String url = "https://ko.wikipedia.org/w/api.php?action=query&format=json&list=search&srprop=sectiontitle&srlimit=1&srsearch=grand-theft-auto-v";
String test = restTemplate.getForObject(url, String.class);
Map<String, String> testToJson = objectMapper.readValue(test, Map.class);
testToJson is:
{
batchcomplete: "",
continue: {
sroffset: 1,
continue: "-||",
},
query: {
searchinfo: {
totalhits: 12
},
search: [
{
ns: 0,
title: "그랜드 테프트 오토 V",
pageid: 797633,
}
],
},
}
I want to get title value.
I try
testToJson.get("title")
but it returns null.
How to get title value with jackson?
You can deserialise it to a JsonNode and use JSON Pointer to get required field:
JsonNode node = mapper.readValue(jsonFile, JsonNode.class);
String title = node.at("/query/search/0/title").asText();
you could build a class for this json result then read from it.
public class Result {
private JsonNode searchinfo;
private JsonNode[] searches;
}
// then read:
Result testToJson = objectMapper.readValue(test, Result.class);
System.out.println(testToJson.getSearches(0).get("title"));
refer
It is impossible to read JSON into an instance of a generic class like that because the info about generics are used in compile time and already lost when program is running.
Jackson captures the data about generics using a sub-classed instance of TypeReference<T>.
Map<String, String> testToJson = objectMapper.readValue(test, new TypeReference<Map<String, String>>(){});
The problem with this approach is that Map<String, String> almost never describes complex data (like in the example) correctly. The example contains not only string values, there are numbers and even nested objects.
In situations like that, when you don't want or cannot write a class that describes the structure of the JSON, the better choice is parsing the JSON into a tree structure and traverse it. For example:
JsonNode node = objectMapper.readTree(test);
String title = node.get("query").get("search").get(0).get("title").asText();
Integer offset = node.get("continue").get("strOffset").asInt()
I have a Problem which I have to solve in Java.I have a data in YAML where the data is in this structure
600450:
STATE:STATE1
CITY:CITY1
ID:1
CONTACT:1234
600453:
STATE:STATE1
CITY:CITY1
ID:2
CONTACT:3456
600451:
STATE:STATE2
CITY:CITY2
ID:3
CONTACT:2234
.....
I converted this into JSONObject but I am strugling to change this into this JSONObject object where the structure should be of this form
{
STATE1:
{[
CITY1:{
[{ID:1,CODE:600450,CONTACT:1234},
{ID:2,CODE:600453,CONTACT:3456}
]
},
CITY2:{
[
{ID:3,CODE:600451,CONTACT:1234}
]
}
]}
}
I have almost lost a hour by doing different Things with JSONObject and JSONArray and then switched to HashMap and ArrayList of HashMap but I am not able to get it !
This was my try I am sure this is absurd I know that How to achieve this in Java .
Assuming that your converted initial JSON looks like this:
{
"600450": {
"STATE": "STATE1",
"CITY": "CITY1",
"ID": 1,
"CONTACT": 1234
},
"600451": {
"STATE": "STATE2",
"CITY": "CITY2",
"ID": 3,
"CONTACT": 2234
},
"600453": {
"STATE": "STATE1",
"CITY": "CITY1",
"ID": 2,
"CONTACT": 3456
}
}
Here is a static method that does the full conversion to your desired format:
static JSONObject convert(JSONObject initial) {
// STATE -> CITY -> Address[]
Map<String, Map<String, List<Map<String, Object>>>> stateToCityToAddresses = new HashMap<>();
// Get list of codes
String[] codes = JSONObject.getNames(initial);
// Loop over codes - "600450", "600451", "600453", ...
for (String code : codes) {
// Get the JSONObject containing state data
JSONObject state = initial.getJSONObject(code);
// Extract information from state JSONObject
String stateName = state.getString("STATE");
String cityName = state.getString("CITY");
long id = state.getLong("ID");
long contact = state.getLong("CONTACT");
// Some Java 8 awesomeness!
