I have an entity class called Task which is mapped in hibernate.
I'm able to fetch existing items belonging to this class correctly, so I don't think this is an issue with the mapping of the class.
However, when I try to insert a new item, I get the following error:
org.hibernate.exception.SQLGrammarException: error performing isolated work
at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:80)
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112)
at org.hibernate.engine.transaction.internal.jdbc.JdbcIsolationDelegate.delegateWork(JdbcIsolationDelegate.java:96)
at org.hibernate.id.enhanced.TableStructure$1.getNextValue(TableStructure.java:131)
at org.hibernate.id.enhanced.NoopOptimizer.generate(NoopOptimizer.java:58)
at org.hibernate.id.enhanced.SequenceStyleGenerator.generate(SequenceStyleGenerator.java:422)
at org.hibernate.event.internal.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:117)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:209)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:194)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.performSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:114)
at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:90)
at org.hibernate.internal.SessionImpl.fireSaveOrUpdate(SessionImpl.java:680)
at org.hibernate.internal.SessionImpl.saveOrUpdate(SessionImpl.java:672)
In the following code:
Task t = new Task();
t.title = "foo";
t.comment = "bar";
//snip... (every single field of task is given some value, except for id)
session.saveOrUpdate("Task", t); //This is the line on which the exception occurs
If I don't do saveOrUpdate(), then the new task isn't inserted into the db.
What am I doing wrong?
Edit: session.save(task) doesn't work either
Got this to work with the help of this link: http://www.coderanch.com/t/487173/ORM/databases/hibernate-sequence-exist
Apparently hibernate looks for sequence tables for generating the id. Setting the following:
#GeneratedValue(strategy = GenerationType.IDENTITY)
on the id, causes it to use the underlying db's auto increment and not try to generate the id itself, and now it works.
I accidentally removed hibernate_sequence table in my db.
Change:
spring.jpa.hibernate.ddl-auto=none
to
spring.jpa.hibernate.ddl-auto=create
In your application.properties file
so Hibernate could recreate this table by himself
If someone else is struggling with this error, I fixed it by removing
<prop key="hibernate.id.new_generator_mappings">true</prop>
From hibernate properties.
Related
I try to prepare an integration test with test data. I read insert queries from an external file and execute them as native queries. After the insertions I execute select setval('vlan_id_seq', 2000, true );. Here is the entity ID definition:
#Id
#Column(name = "id", unique = true, nullable = false)
#GeneratedValue(strategy = IDENTITY)
private Integer id;
When I try tor persist a new entry, I got a Caused by: org.postgresql.util.PSQLException: ERROR: duplicate key value violates unique constraint "vlan_pkey"
Detail: Key (id)=(1) already exists. exception. The ID of the sequence is 2000. The column definition is done by the serial macro and is id integer NOT NULL DEFAULT nextval('vlan_id_seq'::regclass).
I executed the native queries in a user transaction, so all test entries are stored in the postgresql data base, but it seems that hibernate not sync the sequence. The entityManager.flush(); also didn't force a sequence synchronisation. It seems that hibernate did not use sequences with #GeneratedValue(strategy = IDENTITY). I use a XA-Datasource and wildfly 13.
I tested now an other initialisation method. I defined a SQL data script (I generated the script with Jailer) in the persitence.xml (javax.persistence.sql-load-script-source) and end the script with select pg_catalog.setval('vlan_id_seq', (SELECT max(id) FROM vlan), true );. I set a breakpoint before the first persist command, check the sequence in the postgresql db, the sequence has the max id value 16. Now persisting works and the entry has the id 17. The scripts are executed before the entity manager is started and hibernate read the the updated sequences while starting. But this solution did not answer my question.
Is there a possibility that hibernate reread the sequences to use the nextval value?
if the strategy is Identity this means hibernate will create a sequence table and fetch the IDs from it, by using native sql you are just inserting your own values without updating that table so you have TWO solutions
Insert using hibernate itself which will be fairly easy, in your
integration test inject your DAOs and let hibernate do the insertion
for you which is recommended so you do not need to rehandle what
hibernate already handled
Update the sequence table whenever you do the insert by increment the
value which I do not recommend.
