java with Amazon AWS NoSuchFieldError - java

java with Amazon AWS NoSuchFieldError
Here is the console log:
Exception in thread "AWT-EventQueue-0" java.lang.NoSuchFieldError: INSTANCE
at org.apache.http.client.utils.URLEncodedUtils.parse(URLEncodedUtils.java:246)
at org.apache.http.client.utils.URLEncodedUtils.parse(URLEncodedUtils.java:225)
at org.apache.http.client.utils.URIBuilder.parseQuery(URIBuilder.java:95)
at org.apache.http.client.utils.URIBuilder.digestURI(URIBuilder.java:165)
at org.apache.http.client.utils.URIBuilder.<init>(URIBuilder.java:90)
at org.apache.http.client.utils.URIUtils.rewriteURI(URIUtils.java:138)
at org.apache.http.impl.client.DefaultRequestDirector.rewriteRequestURI(DefaultRequestDirector.java:353)
at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:476)
at org.apache.http.impl.client.AbstractHttpClient.doExecute(AbstractHttpClient.java:863)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:82)
at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:57)
at com.amazonaws.http.AmazonHttpClient.executeOneRequest(AmazonHttpClient.java:837)
at com.amazonaws.http.AmazonHttpClient.executeHelper(AmazonHttpClient.java:607)
at com.amazonaws.http.AmazonHttpClient.doExecute(AmazonHttpClient.java:376)
at com.amazonaws.http.AmazonHttpClient.executeWithTimer(AmazonHttpClient.java:338)
at com.amazonaws.http.AmazonHttpClient.execute(AmazonHttpClient.java:287)
at com.amazonaws.services.s3.AmazonS3Client.invoke(AmazonS3Client.java:3826)
at com.amazonaws.services.s3.AmazonS3Client.invoke(AmazonS3Client.java:3778)
at com.amazonaws.services.s3.AmazonS3Client.listObjects(AmazonS3Client.java:610)
at net.pocketsurvey.cloud.Amazon.listObjectsInBucket(Amazon.java:93)
The bottom line is where my code hands over to Amazon's S3. The code is as follows:
public static ObjectListing listObjectsInBucket(String bucketName,
String key) throws Exception {
ObjectListing list = null;
AmazonS3Client client = Client.s3(Client.DESKTOP);
try {
boolean b_exists = client.doesBucketExist(bucketName);
boolean o_exists = client.doesObjectExist(bucketName, key);
if(b_exists) {
list = client.listObjects(bucketName, key);
}
} catch ( AmazonServiceException e){
String err = e.getErrorMessage();
e.printStackTrace();
} catch ( AmazonClientException e){
e.printStackTrace();
} catch ( Exception e){
e.printStackTrace();
}
return list;
}
'client.listObjects' is where it bombs out.
libraries used include:
aws-java-sdk-1.10.77.jar
httpclient-osgi-4.3.jar
org.apache.httpcomponents.httpcore_4.2.1.jar
'b_exists' is true but 'o_exists' returns as false even tho the key most definitely exists.
I am using credentials that work for other things such as email, and downloading a known object, i.e. a complete key string. But trying to get a listing using a partial key string (such as "hhs/") I get the above eror.
Also the 'catches' don't catch it.
The code currently runs on the UI thread but I have tried it on its own thread with similar results.
The platform is Windows 7.
Any help would be greatly appreciated.

Problem sorted - library mismatch.
'aws-java-sdk-1.10.77.jar' needs 'org.apache.httpcomponents.httpcore_4.4.4.jar' to bein the build path.

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But it's throwing org.jivesoftware.smack.XMPPException$XMPPErrorException: XMPPError: feature-not-implemented - cancel exception on executing queryArchive() function. Does anyone have any idea how to resolve this issue? Any help would be appreciated.
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Mongo client {Mongo-Java-driver} creation hangs duration . No exception thrown

I have a cron-job running at a Linux machine running after every 5 minutes. The job executes a Java class.
private MongoClient createConnection(int retry,List<ServerAddress> host){
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I recently upgraded Linux machine OS (from CentOS 5 to CentOS 6). Can this be responsible for this because this script was working fine earlier.
Please help.
Regards,
Vibhav
The thing what you can do is you can throw mongo exception try out that of mongo client is stuck you will get to know try out this https://api.mongodb.org/java/2.6/com/mongodb/MongoException.html
Yes of course, actually i was creating crawler in java which fetch all the links of any particular website and validate the css and html structure Using the Jsoup and jcabi api but when i used to store links to the database it was not throwing any exception and even not storing the data also. so i did this
catch (MongoException e){
System.err.print(e.getClass().getName()+": "+e.getMessage());
}
Have you checked the compatibility like of jar that you have uploaded for your project like before it was like Mongo mongo = new Mongo(host,port); but That is deprecated. Try to check that and even your MongoDb jar.