List<Map<String, Object>> addresses = stateToCityToAddresses
.computeIfAbsent(stateName, sn -> new HashMap<>()) // This makes sure that there is a Map available to hold cities for a given state
.computeIfAbsent(cityName, cn -> new ArrayList<>()); // This makes sure that there is a List available to hold addresses for a given city
// Save data in a map representing a json object like: {"CONTACT":1234,"CODE":600450,"ID":1}
Map<String, Object> address = new HashMap<>();
address.put("ID", id);
address.put("CONTACT", contact);
address.put("CODE", Long.parseLong(code));
// Add the address under city
addresses.add(address);
}
// Just use the JSONObject.JSONObject(Map<?, ?>) constructor to get the final result
JSONObject result = new JSONObject(stateToCityToAddresses);
// You can sysout the result to see the data
// System.out.println(result);
return result;
}
Allow me to play Devil's Advocate.
I think you may risk deviating away from the relationships that have been described in the .yaml. You should try to avoid embedding any application-specific logic inside of your data models, since your assumptions may land you in trickier places in the future.
Generally speaking, you should respect the initial form of the data and interpret the relationships or associated logic with the flexibility of runtime processing. Otherwise, you end up serializing data structures which do not correlate directly with the source, and your assumptions may land you in a hot spot.
The "real" JSON equivalent, I suspect; would look something like this:
{
"600450": {
"STATE": "STATE1",
"CITY": "CITY1",
"ID": 1,
"CONTACT": 1234
},
"600453": { ...etc }
}
It would still be possible to pair these relationships. If you want to relate all Objects by city, you could first separate them into bins. You could do this by using a Map which relates a String city to a List of JSONObjects:
// This will be a Map of List of JSONObjects separated by the City they belong to.
final Map<String, List<JSONObject>> mCityBins = new ArrayList();
// Iterate the List of JSONObjects.
for(final JSONObject lJSONObject : lSomeListOfJSONObjects) {
// Fetch the appropriate bin for this kind of JSONObject's city.
List<JSONObject> lBin = mCityBins.get(lJSONObject.get("city"));
// Does the right bin not exist yet?
if (lBin == null) {
// Create it!
lBin = new ArrayList();
// Make sure it is in the Map for next time!
mCityBins.add(lJSONObject.get("city"), lBin);
}
// Add the JSONObject to the selected bin.
lBin.add(lJSONObject);
}
Whilst you process the JSONObjects, whenever you come across a city whose key does not exist in the Map, you can allocate a new List<JSONObject>, add the current item to that List and add it into the Map. For the next JSONObject you process, if it belongs to the same city, you'd find the existing List to add it to.
Once they're separated into bins, generating the corresponding JSON will be easy!
As I see your git repo you just try to convert first Json structure to new Structure you want. I must to tell you probably you could create this structure directly from YAML file.
As I don't see your first Json structure so I guess that must be something like this :
{600450:{STATE:STATE1 , CITY:CITY2 , ...} , ...}
If this is true so this way can help you :
public static JSONObject convert(JSONObject first) throws JSONException {
HashMap<String , HashMap<String , JSONArray>> hashMap = new HashMap<>();
Iterator<String> keys = first.keys();
while (keys.hasNext())
{
String key = keys.next();
JSONObject inner = first.getJSONObject(key);
String state = inner.getString("STATE");
HashMap<String , JSONArray> stateMap =
hashMap.computeIfAbsent(state , s -> new HashMap<>());
String city = inner.getString("CITY");
JSONArray array = stateMap.computeIfAbsent(city , s->new JSONArray());
JSONObject o = new JSONObject();
o.put("ID" , inner.getInt("ID"));
//in this section you could create int key by calling Integer.parse(String s);
o.put("CODE" , Integer.valueOf(key));
o.put("CONTACT" , inner.getInt("CONTACT"));
array.put(o);
}
JSONObject newStructureObject = new JSONObject();
for(String stateKey:hashMap.keySet())
{
JSONArray array = new JSONArray();
JSONObject cityObject = new JSONObject();
HashMap<String , JSONArray> cityMap = hashMap.get(stateKey);
for(String cityKey : cityMap.keySet())
{
cityObject.put(cityKey , cityMap.get(cityKey));
}
array.put(cityObject);
newStructureObject.put(stateKey , array);
}
return newStructureObject;
}
I want to represent this file in my java program.
What I want to do is quickly search through it by "key" value, so for instance, given the value P26 I'd want to return spouse.
Maybe I can read it in as a HashMap using gson as I did with this program.