In my project I use hibernate hbm and spring,i run an sql query to update a single column,
Query sql = getSession().createSQLQuery("update HISTORIQUE_DETAIL_APPELS set token_otp = '"+historiqueDetailAppelsVO.getCodeOtp()+"' where id = '"+historiqueDetailAppelsVO.getId()+"'");
try {
sql.executeUpdate();
} catch (Exception e) {
e.printStackTrace();
}
I found that another query is executed and update the table in data base,
Hibernate: update HISTORIQUE_DETAIL_APPELS set token_otp = '14d3fc' where id = '150017'
Hibernate: update HISTORIQUE_DETAIL_APPELS set cod_cent=?, adresse_ip=?, id_conseiller=?, type_piece=?, num_piece_ident=?, msisdn=?, mois1_detail=?, mois2_detail=?, mois3_detail=?, date_demande=?, no_ticket_caisse=?, date_ticket=?, cod_user=?, dat_maj=?, flag_imp_data=?, date_imp_data=?, token_otp=?, send_mail=?, client_mail=?, date_debut=?, date_fin=? where id=?
where does the origin of the second update ?
I faced the same issue before, and after some research i found :
When user update any record by using direct query based operation, it is directly updated to database.
But, if the same record(previous copy) is already present in current session(that is previously read by user in current session) then, there is a difference occurs between database record(that is updated by query based operation) and current session record, due to this, hibernate again runs update query to update session record during either flushing of session or on transaction completion.
To avoid the second execution executed by hibernate either during flushing of session or on transaction completion.
I wish it will help you.
Thanks
I solve this probleme by adding : dynamic-update="true" in hbm.xml file
I found the solution here:
"The dynamic-update attribute tells Hibernate whether to include
unmodified properties in the SQL UPDATE statement."
Hi guys I am trying to save an object to a MySQL data base via Hibernate. if I execute following code
User user = new User();
user.setData_1("my data 5");
user.setFirstname("Freddy");
user.setLastname("Bob");
user.setId(5);
session.save(user);
session.getTransaction().commit();
I get a
'com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Table 'xxx.my_table_1' doesn't exist'
exception. However, querying from the same table using the same config works just fine.
What could be the issue?
Check your connection string in the configuration something like hibernate.connection.url = jdbc:postgresql://localhost/mydatabase You may be missing the schema name in the url(mydatabase).
So, after some trial and error, I came to find out that the issue with the .get() (and apparently .save() too) was that I did not have a hibernate.default_schema set in config. Looks like it is used to create the 'dynamic' SQL for .save() and .get(), but if you use .createSQLQuery(), it just uses what ever String you pass as an argument for the SQL, and therefor works with out needing to have hibernate.default_schema set.
I am new to using hibernate. I have written the following code get the max id in my order table.
public int getOrderMaxUID() {
Session session = sessionFactory.getCurrentSession();
String query = "SELECT max(o.UID) FROM Order o";
List list = session.createQuery(query).list();
int maxOrderUID = ((Integer) list.get(0)).intValue();
return maxOrderUID;
}
and I call this method in my controller before I add a new record to the table.
orderService.getOrderMaxUID();
orderService.add(o);
The Issue : Records are added to our Order table by other processes as well. So to avoid Duplicate PK issue, I get the max id from the order table before inserting record. But I still get following error when other process add records
2013-04-04 09:27:24,841 WARN ["ajp-bio-8009"-exec-2] org.hibernate.util.JDBCExceptionReporter - SQL Error: 2627, SQLState: S1000
2013-04-04 09:27:24,841 ERROR ["ajp-bio-8009"-exec-2] org.hibernate.util.JDBCExceptionReporter - Violation of PRIMARY KEY constraint 'PK_Order'. Cannot insert duplicate key in object 'Order'. The duplicate key value is (1001508).
and
org.springframework.dao.DuplicateKeyException: Hibernate flushing: could not insert:
I want hibernate to store the id retrieved by getMaxOrderId() method in memory and use the next number as when adding new record.
Any help on this would be appreciated.
Why don't you get Hibernate to just generate the ID for you?
/** The id. */
#Id #GeneratedValue
private Long id;
EDIT:
You can create entries from multiple processes as long as you do it through hibernate and the id's will be adjusted accordingly.
Inserting into the database outside of hibernate however, will cause you issues. You may be able to use a Customer ID Generator to work around this. I found this example that may help
If you edit the database outside of hibernate, you may run into other problems as well (particularly if you use the second level cache for example)
If you use the same Session, you will run into issues caused by the first level cache as well.
I am using Hibernate and getting
Exception in thread "main" org.hibernate.ObjectNotFoundException: No row with the given identifier exists: [#271]
What is pretty weird about this error is, that the object with the given id exists in the database. I inserted the problematic record in another run of the application. If I access it in the same run (i.e. same hibernate session) there seem to be no problems retrieving the data.
