the code you have posted we can actually see how the author intended to transform the original if-then somehow literally into its negation required for the early return condition. But then he messed up and inserted an effective "double negative" by reversing the inequality sign.
Coding style issues aside, stochastic logging is quite a dubious practice all by itself, especially since the log entry does not document its own peculiar behavior. The intention is, obviously, reducing restatements of the same fact: that the server is currently down. The appropriate solution is to log only changes of the server state, and not each its observation, let alone a random selection of 10% such observations. Yes, that takes just a little bit more effort, so let's see some.
I can only hope that all this evidence of incompetence, accumulated from inspecting just three lines of code, does not speak fairly of the project as a whole, and that this piece of work will be cleaned up ASAP.
https://github.com/mongodb/mongo-java-driver/commit/d51b3648a8e1bf1a7b7886b7ceb343064c9e2225#commitcomment-3315694
11 hours ago by gareth-rees:
Presumably the idea is to log only about 1/10 of the server failures (and so avoid massively spamming the log), without incurring the cost of maintaining a counter or timer. (But surely maintaining a timer would be affordable?)
Add a class member initialized to negative 1:
private int logit = -1;
In the try block, make the test:
if( !ok && (logit = (logit + 1 ) % 10) == 0 ) { //log error
This always logs the first error, then every tenth subsequent error. Logical operators "short-circuit", so logit only gets incremented on an actual error.
If you want the first and tenth of all errors, regardless of the connection, make logit class static instead of a a member.
As had been noted this should be thread safe:
private synchronized int getLogit() {
return (logit = (logit + 1 ) % 10);
}
In the try block, make the test:
if( !ok && getLogit() == 0 ) { //log error
Note: I don't think throwing out 90% of the errors is a good idea.
I have seen this kind of thing before.
There was a piece of code that could answer certain 'questions' that came from another 'black box' piece of code. In the case it could not answer them, it would forward them to another piece of 'black box' code that was really slow.
So sometimes previously unseen new 'questions' would show up, and they would show up in a batch, like 100 of them in a row.
The programmer was happy with how the program was working, but he wanted some way of maybe improving the software in the future, if possible new questions were discovered.
So, the solution was to log unknown questions, but as it turned out, there were 1000's of different ones. The logs got too big, and there was no benefit of speeding these up, since they had no obvious answers. But every once in a while, a batch of questions would show up that could be answered.
Since the logs were getting too big, and the logging was getting in the way of logging the real important things he got to this solution:
Only log a random 5%, this will clean up the logs, whilst in the long run still showing what questions/answers could be added.
So, if an unknown event occurred, in a random amount of these cases, it would be logged.
I think this is similar to what you are seeing here.
I did not like this way of working, so I removed this piece of code, and just logged these
messages to a different file, so they were all present, but not clobbering the general logfile.
I have requirement in which I continuously receive messages that needs to be written in a file. Every time a new message is received it needs to be written in a separate file. What I want is to generate an unique identifier to be used as a file-name. I also want to preserve the order of the messages as well. By this I mean, the identifier generated as a file-name should always be incremental.
I was using UUID.randomUUID() to generate file-names but the problem with this approach is that UUID only assures randomness of the identifier but is not incremental. As a result I am losing the ordering of the file (I want file generated first should appear first in the list).
Approaches known
Can use System.currentTimeMillis() but I can receive multiple messages at same time stamp.
2.Another approach could be to implement static long value and increment it whenever a file is to be created and use the long value as a file-name. But I am not sure about this approach. Also it doesn't seem to be a proper solution to my problem. I think there could be far better solutions than this one.
If someone could suggest me a better solution to this problem, will be highly appreciated.
If you want your id value to uniformly rise even between server restarts, then you must either base it on the system time or have some elaborately robust logic that persists the last ID used. Note that achieving robustness on its own is not hard, but achieving it in a performant and scalable way is.
If you additionally need the id to be unique across multiple nodes in a redundant server cluster, then you need even more elaborate logic, which definitely involves a persistent store to which all the boxes synchronize access. Making this performant is, of course, even harder.
The best option I can see is to have a quite long ID so there's room for these parts:
System.currentTimeMillis for long-term uniqueness (across restarts);
System.nanotime for finer granularity;
a unique id of each server node (determined in a platform-specific way).
The method will still have to remember the last value generated and retry in case of a duplicate. It won't have to retry too many times, though, just until the next nanoTime clock tick—it could even busy-wait for it.
Sketch of code without point 3 (single-node implementation):
private static long lastNanos;
public static synchronized String uniqueId() {
for (;/*ever*/;) {
final long n = System.nanoTime();
if (n == lastNanos) continue;
lastNanos = n;
return "" + System.currentTimeMillis() + n;
}
}
Ok, my hands up. My last answer was fairly flaky and I've deleted it.
Keeping with the spirit of the site, I thought I'd try a different tac.
If you say you are keeping these messages in a single file then you could try something like creating an unique Id out of the size of the file?
Before you write the message to the file it's id could be the current size of the file.
You could add the filename + size as the id if these messages need to be unique across a number of files.