But what to do about this wonky structure:
{
"properties": {
"P6": "head of government",
"P7": "brother",
...
How could I fit that well into a HashMap? Is HashMap even the best choice?
I've sort of simplified it to this:
{
"P6": "head of government",
"P7": "brother",
"P9": "sister",
"P10": "video",
"P14": "highway marker",
"P15": "road map",
"P16": "highway system",
"P17": "country",
"P18": "image",
I've tried to use this code, but it outputs null
/*
* P values file
*/
String jsonTxt_P = null;
File P_Value_file = new File("properties-es.json");
//read in the P values
if (P_Value_file.exists())
{
InputStream is = new FileInputStream("properties-es.json");
jsonTxt_P = IOUtils.toString(is);
}
Gson gson = new Gson();
Type stringStringMap = new TypeToken<Map<String, String>>(){}.getType();
Map<String,String> map = gson.fromJson(jsonTxt_P, stringStringMap);
System.out.println(map);
It doesn't work because that file is not a Map<String, String>. it has a properties element, which contains a mapping, and a missing element, which contains an array. This mismatch will cause Json to return null, which is what you're seeing. Instead, try doing this:
public class MyData {
Map<String, String> properties;
List<String> missing;
}
And then, to deserialize, do:
MyData data = gson.fromJson(jsonTxt_P, MyData.class);
Map<String, String> stringStringMap = data.properties;
This will make the data structure match the structure of the json, and allow json to properly deserialize.
I have a JSON array which contains objects such as this:
{
"bjones": {
"fname": "Betty",
"lname": "Jones",
"password": "ababab",
"level": "manager"
}
}
my User class has a username which would require the JSON object's key to be used. How would I get the key of my JSON object?
What I have now is getting everything and creating a new User object, but leaving the username null. Which is understandable because my JSON object does not contain a key/value pair for "username":"value".
Gson gson = new Gson();
JsonParser p = new JsonParser();
JsonReader file = new JsonReader(new FileReader(this.filename));
JsonObject result = p.parse(file).getAsJsonObject().getAsJsonObject("bjones");
User newUser = gson.fromJson(result, User.class);
// newUser.username = null
// newUser.fname = "Betty"
// newUser.lname = "Jones"
// newUser.password = "ababab"
// newUser.level = "manager"
edit:
I'm trying to insert "bjones" into newUser.username with Gson, sorry for the lack of clarification
Use entrySet to get the keys. Loop through the entries and create a User for every key.
JsonObject result = p.parse(file).getAsJsonObject();
Set<Map.Entry<String, JsonElement>> entrySet = result.entrySet();
for(Map.Entry<String, JsonElement> entry : entrySet) {
User newUser = gson.fromJson(p.getAsJsonObject(entry.getKey()), User.class);
newUser.username = entry.getKey();
//code...
}
Using keySet() directly excludes the necessity in iteration:
ArrayList<String> objectKeys =
new ArrayList<String>(
myJsonObject.keySet());
Your JSON is fairly simple, so even the manual sort of methods (like creating maps of strings etc for type) will work fine.
For complex JSONs(where there are many nested complex objects and lists of other complex objects inside your JSON), you can create POJO for your JSON with some tool like http://www.jsonschema2pojo.org/
And then just :
final Gson gson = new Gson();
final MyJsonModel obj = gson.fromJson(response, MyJsonModel.class);
// Just access your stuff in object. Example
System.out.println(obj.getResponse().getResults().get(0).getId());
How to convert or cast hashmap to JSON object in Java, and again convert JSON object to JSON string?
You can use:
new JSONObject(map);
Other functions you can get from its documentation
http://stleary.github.io/JSON-java/index.html
Gson can also be used to serialize arbitrarily complex objects.
Here is how you use it:
Gson gson = new Gson();
String json = gson.toJson(myObject);
Gson will automatically convert collections to JSON arrays. Gson can serialize private fields and automatically ignores transient fields.
You can convert Map to JSON using Jackson as follows:
Map<String,Object> map = new HashMap<>();
//You can convert any Object.