Just because it could be a fault of the mapping:
public class ProblemClass implements Persistent {
#ManyToOne(optional = false)
private MyDbObject myDbObject;
}
public class MyDbObject implements Persistent {
#OneToMany(mappedBy = "myDbObject")
private List<ProblemClass> problemClasses;
#ManyToOne(optional = false)
private ThirdClass thirdClass;
}
I have absolutely no clue even where to look at. Any hints highly appreciated!
Just to clarify:
The data was inserted in another RUN of the application. It is definitely in the database, as I can see it via an SQL-Query after the application terminated. And after THAT, i.e. when starting the application again, I get the error in the FIRST query of the database -- no deletion, no rollback involved.
Addition:
Because it was asked, here is the code to fetch the data:
public List<ProblemClass> getProblemClasses() {
Query query = session.createQuery("from ProblemClass");
return query.list();
}
And just to make it complete, here is the generic code to insert it (before fetching in another RUN of the application):
public void save(Persistent persistent) {
session.saveOrUpdate(persistent);
}
Eureka, I found it!
The problem was the following:
The data in the table ThirdClass was not persisted correctly. Since this data was referenced from MyDbObject via
optional = false
Hibernate made an inner join, thus returning an empty result for the join. Because the data was there if executed in one session (in the cache I guess), that made no problems.
MySQL does not enforce foreign key integrity, thus not complaining upon insertion of corrupt data.
Solution: optional = true or correct insertion of the data.
Possible reasons:
The row was inserted by the first session, but transaction was not committed when second session tried to access it.
First session is roll-backed due to some reason.
Sounds like your transaction inserting is rollbacked
Main reason behind this issue is data mismatch, for example i have entity mapping class called "X" and it has column "column1" and it has reference to the table "Y" column "column1" as below
#OneToOne(cascade = CascadeType.ALL)
#JoinColumn(name = "column1", referencedColumnName = "column1")
public Y getColumn1() {
return Y;
}
In this if X table column1 has value but Y table column1 is not having the value. Here link will be failed.
This is the reason we will get Hibernate objectNotFound exception
This issue can also be resolved by creating proper data model like creating proper indexing and constraints (primary key/foreign key) ..
This might be your case, kindly check my answer on another post.
https://stackoverflow.com/a/40513787/6234057
I had the same Hibernate exception.
After debugging for sometime, i realized that the issue is caused by the Orphan child records.
As many are complaining, when they search the record it exists.
What i realized is that the issue is not because of the existence of the record but hibernate not finding it in the table, rather it is due to the Orphan child records.
The records which have reference to the non-existing parents!
What i did is, find the Foreign Key references corresponding to the Table linked to the Bean.
To find foreign key references in SQL developer
1.Save the below XML code into a file (fk_reference.xml)
<items>
<item type="editor" node="TableNode" vertical="true">
<title><![CDATA[FK References]]></title>
<query>
<sql>
<![CDATA[select a.owner,
a.table_name,
a.constraint_name,
a.status
from all_constraints a
where a.constraint_type = 'R'
and exists(
select 1
from all_constraints
where constraint_name=a.r_constraint_name
and constraint_type in ('P', 'U')
and table_name = :OBJECT_NAME
and owner = :OBJECT_OWNER)
order by table_name, constraint_name]]>
</sql>
</query>
</item>
2.Add the USER DEFINED extension to SQL Developer
Tools > Preferences
Database > User Defined Extensions
Click "Add Row" button
In Type choose "EDITOR", Location - where you saved the xml file above
Click "Ok" then restart SQL Developer
3.Navigate to any table and you will be able to see an additional tab next to SQL, labelled FK References, displaying FK information.
4.Reference
http://www.oracle.com/technetwork/issue-archive/2007/07-jul/o47sql-086233.html
How can I find which tables reference a given table in Oracle SQL Developer?
To find the Orphan records in all referred tables
select * from CHILD_TABLE
where FOREIGNKEY not in (select PRIMARYKEY from PARENT_TABLE);
Delete these Orphan records, Commit the changes and restart the server if required.
This solved my exception. You may try the same.
Please update your hibernate configuration file as given below:
property start tag name="hbm2ddl.auto" create/update property close tag
I have found that in Oracle this problem can also be caused by a permissions issue. The ProblemClass instance referred to by the MyDbObject instance may exist but have permissions that do not allow the current user to see it, even though the user can see the current MyDbObject.