try-catch-finally block in java

As per my understanding, I want to follow the best practice for releasing the resources at the end to prevent any connection leaks. Here is my code in HelperClass.
public static DynamoDB getDynamoDBConnection()
{
try
{
dynamoDB = new DynamoDB(new AmazonDynamoDBClient(new ProfileCredentialsProvider()));
}
catch(AmazonServiceException ase)
{
//ase.printStackTrace();
slf4jLogger.error(ase.getMessage());
slf4jLogger.error(ase.getStackTrace());
slf4jLogger.error(ase);
}
catch (Exception e)
{
slf4jLogger.error(e);
slf4jLogger.error(e.getStackTrace());
slf4jLogger.error(e.getMessage());
}
finally
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dynamoDB.shutdown();
}
return dynamoDB;
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My doubt is, since the finally block will be executed no matter what, will the dynamoDB returns empty connection because it will be closed in finally block and then execute the return statement? TIA.
Your understanding is correct. dynamoBD.shutdown() will always execute before return dynamoDB.
I'm not familiar with the framework you're working with, but I would probably organize the code as follows:
public static DynamoDB getDynamoDBConnection()
throws ApplicationSpecificException {
try {
return new DynamoDB(new AmazonDynamoDBClient(
new ProfileCredentialsProvider()));
} catch(AmazonServiceException ase) {
slf4jLogger.error(ase.getMessage());
slf4jLogger.error(ase.getStackTrace());
slf4jLogger.error(ase);
throw new ApplicationSpecificException("some good message", ase);
}
}
and use it as
DynamoDB con = null;
try {
con = getDynamoDBConnection();
// Do whatever you need to do with con
} catch (ApplicationSpecificException e) {
// deal with it gracefully
} finally {
if (con != null)
con.shutdown();
}
You could also create an AutoCloseable wrapper for your dynamoDB connection (that calls shutdown inside close) and do
try (DynamoDB con = getDynamoDBConnection()) {
// Do whatever you need to do with con
} catch (ApplicationSpecificException e) {
// deal with it gracefully
}
Yes,dynamoDB will return an empty connection as dynamoBD.shutdow() will be executed before return statement, Always.
Although I am not answering your question about the finally block being executed always (there are several answers to that question already), I would like to share some information about how DynamoDB clients are expected to be used.
The DynamoDB client is a thread-safe object and is intended to be shared between multiple threads - you can create a global one for your application and re-use the object where ever you need it. Generally, the client creation is managed by some sort of IoC container (Spring IoC container for example) and then provided by the container to whatever code needs it through dependency injection.
Underneath the hood, the DynamoDB client maintains a pool of HTTP connections for communicating the DynamoDB endpoint and uses connections from within this pool. The various parameters of the pool can be configured by passing an instance of the ClientConfiguration object when constructing the client. For example, one of the parameters is the maximum number of open HTTP connections allowed.
With the above understanding, I would say that since the DynamoDB client manages the lifecycle of HTTP connections, resource leaks shouldn't really be concern of code that uses the DynamoDB client.
How about we "imitate" the error and see what happens ? This is what I mean:
___Case 1___
try{
// dynamoDB = new DynamoDB(new AmazonDynamoDBClient(new ProfileCredentialsProvider()));
throw new AmazonServiceException("Whatever parameters required to instantiate this exception");
} catch(AmazonServiceException ase)
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//ase.printStackTrace();
slf4jLogger.error(ase.getMessage());
slf4jLogger.error(ase.getStackTrace());
slf4jLogger.error(ase);
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catch (Exception e)
{
slf4jLogger.error(e);
slf4jLogger.error(e.getStackTrace());
slf4jLogger.error(e.getMessage());
}
finally
{
//dynamoDB.shutdown();
slf4jLogger.info("Database gracefully shutdowned");
}
___Case 2___
try{
// dynamoDB = new DynamoDB(new AmazonDynamoDBClient(new ProfileCredentialsProvider()));
throw new Exception("Whatever parameters required to instantiate this exception");
} catch(AmazonServiceException ase)
{
//ase.printStackTrace();
slf4jLogger.error(ase.getMessage());
slf4jLogger.error(ase.getStackTrace());
slf4jLogger.error(ase);
}
catch (Exception e)
{
slf4jLogger.error(e);
slf4jLogger.error(e.getStackTrace());
slf4jLogger.error(e.getMessage());
}
finally
{
//dynamoDB.shutdown();
slf4jLogger.info("Database gracefully shutdowned");
}
These exercise could be a perfect place to use unit tests and more specifically mock tests. I suggest you to take a close look at JMockit, which will help you write such tests much more easily.