String[] value1 = new String[] { "value11", "value12", "value13" };
String[] value2 = new String[] { "value21", "value22", "value23" };
map.put("key1", value1);
map.put("key2", value2);
map.put("key3","string1");
map.put("key4","string2");
String json = new ObjectMapper().writeValueAsString(map);
System.out.println(json);
Maven Dependencies for Jackson :
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-core</artifactId>
<version>2.5.3</version>
<scope>compile</scope>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.5.3</version>
<scope>compile</scope>
</dependency>
If you are using `JSONObject` library, you can convert map to `JSON` as follows:
JSONObject Library:
import org.json.JSONObject;
Map<String, Object> map = new HashMap<>();
// Convert a map having list of values.
String[] value1 = new String[] { "value11", "value12", "value13" };
String[] value2 = new String[] { "value21", "value22", "value23" };
map.put("key1", value1);
map.put("key2", value2);
JSONObject json = new JSONObject(map);
System.out.println(json);
Maven Dependencies for `JSONObject` :
<dependency>
<groupId>org.json</groupId>
<artifactId>json</artifactId>
<version>20140107</version>
</dependency>
Hope this will help. Happy coding.
Example using json
Map<String, Object> data = new HashMap<String, Object>();
data.put( "name", "Mars" );
data.put( "age", 32 );
data.put( "city", "NY" );
JSONObject json = new JSONObject();
json.putAll( data );
System.out.printf( "JSON: %s", json.toString(2) );
output::
JSON: {
"age": 32,
"name": "Mars",
"city": "NY"
}
You can also try to use Google's GSON.Google's GSON is the best library available to convert Java Objects into their JSON representation.
http://code.google.com/p/google-gson/
You can just enumerate the map and add the key-value pairs to the JSONObject
Method :
private JSONObject getJsonFromMap(Map<String, Object> map) throws JSONException {
JSONObject jsonData = new JSONObject();
for (String key : map.keySet()) {
Object value = map.get(key);
if (value instanceof Map<?, ?>) {
value = getJsonFromMap((Map<String, Object>) value);
}
jsonData.put(key, value);
}
return jsonData;
}
In my case I didn't want any dependancies. Using Java 8 you can get JSON as a string this simple:
Map<String, Object> map = new HashMap<>();
map.put("key", "value");
map.put("key2", "value2");
String json = "{"+map.entrySet().stream()
.map(e -> "\""+ e.getKey() + "\":\"" + String.valueOf(e.getValue()) + "\"")
.collect(Collectors.joining(", "))+"}";
Underscore-java library can convert hash map or array list to json and vice verse.
import com.github.underscore.U;
import java.util.*;
public class Main {
public static void main(String[] args) {
Map<String, Object> map = new LinkedHashMap<>();
map.put("1", "a");
map.put("2", "b");
System.out.println(U.toJson(map));
// {
// "1": "a",
// "2": "b"
// }
}
}
Late to the party but here is my GSON adhoc writer for serializing hashmap. I had to write map of key-value pairs as json string attributes, expect one specific to be integer type. I did not want to create custom JavaBean wrapper for this simple usecase.
GSON JsonWriter class is easy to use serializer class containing few strongly typed writer.value() functions.
// write Map as JSON document to http servlet response
Map<String,String> sd = DAO.getSD(123);
res.setContentType("application/json; charset=UTF-8");
res.setCharacterEncoding("UTF-8");
JsonWriter writer = new JsonWriter(new OutputStreamWriter(res.getOutputStream(), "UTF-8"));
writer.beginObject();
for(String key : sd.keySet()) {
String val = sd.get(key);
writer.name(key);
if (key.equals("UniqueID") && val!=null)
writer.value(Long.parseLong(val));
else
writer.value(val);
}
writer.endObject();
writer.close();
If none of the custom types be needed I could have just use toJson() function. gson-2.2.4.jar library is just under 190KB without any brutal dependencies. Easy to use on any custom servlet app or standalone application without big framework integrations.
Gson gson = new Gson();
String json = gson.toJson(myMap);
If you need use it in the code.
Gson gsone = new Gson();
JsonObject res = gsone.toJsonTree(sqlParams).getAsJsonObject();
This is typically the work of a Json library, you should not try to do it yourself. All json libraries should implement what you are asking for, and you can
find a list of Java Json libraries on json.org, at the bottom of the page.