I'll leave the hot potato of synchronization to another day. But you could wrap all of this up in a syncronized object that keeps track of things.
Also, I am assuming that any messages written to the file will not be removed in the future.
ADDITIONAL NOTE:
You could create an message processing object that opens the file on construction (or via a create method).
This object will get the initial size of the file and this will be used as the unique id.
As each message is added (in a synchronized manner), the id is incremented by the size of the message.
This would address the performance issues. Will not work if more than one JVM/Node accesses the same file.
Skeletal Idea:
public class MessageSink {
private long id = 0;
public MessageSink(String filename) {
id = ... get file size ..
}
public synchronized addMessage(Message msg) {
msg.setId(id);
.. write to file + flush ..
.. or add to stack of messages that need to be written to file
.. at a later stage.
id = id + msg.getSize();
}
public void flushMessages() {
.. open file
.. for each message in stack write ...
.. flush and close file
}
}
I had the same requirement and found a suitable solution. Twitter Snowflake uses a simple algorithm to generate sortable 64bit (long) ids. Snowflake is written on Scala but the approach is simple and could be easily used in a Java code.
id is composed of:
timestamp - 41 bits (millisecond precision w/ a custom epoch gives us 69 years);
machine id - 10 bits (MAC address could be used as a hardware id);
sequence number - 12 bits - rolls over every 4096 per machine (with protection to avoid rollover in the same ms)
Formula looks like: ((timestamp - customEpoch) << timestampShift) | (machineId << machineIdShift) | sequenceNumber;
Shift for each component depends on it's bits position in ID.
Detailed description and source code could be found at github:
Twitter Snowflake
Basic Java implementation of the Snowflake algorithm
As you can probably understand from the question itself, I'm new to Java.
I was given an exercise to write a Java program which receives a character, prints it and the next character in the Unicode table.
Now, I have the solution to this exercise:
public static void main(String[] args){
char c = args[0].charAt(0);
char c1 = (char)(c + 1);
System.out.println(c + "\t" + c1);
}
I understand basic idea of this code, but I'm trying to run this code in Eclipse I get an annoying error:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
at MainClass.main(MainClass.java:9)
Note: I have yet to run a Java program that actually receives something as a parameter so I guess it's a stupid beginners' mistake... Here is the full code that I tried to compile in Eclipse:
public class MainClass {
/**
* #param args
*/
public static void main(String[] args){
char c = args[0].charAt(0);
char c1 = (char)(c + 1);
System.out.println(c + "\t" + c1);
}
}
Thanks in advance
Select "Run -> Run Configurations" from the menu.
Search for you project in the list on the left and select it.
Select the "Arguments" tab on the right.
Write the argument you want to pass to the programm in "Programm arguments".
Click "Run"
Right click on your java file in project explorer of your eclipse. Then Run As> Run Configuration
Then you will get a window. Like-
Click on Arguments Tabs, and then write some text there, may be a character.
And then Click on Apply button and Run Button.
The default run configuration in Eclipse runs a Java program without any arguments, hence the ArrayIndexOutOfBoundsException. Your code is trying to get first element of the args array when there aren't any!
You can edit the run configuration to provide the arguments to run your program with. Then it should not throw this exception.
However, a good practice is to check the size of array before accessing it's elements, more so when the array is coming as an argument from outside of your code.
This is a great question with some very good answers. I would like to add some pointers about how to debug your own program. Debugging is as important (if not more important) than writing code.
For one thing, Eclipse has some great debugging features. You can use this debugger to find problems in your code. I suggest that you learn how to use it. In particular, you can set watches for variables to see what value they have as you step through the execution of your code.
Alternatively, you can add calls to System.out.println() to print out the values of any variables. For example, adding the following line at the beginning of your code might help you narrow down the problem:
System.out.println(args[0]);
This would also give an ArrayIndexOutOfBoundsException if no command-line arguments are given. Then you could do something like
System.out.println(args.length);
which would print out 0. This then gives you a clue as to where the problem is.
Of course, even when you get to this point, you still might not know how to solve the problem. This is where sites like StackOverflow come in handy.
Good luck with your Java experience. Please come back when you need more help.
If your Run Configurations are in place (as already shown in above answers):
Shortcut to Run a class is:
Ctrl + F11
I'm currently working on a basic parser in Java and I have run into a problem when it comes to loops. Say I want to parse a while loop it would look something like:
a = 0
WHILE a < 10
a = a + 1
WEND
This example contains 4 expressions one of which will only need to be parsed ones the others will need to be parsed 10 times. The first one being the initial a = 0, second and third being on each side of the condition in the WHILE statement and the last one being within the WHILE block.
When I wrote the interpreted for this it loads the expression class into 4 different variables as new, the reevaluates them for each time it runs.
My problem is that even though they are initially loaded as new classes each time, there is over flow between them so when I re-parse them all of them looks like the last one:
a + 1
Any advice on how to circumvent this?
The code base is rather big so I wont post it here but its available at: http://git.life-hack.org/basic-parser/tree/src/parser
The file I'm working in is LoopBlock.java