ldap transaction protocol error

I’m writing in order to get some help.
To be short, I’m trying to use com.unboundid.ldap.sdk (but it is not necessary - the same problem i get if i use oracle's javax.naming.ldap.*) to handle with ldap transactions, and I get the following error:
Exception in thread "Main Thread" java.lang.AssertionError: Result EndTransactionExtendedResult(resultCode=2 (protocol error), diagnosticMessage='protocol error') did not have the expected result code of '0 (success)'.
at com.unboundid.util.LDAPTestUtils.assertResultCodeEquals(LDAPTestUtils.java:1484)
at pkg.Main.main(Main.java:116)
My program is the following ( I’m using simple example from https://www.unboundid.com/products/ldap-sdk/docs/javadoc/com/unboundid/ldap/sdk/extensions/StartTransactionExtendedRequest.html ) :
public class Main {
public static void main( String[] args ) throws LDAPException {
LDAPConnection connection = null;
try {
connection = new LDAPConnection("***", ***, "***", "***");
} catch (LDAPException e1) {
e1.printStackTrace();
}
// Use the start transaction extended operation to begin a transaction.
StartTransactionExtendedResult startTxnResult;
try
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connection.processExtendedOperation(
new StartTransactionExtendedRequest());
// This doesn't necessarily mean that the operation was successful, since
// some kinds of extended operations return non-success results under
// normal conditions.
}
catch (LDAPException le)
{
// For an extended operation, this generally means that a problem was
// encountered while trying to send the request or read the result.
startTxnResult = new StartTransactionExtendedResult(
new ExtendedResult(le));
}
LDAPTestUtils.assertResultCodeEquals(startTxnResult, ResultCode.SUCCESS);
ASN1OctetString txnID = startTxnResult.getTransactionID();
// At this point, we have a transaction available for use. If any problem
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boolean commit = false;
try
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try
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}
catch (LDAPException le)
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endTxnResult = new EndTransactionExtendedResult(new ExtendedResult(le));
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LDAPTestUtils.assertResultCodeEquals(endTxnResult, ResultCode.SUCCESS);
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}
}
As you can see, I do nothing with the transaction: just start and rolling back, but it still not working.
Connection is ok, and I receive transaction id = F10285501E20C32AE040A8C0070F7502 BUT IT ALWAYS THE SAME - is it all wrigth???
If “// do nothing” replace with some action exception: unwilling to perform.
I’m starting to think that it is OID problem, but I just can’t figure out what is wrong…
OID is on a WebLogic server and it’s version is :
Version Information
ODSM 11.1.1.6.0
OID 11.1.1.6.0
DB 11.2.0.2.0
All ideas will be appreciated.

How to handle java.rmi.UnknownHostException

I'm working with Eclipse and the code below is the code that I use for RMI initialization.
public void init(String serviceName) throws RemoteException {
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String host = InetAddress.getLocalHost().getHostName();
String url = "rmi://"+ host + serviceName;
Naming.rebind(url,this);
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (MalformedURLException e) {
e.printStackTrace();
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}
I'm getting an UnknownHostException.
Since I'm new to this issue, the question may be simple, but I could not handle it.
Thanks in advance.
UnknownHostException means it can't find that host at the network level. There's no handling this type of exception because it means something is broken. I'd print out the URL sent to RMI. It should look something like this:
//localhost/ServiceImTryingToAccess
If you didn't put a leading "/" on your service it might be:
//localhostServiceImTryingToAccess
And that certainly would create an UnknownHostException. You really don't need to use InetAddress.getLocalHost() as you could just simply do:
String url = "//localhost" + serviceName;
Also notice I dropped the rmi:// scheme portion of the URL. It's in the docs that's not needed.
http://docs.oracle.com/javase/1.4.2/docs/api/java/rmi/Naming.html

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