This solution works with complex JSONs:
public Object toJSON(Object object) throws JSONException {
if (object instanceof HashMap) {
JSONObject json = new JSONObject();
HashMap map = (HashMap) object;
for (Object key : map.keySet()) {
json.put(key.toString(), toJSON(map.get(key)));
}
return json;
} else if (object instanceof Iterable) {
JSONArray json = new JSONArray();
for (Object value : ((Iterable) object)) {
json.put(toJSON(value));
}
return json;
}
else {
return object;
}
}
Better be late than never. I used GSON to convert list of HashMap to string if in case you want to have a serialized list.
List<HashMap<String, String>> list = new ArrayList<>();
HashMap<String,String> hashMap = new HashMap<>();
hashMap.add("key", "value");
hashMap.add("key", "value");
hashMap.add("key", "value");
list.add(hashMap);
String json = new Gson().toJson(list);
This json produces [{"key":"value","key":"value","key":"value"}]
Here my single-line solution with GSON:
myObject = new Gson().fromJson(new Gson().toJson(myHashMap), MyClass.class);
For those using org.json.simple.JSONObject, you could convert the map to Json String and parse it to get the JSONObject.
JSONObject object = (JSONObject) new JSONParser().parse(JSONObject.toJSONString(map));
I found another way to handle it.
Map obj=new HashMap();
obj.put("name","sonoo");
obj.put("age",new Integer(27));
obj.put("salary",new Double(600000));
String jsonText = JSONValue.toJSONString(obj);
System.out.print(jsonText);
Hope this helps.
Thanks.
If you don't really need HashMap then you can do something like that:
String jsonString = new JSONObject() {{
put("firstName", user.firstName);
put("lastName", user.lastName);
}}.toString();
Output:
{
"firstName": "John",
"lastName": "Doe"
}
we use Gson.
Gson gson = new Gson();
Type gsonType = new TypeToken<HashMap>(){}.getType();
String gsonString = gson.toJson(elements,gsonType);
If you are using net.sf.json.JSONObject then you won't find a JSONObject(map) constructor in it. You have to use the public static JSONObject fromObject( Object object ) method. This method accepts JSON formatted strings, Maps, DynaBeans and JavaBeans.
JSONObject jsonObject = JSONObject.fromObject(myMap);
No need for Gson or JSON parsing libraries.
Just using new JSONObject(Map<String, JSONObject>).toString(), e.g:
/**
* convert target map to JSON string
*
* #param map the target map
* #return JSON string of the map
*/
#NonNull public String toJson(#NonNull Map<String, Target> map) {
final Map<String, JSONObject> flatMap = new HashMap<>();
for (String key : map.keySet()) {
try {
flatMap.put(key, toJsonObject(map.get(key)));
} catch (JSONException e) {
e.printStackTrace();
}
}
try {
// 2 indentSpaces for pretty printing
return new JSONObject(flatMap).toString(2);
} catch (JSONException e) {
e.printStackTrace();
return "{}";
}
}
I'm using Alibaba fastjson, easy and simple:
<dependency>
<groupId>com.alibaba</groupId>
<artifactId>fastjson</artifactId>
<version>VERSION_CODE</version>
</dependency>
and import:
import com.alibaba.fastjson.JSON;
Then:
String text = JSON.toJSONString(obj); // serialize
VO vo = JSON.parseObject("{...}", VO.class); //unserialize
Everything is ok.
If you are using JSR 374: Java API for JSON Processing ( javax json )
This seems to do the trick:
JsonObjectBuilder job = Json.createObjectBuilder((Map<String, Object>) obj);
JsonObject jsonObject = job.build();
Gson way for a bit more complex maps and lists using TypeToken.getParameterized method:
We have a map that looks like this:
Map<Long, List<NewFile>> map;
We get the Type using the above mentioned getParameterized method like this:
Type listOfNewFiles = TypeToken.getParameterized(ArrayList.class, NewFile.class).getType();
Type mapOfList = TypeToken.getParameterized(LinkedHashMap.class, Long.class, listOfNewFiles).getType();
And then use the Gson object fromJson method like this using the mapOfList object like this:
Map<Long, List<NewFile>> map = new Gson().fromJson(fileContent, mapOfList);
The mentioned object NewFile looks like this:
class NewFile
{
private long id;
private String fileName;
public void setId(final long id)
{
this.id = id;
}
public void setFileName(final String fileName)
{
this.fileName = fileName;
}
}
The deserialized JSON looks like this:
{
"1": [
{
"id": 12232,
"fileName": "test.html"
},
{
"id": 12233,
"fileName": "file.txt"
},
{
"id": 12234,
"fileName": "obj.json"
}
],
"2": [
{
"id": 122321,
"fileName": "test2.html"
},
{
"id": 122332,
"fileName": "file2.txt"
},
{
"id": 122343,
"fileName": "obj2.json"
}
]
}
You can use XStream - it is really handy. See the examples here
package com.thoughtworks.xstream.json.test;
import com.thoughtworks.xstream.XStream;
import com.thoughtworks.xstream.io.json.JettisonMappedXmlDriver;
public class WriteTest {
public static void main(String[] args) {
HashMap<String,String> map = new HashMap<String,String>();
map.add("1", "a");
map.add("2", "b");
XStream xstream = new XStream(new JettisonMappedXmlDriver());
System.out.println(xstream.toXML(map));
}
}
If you use complex objects, you should apply enableComplexMapKeySerialization(), as stated in https://stackoverflow.com/a/24635655/2914140 and https://stackoverflow.com/a/26374888/2914140.
