I want to add a value to an existing column, but I don't want to have to select it first. Right now I would have to do something like
// run hql in a named query
from Employee where id = :id
// after running the above
e.setBonus(e.getBonus() + 100); // add 100 to e's bonus
// commit to database
HibernateUtil.saveOrUpdate(e);
But I want something that's just one-and-done - something like
update Employee e set e.bonus = e.bonus + 100
Is this something I can do in Hibernate? If so, how. If not, what's the suggested best practice for such an update?
You could create a hql query that just does an update
Query updateBonus = createQuery("UPDATE Employee SET bonus = bonus+100 WHERE id = :id" );
updateBonus.setInteger("id", employee.getId());
updateBonus.executeUpdate();
Yes, you can do it as intended with hql query. Try such code:
Session session = sessionFactory.openSession();
Transaction tx = session.beginTransaction();
String hql="update Employee e set e.bonus = e.bonus + :p where id=:id";
session.createQuery(hql).setInteger("p",100).setInteger("id",id).executeUpdate();
tx.commit();
session.close();
More info you can find by the link
Related
Hi guys I am new to jpa, named queries, etc.. and I need something like this:
select t from :tableName t
Later in code I want something like this:
em.createQuery(...);
setParameter("tableName", "Person")
Result would be:
select * from person
How to write such a generic jpa query statement allowing to select all rows from :tableName which may be defined at runtime? thanks in advance
Try this I think this works well
EntityManagerFactory emfactory=Persistence.createEntityManagerFactory("Eclipselink_JPA" );
EntityManager entitymanager = emfactory.createEntityManager();
Query query = entitymanager.
createQuery("Select p from Person p");
List<String> list = query.getResultList();
setParameter("foo", foo) is used to set the value for column of the table not to set the table name. I do not think it will work, as you want to set the table name dynamically.
You can try this:
public returnType foo(String tableName){
String jpql = "SELECT t FROM " + tableName+ " t";
Query query = em.createQuery(jpql);
//rest of the code
}
I am trying to update MySQL table with hibernate. It looks like that it does work, result from hibernate is 1, but table doesn´t change. My code for update :
Session session = GeneralSession.getSession();
session.beginTransaction();
//some code - initialization and logics
//loop
Query updateDuplicity = session .createSQLQuery("UPDATE `t_inzerat` set `actual` = 'D'
WHERE `id` = "+ idSimi);
int resultUpdate = updateDuplicity.executeUpdate();
session.flush();
//end of loop
session.getTransaction().commit();
In console hibernate writes this as:
Hibernate: UPDATE `t_inzerat` set `actual` = 'D' WHERE `id` = 5611
Affected rows : 1
Please what is wrong? Thank you
Have a look hereexample. Do the commit in the tx returned by beginTransaction method
Is it possible to execute an update while using Criteria in Hibernate? For example:
Session session = getSession();
Criteria crit = session.createCriteria(User.class);
crit.add(Restrictions.eq("token", sessionToken));
User user= new User();
Transaction tx = session.getTransaction();
try
{
tx.begin();
session.updateWithCriteria(user, crit); //my imaginary function
tx.commit();
}
catch (Exception e)
{
e.printStackTrace();
tx.rollback();
}
session.close();
There is a very powerful feature called:
15.4. DML-style operations
small cite from doc:
... However, Hibernate provides methods for bulk SQL-style DML statement execution that is performed through the Hibernate Query Language...
So, while this is not about criteria - we still can use our domain model for querying, because it is about HQL. This is a snippet showing the power:
Session session = sessionFactory.openSession();
Transaction tx = session.beginTransaction();
String hqlUpdate = "update Customer c set c.name = :newName where c.name = :oldName";
// or String hqlUpdate = "update Customer set name = :newName where name = :oldName";
int updatedEntities = s.createQuery( hqlUpdate )
.setString( "newName", newName )
.setString( "oldName", oldName )
.executeUpdate();
tx.commit();
session.close();
SUMMARY: Having that in place:
we can use query to filter results
we can apply bulk update on it
we won't need to load these rows in memory, into the session...
Now we can do something like this for bulk update and delete. New api's released for criteriaUpdate and CriteriaDelete
CriteriaBuilder cb = this.em.getCriteriaBuilder();
// create update
CriteriaUpdate<Order> update = cb.createCriteriaUpdate(Order.class);
// set the root class
Root e = update.from(Order.class);
// set update and where clause
update.set("amount", newAmount);
update.where(cb.greaterThanOrEqualTo(e.get("amount"), oldAmount));
// perform update
this.em.createQuery(update).executeUpdate();
First you should get the object then modify and update:
Query q = session.createQuery("from StockTransaction where tranId = :tranId ");
q.setParameter("tranId", 11);
StockTransaction stockTran = (StockTransaction)q.list().get(0);
stockTran.setVolume(4000000L);
session.update(stockTran);
If you want to use partial/dynamic update feature then put
#org.hibernate.annotations.Entity(
dynamicUpdate = true
)
annotation on top of the dao class.