Gson gson = new GsonBuilder().enableComplexMapKeySerialization().create();
Map<Point, String> original = new LinkedHashMap<Point, String>();
original.put(new Point(5, 6), "a");
original.put(new Point(8, 8), "b");
System.out.println(gson.toJson(original));
Output will be:
{
"(5,6)": "a",
"(8,8)": "b"
}
import org.json.JSONObject;
HashMap<Object, Object> map = new HashMap<>();
String[] list={"Grader","Participant"};
String[] list1={"Assistant","intern"};
map.put("TeachingAssistant",list);
map.put("Writer",list1);
JSONObject jsonObject = new JSONObject(map);
System.out.printf(jsonObject.toString());
// Result: {"TeachingAssistant":["Grader","Participant"],"Writer":["Assistant","intern"]}
You can use Gson.
This library provides simple methods to convert Java objects to JSON objects and vice-versa.
Example:
GsonBuilder gb = new GsonBuilder();
Gson gson = gb.serializeNulls().create();
gson.toJson(object);
You can use a GsonBuilder when you need to set configuration options other than the default. In the above example, the conversion process will also serialize null attributes from object.
However, this approach only works for non-generic types. For generic types you need to use toJson(object, Type).
More information about Gson here.
Remember that the object must implement the Serializable interface.
this works for me :
import groovy.json.JsonBuilder
properties = new Properties()
properties.put("name", "zhangsan")
println new JsonBuilder(properties).toPrettyString()
I faced a similar problem when deserializing the Response from custom commands in selenium. The response was json, but selenium internally translates that into a java.util.HashMap[String, Object]
If you are familiar with scala and use the play-API for JSON, you might benefit from this:
import play.api.libs.json.{JsValue, Json}
import scala.collection.JavaConversions.mapAsScalaMap
object JsonParser {
def parse(map: Map[String, Any]): JsValue = {
val values = for((key, value) <- map) yield {
value match {
case m: java.util.Map[String, _] #unchecked => Json.obj(key -> parse(m.toMap))
case m: Map[String, _] #unchecked => Json.obj(key -> parse(m))
case int: Int => Json.obj(key -> int)
case str: String => Json.obj(key -> str)
case bool: Boolean => Json.obj(key -> bool)
}
}
values.foldLeft(Json.obj())((temp, obj) => {
temp.deepMerge(obj)
})
}
}
Small code description:
The code recursively traverses through the HashMap until basic types (String, Integer, Boolean) are found. These basic types can be directly wrapped into a JsObject. When the recursion is unfolded, the deepmerge concatenates the created objects.
'#unchecked' takes care of type erasure warnings.
First convert all your objects into valid Strings
HashMap<String, String> params = new HashMap<>();
params.put("arg1", "<b>some text</b>");
params.put("arg2", someObject.toString());
Then insert the entire map into a org.json.JSONObject
JSONObject postData = new JSONObject(params);
Now you can get the JSON by simply calling the object's toString
postData.toString()
//{"arg1":"<b>some text<\/b>" "arg2":"object output"}
Create a new JSONObject
JSONObject o = new JSONObject(postData.toString());
Or as a byte array for sending over HTTP
postData.toString().getBytes("UTF-8");