Example from: http://www.mkyong.com/hibernate/hibernate-dynamic-update-attribute-example/
Note: The Question is "with criteria" but the accepted answer is NOT "with criteria" but SQL.
When I try to execute the following HQL query:
Query query = getSession().createQuery("update XYZ set status = 10");
query.executeUpdate();
I get this exception:
Exception in thread "main" org.hibernate.QueryException: query must begin with SELECT or FROM: update
EDIT:
I also tried following .But it doennot work either.
org.hibernate.Query query = getSession().createQuery("update XYZ t set t.status = 10");
EDIT2:
Making changes in hinbernate.cfg.xml solved my problem
Earlier i was using
setting hibernate.query.factory_class" = org.hibernate.hql.classic.ClassicQueryTranslatorFactor
Now am using following property
<property name="hibernate.query.factory_class">org.hibernate.hql.ast.ASTQueryTranslatorFactory</property>
Thats not an HQL query.
You want to import javax.persistence.Query which allows normal sql,
not org.hibernate.Query which works on entity objects.
If you want to use simple sql, you could also use PreparedStatement
However, if you really want to use hibernate, without taking advantage of entityobjects (totally defeating the point of using hibernate in the first place, imho) you could do it like this (reference docs):
String myUpdate = "update XYZ myAlias set myAlias.status = :newStatus";
// or String noAliasMyUpdate = "update XYZ set status = :newStatus";
int updatedEntities = getSession().createQuery(myUpdate) //or noAliasMyUpdate
.setInt( "newStatus", 10 )
.executeUpdate();
The question is thinking in SQL, when you should be thinking in objects:
XYZ xyz = new XYZ();
xyz.setStatus(10);
getSession().merge(xyz);
Try:
Query query = getSession().createQuery("update XYZ o set o.status = 10");
query.executeUpdate();
Take a look at this also.
Session sesssion = getSession(); //getter for session
For HQL :
String hql = "update Activity " +
"set startedOn = :taskStartedOn " +
"where id = :taskId";
Query query = session.createQuery(hql);
query.setDate("taskStartedOn",new Date());
query.setLong("taskId",1)
int rowCount = query.executeUpdate();
Here Activity is POJO.
Use
hibernate.query.factory_class = org.hibernate.hql.ast.ASTQueryTranslatorFactory
in hibernate.cfg.xml file to resolve exception:
org.hibernate.QueryException: query must begin with SELECT or FROM: update.....
How can I write DAO method which will return as a result only first entry from the database. For instance lets say I'm looking at Users table and I want to retrieve only the first entry, I'd declare method like:
public User getFirstUser(){
//method logic
}
EDIT:
User has primary key id if that matters at all.
I apologize if this question is too simple/stupid/whatever I'm beginner with Java so I'm trying new things. thank you
My attempt :
public User getFirstUser(){
try {
final String getQuery = "SELECT * FROM Users WHERE Id = (SELECT MIN(Id) FROM Users)";
final Query query = getSession().createQuery(getQuery);
final int rowCount = query.executeUpdate(); // check that the rowCount is 1
log.debug("get successful");
// return what??
} catch (RuntimeException re) {
log.error("get not successful", re);
throw re;
}
}
You can
use:
Query query = session.createQuery("from User");
query.setMaxResults(1);
User result = (User) query.uniqueResult();
use User user = session.get(User.class, id); if you know the ID upfront.
Get all users ordered by id and limit the results to 1 (but don't use LIMIT, use setMaxResults() to remain portable):
Query q = session.createQuery("from User u order by u.id");
q.setMaxResults(1);
User u = (User) q.uniqueResult();
SELECT * FROM Users WHERE Id = (SELECT MIN(Id) FROM Users)
:)
Don't remember exactly but i think there is a method getSingleResult in JPA and also in Hibernate so...
But this method perhaps throw exception when multiple results are returned... can't remember...
Actually there is also getResultList returning a List of entities, and you could do list.get(0) no?
Or create a query with LIMIT 1?
In MS SQL Server we do it like,
First user, min ID,
SELECT TOP 1 * FROM Users ORDER BY Id
Latest user, max ID,
SELECT TOP 1 * FROM Users ORDER BY Id DESC
thanks.